¡¾ÌâÄ¿¡¿¸ñÊÏÊÔ¼Á£¨RMgX£©ÊÇÓлú·´Ó¦ÖеÄÒ»ÖÖÖØÒªÊÔ¼Á£¬ËüµÄÖÆ·¨Îª£º£¨RΪÌþ»ù£¬XΪ±ËØ£©¡£
ÏÖÓÃÒÒÏ©ºÍÊʵ±µÄÎÞ»úÎïºÏ³ÉÒÒËáÒ춡õ¥µÄ¹ý³ÌÈçÏ£¨·´Ó¦Ìõ¼þûÓÐÁгö£©£º
ÊԻشðÏÂÁÐÎÊÌ⣺
£¨1£©ÉÏÊö¹ý³ÌÖУ¬ÊôÓÚ£¨»ò°üº¬£©¼Ó³É·´Ó¦µÄÊÇ________________________£¨ÌîÐòºÅ£©¡£
£¨2£©AÖÐËùº¬¹ÙÄÜÍŵÄÃû³ÆÊÇ____________£»CÖÐËùº¬¹ÙÄÜÍŵÄÃû³ÆÊÇ____________¡£
£¨3£©ÓÃϵͳÃüÃû·¨¶ÔFÃüÃû£¬ÆäÃû³ÆÊÇ________________________¡£
£¨4£©Ð´³öEµÄ½á¹¹¼òʽ________________________¡£
£¨5£©·´Ó¦¢ÚµÄ»¯Ñ§·½³Ìʽ____________________________________¡£
£¨6£©·´Ó¦¢ßµÄ»¯Ñ§·½³Ìʽ____________________________________¡£
£¨7£©BÓëÒø°±ÈÜÒº·´Ó¦µÄ·½³Ìʽ____________________________________¡£
£¨8£©Ð´³öCµÄÁ½¸ö²»Í¬ÀàµÄÓлúÎïµÄÒì¹¹Ìå____________£»____________¡£
¡¾´ð°¸¡¿ ¢Ù¢Ü¢Þ ôÇ»ù ôÈ»ù 2-¶¡´¼ CH3CH2MgX 2CH3CH2OH+O22CH3CHO+2H2O CH3CH2CH£¨OH£©CH3+CH3COOHCH3COOCH(CH3)CH2CH3+H2O CH3CHO+2Ag£¨NH3£©2OHCH3COONH4+3NH3¡ü+2Ag+H2O HCOOCH3 HOCH2CHO
¡¾½âÎö¡¿ÒÒÏ©ÓëË®·¢Éú¼Ó³É·´Ó¦Éú³ÉAΪCH3CH2OH£¬ÒÒ´¼·¢Éú´ß»¯Ñõ»¯Éú³ÉBΪCH3CHO£¬ÒÒÈ©½øÒ»²½·¢ÉúÑõ»¯·´Ó¦Éú³ÉCΪCH3COOH¡£ÒÒÏ©ÓëHX·¢Éú¼Ó³É·´Ó¦Éú³ÉDΪCH3CH2X£¬DÓëMgÔÚÒÒÃÑÌõ¼þÏ·¢Éú·´Ó¦Éú³ÉEΪCH3CH2MgX£¬EÓëÒÒÈ©·¢Éú¼Ó³É·´Ó¦²¢Ë®½âÉú³ÉFΪCH3CH2CH£¨OH£©CH3£¬ÓëÒÒËá·¢Éúõ¥»¯·´Ó¦µÃµ½ÒÒËáÒ춡õ¥£¬Ôò
£¨1£©¸ù¾ÝÒÔÉÏ·ÖÎö¿ÉÖªÉÏÊö¹ý³ÌÖУ¬ÊôÓÚ£¨»ò°üº¬£©¼Ó³É·´Ó¦µÄÊǢ٢ܢޡ££¨2£©AÊÇÒÒ´¼£¬ÆäÖÐËùº¬¹ÙÄÜÍŵÄÃû³ÆÊÇôÇ»ù£»CÊÇÒÒËᣬÆäÖÐËùº¬¹ÙÄÜÍŵÄÃû³ÆÊÇôÈ»ù¡££¨3£©FΪCH3CH2CH£¨OH£©CH3£¬ÆäÃû³ÆÊÇ2-¶¡´¼¡££¨4£©EµÄ½á¹¹¼òʽΪCH3CH2MgX¡££¨5£©·´Ó¦¢ÚÊÇÒÒ´¼·¢ÉúÑõ»¯·´Ó¦Éú³