ʵÑéÊҼס¢ÒÒÁ½Æ¿¶ªÊ§±êÇ©µÄÎÞÉ«ÈÜÒº£¬ÆäÖÐһƿÊÇÑÎËᣬÁíһƿÊÇ̼ËáÄÆÈÜÒº£®ÎªÈ·¶¨¼×¡¢ÒÒÁ½Æ¿ÈÜÒºµÄ³É·Ö¼°ÆäÎïÖʵÄÁ¿Å¨¶È£¬ÏÖ²Ù×÷ÈçÏ£º¢ÙÁ¿È¡25.00 mL¼×ÈÜÒº£¬ÏòÆäÖлºÂýµÎ¼ÓÒÒÈÜÒº15.00 mL£¬¹²ÊÕ¼¯µ½¶þÑõ»¯Ì¼ÆøÌå224 mL£»¢ÚÁíÈ¡15.00 mLÒÒÈÜÒº£¬ÏòÆäÖлºÂýµÎ¼Ó¼×ÈÜÒº25.00 mL£¬¹²ÊÕ¼¯µ½¶þÑõ»¯Ì¼ÆøÌå112 mL£®ÉÏÊöÆøÌåÌå»ý¾ùÒÑ»»ËãΪ±ê×¼×´¿ö£®Ôò¸ù¾ÝÉÏÊõ²Ù×÷¼°ÊµÑéÊý¾ÝÌî¿Õ£®

(1)д³öÉÏÊö¹ý³ÌËùÉæ¼°·´Ó¦µÄÀë×Ó·½³Ìʽ£º________£»________

(2)¼×ÊÇ________£¬¼×ÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶ÈΪ________£¬ÒÒÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶ÈΪ________(¶þÑõ»¯Ì¼ÔÚÈÜÒºÖеÄСÁ¿ÈܽâºöÂÔ²»¼Æ)£®

(3)½«n mLµÄ¼×ÈÜÒºÓëµÈÌå»ýµÄÒÒÈÜÒº°´¸÷ÖÖ¿ÉÄܵķ½Ê½»ìºÏ£¬²úÉúµÄÆøÌåÌå»ýΪx mL(±ê×¼×´¿ö)£¬ÔòXµÄÈ¡Öµ·¶Î§Îª________£®

