Question

ij½á¾§Ë®ºÏÎïµÄ»¯Ñ§Ê½ÎªA?xH₂O£¬ÆäÏà¶Ô·Ö×ÓÖÊÁ¿ÎªB£®ÔÚ60¡ãCʱ£¬mg¸Ã¾§ÌåÈÜÓÚngË®ÖУ¬ÖƵÃVmLÃܶÈΪdg?mL-1µÄ±¥ºÍÈÜÒº£®ÏÂÁбíʾʽ»òÅжÏÕýÈ·µÄÊÇ£¨¡¡¡¡£©

• A¡¢¸ÃÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶ÈΪ

  1000m

  BV

  mol/L
• B¡¢¸ÃζÈÏÂAµÄÈܽâ¶ÈΪ

  100(B-18x)

  nB+18mxV

  g
• C¡¢½«10gAͶÈëµ½¸Ã±¥ºÍÈÜÒºÖУ¬Îö³öµÄ¾§Ìå´óÓÚ10g£¬ÇÒÈÜÒºÖÊÁ¿¼õÉÙ£¬µ«Å¨¶È²»±ä
• D¡¢¸ÃÈÜÒºµÄÖÊÁ¿·ÖÊýΪ

  100m

  m+n

  %

Answer 1

¿¼µã£ºÎïÖʵÄÁ¿Å¨¶ÈµÄÏà¹Ø¼ÆËã

רÌ⣺¼ÆËãÌâ

·ÖÎö£ºA£®¸ù¾Ýn=

m

M

¼ÆËãA?xH₂OµÄÎïÖʵÄÁ¿£¬¼´ÎªAµÄÎïÖʵÄÁ¿£¬ÔÙ¸ù¾Ýc=

n

V

¼ÆË㣻
B£®¸ù¾Ý»¯Ñ§Ê½ÖÐAµÄÖÊÁ¿·ÖÊý¼ÆËãmg A?xH₂OÖÐAµÄÖÊÁ¿£¬ÐγÉÈÜÒºÖÐË®µÄÖÊÁ¿=ng+A?xH₂O½á¾§Ë®ÖÊÁ¿£¬ÔÙ¸ù¾ÝÈܽâ¶È¶¨Òå¼ÆË㣻
C.10gAͶÈëµ½¸Ã±¥ºÍÈÜÒºÖУ¬²»ÄÜÈܽ⣬Îö³öA?xH₂O£¬Ê£ÓàÈÜÒºÈÔΪ±¥ºÍÈÜÒº£»
D£®¼ÆËãmg¸Ã½á¾§Ë®ºÏÎïÖÐAµÄÖÊÁ¿£¬ÈÜÒºÖÊÁ¿Îª£¨m+n£©g£¬ÔÙÀûÓÃÖÊÁ¿·ÖÊýµÄ¶¨Òå¼ÆË㣮

½â´ð£º ½â£ºA£®mg½á¾§Ë®ºÏÎïA?xH₂OµÄÎïÖʵÄÁ¿Îª

mg

Bg/mol

=

m

B

mol£¬ËùÒÔAµÄÎïÖʵÄÁ¿Îª

m

B

mol£¬ÈÜÒºÈÜÒºVmL£¬ÎïÖʵÄÁ¿Å¨¶Èc=

m B

V¡Á10-3L

=

1000m

BV

mol/L£¬¹ÊAÕýÈ·£»
B£®mg¸Ã½á¾§Ë®ºÏÎïA?nH₂OÖÐAµÄÖÊÁ¿Îªmg¡Á

B-18x

B

£¬ÐγÉÈÜÒºÖÐÈܼÁË®µÄÖÊÁ¿Îªng+mg¡Á

18x

B

£¬Áî¸ÃζÈÏ£¬Èܽâ¶ÈΪSg£¬Ôò100g£ºSg=£¨ng+mg¡Á

18x

B

£©£ºmg¡Á

B-18x

B

£¬½âµÃS=

100m(B-18x)

nB+18mx

£¬¹ÊB´íÎó£»
C£®10gAͶÈëµ½¸Ã±¥ºÍÈÜÒºÖУ¬²»ÄÜÈܽ⣬Îö³öA?xH₂O£¬Îö³öµÄ¾§Ìå´óÓÚ10g£¬ÈÜÒºÖÊÁ¿¼õÉÙ£¬Ê£ÓàÈÜÒºÈÔΪ±¥ºÍÈÜÒº£¬ÔòÈÜÒºÖÊÁ¿¼õÉÙ£¬¹ÊCÕýÈ·£»
D£®mg¸Ã½á¾§Ë®ºÏÎïA?nH₂OÖÐAµÄÖÊÁ¿Îªmg¡Á

B-18x

B

£¬ÈÜÒºÖÊÁ¿Îª£¨m+n£©g£¬¹ÊÈÜÒºÖÐAµÄÖÊÁ¿·ÖÊý=

mg¡Á B-18x B

(m+n)g

¡Á100%=

m(B-18x)

B(m+n)

¡Á100%£¬¹ÊD´íÎó£¬
¹ÊÑ¡£ºAC£®

µãÆÀ£º±¾Ì⿼²éÈÜҺŨ¶È¼ÆË㣬Éæ¼°Èܽâ¶È¡¢ÖÊÁ¿·ÖÊý¡¢ÎïÖʵÄÁ¿Å¨¶ÈµÄ¼ÆËãÓëÏ໥¹Øϵ£¬ÄѶÈÖеȣ¬×¢Òâ¶Ô¹«Ê½µÄÀí½âÓëÁé»îÔËÓã®