ÉÒÒÈ©£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º2CH3CH2OH+O22CH3CHO+2H2O¡££¨6£©·´Ó¦¢ßÊÇõ¥»¯·´Ó¦£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪCH3CH2CH£¨OH£©CH3+CH3COOHCH3COOCH(CH3)CH2CH3+H2O¡££¨7£©BÓëÒø°±ÈÜÒº·´Ó¦µÄ·½³ÌʽΪCH3CHO+2Ag£¨NH3£©2OHCH3COONH4+3NH3¡ü+2Ag+H2O¡££¨8£©CÊÇÒÒËᣬCµÄÁ½¸ö²»Í¬ÀàµÄÓлúÎïµÄÒì¹¹ÌåΪHCOOCH3¡¢HOCH2CHO¡£
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
¡¾ÌâÄ¿¡¿Ä³ÈÜÒºÖпÉÄܺ¬ÓдóÁ¿µÄMg2£«¡¢Al3£«¡¢H£«¡¢Cl£ºÍÉÙÁ¿OH££¬Ïò¸ÃÈÜÒºÖÐÖðµÎ¼ÓÈë0.5 mol¡¤L£1NaOHÈÜÒº£¬Éú³É³ÁµíµÄÖÊÁ¿ºÍ¼ÓÈëNaOHÈÜÒºµÄÌå»ýÖ®¼äµÄ¹ØϵÈçÏÂͼËùʾ£¬Ôò¿ÉÅжÏÔÈÜÒºÖÐ(¡¡¡¡)
A. ÓÐMg2£«£¬Ã»ÓÐAl3£«
B. ÓÐAl3£«£¬Ã»ÓÐMg2£«
C. ÓÐMg2£«ºÍAl3£«
D. ÓдóÁ¿µÄH£«¡¢Mg2£«ºÍAl3£«
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
¡¾ÌâÄ¿¡¿ÖÜÆÚ±íÇ°ËÄÖÜÆÚµÄÔªËØa¡¢b¡¢c¡¢d¡¢e£¬Ô×ÓÐòÊýÒÀ´ÎÔö´ó£¬aºÍbÊÇ×é³ÉÎïÖÊÖÖÀà×î¶àµÄÔªËØ£¬cÊǵؿÇÖк¬Á¿×î¶àµÄÔªËØ£¬dÓëbͬ×壬e2+Àë×ÓµÄ3d¹ìµÀÖÐÓÐ9¸öµç×Ó¡£»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©c¡¢dÁ½ÖÖÔªËØÐγɵĻ¯ºÏÎïͳ³Æ¹èʯ£¬¿Éͨ¹ý______________·½·¨Çø·ÖÆä½á¾§ÐκÍÎÞ¶¨ÐεÄÁ½ÖÖ´æÔÚÐÎ̬£¬cµÄµç×ÓÅŲ¼Í¼Îª_______________________¡£
£¨2£©AºÍBÊÇÉú»îÖÐÁ½ÖÖ³£¼ûµÄÓлúÎAÄÜÓëCaCO3·´Ó¦£¬¿ÉÓÃÓÚ³ø·¿³ýË®¹¸£»B·Ö×ÓÖеÄ̼Ô×ÓÊýÄ¿ÓëAÖÐÏàͬ£¬¿É·¢ÉúÒø¾µ·´Ó¦¡£AÖдæÔÚ»¯Ñ§¼üµÄÀàÐÍÊÇ______£»
A.Àë×Ó¼ü B.¼«ÐÔ¼ü C.·Ç¼«ÐÔ¼ü D.¦Ò¼ü E.¦Ð¼ü
B·Ö×Ó¹ÙÄÜÍÅÖÐ̼Ô×ӵĹìµÀÔÓ»¯ÀàÐÍÊÇ____¡£
£¨3£©Óá°>¡±»ò¡°<¡±Ìî¿Õ£º
µÚÒ»µçÀëÄÜ | ÈÛµã |
b___d | dc2¾§Ìå___d¾§Ìå |
