ÐÂÖÆÂÈË®Öк¬ÓжàÖÖÁ£×Ó,ijУ»¯Ñ§Ñо¿ÐÔѧϰС×éµÄͬѧΪ̽¾¿ÆäÐÔÖÊ,×öÁËÈçÏÂʵÑé,ÇëÄã°ïÖúÍê³É£º

£¨1£©ÂÈÆøÄÜʹʪÈóµÄºìÉ«²¼ÌõÍÊÉ«¡£Ê¹ÆäÍÊÉ«µÄ΢Á£µÄ»¯Ñ§Ê½ÊÇ______         

£¨2£©½«ÂÈË®ÔÚ¹âÕÕÉÏÒ»¶Îʱ¼ä£¬ÈÜÒºÑÕÉ«Öð½¥±ädz£¬ÆäÓйط´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º

                                  ¡¢                         

£¨3£©Æ½ºâ³£Êý±íÃ÷ÁË·â±ÕÌåϵµÄ¿ÉÄæ·´Ó¦ÔÚ¸ø¶¨µÄζÈϽøÐеij̶ȣ¬¶ÔÓÚͬһ¸öÀàÐ͵ķ´Ó¦£¬Æ½ºâ³£ÊýÔ½´ó£¬±íÃ÷·´Ó¦½øÐеij̶ÈÔ½´ó¡£

H2CO3   £«H£«           Ka1£¨H2CO3£©=4.45¡Á10¡ª7

    £«H£«             Ka2(HCO3£­)=5.61¡Á10£­11

HclO  H£«£«                Ka(HClO)=2.95¡Á10£­8

ÇëÒÀ¾ÝÒÔÉϵçÀëƽºâ³£Êý£¬Çëд³ö½«ÉÙÁ¿µÄÂÈÆøͨÈëµ½¹ýÁ¿µÄ̼ËáÄÆÈÜÒºÖÐËù·¢Éú·´Ó¦µÄÀë×Ó·½³Ìʽ£º¡¡                                                               

£¨4£©±¥ºÍÂÈË®Óëʯ»ÒʯµÄ·´Ó¦ÊÇÖÆÈ¡½ÏŨHClOÈÜÒºµÄ·½·¨Ö®Ò»¡£

ʵÑéÒ»¡¢¶¨ÐÔÑо¿£º

¢Ù   ÔÚÊÔ¹ÜÖмÓÈë¹ýÁ¿µÄ¿é״̼Ëá¸Æ£¬ÔÙ¼ÓÈëÔ¼20mL±¥ºÍÂÈË®£¬³ä·Ö·´Ó¦£¬

 ÓÐÉÙÁ¿ÆøÅݲúÉú£¬ÈÜҺdz»ÆÂÌÉ«ÍÊÈ¥£»

¢Ú ¹ýÂË£¬½«ÂËÒºµÎÔÚÓÐÉ«²¼ÌõÉÏ£¬·¢ÏÖÆä±ÈÂÈË®µÄƯ°×ÐÔ¸üÇ¿£»

¢Û ΪÁËÈ·¶¨·´Ó¦²úÎ½«ÂËÒº·ÖΪÈý·Ý£¬·Ö±ð½øÐÐÒÔÏÂʵÑ飺

µÚÒ»·ÝÓëʯ»ÒË®»ìºÏ£¬Á¢¼´²úÉú´óÁ¿°×É«³Áµí£»

µÚ¶þ·ÝÓëÏ¡ÑÎËá»ìºÏ£¬Á¢¼´²úÉú´óÁ¿ÎÞÉ«ÆøÌ壻

½«µÚÈý·Ý¼ÓÈÈ£¬¿´µ½ÈÜÒº±ä»ë×ÇÇÒÓдóÁ¿ÎÞÉ«ÆøÌå²úÉú¡£    

¾­¼ì²â£¬ÉÏÊöʵÑéÖвúÉúµÄÎÞÉ«ÆøÌå¾ùΪCO2¡£

Çë»Ø´ð£º

¢Ù ·´Ó¦ºóËùµÃµÄÈÜҺƯ°×ÐÔÔöÇ¿µÄÔ­ÒòÊÇ______  ___________             ____                           

¢ÚÒÀ¾ÝÉÏÊöʵÑé¿ÉÍÆÖª£º¢ÚµÄÂËÒºÖеÄÈÜÖʳýCaCl2¡¢HClOÍ⣬»¹º¬ÓÐ______ _                                ¡£

