17£®ÏÖÓÐÏÂÁÐÎïÖÊ£º
¢Ù¸É±ù   ¢ÚNaHCO3¾§Ìå  ¢Û°±Ë®  ¢Ü´¿´×Ëá¢ÝFeCl3ÈÜÒº    ¢ÞÍ­        ¢ßFe£¨OH£©3½ºÌå    ¢àÕáÌÇ£¬
£¨1£©ÆäÖÐÊôÓÚµç½âÖʵÄÊǢڢܣ¬
£¨2£©Ð´³öNaOH£¨aq£© ÓëAl·´Ó¦µÄÀë×Ó·½³Ìʽ£º2Al+2OH-+2H2O¨T2AlO2-+3H2¡ü£¬
£¨3£©½ºÌåÊÇÒ»ÖÖ³£¼ûµÄ·Öɢϵ£¬»Ø´ðÏÂÁÐÎÊÌ⣮
¢ÙÏòFe£¨OH£©3½ºÌåÖмÓÈëNa2SO4±¥ºÍÈÜÒº£¬ÓÉÓÚSO42-Àë×Ó£¨ÌîÀë×Ó·ûºÅ£©µÄ×÷Óã¬Ê¹½ºÌåÐγÉÁ˳Áµí£¬Õâ¸ö¹ý³Ì½Ð×ö½ºÌåµÄ¾Û³Á£®
¢ÚÇø·Ö½ºÌåºÍÈÜÒº³£Óõķ½·¨½Ð×ö¶¡´ï¶ûЧӦ£®

·ÖÎö £¨1£©ÔÚË®ÈÜÒºÀï»òÈÛÈÚ״̬ÏÂÄܵ¼µçµÄ»¯ºÏÎïÊǵç½âÖÊ£¬ÔÚË®ÈÜÒºÀïºÍÈÛÈÚ״̬϶¼²»µ¼µçµÄ»¯ºÏÎïÊǷǵç½âÖÊ£»
£¨2£©ÂÁÓëÇâÑõ»¯ÄÆ·´Ó¦Éú³ÉÆ«ÂÁËáÄƺÍÇâÆø£»
£¨3£©¢ÙÏòÖó·ÐµÄÕôÁóË®ÖÐÖðµÎ¼ÓÈëFeCl3±¥ºÍÈÜÒº£»¼ÌÐøÖó·ÐÖÁÈÜÒº³ÊºìºÖÉ«£¬Í£Ö¹¼ÓÈÈ£¬¿ÉÖƵÃFe£¨OH£©3½ºÌ壻
¢Ú½ºÌåÓöµç½âÖÊ·¢Éú¾Û³Á£»
¢Û½ºÌå¾ßÓж¡´ï¶ûЧӦ£®

½â´ð ½â£º£¨1£©¢Ú¢ÜÔÚË®ÈÜÒºÀï»òÈÛÈÚ״̬ÏÂÄܵçÀë³öÒõÑôÀë×Ó¶øʹÆäË®ÈÜÒº»òÈÛÈÚ״̬µ¼µç£¬ËùÒÔÊôÓÚµç½âÖÊ£¬¹Ê´ð°¸Îª£º¢Ú¢Ü£»
£¨2£©ÂÁÓëÇâÑõ»¯ÄÆ·´Ó¦Éú³ÉÆ«ÂÁËáÄƺÍÇâÆø£¬Àë×Ó·´Ó¦Îª2Al+2OH-+2H2O¨T2AlO2-+3H2¡ü£¬¹Ê´ð°¸Îª£º2Al+2OH-+2H2O¨T2AlO2-+3H2¡ü£»
£¨3£©¢ÙÏòFe£¨OH£©3½ºÌåÖмÓÈëNa2SO4±¥ºÍÈÜÒº£¬ÓÉÓÚÁòËá¸ùÀë×ÓÖкÍÁËÇâÑõ»¯Ìú½ºÁ£µÄµçºÉ£¬µ¼Ö½ºÌå·¢ÉúÁ˾۳Á£¬¹Ê´ð°¸Îª£ºSO42-£»
¢Ú½ºÌå¾ßÓж¡´ï¶ûЧӦ£¬¾Ý´Ë¿ÉÒÔÇø·Ö½ºÌåºÍÈÜÒº£¬½ºÌåµÄ¶¡´ï¶ûЧӦÊǽºÌåÁ£×Ó¶Ô¹âÏßµÄÉ¢Éä×÷ÓÃÐγɵģ¬¹Ê´ð°¸Îª£º¶¡´ï¶ûЧӦ£®

