ÑÎËá¡¢ÁòËáºÍÏõËáÊÇÖÐѧ½×¶Î³£¼ûµÄ¡°Èý´óËᡱ£®Çë¾Í¡°Èý´óËᡱÓë½ðÊôÍ­·´Ó¦µÄÇé¿ö£¬»Ø´ðÏÂÁÐÎÊÌ⣺
(1)ÎÒÃÇÖªµÀ£¬Ï¡ÑÎËáÓëÍ­²»·´Ó¦£¬µ«ÏòÏ¡ÑÎËáÖмÓÈëH2O2ºó£¬Ôò¿ÉʹͭÈܽ⣮¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ_____________________________£®Ä³Í¬Ñ§Î´¼ÓÈëÑõ»¯¼Á£¬¶øÊÇÉè¼ÆÁËÒ»¸öʵÑé×°Öã¬Ò²ÄÜʹͭºÜ¿ìÈÜÓÚÏ¡ÑÎËᣮÇëÔÚÏÂÃæµÄ·½¿òÖл­³ö¸Ã×°Öãº
(2)ÔÚÒ»¶¨Ìå»ýµÄ18 mol/LµÄŨÁòËáÖмÓÈë¹ýÁ¿µÄͭƬ£¬¼ÓÈÈʹ֮·´Ó¦£¬±»»¹Ô­µÄÁòËáÊÇ0.9 mol£¬Ôò¸ÃÁòËáµÄʵ¼ÊÌå»ý________(Ìî¡°£¾¡±¡°£½¡±»ò¡°£¼¡±)100 mL. ÓÐͬѧÌá³ö£ºÈôʹʣÓàµÄͭƬ¼ÌÐøÈܽ⣬¿ÉÏòÆäÖмÓÈëÏõËáÑΣ¬¿ÉÐÐÂð£¿________(Ìî¡°¿ÉÐС±»ò¡°²»¿ÉÐС±)£®
(3)½«µÈÖÊÁ¿µÄͭƬ·Ö±ðÓëµÈÌå»ý¡¢¹ýÁ¿µÄŨÏõËáºÍÏ¡ÏõËá·´Ó¦£¬ËùµÃµ½µÄÈÜҺǰÕß³ÊÂÌÉ«£¬ºóÕß³ÊÀ¶É«£¬Ä³Í¬Ñ§Ìá³ö¿ÉÄÜÊÇCu2£«Å¨¶È²»Í¬ÒýÆðµÄ£¬ÄãͬÒâÕâÖÖ¿´·¨Âð£¿________(ÌͬÒ⡱»ò¡°²»Í¬Ò⡱)£¬Ô­ÒòÊÇ______________________________________£®ÁíһͬѧÌá³öÈÜÒº³Ê¡°ÂÌÉ«¡±ÊÇÈÜÒºÖÐCu2£«ÓëNO2¹²´æµÄ½á¹û£¬ÇëÄãÉè¼ÆʵÑé̽¾¿´Ë˵·¨ÕýÈ·Óë·ñ£¬¼òÊöʵÑé·½°¸¡¢ÊµÑéÏÖÏó¼°Óɴ˵óöµÄ½áÂÛ£º__________________________________________________________________________.
(1)Cu£«H2O2£«2HCl===CuCl2£«2H2O
×÷ͼ£ºÒÔͭΪÑô¼«£¬ÒÔÑÎËáΪµç½âÖÊÈÜÒºµÄµç½â³Ø×°ÖÃ

(2)£¾£»¿ÉÐÐ
(3)²»Í¬Ò⣻µÈÖÊÁ¿µÄͭƬÓëµÈÌå»ý¡¢¹ýÁ¿µÄŨÏõËᡢϡÏõËá·´Ó¦£¬ÈÜÒºÖÐCu2£«½«Ò»¶¨Á¿µÄNO2ͨÈëͭƬÓëÏ¡ÏõËá·´Ó¦ºóµÄÈÜÒºÖУ¬ÈôÈÜÒº³ÊÂÌÉ«£¬Ôò¸ÃͬѧµÄ½áÂÛÕýÈ·£¬·´Ö®£¬²»ÕýÈ·(ÆäËûºÏÀí´ð°¸Ò²¶Ô)
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÑÎËá¡¢ÁòËáºÍÏõËáÊÇÖÐѧ½×¶Î³£¼ûµÄ¡°Èý´óËᡱ£®ÏÖ¾ÍÈý´óËáÓë½ðÊôÍ­·´Ó¦µÄÇé¿ö£¬»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©Ï¡ÑÎËá²»ÓëCu·´Ó¦£¬ÈôÔÚÏ¡ÑÎËáÖмÓÈëH2O2£¨³£¼ûÑõ»¯¼Á£¬×÷Ñõ»¯¼Áʱ»¹Ô­²úÎïΪˮ£©ºó£¬Ôò¿Éʹͭ˳ÀûÈܽ⣮¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º
