¡¾ÌâÄ¿¡¿ÇëÓÃÏÂͼËùʾÒÇÆ÷×°ÖÃÉè¼ÆÒ»¸ö°üÀ¨µç½â±¥ºÍʳÑÎË®²¢²â¶¨µç½âʱ²úÉúµÄÇâÆøµÄÌå»ýºÍ¼ìÑéÂÈÆøµÄÑõ»¯ÐÔµÄʵÑé×°Öá£

£¨1£©ËùÑ¡ÒÇÆ÷ Á¬½Óʱ£¬¸÷½Ó¿ÚµÄ˳ÐòÊÇ(Ìî¸÷½Ó¿ÚµÄ´úºÅ×Öĸ)£ºA ½Ó £¬ ½Ó £¬B ½Ó £¬ ½Ó ¡£_____________

£¨2£©Êµ Ñé ʱ £¬ ×° Öà ÖÐ µÄ ʯ Ä« µç ¼« ½Ó µç Ô´ µÄ _____¼« £¬ Ëù ·¢ Éú µÄ µç ¼« ·´ Ó¦ ʽ Ϊ_____£»Ìúµç¼«½ÓµçÔ´µÄ_____¼«£¬Ëù·¢ÉúµÄµç¼«·´Ó¦Ê½Îª_____£» ´Ëµç½â×Ü·´Ó¦·½³ÌʽΪ_________¡£

£¨3£©ÊµÑé²âµÃ²úÉúµÄÇâÆøÌå»ý(ÒÑÕÛËã³É±ê×¼×´¿ö)Ϊ 5.60 mL£¬µç½âºóÈÜÒºµÄÌå»ýÇ¡ºÃΪ50.0 mL£¬ÔòÈÜÒºÖÐ OH£­µÄŨ¶ÈΪ_____¡£

¡¾´ð°¸¡¿GFHDECÕý2Cl£­£­2e£­===Cl2¡ü¸º2H£«£«2e£­=H2¡ü2NaCl£«2H2O2NaOH£«H2¡ü£«Cl2¡üc(OH£­)£½0.01 mol¡¤L£­1

¡¾½âÎö¡¿

£¨1£©UÐ͹ܷ´Ó¦Æ÷ÖеÄÁ½¸öµç¼«Î´ÏÞ¶¨ÄĸöÊÇÑô¼«»òÒõ¼«£¬¿ÉÒÔÈÎÒâÑ¡Ó᣶ø·´Ó¦Æ÷Á½±ßÁ¬½ÓÄÄЩÒÇÆ÷¼°ÆäÁ¬½Ó˳Ðò£¬È¡¾öÓÚA¡¢BΪÄÄÖֵ缫¡¢Æäµç¼«²úÎïºÍʵÑéÒªÇó¡£ÉèAÉϵ缫ΪÌúÖʵ缫¡¢BÉϵ缫Ϊʯīµç¼«£¬Ôò·´Ó¦Æ÷Á½±ßËùÑ¡Óõĸ÷ÒÇÆ÷½Ó¿ÚÁ¬½Ó˳ÐòΪA½ÓÖüÆøÆ¿µÄG¨D¡úF£¬°ÑË®¼·ÈëÁ¿Í²ÉÏHµ¼¹Ü£¬ÓÃÁ¿Í²²âÁ¿³öÅųöµÄË®Á¿£¬ÒԲⶨÇâÆø²úÉúµÄÌå»ý¡£B½ÓÏ´ÆøÆ¿µÄD¨D¡úE£¬Éú³ÉµÄÂÈÆøÔÚÏ´ÆøÆ¿ÀïÑõ»¯µí·Ûµâ»¯¼ØÈÜÒº£¬ÒÔÖ¤Ã÷ÆäÑõ»¯ÐÔ£¬¶àÓàµÄÂÈÆøͨÈëÉÕ±­ÀïµÄCµ¼¹Ü£¬½èÖúÇâÑõ»¯ÄÆÎüÊÕÂÈÆø£¬·ÀÖ¹ÎÛȾ´óÆø£¬¹Ê´ð°¸Îª£ºG¡¡F¡¡H¡¡D¡¡E¡¡C£»£¨2£©¸ù¾Ýµç½â±¥ºÍʳÑÎË®Ñô¼«Ëù·¢ÉúµÄ·´Ó¦Ê½£º2Cl¡ª£­2e¡ª===Cl2¡ü£¬Îª·ÀÖ¹µç¼«±»¸¯Ê´£¬ÊµÑéÖÐÒ»°ãÑ¡ÓÃʯī×÷Ñô¼«£¬Òõ¼«·¢ÉúµÄÊÇË®µçÀë³öµÄH£«Àë×Ó±»»¹Ô­£¬2H£«£«2e¡ª===H2¡ü£¬´Ó¶øÆÆ»µË®µÄµçÀëƽºâ£¬ÔÚÒõ¼«ÇøÓòÀïÐγÉÇâÑõ»¯ÄÆ£¬ÏÔ¼îÐÔ£¬Òõ¼«Í¨³£Ê¹ÓÃÌúµç¼«¡£µç½âµÄ×Ü·´Ó¦·½³ÌʽΪ£º2NaCl£«2H2O2NaOH£«H2¡ü£«Cl2¡ü£¬¹Ê´ð°¸Îª£ºÕý¡¢2Cl£­£­2e£­===Cl2¡ü¡¢¸º¡¢2H£«£«2e£­===H2¡ü¡¢2NaCl£«2H2O2NaOH£«H2¡ü£«Cl2¡ü£»£¨3£©

