ÒÒËáÒÒõ¥ÊÇÖØÒªµÄÓлúºÏ³ÉÖмäÌ壬¹ã·ºÓ¦ÓÃÓÚ»¯Ñ§¹¤Òµ¡£ÊµÑéÊÒÖƱ¸ÒÒËáÒÒõ¥µÄ»¯Ñ§·½³Ìʽ£ºCH3COOH£«C2H5OHCH3COOC2H5£«H2O£¬ÎªÖ¤Ã÷ŨÁòËáÔڸ÷´Ó¦ÖÐÆðµ½ÁË´ß»¯¼ÁºÍÎüÊÕ¼ÁµÄ×÷Óã¬Ä³Í¬Ñ§ÀûÓÃÏÂͼËùʾװÖýøÐÐÁËÒÔÏÂËĸöʵÑ飬ʵÑ鿪ʼÏÈÓþƾ«µÆ΢ÈÈ3 min£¬ÔÙ¼ÓÈÈʹ֮΢΢·ÐÌÚ3 min¡£ÊµÑé½áÊøºó³ä·ÖÕñµ´ÊԹܢòÔÙ²âÓлú²ãµÄºñ¶È£¬ÊµÑé¼Ç¼ÈçÏ£º

ʵÑé±àºÅ
ÊԹܢñÖеÄÊÔ¼Á
ÊԹܢòÖÐÊÔ¼Á
²âµÃÓлú²ãµÄºñ¶È/cm
A
2 mLÒÒ´¼¡¢2 mLÒÒËá¡¢1 mL 18 mol¡¤L£­1ŨÁòËá
±¥ºÍ̼ËáÄÆÈÜÒº
5.0
B
3 mLÒÒ´¼¡¢2 mLÒÒËá
0.1
C
3 mLÒÒ´¼¡¢2 mLÒÒËá¡¢6mL 3 mol¡¤L£­1ÁòËá
1.2
D
3 mLÒÒ´¼¡¢2 mLÒÒËá¡¢ÑÎËá
1.2
 
£¨1£©ÊµÑéDµÄÄ¿µÄÊÇÓëʵÑéCÏà¶ÔÕÕ£¬Ö¤Ã÷H£«¶Ôõ¥»¯·´Ó¦¾ßÓд߻¯×÷Óá£ÊµÑéDÖÐÓ¦¼ÓÈëÑÎËáµÄÌå»ýºÍŨ¶È·Ö±ðÊÇ________mLºÍ________mol/L¡£
£¨2£©·ÖÎöʵÑé________£¨ÌîʵÑé±àºÅ£©µÄÊý¾Ý£¬¿ÉÒÔÍƲâ³öŨÁòËáµÄÎüË®ÐÔÌá¸ßÁËÒÒËáÒÒõ¥µÄ²úÂÊ¡£Å¨ÁòËáµÄÎüË®ÐÔÄܹ»Ìá¸ßÒÒËáÒÒõ¥²úÂʵÄÔ­ÒòÊÇ_______________________________________________________________¡£
£¨3£©¼ÓÈÈÓÐÀûÓÚÌá¸ßÒÒËáÒÒõ¥µÄ²úÂÊ£¬µ«ÊµÑé·¢ÏÖζȹý¸ßÒÒËáÒÒõ¥µÄ²úÂÊ·´¶ø½µµÍ£¬¿ÉÄܵÄÔ­ÒòÊÇ____________________________________________£¨´ð³öÁ½Ìõ¼´¿É£©¡£

£¨1£©6¡¡6
£¨2£©A¡¢C¡¡Å¨ÁòËá¿ÉÒÔÎüÊÕõ¥»¯·´Ó¦Éú³ÉµÄË®£¬Æ½ºâÏòÉú³ÉÒÒËáÒÒõ¥µÄ·½ÏòÒƶ¯
£¨3£©ÓдóÁ¿ÒÒËáºÍÒÒ´¼±»Õô³ö£»Î¶ȹý¸ß¶ø·¢ÉúÆäËû·´Ó¦