ʵÑé¶þ¡¢¶¨Á¿Ñо¿£º                              

ÔÚÔ²µ×ÉÕÆ¿µ×²¿£¬ÓÐÒ»ÓÃËÜÁÏÍø°üסµÄ¹ýÁ¿¿é×´  ̼Ëá¸ÆºÍ150mL±¥ºÍÂÈË®£¬°´ÈçͼËùʾװÖÃʵÑ飬´ý²»ÔÙ²úÉúÆøÅݺ󣬽«ËÜÁÏÍøÖÐÊ£ÓàµÄʯ»ÒʯÌá³öÒºÃ棬ÃÜ·âºóÔÙ¼ÓÈÈ¡¢Öó·ÐÉÕÆ¿ÖеÄÒºÌ壬ֱµ½Á¿Í²ÖеÄÆøÌå²»ÔÙÔö¼Ó£¨²»¿¼ÂÇHClOµÄ·Ö½â£©¡£

Çë»Ø´ð£º

¢Û д³öÒÇÆ÷£¨1£©ÓëÒÇÆ÷£¨3£©µÄÃû³Æ

£¨1£©           £¨3£©               

¢Ü Ϊ¼õÉÙÓÃ×°ÖâóÊÕ¼¯ÆøÌå¹ý³ÌÖÐCO2ÒòÈܽâ¶øÔì³ÉµÄËðʧ£¬ÇÒË®²ÛÖÐÈÔȻΪˮ£¬ÇëÄã¶Ô×°Öâó½øÐиĽø£¬×î¼òµ¥µÄ·½·¨ÊÇ                                ¡£

¢Ý ÈçºÎ׼ȷ¶Á³öÁ¿Í²ÖÐÆøÌåµÄÌå»ý

a________      _    

b ÉÏÏÂÒƶ¯Á¿Í²ÖÁÁ¿Í²ÄÚÒºÃæÓëË®²ÛÒºÃæÏàƽ

c                                       

 