Cu+H2O2+2HCl=2H2O+CuCl2
Cu+H2O2+2HCl=2H2O+CuCl2
£®
£¨2£©ÔÚÒ»¶¨Ìå»ýµÄ10mol?L-1µÄŨÁòËáÖмÓÈë¹ýÁ¿Í­Æ¬£¬¼ÓÈÈʹ֮·´Ó¦£¬±»»¹Ô­µÄÁòËáΪ0.9mol£®ÔòŨÁòËáµÄʵ¼ÊÌå»ý
´óÓÚ
´óÓÚ
£¨Ìî¡°´óÓÚ¡±¡¢¡°µÈÓÚ¡±»ò¡°Ð¡ÓÚ¡±£©180mL£®ÈôʹʣÓàµÄͭƬ¼ÌÐøÈܽ⣬¿ÉÔÚÆäÖмÓÈëÏõËáÑÎÈÜÒº£¨ÈçKNO3ÈÜÒº£©£¬Ôò¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽΪ
3Cu+2NO3-+8H+=3Cu2++2NO¡ü+4H2O
3Cu+2NO3-+8H+=3Cu2++2NO¡ü+4H2O
£®
£¨3£©¸ù¾ÝÏÂͼ²Ù×÷¼°ÏÖÏóÍƶÏËáXΪ
b
b
£¨ÌîÐòºÅ£©£®
a¡¢Å¨ÑÎËá          b¡¢Å¨ÁòËá            c¡¢Å¨ÏõËᣮ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÑÎËá¡¢ÁòËáºÍÏõËáÊÇÖÐѧ½×¶Î³£¼ûµÄ¡°Èý´óËᡱ£®ÏÖ¾ÍÈý´óËáÓë½ðÊôÍ­·´Ó¦µÄÇé¿ö£¬»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©Ï¡ÑÎËá²»ÓëCu·´Ó¦£¬ÈôÔÚÏ¡ÑÎËáÖмÓÈëH2O2£¨³£¼ûÑõ»¯¼Á£¬×÷Ñõ»¯¼Áʱ»¹Ô­²úÎïΪˮ£©ºó£¬Ôò¿Éʹͭ˳ÀûÈܽ⣮¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º
Cu+H2O2+2HCl=CuCl2+2H2O
Cu+H2O2+2HCl=CuCl2+2H2O
£®
£¨2£©ÔÚÒ»¶¨Ìå»ýµÄ10mol?l-1µÄŨÁòËáÖмÓÈë¹ýÁ¿Í­Æ¬£¬¼ÓÈÈʹ֮·´Ó¦£¬±»»¹Ô­µÄÁòËáΪ0.9mol£®ÔòŨÁòËáµÄʵ¼ÊÌå»ý
´óÓÚ
´óÓÚ
£¨Ìî¡°´óÓÚ¡±¡¢¡°µÈÓÚ¡±»ò¡°Ð¡ÓÚ¡±£©100ml£®ÈôʹʣÓàµÄͭƬ¼ÌÐøÈܽ⣬¿ÉÔÚÆäÖмÓÈëÏõËáÑÎÈÜÒº£¨ÈçKNO3ÈÜÒº£©£¬Ôò¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽΪ
3Cu+8H++2NO3-=3Cu2++2NO¡ü+4H2O
3Cu+8H++2NO3-=3Cu2++2NO¡ü+4H2O
£®
£¨3£©¸ù¾ÝÏÂͼ²Ù×÷¼°ÏÖÏóÍƶÏËáXΪ
b
b
£¨ÌîÐòºÅ£©£®
a¡¢Å¨ÑÎËá          b¡¢Å¨ÁòËá            c¡¢Å¨ÏõËᣮ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÑÎËá¡¢ÁòËáºÍÏõËáÊÇÈýÖÖÖØÒªµÄËᣮ