ÒÑÖªµç½â²úÉúÇâÆø5.60 mL£¬ÆäÎïÖʵÄÁ¿Îª£½2£®5¡Á10£­4mol£¬ÓÉ·½³Ìʽ¿ÉµÃ

x£½2¡Á2.5¡Á10£­4mol£½5¡Á10£­4mol

c(OH¡ª)£½£½0.01 mol¡¤L¡ª1£¬¹Ê´ð°¸Îª£º0.01 mol¡¤L¡ª1¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿¿ÉÄæ·´Ó¦2A+2B 3C+DÏàͬÌõ¼þϵķ´Ó¦ËÙÂÊ£¬·´Ó¦ËÙÂÊ×î¿ìµÄÊÇ( )

A. v(A)= 0.55mol (L¡¤min) B. v(B)= 0.6mol/(L¡¤s)

C. v(C)=0.75mol/(L¡¤min) D. v(D)== 0.4mol/ (L¡¤min)

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿Ö»ÓÃÒ»ÖÖÊÔ¼Á»ò²Ù×÷,³ýÈ¥ÏÂÁÐÎïÖÊÖеÄÔÓÖÊ(À¨ºÅÄÚΪÔÓÖÊ)д³öÊÔ¼Á»ò²Ù×÷µÄÃû³Æ¡¢·½·¨¼°ÓйصĻ¯Ñ§·½³Ìʽ»òÀë×Ó·½³Ìʽ:

(1)Fe2O3(Al2O3)_________________;Àë×Ó·½³Ìʽ__________¡£

(2)Fe2O3[Fe(OH)3]________;»¯Ñ§·½³Ìʽ_______________¡£

(3)FeSO4ÈÜÒº(CuSO4)_____________;Àë×Ó·½³Ìʽ_________¡£

(4)FeCl3ÈÜÒº(FeCl2)_____________;Àë×Ó·½³Ìʽ__________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÈçͼËùʾ£¬a¡¢b¡¢c¡¢d¾ùΪʯīµç¼«£¬Í¨µç½øÐеç½â£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ(¡¡ ¡¡)