£¨1£©   £¨1·Ö£© 

£¨2£©++ £¨1·Ö£© 

        2  2+    £¨1·Ö£©

£¨3£©+2+ 2++   £¨2·Ö£©

£¨4£©¢ÙÏûºÄÁËÂÈË®Öеģ¬Ê¹++ƽºâÏòÓÒÒƶ¯ Ũ¶ÈÔö´ó£¨2·Ö£©

¢Ú  £¨Ð´Ãû³ÆÒ²¶Ô£©2·Ö

¢Û£¨1£©Ô²µ×ÉÕÆ¿  £¨1·Ö£©  £¨3£©Á¿Í²£¨1·Ö£©

¢ÜÔÚµ¼¹ÜÄ©¶ËÔÙÁ¬½Ó³¤µ¼¹Ü£¬Ê¹µ¼¹ÜµÄ³ö¿Ú½Ó½üÁ¿Í²µ×²¿£¨2·Ö£©

¢ÝaÉÕÆ¿ÀäÈ´ÖÁÊÒΠ£¨1·Ö£©    cƽÊӿ̶ÈÏ߶ÁÊý£¨1·Ö£©

½âÎö:ÂÔ

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â

ÐÂÖÆÂÈË®Öк¬ÓжàÖÖÁ£×Ó£¬Ä³Ð£»¯Ñ§Ñо¿ÐÔѧϰС×éµÄͬѧΪ̽¾¿ÆäÐÔÖÊ£¬×öÁËÈçÏÂʵÑ飬ÇëÄã°ïÖúÍê³É£º
£¨1£©HClO²»Îȶ¨£¬¼û¹âÒ×·Ö½âÉú³ÉHClºÍO2£¬ÇëÉè¼ÆʵÑéÖ¤Ã÷ÓÐO2Éú³É£®
½«Ê¢ÂúÂÈË®µÄÎÞÉ«ËÜÁÏÆ¿µ¹ÖÃÔÚË®²ÛÖУ¬¹âÕÕÒ»¶Îʱ¼äºó£¬ÓÐÎÞÉ«ÆøÌåÉú³É£¬½«Æ¿×Óµ¹×ª¹ýÀ´£¬Óôø»ðÐǵÄľÌõ²åÈëÆ¿¿Ú¼ìÑéÆøÌ壬ÈôľÌõ¸´È¼£¬Ö¤Ã÷HClO·Ö½âÉú³ÉµÄÆøÌåΪÑõÆø
½«Ê¢ÂúÂÈË®µÄÎÞÉ«ËÜÁÏÆ¿µ¹ÖÃÔÚË®²ÛÖУ¬¹âÕÕÒ»¶Îʱ¼äºó£¬ÓÐÎÞÉ«ÆøÌåÉú³É£¬½«Æ¿×Óµ¹×ª¹ýÀ´£¬Óôø»ðÐǵÄľÌõ²åÈëÆ¿¿Ú¼ìÑéÆøÌ壬ÈôľÌõ¸´È¼£¬Ö¤Ã÷HClO·Ö½âÉú³ÉµÄÆøÌåΪÑõÆø
£®
£¨2£©ÂÈÆøÄÜʹʪÈóµÄºìÉ«²¼ÌõÍÊÉ«£®¶ÔÓÚʹºìÉ«²¼ÌõÍÊÉ«µÄÎïÖÊ£¬Í¬Ñ§ÃǵĿ´·¨²»Ò»Ö£¬ÈÏΪÂÈË®ÖдæÔڵļ¸ÖÖÁ£×Ó¶¼ÓпÉÄÜ£®ÇëÄãÉè¼ÆʵÑ飬µÃ³öÕýÈ·½áÂÛ£®
Ìá³öÎÊÌ⣺ÂÈË®ÖкÎÖÖÎïÖÊÄÜʹʪÈóµÄºìÉ«²¼ÌõÍÊÉ«
ÊÕ¼¯×ÊÁÏ£º¢ÙÂÈÆøÓÐÇ¿Ñõ»¯ÐÔ£»¢ÚÂÈÆøÓëÀäË®·´Ó¦Éú³ÉÑÎËáºÍ´ÎÂÈË᣻¢Û´ÎÂÈËáÓÐÇ¿Ñõ»¯ÐÔ
Ìá³ö¼ÙÉ裺
¢Ù
ÂÈÆøʹ²¼ÌõÍÊÉ«
ÂÈÆøʹ²¼ÌõÍÊÉ«
£»
¢Ú
´ÎÂÈËáʹ²¼ÌõÍÊÉ«
´ÎÂÈËáʹ²¼ÌõÍÊÉ«
£»
¢Û
ÑÎËáʹ²¼ÌõÍÊÉ«
ÑÎËáʹ²¼ÌõÍÊÉ«
£»
¢ÜH2Oʹ²¼ÌõÍÊÉ«
£¨3£©ÑéÖ¤¼ÙÉ裺ʵÑé¢Ù£º°ÑºìÉ«¸É²¼Ìõ·ÅÈë³äÂúÂÈÆøµÄ¼¯ÆøÆ¿ÖУ¬²¼Ìõ²»ÍÊÉ«
ʵÑé¢Ú£º
°ÑºìÉ«²¼ÌõÉìÈëÂÈË®ÖУ¬ºìÉ«²¼ÌõÍÊÉ«
°ÑºìÉ«²¼ÌõÉìÈëÂÈË®ÖУ¬ºìÉ«²¼ÌõÍÊÉ«

ʵÑé¢Û£º
°ÑºìÉ«²¼ÌõÉìÈëÏ¡ÑÎËáÖУ¬ºìÉ«²¼Ìõ²»ÍÊÉ«
°ÑºìÉ«²¼ÌõÉìÈëÏ¡ÑÎËáÖУ¬ºìÉ«²¼Ìõ²»ÍÊÉ«

ʵÑé¢Ü£º°ÑºìÉ«²¼Ìõ·ÅÔÚË®Àï²¼Ìõ²»ÍÊÉ«
µÃ³ö½áÂÛ£º
´ÎÂÈËáʹÓÐÉ«²¼ÌõÍÊÉ«
´ÎÂÈËáʹÓÐÉ«²¼ÌõÍÊÉ«
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÐÂÖÆÂÈË®Öк¬ÓжàÖÖÁ£×Ó£¬Ä³Ð£»¯Ñ§Ñо¿ÐÔѧϰС×éµÄͬѧΪ̽¾¿ÆäÐÔÖÊ£¬×öÁËÈçÏÂʵÑ飬ÇëÄã°ïÖúÍê³É£º
£¨1£©HClO²»Îȶ¨£¬¼û¹âÒ×·Ö½âÉú³ÉHClºÍO2£¬ÇëÉè¼ÆʵÑéÖ¤Ã÷ÓÐO2Éú³É£®
 