£¨4£©cÓëeÁ½ÖÖÔªËØ¿ÉÐγÉÒ»ÖÖ°ëµ¼Ìå²ÄÁÏ£¬»¯Ñ§Ê½Îªe2c£¬ÔÚÆäÁ¢·½¾§°ûÄÚ²¿ÓÐËĸöcÔ×Ó£¬ÆäÓàcÔ×ÓλÓÚÃæÐĺͶ¥µã£¬Ôò¸Ã¾§°ûÖÐÓÐ____¸öeÔ×Ó£¬eÔªËØλÓÚÔªËØÖÜÆÚ±íµÄ_______Çø¡£
£¨5£©Ïòe2+ÁòËáÑεÄË®ÈÜÒºÖмÓÈë¹ýÁ¿µÄ°±Ë®£¬¿ÉµÃµ½ÉîÀ¶É«Í¸Ã÷ÈÜÒº£¬¼ÓÈëÒÒ´¼¿ÉÎö³öÉîÀ¶É«¾§Ì壬ÇëÊéдÎö³ö¾§ÌåµÄÀë×Ó·½³Ìʽ___________________¡£
£¨6£©eµ¥ÖÊΪÃæÐÄÁ¢·½¾§Ì壬ÆäÔ×Ӱ뾶Ϊrcm£¬Æ侧°ûÀⳤΪa nm£¬Ôòeµ¥ÖʵÄÃܶÈΪ__________g¡¤cm-3£¬Æä¿Õ¼äÀûÓÃÂʵļÆËãʽΪ_______________________¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
¡¾ÌâÄ¿¡¿ÀûÓÃÏÂͼËùʾʵÑé×°ÖÃÄÜÑéÖ¤ÈÈÎȶ¨ÐÔNa2CO3Ç¿ÓÚNaHCO3¡£Çë»Ø´ð:
(1) NaHCO3ÊÜÈÈ·Ö½âµÄ»¯Ñ§·½³ÌʽÊÇ_________¡£
(2)Ö¤Ã÷ÈÈÎȶ¨ÐÔNa2CO3Ç¿ÓÚNaHCO3µÄʵÑéÏÖÏóÊÇ_________¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
¡¾ÌâÄ¿¡¿µç×Ó¹¤Òµ³£ÓÃFeCl3ÈÜÒº¸¯Ê´¾øÔµ°åÉϵÄͲ£¬ÖÆÔìÓ¡Ë¢µç·°å¡£´Ó¸¯Ê´·ÏÒº(Ö÷Òªº¬FeCl3¡¢FeCl2¡¢CuCl2 )ÖлØÊÕÍ£¬²¢ÖØлñµÃFeCl3ÈÜÒº¡£·ÏÒº´¦ÀíÁ÷³ÌÈçÏ£º
£¨1£©²½Öè(¢ñ)ÖзÖÀë²Ù×÷Ãû³Æ ÊÇ____________¡£
£¨2£©³ÁµíBÖÐÖ÷Òªº¬ÓÐ_________£¬ÆøÌåDÊÇ______________£»
£¨3£©Ð´³ö²½Öè(¢ó)ÖÐÉú³ÉFeCl3µÄ»¯Ñ§·½³Ìʽ____________________£»
£¨4£©²½Öè(¢ó)ÖУ¬½«ÂÈÆø»»³ÉH2O2Ò²ÄܴﵽͬÑùµÄÄ¿µÄ£¬Ð´³öH2O2½«Fe2+Ñõ»¯ÎªFe3+µÄÀë×Ó·½³Ìʽ:_______________________¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
¡¾ÌâÄ¿¡¿ÏÂÁÐÀë×ÓÔÚÈÜÒºÖпÉÒÔ´óÁ¿¹²´æµÄÒ»×éÊÇ£¨£©
A. H+ Na+ OH£ B. Na+ NO3£ Cl£
C. K+ H+ HCO3£ D. Ca2+ SO42£ CO32£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
¡¾ÌâÄ¿¡¿Ä³ï®Àë×Óµç³Ø¹¤×÷ÔÀíÈçÏÂͼËùʾ£¬µç³Ø·´Ó¦Îª£ºLi1£xCoO2£«LixCLiCoO2£«C¡£ÏÂÁÐ˵·¨²»ÕýÈ·µÄÊÇ