½âÎö

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

I£®ÒÑÖªÓлúÎïA½öº¬Ì¼¡¢Çâ¡¢Ñõ3ÖÖÔªËØ£¬ÖÊÆ×·ÖÎö¿ÉÖªÆäÏà¶Ô·Ö×ÓÖÊÁ¿Îª46£¬ºË´Å¹² ÕñÇâÆ×ÏÔʾ·Ö×ÓÖÐÓÐÈýÖÖ²»Í¬»¯Ñ§»·¾³µÄÇâÔ­×Ó£¬ÇÒÓÐÈçϵÄת»¯¹Øϵ£º

£¨1£©ÓÉA¡úBµÄ·´Ó¦ÀàÐÍÊÇ________
£¨2£©DµÄºìÍâ¹âÆ×±íÃ÷·Ö×ÓÄÚ³ýCÒ»H¼ü¡¢CÒ»C¼üÍ⻹º¬ÓÐÁ½¸öCÒ»Oµ¥¼ü£¬·´Ó¦¢ÙÖÐ DÓëHCl°´ÎïÖʵÄÁ¿Ö®±È1:1·´Ó¦£¬ÔòDµÄ½á¹¹¼òʽÊÇ    ______
II »¯ºÏÎïEºÍFÊÇÒ©Æ·ÆÕ³¿¨ÒòºÏ³ÉµÄÖØÒªÔ­ÁÏ£¬ÆÕ³¿¨ÒòµÄºÏ³É·ÏßÈçÏ£¨ÒÑÖª

£¨3£©¶¡µÄ½á¹¹¼òʽΪ_______________
£¨4£©·´Ó¦¢ÛµÄ»¯Ñ§·½³ÌʽÊÇ__________________
£¨5£©ÆÕ³¿¨ÒòÓÐÁ½ÖÖË®½â²úÎïÎìºÍ¼º£¬ÇÒÎìÓë¼×¾ßÓÐÏàͬµÄ·Ö×Óʽ¡£·ûºÏÏÂÁÐÌõ¼þµÄÎìµÄͬ·ÖÒì¹¹ÌåÓÐ______ÖÖ£¨°üº¬Î죩£»
a£®·Ö×ӽṹÖꬱ½»·£¬ÇÒÿ¸ö±½»·ÓÐ2¸ö²àÁ´
b£®·Ö×ӽṹÖÐÒ»¶¨º¬¹ÙÄÜÍÅÒ»NH2ÇÒÒ»NH2Ö±½ÓÓë̼ԭ×ÓÏàÁ¬
£¨6£©Îì¾­¾ÛºÏ·´Ó¦ÖƳɵĸ߷Ö×ÓÏËά¹ã·ºÓÃÓÚͨѶ¡¢ÓµÈÁìÓò¡£¸Ã¾ÛºÏ·´Ó¦µÄ»¯Ñ§·½ ³ÌʽÊÇ__________________

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º¼ÆËãÌâ

ijÓлúÎïAÖ»º¬ÓÐÒ»¸öÑõÔ­×Ó¡£½«0.1 mol AÔÚ×ãÁ¿ÑõÆøÖÐÍêȫȼÉÕ²úÉú3.6gË®£¬²úÎﻹÄÜÓë100 mL 2mol/LÉÕ¼îÈÜҺǡºÃÍêÈ«·´Ó¦£¬½«ËùµÃÈÜÒºÔÚµÍÎÂÏÂÕô¸É£¬Äܵõ½16.8g´¿¾»Îï¡£Çë¼ÆË㣺¢ÙAµÄ·Ö×Óʽ£»¢ÚÈôAµÄºË´Å¹²ÕñÇâÆ×Ö»ÓÐÒ»¸öÎüÊշ壬Çëд³öAµÄ½á¹¹¼òʽ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÊµÑéÌâ

(10·Ö)ÒÒËáÒìÎìõ¥ÊÇ×é³ÉÃÛ·äÐÅÏ¢ËصijɷÖÖ®Ò»£¬¾ßÓÐÏ㽶µÄÏãζ£¬ÊµÑéÊÒÖƱ¸ÒÒËáÒìÎìõ¥µÄ·´Ó¦¡¢×°ÖÃʾÒâͼºÍÓйØÊý¾ÝÈçÏ£º