£®
£¨2£©ÂÈÆøÄÜʹʪÈóµÄºìÉ«²¼ÌõÍÊÉ«£®¶ÔÓÚʹºìÉ«²¼ÌõÍÊÉ«µÄÎïÖÊ£¬Í¬Ñ§ÃǵĿ´·¨²»Ò»Ö£¬ÈÏΪÂÈË®ÖдæÔڵļ¸ÖÖÁ£×Ó¶¼ÓпÉÄÜ£®ÇëÄãÉè¼ÆʵÑ飬µÃ³öÕýÈ·½áÂÛ£®
Ìá³öÎÊÌâ ÊÕ¼¯×ÊÁÏ Ìá³ö¼ÙÉè ÑéÖ¤¼ÙÉè µÃ³ö½áÂÛ
ÂÈË®ÖкÎÖÖÎïÖÊÄÜʹʪÈóµÄºìÉ«²¼ÌõÍÊÉ« ¢ÙÂÈÆøÓÐÇ¿Ñõ»¯ÐÔ
¢ÚÂÈÆøÓëÀäË®·´Ó¦Éú³ÉÑÎËáºÍ´ÎÂÈËá
¢Û´ÎÂÈËáÓÐÇ¿Ñõ»¯ÐÔ
¢Ù
 

¢Ú
 

¢Û
 

¢ÜH2Oʹ²¼ÌõÍÊÉ«
ʵÑé¢Ù£º°ÑºìÉ«¸É²¼Ìõ·ÅÈë³äÂúÂÈÆøµÄ¼¯ÆøÆ¿ÖУ¬²¼Ìõ²»ÍÊÉ«
ʵÑé¢Ú£º
 

ʵÑé¢Û£º
 

ʵÑé¢Ü£º°ÑºìÉ«²¼Ìõ·ÅÔÚË®Àï²¼Ìõ²»ÍÊÉ«
 
£¨3£©Æ½ºâ³£Êý±íÃ÷ÁË·â±ÕÌåϵµÄ¿ÉÄæ·´Ó¦ÔÚ¸ø¶¨µÄζÈϽøÐеij̶ȣ¬¶ÔÓÚͬһ¸öÀàÐ͵ķ´Ó¦£¬Æ½ºâ³£ÊýÔ½´ó£¬±íÃ÷·´Ó¦½øÐеij̶ÈÔ½´ó£®
H2CO3?HCO3-+H+            Ka1£¨H2CO3£©=4.45¡Á10-7
HCO3-?CO32-+H+              Ka2£¨HCO3-£©=5.61¡Á10-11
HClO?H++ClO-                 Ka£¨HClO£©=2.95¡Á10-8
ÇëÒÀ¾ÝÒÔÉϵçÀëƽºâ³£Êý£¬Ð´³öÔÚÏÂÁÐÌõ¼þÏÂËù·¢Éú·´Ó¦µÄÀë×Ó·½³Ìʽ£º
¢Ù½«ÉÙÁ¿µÄÂÈÆøͨÈëµ½¹ýÁ¿µÄ̼ËáÄÆÈÜÒºÖУ»
 

¢ÚÂÈÆøºÍ̼ËáÄÆ°´ÕÕ1£º1µÄ±ÈÀýÇ¡ºÃ·´Ó¦£»
 

¢Û½«¹ýÁ¿µÄÂÈÆøͨÈëµ½ÉÙÁ¿µÄ̼ËáÄÆÈÜÒºÖУ®
 
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â

ÐÂÖÆÂÈË®Öк¬ÓжàÖÖÁ£×Ó£¬Ä³Ð£»¯Ñ§Ñо¿ÐÔѧϰС×éµÄͬѧΪ̽¾¿ÆäÐÔÖÊ£¬×öÁËÈçÏÂʵÑé,ÇëÄã°ïÖúÍê³É£º