A. µç·Öеç×ÓÁ÷Ïò£º¸º¼«¡úd¡úc¡úb¡úa¡úÕý¼«

B. a¡¢cÁ½¼«²úÉúÆøÌåµÄÎïÖʵÄÁ¿ÏàµÈ

C. SO42-Ïòbµç¼«Ô˶¯£¬Cl-Ïòcµç¼«Ô˶¯

D. ͨµçºóÒÒÉÕ±­µÎÈë·Ó̪ÈÜÒºd¼«»á±äºì

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÈçͼËùʾΪһ¶¨Á¿AlCl3ÈÜÒºÖмÓÈëNaOHÈÜÒººó£¬²úÉúAl(OH)3°×É«³ÁµíµÄÖÊÁ¿ÓëNaOHµÄÎïÖʵÄÁ¿Ö®¼äµÄ¹ØϵÇúÏß¡£

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©AµãʱÒѲμӷ´Ó¦µÄAlCl3ºÍNaOHµÄÎïÖʵÄÁ¿Ö®±ÈΪ________¡£

£¨2£©AB¶ÎÇúÏßËù±íʾµÄ·´Ó¦µÄÀë×Ó·½³ÌʽΪ_________________________¡£

£¨3£©ÏòB´¦Éú³ÉµÄÈÜÒºÖÐͨÈë¶þÑõ»¯Ì¼£¬¿É¹Û²ìµ½µÄÏÖÏóÊÇ_______________________¡£

£¨4£©Ïòº¬ÓÐ0.1 mol NH4Al(SO4)2µÄÈÜÒºÖÐÖðµÎ¼ÓÈë5 mol¡¤L£­1 NaOHÈÜÒº£¬¿ªÊ¼·¢ÏÖÈÜÒºÖгöÏÖ°×É«³Áµí²¢Öð½¥Ôö¶à£»Ò»¶Îʱ¼äºóÓд̼¤ÐÔÆøζµÄÆøÌåÒݳö£»×îºó°×É«³ÁµíÖð½¥¼õÉÙ²¢×îÖÕÏûʧ¡£ÇëÔÚÏÂͼÖл­³öÉú³É³ÁµíµÄÎïÖʵÄÁ¿Óë¼ÓÈëNaOHÈÜÒºÌå»ýµÄ¹ØϵʾÒâͼ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿Ä³Ð£»¯Ñ§ÐËȤС×éÓÃÈçͼËùʾ¹ý³Ì³ýÈ¥AlCl3Öк¬ÓеÄMg2+¡¢K+ÔÓÖÊÀë×Ó²¢¾¡¿ÉÄܼõÉÙAlCl3µÄËðʧ¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺

(1)д³ö»ìºÏÎïÖмÓÈë×ãÁ¿ÇâÑõ»¯ÄÆÈÜҺʱ£¬ÈÜÒºÖз¢Éú·´Ó¦µÄÀë×Ó·½³Ìʽ£º_______________________¡£

(2)ÇâÑõ»¯ÄÆÈÜÒºÄÜ·ñÓð±Ë®´úÌ棬Ϊʲô£¿___________________________¡£

(3)ÈÜÒºaÖдæÔÚµÄÀë×ÓÓÐ________________£»ÔÚÈÜÒºaÖмÓÈëÑÎËáʱÐè¿ØÖÆÑÎËáµÄÁ¿£¬ÎªÊ²Ã´£¿__________________________________¡£Îª´Ë£¬¸Ä½ø·½·¨ÊÇ___________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÏÂÁÐ˵·¨ÖдíÎóµÄÊÇ£¨ £©