A. ·Åµçʱ£¬µç×Ó´Ób¼«¾ÓõçÆ÷Á÷Ïòa¼«
B. ·Åµçʱ£¬ÈôתÒÆ1mol e££¬Ì¼²ÄÁϽ«ÔöÖØ7 g
C. ³äµçʱ£¬ï®Àë×Óͨ¹ý¸ôĤ½øÈëÓÒÊÒ
D. ³äµçʱ£¬a¼«·´Ó¦£ºLiCoO2£xe£= Li1-xCoO2£«xLi+
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
¡¾ÌâÄ¿¡¿°±ÊÇÖØÒªµÄÎÞ»ú»¯¹¤²úÆ·Ö®Ò»£¬ÔÚ¹úÃñ¾¼ÃÖÐÕ¼ÓÐÖØÒªµØλ¡£ÎÒ¹ú²ÉÓÃÌú´¥Ã½(ÒÔÌúΪÖ÷µÄ»ìºÏÎï)×ö´ß»¯¼ÁºÏ³É°±¡£»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©Fe»ù̬Ô×ÓºËÍâµç×ÓÅŲ¼Ê½Îª____¡£µª»¯ÌúÊÇÒ»ÖÖÖØÒªµÄÎÞ»ú»¯ºÏÎ²»ÈÜÓÚË®£¬±©Â¶ÔÚ³±Êª»·¾³ÖпÉÊͷųö°±Æø£¬ÔªËØFeºÍNÖУ¬µÚÒ»µçÀëÄܽϴóµÄÊÇ_____£¬»ù̬Ô×ÓºËÍâδ³É¶Ôµç×ÓÊý½Ï¶àµÄÊÇ_______¡£
£¨2£©NµÄÑõ»¯ÎïÓÐN2OµÈ£¬N2OÓëCO2»¥ÎªµÈµç×ÓÌ壬N2OµÄ¿Õ¼ä¹¹ÐÍΪ__________¡£
£¨3£©NÓжàÖÖÇ⻯ÎÆäÖÐëÂ(N2H4)³£ÓÃ×÷»ð¼ýÍƽø¼ÁµÄȼÁÏ£¬N2H4ÖÐNÔ×ÓµÄÔÓ»¯ÐÎʽΪ____¡£
£¨4£©N¡¢P¡¢AsΪͬ×åÔªËØ£¬NH3¡¢PH3¡¢AsH3ÈýÖÖÎïÖʵķеãÓɸߵ½µÍµÄ˳ÐòΪ_____¡£ÔÒòÊÇ____¡£
£¨5£©K3[Fe(CN)6]³£ÓÃÓÚ¼ìÑéFe2£«£¬K3[Fe(CN)6]ÖдæÔڵĻ¯Ñ§¼üÀàÐÍÓÐ_______¡£
£¨6£©FeO¾§ÌåµÄ¾§°ûÓëNaClµÄÏàËÆ£¬NaClµÄ¾§°ûÈçͼËùʾ¡£ÓÉÓÚ¾§ÌåȱÏÝ£¬Ä³Ñõ»¯ÑÇÌú¾§ÌåµÄʵ¼Ê×é³ÉΪFe0.9O£¬ÆäÖаüº¬ÓÐFe2£«ºÍFe3£«£¬¾§°û±ß³¤Îª428pm£¬Ôò¸Ã¾§ÌåµÄÃܶÈΪ____g/cm3(Áгö¼ÆËãʽ¼´¿É£¬ÓÃNA±íʾ°¢·ü¼ÓµÂÂÞ³£ÊýµÄÖµ)¡£
¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
¡¾ÌâÄ¿¡¿ÒÀ¾Ý2Fe2£«£«Cl2£½2Fe3£«£«Cl££»2Fe3£«£«Cu£½2Fe2£«£«Cu2£«£»Fe£«Cu2£«£½Fe2£«£«CuÉÏÊö·´Ó¦ÅжÏÑõ»¯¼ÁµÄÑõ»¯ÐÔÇ¿Èõ˳ÐòÕýÈ·µÄÊÇ
A.Cl2£¾Fe3£«£¾Cu2£«B.Fe3£«£¾Cl2£¾Cu2£«
C.Cu2£«£¾Fe3£«£¾Cl2D.Cl2£¾Cu2£«£¾Fe3£«
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com