ʵÑé²½Ö裺
ÔÚAÖмÓÈë4.4 gµÄÒìÎì´¼¡¢6.0 gµÄÒÒËá¡¢ÊýµÎŨÁòËáºÍ2¡«3ƬËé´ÉƬ¡£¿ªÊ¼»ºÂý¼ÓÈÈA£¬»ØÁ÷50min¡£·´Ó¦ÒºÀäÖÁÊÒκóµ¹Èë·ÖҺ©¶·ÖУ¬·Ö±ðÓÃÉÙÁ¿Ë®¡¢±¥ºÍ̼ËáÇâÄÆÈÜÒººÍˮϴµÓ£»·Ö³öµÄ²úÎï¼ÓÈëÉÙÁ¿ÎÞË®MgSO4¹ÌÌ壬¾²ÖÃƬ¿Ì£¬¹ýÂ˳ýÈ¥MgSO4¹ÌÌ壬½øÐÐÕôÁó´¿»¯£¬ÊÕ¼¯140¡«143 ¡æÁó·Ö£¬µÃÒÒËáÒìÎìõ¥3.9 g¡£
»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÒÇÆ÷BµÄÃû³ÆÊÇ      ¡£
£¨2£©ÔÚÏ´µÓ²Ù×÷ÖУ¬µÚÒ»´ÎˮϴµÄÖ÷ҪĿµÄÊÇ      £¬µÚ¶þ´ÎˮϴµÄÖ÷ҪĿµÄÊÇ    ¡£
£¨3£©ÔÚÏ´µÓ¡¢·ÖÒº²Ù×÷ÖУ¬Ó¦³ä·ÖÕñµ´£¬È»ºó¾²Ö㬴ý·Ö²ãºó    £¨Ìî±êºÅ£©¡£
a£®Ö±½Ó½«ÒÒËáÒìÎìõ¥´Ó·ÖҺ©¶·µÄÉÏ¿Úµ¹³ö
b£®Ö±½Ó½«ÒÒËáÒìÎìõ¥´Ó·ÖҺ©¶·µÄÏ¿ڷųö
c£®ÏȽ«Ë®²ã´Ó·ÖҺ©¶·µÄÏ¿ڷųö£¬ÔÙ½«ÒÒËáÒìÎìõ¥´ÓÏ¿ڷųö
d£®ÏȽ«Ë®²ã´Ó·ÖҺ©¶·µÄÏ¿ڷųö£¬ÔÙ½«ÒÒËáÒìÎìõ¥´ÓÉÏ¿Úµ¹³ö
£¨4£©±¾ÊµÑéÖмÓÈë¹ýÁ¿ÒÒËáµÄÄ¿µÄÊÇ      ¡£
£¨5£©ÊµÑéÖмÓÈëÉÙÁ¿ÎÞË®MgSO4µÄÄ¿µÄÊÇ     ¡£
£¨6£©ÔÚÕôÁó²Ù×÷ÖУ¬ÒÇÆ÷Ñ¡Ôñ¼°°²×°¶¼ÕýÈ·µÄÊÇ      £¨Ìî±êºÅ£©¡£
£¨7£©±¾ÊµÑéµÄ²úÂÊÊÇ      £¨Ìî±êºÅ£©¡£
a£®30¨G  b£®40¨G   c£®60¨G   d£®90¨G
£¨8£©ÔÚ½øÐÐÕôÁó²Ù×÷ʱ£¬Èô´Ó130 ¡æ±ã¿ªÊ¼ÊÕ¼¯Áó·Ö£¬»áʹʵÑéµÄ²úÂÊÆ«  (Ìî¡°¸ß¡±»ò¡°µÍ¡±)£¬ Ô­ÒòÊÇ             ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÊµÑéÌâ

(12·Ö)ijʵÑéС×éÓÃÏÂÁÐ×°ÖýøÐÐÒÒ´¼´ß»¯Ñõ»¯µÄʵÑé¡£

£¨1£©ÊµÑé¹ý³ÌÖÐÍ­Íø³öÏÖºìÉ«ºÍºÚÉ«½»ÌæµÄÏÖÏó£¬Çëд³öÏàÓ¦µÄ»¯Ñ§·½³Ìʽ_________________¡£
£¨2£©¼×ºÍÒÒÁ½¸öˮԡ×÷Óò»Ïàͬ£¬ÒÒµÄ×÷ÓÃÊÇ___________________¡£¼¯ÆøÆ¿ÖÐÊÕ¼¯µ½µÄÆøÌåµÄÖ÷Òª³É·ÖÊÇ_____________________¡£
£¨3£©ÈôÊÔ¹ÜaÖÐÊÕ¼¯µ½µÄÒºÌåÓÃ×ÏɫʯÈïÊÔÖ½£¬ÊÔÖ½ÏÔºìÉ«£¬ËµÃ÷ÒºÌåÖл¹ÓÐ____________¡£Òª³ýÈ¥¸ÃÎïÖÊ£¬¿ÉÏÈÔÚ»ìºÏÒºÖмÓÈë_________£¨Ìîд×Öĸ£©¡£

A£®ÂÈ»¯ÄÆÈÜÒº B£®±½ C£®Ì¼ËáÇâÄÆÈÜÒº D£®ËÄÂÈ»¯Ì¼
È»ºóÔÙͨ¹ý___________£¨ÌîʵÑé²Ù×÷Ãû³Æ£©¼´¿É³ýÈ¥¡£   
£¨4£©ÊµÑéÒ»¶Îʱ¼äºó£¬½«ÊÔ¹ÜaÖеÄÒºÌåÈ¡³ö£¬¼ÓÈë×ãÁ¿µÄÒø°±ÈÜÒº£¬ÔÙ·ÅÈë¼×ÉÕ±­ÖУ¬ºÜ¿ì³öÏÖÃ÷ÏÔµÄÏÖÏó¡£Ð´³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º                                 £»·´Ó¦ÀàÐÍΪ              

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÊµÑéÌâ

ij»¯Ñ§Ð¡×é²ÉÓÃÀàËÆÖÆÒÒËáÒÒõ¥µÄ×°Öã¨ÈçÏÂͼ£©£¬ÒÔ»·¼º´¼ÖƱ¸»·¼ºÏ©


 
 
Ãܶȣ¨g/cm3£©
 
È۵㣨¡æ£©
 
·Ðµã£¨¡æ£©
 
ÈܽâÐÔ
 
»·¼º´¼
 
0.96
 
25
 
161
 
ÄÜÈÜÓÚË®
 
»·¼ºÏ©
 
0.81
 
-103
 
83
 
ÄÑÈÜÓÚË®
 
£¨1£©ÖƱ¸´ÖÆ·£º½«12.5mL»·¼º´¼¼ÓÈëÊÔ¹ÜAÖУ¬ÔÙ¼ÓÈë1mLŨÁòËᣬҡÔȺó·ÅÈëËé´ÉƬ£¬»ºÂý¼ÓÈÈÖÁ·´Ó¦ÍêÈ«£¬ÔÚÊÔ¹ÜCÄڵõ½»·¼ºÏ©´ÖÆ·¡£
¢ÙAÖÐËé´ÉƬµÄ×÷ÓÃÊÇ ¡¡   £¬µ¼¹ÜB³ýÁ˵¼ÆøÍ⻹¾ßÓеÄ×÷ÓÃÊÇ ¡¡   ¡£
¢ÚÊÔ¹ÜCÖÃÓÚ±ùˮԡÖеÄÄ¿µÄÊÇ ¡¡    ¡£
£¨2£©ÖƱ¸¾«Æ·£º
¢Ù»·¼ºÏ©´ÖÆ·Öк¬Óл·¼º´¼ºÍÉÙÁ¿ËáÐÔÔÓÖʵȡ£¼ÓÈë±¥ºÍʳÑÎË®£¬Õñµ´¡¢¾²Öᢷֲ㣬»·¼ºÏ©ÔÚ ¡¡   ²ã£¨ÌîÉÏ»òÏ£©£¬·ÖÒººó£¬Óà¡¡   £¨Ìî±àºÅ£©Ï´µÓ»·¼ºÏ©¡£
A.KMnO4ÈÜÒº         B.Ï¡H2SO4            C.Na2CO3ÈÜÒº      D.NaOHÈÜÒº
¢ÚÔÙ½«»·¼ºÏ©°´ÏÂͼװÖÃÕôÁó£¬ÀäÈ´Ë®´Ó ¡¡   £¨Ìîf»òg£©¿Ú½øÈ룬ÕôÁóʱҪ¼ÓÈëÉúʯ»Ò£¬Ä¿µÄÊÇ ¡¡   ¡£