´ð°¸£º
½âÎö£º

¡¡¡¡(1)CO32£­£«2H+£½CO2¡ü£«H2O¡¡CO32£­£«H+£½HCO3£­¡¡HCO3£­£«H+£½H2O£«CO2¡ü

¡¡¡¡(2)ÑÎËá(»òHCl)¡¡0.8 mol/L¡¡1.0 mol/L

¡¡¡¡(3)0¡Üx¡Ü8.96n


Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2009?ÉÇÍ·Ä£Ä⣩ʵÑéÊÒÓмס¢ÒÒÁ½Æ¿¶ªÊ§±êÇ©µÄÎÞÉ«ÈÜÒº£¬ÆäÖÐһƿÊÇÑÎËᣬÁíһƿÊÇ̼ËáÄÆÈÜÒº£®ÎªÈ·¶¨¼×¡¢ÒÒÁ½Æ¿ÈÜÒºµÄ³É·Ö¼°ÆäÎïÖʵÄÁ¿Å¨¶È£¬ÏÖ²Ù×÷ÈçÏ£º
¢ÙÁ¿È¡25.00mL¼×ÈÜÒº£¬ÏòÆäÖлºÂýµÎ¼ÓÒÒÈÜÒº15.00mL£¬¹²ÊÕ¼¯µ½¶þÑõ»¯Ì¼ÆøÌå224mL£®
¢ÚÁíÈ¡15.00mLÒÒÈÜÒº£¬ÏòÆäÖлºÂýµÎ¼Ó¼×ÈÜÒº25.00mL£¬¹²ÊÕ¼¯µ½¶þÑõ»¯Ì¼ÆøÌå112mL£®
ÉÏÊöÆøÌåÌå»ý¾ùÒÑ»»ËãΪ±ê×¼×´¿ö£¬Ôò¸ù¾ÝÉÏÊö²ÙÊö¼°ÊµÑéÊý¾ÝÌî¿Õ£º
£¨1£©Ð´³ö²Ù×÷¢ÙËùÉæ¼°·´Ó¦µÄÀë×Ó·½³Ìʽ
CO32-+2H+¨TCO2+H2O
CO32-+2H+¨TCO2+H2O
£»
£¨2£©¼×ÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶ÈΪ
0.8mol?L-1
0.8mol?L-1
£¬ÒÒÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶ÈΪ
1.0mol?L-1
1.0mol?L-1
£»£¨¶þÑõ»¯Ì¼ÔÚÈÜÒºÖеÄÉÙÁ¿ÈܽâºöÂÔ²»¼Æ£©
£¨3£©½«n mLµÄ¼×ÈÜÒºÓëµÈÌå»ýµÄÒÒÈÜÒº°´¸÷ÖÖ¿ÉÄܵķ½Ê½»ìºÏ£¬²úÉúµÄÆøÌåÌå»ýΪV mL£¨±ê×¼×´¿ö£©£¬ÔòVµÄÈ¡Öµ·¶Î§Îª
0£¼V£¼8.96n
0£¼V£¼8.96n
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ʵÑéÊÒÓмס¢ÒÒÁ½Æ¿¶ªÊ§±êÇ©µÄÎÞÉ«ÈÜÒº£¬ÆäÖÐһƿÊÇÑÎËᣬÁíһƿÊÇ̼ËáÄÆÈÜÒº¡£ÎªÈ·¶¨Á½Æ¿ÈÜÒºµÄ³É·Ö¼°ÆäÎïÖʵÄÁ¿Å¨¶È£¬ÏÖ²Ù×÷ÈçÏ£º
¢ÙÁ¿È¡25.00mL¼×ÈÜÒº£¬ÏòÆäÖлº»ºµÎ¼ÓÒÒÈÜÒº15.00mL£¬¹²ÊÕ¼¯µ½CO2ÆøÌå224mL£¨±ê×¼×´¿ö£¬ÏÂͬ£©¡£
¢ÚÁíÈ¡15.00mLÒÒÈÜÒº£¬ÏòÆäÖлº»ºµÎ¼Ó¼×ÈÜÒº25.00mL£¬¹²ÊÕ¼¯µ½CO2ÆøÌå112mL¡£
£¨1£©¼×ÊÇ______£¬¼×ÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶ÈΪ_______£¬ÒÒÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶ÈΪ_______£¨¶þÑõ»¯Ì¼µÄÈܽâºöÂÔ²»¼Æ£©¡£
£¨2£©½«amL¼×ÈÜÒºÓëµÈÌå»ýµÄÒÒÈÜÒº°´¸÷ÖÖ¿ÉÄܵķ½Ê½»ìºÏ£¬²úÉúµÄÆøÌåµÄÌå»ýΪV£¨±ê×¼×´¿ö£©£¬ÔòVµÄÈ¡Öµ·¶Î§Îª________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ʵÑéÊÒÖÐÓмס¢ÒÒÁ½Æ¿¶ªÊ§±êÇ©µÄÎåÉ«ÈÜÒº£¬ÆäÖÐһƿÊÇÑÎËᣬÁíһƿÊÇ̼ËáÄÆÈÜÒº¡£ÎªÈ·¶¨¼×¡¢ÒÒÁ½Æ¿ÈÜÒºµÄ³É·Ö¼°ÆäÎïÖʵÄÁ¿Å¨¶È£¬ÏÖ²Ù×÷ÈçÏ£º¢ÙÁ¿È¡25.00mL¼×ÈÜÒº£¬ÏòÆäÖлº»ºµÎ¼ÓÒÒÈÜÒº15.00mL£¬¹²ÊÕ¼¯µ½CO2ÆøÌå224 mL(±ê×¼×´¿ö)¡£¢ÚÁ¿È¡15.00 mLÒÒÈÜÒº£¬ÏòÆäÖлº»ºµÎ¼Ó¼×ÈÜÒº25.00 mL£¬¹²ÊÕ¼¯µ½CO2ÆøÌå112mL¡£(±ê×¼×´¿ö)