£¨1£©ÂÈÆøÄÜʹʪÈóµÄºìÉ«²¼ÌõÍÊÉ«¡£Ê¹ÆäÍÊÉ«µÄ΢Á£µÄ»¯Ñ§Ê½ÊÇ______         

£¨2£©½«ÂÈË®ÔÚ¹âÕÕÉÏÒ»¶Îʱ¼ä£¬ÈÜÒºÑÕÉ«Öð½¥±ädz£¬ÆäÓйط´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º

                           ¡¢                         

£¨3£©Æ½ºâ³£Êý£¨K£©±íÃ÷ÁË·â±ÕÌåϵµÄ¿ÉÄæ·´Ó¦ÔÚ¸ø¶¨µÄζÈϽøÐеij̶ȣ¬¶ÔÓÚͬһ¸öÀàÐ͵ķ´Ó¦£¬Æ½ºâ³£ÊýÔ½´ó£¬±íÃ÷·´Ó¦½øÐеij̶ÈÔ½´ó¡£

H2CO3 HCO3-£« H£«   Ka1(H2CO3)=4.45¡Á10-7

HCO3- CO32-£«H£«     Ka2(HCO3-)=5.61¡Á10-11

HClOH£«£«ClO-        Ka(HClO)=2.95¡Á10-8

ÇëÒÀ¾ÝÒÔÉϵçÀëƽºâ³£Êý£¬Çëд³ö½«ÉÙÁ¿µÄÂÈÆøͨÈëµ½¹ýÁ¿µÄ̼ËáÄÆÈÜÒºÖÐËù·¢Éú·´Ó¦µÄÀë×Ó·½³Ìʽ£º                                

£¨4£©±¥ºÍÂÈË®Óëʯ»ÒʯµÄ·´Ó¦ÊÇÖÆÈ¡½ÏŨHClOÈÜÒºµÄ·½·¨Ö®Ò»¡£

ʵÑéÒ»¡¢¶¨ÐÔÑо¿£º

¢ÙÔÚÊÔ¹ÜÖмÓÈë¹ýÁ¿µÄ¿é״̼Ëá¸Æ£¬ÔÙ¼ÓÈëÔ¼20mL±¥ºÍÂÈË®£¬³ä·Ö·´Ó¦£¬ ÓÐÉÙÁ¿ÆøÅݲúÉú£¬ÈÜҺdz»ÆÂÌÉ«ÍÊÈ¥£»

¢Ú¹ýÂË£¬½«ÂËÒºµÎÔÚÓÐÉ«²¼ÌõÉÏ£¬·¢ÏÖÆä±ÈÂÈË®µÄƯ°×ÐÔ¸üÇ¿£»

¢ÛΪÁËÈ·¶¨·´Ó¦²úÎ½«ÂËÒº·ÖΪÈý·Ý£¬·Ö±ð½øÐÐÒÔÏÂʵÑ飺

µÚÒ»·ÝÓëʯ»ÒË®»ìºÏ£¬Á¢¼´²úÉú´óÁ¿°×É«³Áµí£»

µÚ¶þ·ÝÓëÏ¡ÑÎËá»ìºÏ£¬Á¢¼´²úÉú´óÁ¿ÎÞÉ«ÆøÌ壻

½«µÚÈý·Ý¼ÓÈÈ£¬¿´µ½ÈÜÒº±ä»ë×ÇÇÒÓдóÁ¿ÎÞÉ«ÆøÌå²úÉú¡£   

¾­¼ì²â£¬ÉÏÊöʵÑéÖвúÉúµÄÎÞÉ«ÆøÌå¾ùΪCO2¡£

Çë»Ø´ð£º

¢Ù·´Ó¦ºóËùµÃµÄÈÜҺƯ°×ÐÔÔöÇ¿µÄÔ­ÒòÊÇ______  ___________              ____ 

¢ÚÒÀ¾ÝÉÏÊöʵÑé¿ÉÍÆÖª£º¢ÚµÄÂËÒºÖеÄÈÜÖʳýCaCl2¡¢HClOÍ⣬»¹º¬ÓÐ______ _                                 ¡£