¢ÛÊÕ¼¯²úƷʱ£¬¿ØÖƵÄζÈÓ¦ÔÚ ¡¡   ×óÓÒ£¬ÊµÑéÖƵõĻ·¼ºÏ©¾«Æ·ÖÊÁ¿µÍÓÚÀíÂÛ²úÁ¿£¬¿ÉÄܵÄÔ­ÒòÊÇ ¡¡    ¡£
A.ÕôÁóʱ´Ó70¡æ¿ªÊ¼ÊÕ¼¯²úÆ·  B.»·¼º´¼Êµ¼ÊÓÃÁ¿¶àÁË 
C.ÖƱ¸´ÖƷʱ»·¼º´¼Ëæ²úÆ·Ò»ÆðÕô³ö
£¨3£©ÒÔÏÂÇø·Ö»·¼ºÏ©¾«Æ·ºÍ´ÖÆ·µÄ·½·¨£¬×î¼òµ¥µÄ·½·¨ÊÇ ¡¡   ¡£
A.ËáÐÔKMnO4ÈÜÒº      B.ÓýðÊôÄÆ      C.²â¶¨·Ðµã   D.äåµÄËÄÂÈ»¯Ì¼ÈÜÒº

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÊµÑéÌâ

Õý¶¡È©ÊÇÒ»ÖÖ»¯¹¤Ô­ÁÏ¡£Ä³ÊµÑéС×éÀûÓÃÈçÏÂ×°ÖúϳÉÕý¶¡È©¡£

·¢ÉúµÄ·´Ó¦ÈçÏ£º
CH3CH2CH2CH2OHCH3CH2CH2CHO
·´Ó¦ÎïºÍ²úÎïµÄÏà¹ØÊý¾ÝÁбíÈçÏ£º

 
·Ðµã/¡£c
ÃܶÈ/(g¡¤cm-3)
Ë®ÖÐÈܽâÐÔ
Õý¶¡´¼
11.72
0.8109
΢ÈÜ
Õý¶¡È©
75.7
0.8017
΢ÈÜ
 
ʵÑé²½ÖèÈçÏ£º
½«6.0gNa2Cr2O7·ÅÈë100mLÉÕ±­ÖУ¬¼Ó30mLË®Èܽ⣬ÔÙ»ºÂý¼ÓÈë5mLŨÁòËᣬ½«ËùµÃÈÜҺСÐÄתÒÆÖÁBÖС£ÔÚAÖмÓÈë4.0gÕý¶¡´¼ºÍ¼¸Á£·Ðʯ£¬¼ÓÈÈ¡£µ±ÓÐÕôÆû³öÏÖʱ£¬¿ªÊ¼µÎ¼ÓBÖÐÈÜÒº¡£µÎ¼Ó¹ý³ÌÖб£³Ö·´Ó¦Î¶ÈΪ90¡ª95¡æ£¬ÔÚEÖÐÊÕ¼¯90¡æÒÔϵÄÁó·Ö¡£
½«Áó³öÎïµ¹Èë·ÖҺ©¶·ÖУ¬·Öȥˮ²ã£¬Óлú²ã¸ÉÔïºóÕôÁó£¬ÊÕ¼¯75¡ª77¡æÁó·Ö£¬²úÁ¿2.0g¡£
»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÊµÑéÖУ¬ÄÜ·ñ½«Na2Cr2O7ÈÜÒº¼Óµ½Å¨ÁòËáÖУ¬²¢ËµÃ÷ÀíÓÉ                                     ¡£
£¨2£©¼ÓÈë·ÐʯµÄ×÷ÓÃÊÇ                ¡£Èô¼ÓÈȺó·¢ÏÖδ¼Ó·Ðʯ£¬Ó¦²ÉÈ¡µÄÕýÈ··½·¨ÊÇ                  ¡£
£¨3£©ÉÏÊö×°ÖÃͼÖУ¬BÒÇÆ÷µÄÃû³ÆÊÇ            £¬DÒÇÆ÷µÄÃû³ÆÊÇ            ¡£
£¨4£©·ÖҺ©¶·Ê¹ÓÃÇ°±ØÐë½øÐеIJÙ×÷ÊÇ      £¨ÌîÕýÈ·´ð°¸±êºÅ£©¡£
a.Èóʪ         b.¸ÉÔï      c.¼ì©         d.±ê¶¨
£¨5£©½«Õý¶¡È©´Ö²úÆ·ÖÃÓÚ·ÖҺ©¶·ÖзÖˮʱ£¬Ë®ÔÚ       ²ã£¨Ìî¡°ÉÏ¡±»ò¡°Ï¡±£©
£¨6£©·´Ó¦Î¶ÈÓ¦±£³ÖÔÚ90¡ª95¡æ£¬ÆäÔ­ÒòÊÇ                                 ¡£
£¨7£©±¾ÊµÑéÖУ¬Õý¶¡È©µÄ²úÂÊΪ        %¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÊµÑéÌâ

1£¬2-¶þäåÒÒÍéÔÚ³£ÎÂÏÂÊÇÎÞÉ«ÒºÌ壬ÃܶÈÊÇ2.18g/cm£¬·ÐµãÊÇ131.4¡æ£¬ÈÛµãÊÇ9.79¡æ£¬²»ÈÜÓÚË®£¬Ò×ÈÜÓÚ´¼¡¢±ûͪµÈÓлúÈܼÁ¡£ÔÚʵÑéÊÒÖпÉÒÔÓÃÏÂͼËùʾװÖÃÀ´ÖƱ¸1£¬2-¶þäåÒÒÍé¡£ÆäÖÐÊÔ¹ÜcÖÐ×°ÓÐÒºä壨±íÃ渲¸ÇÉÙÁ¿Ë®£©¡£

£¨1£©Ð´³öÖƱ¸1£¬2-¶þäåÒÒÍéµÄ»¯Ñ§·½³Ìʽ________¡£
£¨2£©°²È«Æ¿a¿ÉÒÔ·ÀÖ¹µ¹Îü£¬²¢¿ÉÒÔ¼ì²éʵÑé½øÐÐʱÊÔ¹ÜcÖе¼¹ÜÊÇ·ñ·¢Éú¶ÂÈû¡£Èç¹û·¢Éú¶ÂÈû£¬aÖеÄÏÖÏóÊÇ__________¡£
£¨3£©ÈÝÆ÷bÖÐNaOHÈÜÒºµÄ×÷ÓÃÊÇ__________£¬ÈÝÆ÷dÖÐNaOHÈÜÒºµÄ×÷ÓÃÊÇ__________¡£
£¨4£©ÊÔ¹Üc½þÈëÀäË®ÖУ¬ÒÔ¼°Òºäå±íÃ渲¸ÇÉÙÁ¿Ë®µÄÔ­ÒòÊÇ__________¡£
£¨5£©Ä³Í¬Ñ§ÔÚ×öʵÑéʱ£¬Ê¹ÓÃÒ»¶¨Á¿µÄÒºä壬µ±äåÈ«²¿ÍÊɫʱ£¬Í¨ÈëµÄÒÒÏ©»ìºÏÆøÌåµÄÁ¿±ÈÕý³£Çé¿öϳ¬³öÐí¶à¡£Èç¹û×°ÖõÄÆøÃÜÐÔûÓÐÎÊÌ⣬ÊÔ·ÖÎö¿ÉÄܵÄÔ­Òò________________£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºµ¥Ñ¡Ìâ

²»¿ÉÄÜÊÇÒÒÏ©µÄ¼Ó³É²úÎïµÄÊÇ 

A£®CH3CH3 B£®CH3CHCl2 C£®CH3CH2OH D£®CH3CH2Br

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