Çë»Ø´ð£º(1)¸ù¾ÝÉÏÊöÁ½ÖÖ²»Í¬²Ù×÷¹ý³Ì¼°ÊµÑéÊý¾Ý¿ÉÅжϼ×ÈÜÒºÊÇ___________£¬ÒÒÈÜÒºÊÇ___________¡£

(2)ÓÃÀë×Ó·½³Ìʽ±íʾÁ½´Î²Ù×÷µÃµ½²»Í¬ÆøÌåÌå»ýµÄÔ­Òò£º

¢Ù_______________________________________________________£»

¢Ú_______________________________________________________¡£

(3)¼×ÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶ÈΪ___________mol¡¤L-1¡£(CO2ÔÚË®ÈÜÒºÖеÄÉÙÁ¿ÈܽâºöÂÔ²»¼Æ)

(4)½«nmLµÄ¼×ÈÜÒºÓëµÈÌå»ýµÄÒÒÈÜÒº°´¸÷ÖÖ¿ÉÄܵķ½Ê½»ìºÏ£¬²úÉúµÄÆøÌåÌå»ýΪVmL(±ê×¼×´¿ö)£¬ÔòVµÄÈ¡Öµ·¶Î§Îª__________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ʵÑéÊÒÓмס¢ÒÒÁ½Æ¿¶ªÊ§±êÇ©µÄÎÞÉ«ÈÜÒº£¬ÆäÖÐһƿÊÇÑÎËᣬÁíһƿÊÇ̼ËáÄÆÈÜÒº¡£ÎªÈ·¶¨¼×¡¢ÒÒÁ½Æ¿ÈÜÒºµÄ³É·Ö¼°ÆäÎïÖʵÄÁ¿Å¨¶È£¬ÏÖ²Ù×÷ÈçÏ£º

¢ÙÁ¿È¡25.00 mL¼×ÈÜÒº£¬ÏòÆäÖлºÂýµÎ¼ÓÒÒÈÜÒº15.00 mL£¬¹²ÊÕ¼¯µ½¶þÑõ»¯Ì¼ÆøÌå224 mL¡£

¢ÚÁíÈ¡15.00 mLÒÒÈÜÒº£¬ÏòÆäÖлºÂýµÎ¼Ó¼×ÈÜÒº25.00 mL£¬¹²ÊÕ¼¯µ½¶þÑõ»¯Ì¼ÆøÌå112 mL¡£

ÉÏÊöÆøÌåÌå»ý¾ùÒÑ»»ËãΪ±ê×¼×´¿ö£¬Ôò¸ù¾ÝÉÏÊö²ÙÊö¼°ÊµÑéÊý¾ÝÌî¿Õ£º

£¨1£©Ð´³öÉÏÊö¹ý³ÌÖÐËùÉæ¼°·´Ó¦µÄÀë×Ó·½³Ìʽ£º¢Ù_______________£»¢Ú______________£»¢Û______________¡£

£¨2£©¼×ÊÇ______________£¬¼×ÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶ÈΪ______________£¬ÒÒÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶ÈΪ______________¡££¨¶þÑõ»¯Ì¼ÔÚÈÜÒºÖеÄÉÙÁ¿ÈܽâºöÂÔ²»¼Æ£©

£¨3£©½«n mLµÄ¼×ÈÜÒºÓëµÈÌå»ýµÄÒÒÈÜÒº°´¸÷ÖÖ¿ÉÄܵķ½Ê½»ìºÏ£¬²úÉúµÄÆøÌåÌå»ýΪV mL£¨±ê×¼×´¿ö£©£¬ÔòVµÄÈ¡Öµ·¶Î§Îª____________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