ʵÑé¶þ¡¢¶¨Á¿Ñо¿£º

ÔÚÔ²µ×ÉÕÆ¿µ×²¿£¬ÓÐÒ»ÓÃËÜÁÏÍø°üסµÄ¹ýÁ¿¿é×´  ̼Ëá¸ÆºÍ150mL±¥ºÍÂÈË®£¬°´ÈçͼËùʾװÖÃʵÑ飬´ý²»ÔÙ²úÉúÆøÅݺ󣬽«ËÜÁÏÍøÖÐÊ£ÓàµÄʯ»ÒʯÌá³öÒºÃ棬ÃÜ·âºóÔÙ¼ÓÈÈ¡¢Öó·ÐÉÕÆ¿ÖеÄÒºÌ壬ֱµ½Á¿Í²ÖеÄÆøÌå²»ÔÙÔö¼Ó£¨²»¿¼ÂÇHClOµÄ·Ö½â£©¡£

Çë»Ø´ð£º

¢Ûд³öÒÇÆ÷£¨1£©ÓëÒÇÆ÷£¨3£©µÄÃû³Æ£º£¨1£©            £¨3£©               

¢ÜΪ¼õÉÙÓÃ×°ÖâóÊÕ¼¯ÆøÌå¹ý³ÌÖÐCO2ÒòÈܽâ¶øÔì³ÉµÄËðʧ£¬ÇÒË®²ÛÖÐÈÔȻΪˮ£¬ÇëÄã¶Ô×°Öâó½øÐиĽø£¬×î¼òµ¥µÄ·½·¨ÊÇ                                   ¡£

¢ÝÈçºÎ׼ȷ¶Á³öÁ¿Í²ÖÐÆøÌåµÄÌå»ý

a£®________      _   ________      _   ________      _   ________ 

b£®ÉÏÏÂÒƶ¯Á¿Í²ÖÁÁ¿Í²ÄÚÒºÃæÓëË®²ÛÒºÃæÏàƽ

c£®                                      ________      _   ________

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011½ì½­Î÷Ê¡¾Å½­ÊиßÈý2ÔÂÆßУÁª¿¼£¨Àí×Û£©»¯Ñ§²¿·Ö ÌâÐÍ£ºÊµÑéÌâ

ÐÂÖÆÂÈË®Öк¬ÓжàÖÖÁ£×Ó,ijУ»¯Ñ§Ñо¿ÐÔѧϰС×éµÄͬѧΪ̽¾¿ÆäÐÔÖÊ,×öÁËÈçÏÂʵÑé,ÇëÄã°ïÖúÍê³É£º
£¨1£©ÂÈÆøÄÜʹʪÈóµÄºìÉ«²¼ÌõÍÊÉ«¡£Ê¹ÆäÍÊÉ«µÄ΢Á£µÄ»¯Ñ§Ê½ÊÇ______         
£¨2£©½«ÂÈË®ÔÚ¹âÕÕÉÏÒ»¶Îʱ¼ä£¬ÈÜÒºÑÕÉ«Öð½¥±ädz£¬ÆäÓйط´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º
                           ¡¢                         
£¨3£©Æ½ºâ³£Êý±íÃ÷ÁË·â±ÕÌåϵµÄ¿ÉÄæ·´Ó¦ÔÚ¸ø¶¨µÄζÈϽøÐеij̶ȣ¬¶ÔÓÚͬһ¸öÀàÐ͵ķ´Ó¦£¬Æ½ºâ³£ÊýÔ½´ó£¬±íÃ÷·´Ó¦½øÐеij̶ÈÔ½´ó¡£
H2CO3  £« H£«            Ka1£¨H2CO3£©=4.45¡Á10¡ª7
   £«H£«              Ka2(HCO3£­)=5.61¡Á10£­11
HclO  H£«£«                 Ka(HClO)=2.95¡Á10£­8
ÇëÒÀ¾ÝÒÔÉϵçÀëƽºâ³£Êý£¬Çëд³ö½«ÉÙÁ¿µÄÂÈÆøͨÈëµ½¹ýÁ¿µÄ̼ËáÄÆÈÜÒºÖÐËù·¢Éú·´Ó¦µÄÀë×Ó·½³Ìʽ£º¡¡                                                               
£¨4£©±¥ºÍÂÈË®Óëʯ»ÒʯµÄ·´Ó¦ÊÇÖÆÈ¡½ÏŨHClOÈÜÒºµÄ·½·¨Ö®Ò»¡£