¢Ù»¯Ñ§ÐÔÖÊÏàËƵÄÓлúÎïÊÇͬϵÎï

¢Ú·Ö×Ó×é³ÉÏà²îÒ»¸ö»ò¼¸¸öCH2Ô­×ÓÍŵÄÓлúÎïÊÇͬϵÎï

¢ÛÈôÌþÖÐ̼¡¢ÇâÔªËصÄÖÊÁ¿·ÖÊýÏàͬ£¬ËüÃDZض¨ÊÇͬϵÎï

¢Ü»¥ÎªÍ¬·ÖÒì¹¹ÌåµÄÁ½ÖÖÓлúÎïµÄÎïÀíÐÔÖÊÓвî±ð£¬µ«»¯Ñ§ÐÔÖʱض¨ÏàËÆ£®

A. ¢Ù¢Ú¢Û B. ¢Ú¢Û C. ¢Û¢Ü D. ¢Ù¢Ú¢Û¢Ü

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿25¡æʱ£¬ÏÂÁÐÓйصç½âÖÊÈÜÒºµÄ˵·¨ÕýÈ·µÄÊÇ( )

A. ½«Na2CO3ÈÜÒºÓÃˮϡÊͺó£¬pH±ä´ó£¬Kw²»±ä

B. ÏòÓÐAgCl¹ÌÌåµÄ±¥ºÍÈÜÒºÖмÓÉÙÐíË®£¬c(Ag+)ºÍKsp(AgCl)¶¼²»±ä

C. pH=4.75Ũ¶È¾ùΪ0.1mol/LµÄCH3COOH¡¢CH3COONaµÄ»ìºÏÈÜÒºÖУºc(CH3COO£­)+c(OH£­)<c(H+)+c(CH3COOH)

D. ·Ö±ðÓÃpH=2ºÍpH=3 µÄ CH3COOHÈÜÒºÖк͵ÈÎïÖʵÄÁ¿µÄNaOH£¬ÏûºÄCH3COOHÈÜÒºµÄÌå»ý·Ö±ðΪVaºÍVb£¬Ôò10Va=Vb

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿Ä³ÊµÑéС×éÓÃ100 mL 0.50 mol¡¤L£­1 NaOHÈÜÒºÓë100 mL 0.55 mol¡¤L£­1ÑÎËá½øÐÐÖкÍÈȵIJⶨ¡£×°ÖÃÈçͼËùʾ¡£»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©ÈôʵÑé¹²ÐèÒª400 mL NaOHÈÜÒº£¬ÊµÑéÊÒÔÚÅäÖƸÃÈÜҺʱ£¬ÔòÐèÒª³ÆÁ¿NaOH¹ÌÌå______g¡£

£¨2£©Í¼ÖÐ×°ÖÃȱÉÙµÄÒÇÆ÷ÊÇ______________________________¡£

£¨3£©ÑÎËáÉÔ¹ýÁ¿µÄÔ­ÒòÊÇ________________________________¡£

£¨4£©ËéÅÝÄ­ËÜÁϼ°ÅÝÄ­ËÜÁÏ°åµÄ×÷ÓÃÊÇ___________________¡£

£¨5£©ÈôÓõÈŨ¶ÈµÄ´×ËáÓëNaOHÈÜÒº·´Ó¦£¬Ôò²âµÃµÄÖкÍÈÈ(¦¤H)________(Ìî¡°Æ«´ó¡±¡°Æ«Ð¡¡±»ò¡°²»±ä¡±)£¬ÆäÔ­ÒòÊÇ_______¡£

£¨6£©ÇëÌîдϱíÖеÄƽ¾ùζȲ

ʵÑé´ÎÊý

ÆðʼζÈT1/¡æ

ÖÕֹζÈ

T2/¡æ

ƽ¾ùζȲî

(T2£­T1)/¡æ

HCl

NaOH

ƽ¾ùÖµ

1

26.2

26.0

26.1

30.1

________

2

27.0

27.4

27.2

33.3

3

25.9

25.9

25.9

29.8

4

26.4

26.2

26.3

30.4

£¨7£©Èô²âµÃ¸Ã·´Ó¦·Å³öµÄÈÈÁ¿Îª2.865 kJ£¬Çëд³öÑÎËáÓëNaOHÈÜÒº·´Ó¦µÄÖкÍÈȵķ½³Ìʽ£º__________________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