µãÆÀ ±¾Ì⿼²éÁ˵ç½âÖÊ¡¢·Çµç½âÖʵĸÅÄî¡¢Àë×Ó·´Ó¦·½³ÌʽµÄÊéд¡¢½ºÌåµÄÖƱ¸¼°ÐÔÖʵȣ¬±È½Ï»ù´¡£¬²àÖضԻù´¡ÖªÊ¶µÄ¹®¹Ì£¬×¢Òâ¶Ô»ù´¡ÖªÊ¶µÄÀí½âÕÆÎÕ£¬ÌâÄ¿ÄѶȲ»´ó£®×¢ÒâÕÆÎÕ½ºÌåµÄÖƱ¸·½·¨¡¢½ºÌåµÄÐÔÖʼ°¼ø±ð·½·¨£¬Ã÷È·µç½âÖÊÓë·Çµç½âÖʵÄÇø±ð£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ

16£®¸õ£¨Cr£©ÓжàÖÖ»¯ºÏÎÔÚ¹¤ÒµÉú²úÖÐÓй㷺µÄÓÃ;£®
£¨1£©¹¤ÒµÉÏÀûÓøõÌú¿ó£¨FeO Cr2O3£©Ò±Á¶¸õµÄ¹¤ÒÕÁ÷³ÌÈçÏ£º
a£®²Ù×÷¢ÙÖÐΪ¼ÓÈȱºÉÕËÙÂʺÍÌá¸ßÔ­ÁϵÄÀûÓÃÂÊ£¬¿É²ÉÈ¡µÄ´ëÊ©Êǽ«¸õÌú¿ó·ÛË飨´ðÒ»Ìõ¼´¿É£©£®
b£®½þ³öÒºÖк¬ÓеÄÖ÷Òª³É·ÖΪNa2CrO4£¬ÏòÂËÒºÖмÓËữµÄÂÈ»¯±µÈÜÒºÓа×É«³ÁµíÉú³É£¬Ôò²Ù×÷¢Û·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽCrO42-+Ba2+=BaCrO4¡ý£®
£¨2£©¸õµÄ»¯ºÏÎïÓж¾£¬ÅÅ·ÅÇ°Òª¾­¹ý´¦Àí£¬Í¨³£Óõç½â·¨£º
½«º¬Cr2O72-µÄ·ÏË®·ÅÈëµç½â²ÛÄÚ£¬¼ÓÈëÒ»¶¨Á¿ÂÈ»¯ÄÆ£¬ÓÃÌú×÷µç¼«ÌṩFe2+£¬Cr2O72-½«Fe2+Ñõ»¯Éú³ÉFe3+£¬±¾Éí±»»¹Ô­Éú³ÉCr3+£¬×îºóCr3+ºÍFe3+ÒÔCr£¨OH£©3ºÍFe£¨OH£©3µÄÐÎʽ³ýÈ¥£®Ìú×÷µç½â²ÛµÄÑô¼«£¬Òõ¼«·´Ó¦Ê½Îª2H++2e-=H2¡ü£¬Cr2O72-Ñõ»¯Fe2+µÄÀë×Ó·½³ÌʽΪ6Fe2++Cr2O72-+14H+=6Fe3++2Cr3++7H2O£®
£¨3£©CrO3ÊÇÒ»ÖÖ³£¼ûµÄ¸õµÄÑõ»¯ÎÆäÈÈÎȶ¨ÐԽϲ¼ÓÈÈʱÖ𲽷ֽ⣮ȡ100gCrO3¼ÓÈÈ£¬Ê£Óà¹ÌÌåµÄÖÊÁ¿Ëæζȵı仯ÈçϱíËùʾ£®
ζÈ/K480505615730
ÖÊÁ¿/g94.6792.00x76.00
»¯Ñ§Ê½Cr3O8yCrO2Cr2O3
Ôòx=84.00£¬yΪCr2O5£¨Ð´»¯Ñ§Ê½£©£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ

17£®XÊÇÒ»ÖÖ¼îʽ̼ËáþÂÁ£¬ÏÖÈ¡Ò»¶¨ÖÊÁ¿µÄÑùÆ·£¬Öð½¥¼ÓÈëijŨ¶ÈÑÎËá³ä·Ö·´Ó¦£¬¼ÓÖÁ87.5mLʱ£¬²úÉúÆøÌåµÄÌå»ýΪ112.0mL£¨±ê¿ö£©£¬¼ÌÐø¼ÓÑÎËáÖÁ90mLʱ·´Ó¦ÍêÈ«£¬ÓÖ²úÉúÆøÌå112.0mL£¨±ê¿ö£©£®ÔÚ×îºóËùµÃÈÜÒºÖеμӹýÁ¿µÄNaOHÈÜÒº£¬µÃµ½µÄ°×É«³ÁµíÏ´µÓ¸ÉÔï³ÆÖØΪ3.48g£®£¨ÒÑÖªA1£¨0H£©3+NaOH¨TNaAlO2+2H2O£©
£¨1£©ÇóËùÓÃÑÎËáµÄÎïÖʵÄÁ¿µÄŨ¶È£»
£¨2£©ÇóXÖÐMgÓëA1µÄÎïÖʵÄÁ¿Ö®±È£»
£¨3£©ÇóXµÄ»¯Ñ§Ê½£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ

5£®±½»·ÉÏÔ­ÓеÄÈ¡´ú»ù¶ÔÐÂÈ¡´úµ¼Èë±½»·ÉϵÄÈ¡´ú»ùµÄλÖÃÓÐÒ»¶¨µÄÓ°Ï죬Æä¹æÂÉÊÇ£º
£¨1£©±½»·ÉÏе¼ÈëµÄÈ¡´ú»ùËùÕ¼µÄλÖÃÖ÷Òª¾ö¶¨ÓÚÔ­ÓÐÈ¡´ú»ùµÄÐÔÖÊ£®
£¨2£©¿ÉÒÔ°ÑÔ­ÓÐÈ¡´ú»ù·Ö³ÉÁ½ÀࣺµÚÒ»ÀàÈ¡´ú»ùÖ÷Ҫʹе¼ÈëµÄÈ¡´ú»ù½øÈë±½»·µÄÁÚλºÍ¶Ô룬Èç-OH¡¢-CH3£¨»òÌþ»ù£©¡¢-Cl¡¢-Br¡¢-O-CORµÈ£¬µÚ¶þÀàÈ¡´ú»ùÖ÷Ҫʹе¼ÈëµÄÈ¡´ú»ù½øÈë±½»·µÄ¼äλ£®ÀýÈç-NO2¡¢-SO3H¡¢-CHOµÈ£®
Çëд³öÏÂͼÖТڢܢÝÈý²½·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º¡¢¡¢»ò£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