ʵÑéÒ»¡¢¶¨ÐÔÑо¿£º
¢Ù  ÔÚÊÔ¹ÜÖмÓÈë¹ýÁ¿µÄ¿é״̼Ëá¸Æ£¬ÔÙ¼ÓÈëÔ¼20mL±¥ºÍÂÈË®£¬³ä·Ö·´Ó¦£¬
ÓÐÉÙÁ¿ÆøÅݲúÉú£¬ÈÜҺdz»ÆÂÌÉ«ÍÊÈ¥£»
¢Ú ¹ýÂË£¬½«ÂËÒºµÎÔÚÓÐÉ«²¼ÌõÉÏ£¬·¢ÏÖÆä±ÈÂÈË®µÄƯ°×ÐÔ¸üÇ¿£»
¢Û ΪÁËÈ·¶¨·´Ó¦²úÎ½«ÂËÒº·ÖΪÈý·Ý£¬·Ö±ð½øÐÐÒÔÏÂʵÑ飺
µÚÒ»·ÝÓëʯ»ÒË®»ìºÏ£¬Á¢¼´²úÉú´óÁ¿°×É«³Áµí£»
µÚ¶þ·ÝÓëÏ¡ÑÎËá»ìºÏ£¬Á¢¼´²úÉú´óÁ¿ÎÞÉ«ÆøÌ壻
½«µÚÈý·Ý¼ÓÈÈ£¬¿´µ½ÈÜÒº±ä»ë×ÇÇÒÓдóÁ¿ÎÞÉ«ÆøÌå²úÉú¡£   
¾­¼ì²â£¬ÉÏÊöʵÑéÖвúÉúµÄÎÞÉ«ÆøÌå¾ùΪCO2¡£
Çë»Ø´ð£º
¢Ù ·´Ó¦ºóËùµÃµÄÈÜҺƯ°×ÐÔÔöÇ¿µÄÔ­ÒòÊÇ______ ___________             ____                           
¢ÚÒÀ¾ÝÉÏÊöʵÑé¿ÉÍÆÖª£º¢ÚµÄÂËÒºÖеÄÈÜÖʳýCaCl2¡¢HClOÍ⣬»¹º¬ÓÐ_______                                ¡£
ʵÑé¶þ¡¢¶¨Á¿Ñо¿£º                              
ÔÚÔ²µ×ÉÕÆ¿µ×²¿£¬ÓÐÒ»ÓÃËÜÁÏÍø°üסµÄ¹ýÁ¿¿é×´ Ì¼Ëá¸ÆºÍ150mL±¥ºÍÂÈË®£¬°´ÈçͼËùʾװÖÃʵÑ飬´ý²»ÔÙ²úÉúÆøÅݺ󣬽«ËÜÁÏÍøÖÐÊ£ÓàµÄʯ»ÒʯÌá³öÒºÃ棬ÃÜ·âºóÔÙ¼ÓÈÈ¡¢Öó·ÐÉÕÆ¿ÖеÄÒºÌ壬ֱµ½Á¿Í²ÖеÄÆøÌå²»ÔÙÔö¼Ó£¨²»¿¼ÂÇHClOµÄ·Ö½â£©¡£

Çë»Ø´ð£º
¢Ûд³öÒÇÆ÷£¨1£©ÓëÒÇÆ÷£¨3£©µÄÃû³Æ
£¨1£©           £¨3£©               
¢ÜΪ¼õÉÙÓÃ×°ÖâóÊÕ¼¯ÆøÌå¹ý³ÌÖÐCO2ÒòÈܽâ¶øÔì³ÉµÄËðʧ£¬ÇÒË®²ÛÖÐÈÔȻΪˮ£¬ÇëÄã¶Ô×°Öâó½øÐиĽø£¬×î¼òµ¥µÄ·½·¨ÊÇ                                ¡£
¢ÝÈçºÎ׼ȷ¶Á³öÁ¿Í²ÖÐÆøÌåµÄÌå»ý
a________     _    
b ÉÏÏÂÒƶ¯Á¿Í²ÖÁÁ¿Í²ÄÚÒºÃæÓëË®²ÛÒºÃæÏàƽ
c                                       

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