12£®³£ÎÂÏ£¬¼ÓË®³åϡʱc£¨H+£©/c£¨OH-£©µÄÖµÃ÷ÏÔ¼õСµÄÈÜÒºÖУ¬Ò»¶¨ÄÜ´óÁ¿¹²´æµÄÀë×Ó×éÊÇ£¨¡¡¡¡£©
¢ÙK+¡¢Cl-¡¢NO3-¡¢CH3COO-¡¡¢ÚK+¡¢Fe2+¡¢I-¡¢SO42-
¢ÛBa2+¡¢Cl-¡¢NO3-¡¢Na+¡¡¢ÜNa+¡¢Ca2+¡¢Cl-¡¢HCO3-
¢ÝK+¡¢SO42-¡¢Cl-¡¢NO3-£®
A£®¢ÚB£®¢Ù¢Û¢ÝC£®¢Ú¢ÜD£®¢Ú¢Û¢Ý

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

2£®100mL 6mol•L-1 H2SO4¸ú¹ýÁ¿Ð¿·Û·´Ó¦£¬ÔÚÒ»¶¨Î¶ÈÏ£¬ÎªÁ˼õ»º·´Ó¦½øÐеÄËÙÂÊ£¬µ«ÓÖ²»Ó°ÏìÉú³ÉÇâÆøµÄ×ÜÁ¿£¬¿ÉÏò·´Ó¦ÎïÖмÓÈëÊÊÁ¿µÄ£¨¡¡¡¡£©
A£®Na2CO3£¨s£©B£®Ë®C£®ÏõËá¼ØÈÜÒºD£®ÑÎËá

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ

9£®£¨1£©ÒÑ֪ij¸ß¾ÛÎïµÄ½á¹¹Ê½ÊÇ£¬Æäµ¥ÌåΪ£ºCH2=CHCl¡¢CH2=C£¨CH3£©COOCH3£®
£¨2£©ÂÁÓëijЩ½ðÊôÑõ»¯ÎïÔÚ¸ßÎÂϵķ´Ó¦³ÆΪÂÁÈÈ·´Ó¦£¬¿ÉÓÃÓÚÒ±Á¶¸ßÈÛµã½ðÊô£®
ÒÑÖª£º4Al£¨s£©+3O2£¨g£©¨T2Al2O3£¨s£©¡÷H=-2830kJ•mol-1
Fe2O3£¨s£©+$\frac{3}{2}$C£¨s£©¨T$\frac{3}{2}$CO2£¨g£©+2Fe£¨s£©¡÷H=+230kJ•mol-1
C£¨s£©+O2£¨g£©¨TCO2£¨g£©¡÷H=-390kJ•mol-1
ÂÁÓëÑõ»¯Ìú·¢ÉúÂÁÈÈ·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽÊÇ£º2Al£¨s£©+Fe2O3£¨s£©=Al2O3£¨s£©+2Fe£¨s£©¡÷H=-600kJ/mol£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

6£®¹ØÓÚ·´Ó¦KIO3+6HI¨T3I2+KI+3H2OµÄ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®Ñõ»¯¼ÁÓ뻹ԭ¼ÁµÄÎïÖʵÄÁ¿Ö®±ÈΪ1£º6
B£®Ñõ»¯²úÎïÓ뻹ԭ²úÎïµÄÖÊÁ¿Ö®±ÈΪ1£º1
C£®Éú³É3molˮʱÓÐ1mol KIO3±»Ñõ»¯
D£®1mol KIO3²Î¼Ó·´Ó¦Ê±ÓÐ5molµç×ÓתÒÆ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

7£®ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®HF¡¢HCl¡¢HBr¡¢HIµÄÈÛµã·ÐµãÒÀ´ÎÉý¸ß
B£®HF¡¢HCl¡¢HBr¡¢HIË®ÈÜÒºµÄËáÐÔÒÀ´ÎÉý¸ß
C£®ÒÒ´¼Ò×ÈÜÓÚË®£¬ÊÇÒòΪÒÒ´¼·Ö×ÓÓëË®·Ö×ÓÖ®¼äÖ»´æÔÚ·¶µÂ»ªÁ¦
D£®Âȵĸ÷ÖÖº¬ÑõËáµÄËáÐÔÓÉÇ¿µ½ÈõÅÅÁÐΪHClO£¾HClO2£¾HClO3£¾HClO4

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