£¨1£©¹¤ÒµÉÏÉú²úÑÎËáÓëÏõËáʱ£¬¶¼ÒªÓõ½µÄÆø̬·´Ó¦ÎïÊÇ
¶¼ÒªÓõ½H2
¶¼ÒªÓõ½H2
£»
£¨2£©¹¤ÒµÉÏÉú²úÁòËáÓëÏõËáʱ£¬Óõ½µÄÏàͬµÄÖØÒªÉ豸ÊÇ
ÎüÊÕËþ£¬´ß»¯Ñõ»¯ÔÚ½Ó´¥ÊÒ»òÑõ»¯Â¯ÖÐ
ÎüÊÕËþ£¬´ß»¯Ñõ»¯ÔÚ½Ó´¥ÊÒ»òÑõ»¯Â¯ÖÐ
£»
£¨3£©¹¤ÒµÉú²úÖÐÓûÖƵøßŨ¶ÈµÄÁòËáÓëÏõËᣬ¿ÉʹÓõÄÏàͬÎïÖÊÊÇ
ŨH2SO4
ŨH2SO4
£»
£¨4£©Å¨ÑÎËáÓëŨÏõËᱩ¶ÔÚ¿ÕÆøÖУ¬ÏàͬµÄÏÖÏóÊÇ
²úÉú°×Îí
²úÉú°×Îí
£»
£¨5£©Å¨ÁòËáÓëŨÏõËᶼ¿ÉÓÃÌú¡¢ÂÁÈÝÆ÷Öü´æµÄÏàͬԭÀíÊÇ
Ìú¡¢ÂÁ±»Å¨H2SO4»òŨHNO3¶Û»¯
Ìú¡¢ÂÁ±»Å¨H2SO4»òŨHNO3¶Û»¯
£»
£¨6£©ÊµÑéÊÒÖƱ¸H2¡¢CO2¡¢H2S¡¢SO2ʱ£¬ÓÃÑÎËáºÍŨÁòËá¿ÉÖƱ¸µÄÏàͬÆøÌåÊÇ
SO2
SO2
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÑÎËá¡¢ÁòËáºÍÏõËáÊÇÖÐѧ½×¶Î³£¼ûµÄ¡°Èý´óËᡱ£¬Çë¾Í¡°Èý´óËᡱµÄÐÔÖÊ£¬»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©Ï¡ÑÎËáÓëÍ­²»·´Ó¦£¬µ«ÏòÏ¡ÑÎËáÖмÓÈëH2O2ºó£¬Ôò¿ÉʹͭÈܽ⣮¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ
Cu+H2O2+2HCl¨TCuCl2+2H2O
Cu+H2O2+2HCl¨TCuCl2+2H2O
£®
£¨2£©Ä³¿ÎÍâ»î¶¯Ð¡×éÉè¼ÆÁËÒÔÏÂʵÑé·½°¸ÑéÖ¤CuÓëŨÏõËá·´Ó¦µÄ¹ý³ÌÖпÉÄܲúÉúNO£®ÆäʵÑéÁ÷³ÌͼÈçÏ£º

¢ÙÈôÒª²â¶¨NOµÄÌå»ý£¬´ÓͼËùʾµÄ×°ÖÃÖУ¬ÄãÈÏΪӦѡÓÃ
A
A
×°ÖýøÐÐCuÓëŨÏõËᷴӦʵÑ飬ѡÓõÄÀíÓÉÊÇ
ÒòΪA×°ÖÿÉÒÔͨN2½«×°ÖÃÖеĿÕÆøÅž¡£¬·ÀÖ¹NO±»¿ÕÆøÖÐO2Ñõ»¯
ÒòΪA×°ÖÿÉÒÔͨN2½«×°ÖÃÖеĿÕÆøÅž¡£¬·ÀÖ¹NO±»¿ÕÆøÖÐO2Ñõ»¯
£®
¢ÚÑ¡ÓÃÈçͼËùʾÒÇÆ÷×éºÏÒ»Ì׿ÉÓÃÀ´²â¶¨Éú³ÉNOÌå»ýµÄ×°Öã¬ÆäºÏÀíµÄÁ¬½Ó˳ÐòÊÇ
123547
123547
£¨Ìî¸÷µ¼¹Ü¿Ú±àºÅ£©£®
123547
123547

¢ÛÔڲⶨNOµÄÌå»ýʱ£¬ÈôÁ¿Í²ÖÐË®µÄÒºÃæ±È¼¯ÆøÆ¿µÄÒºÃæÒªµÍ£¬´ËʱӦ½«Á¿Í²µÄλÖÃ
Éý¸ß
Éý¸ß
£¨¡°Ï½µ¡±»ò¡°Éý¸ß¡±£©£¬ÒÔ±£Ö¤Á¿Í²ÖеÄÒºÃæÓ뼯ÆøÆ¿ÖеÄÒºÃæ³Öƽ£®
£¨3£©¹¤ÒµÖÆÁòËáʱ£¬ÁòÌú¿ó£¨FeS2£©¸ßÎÂÏ¿ÕÆøÑõ»¯²úÉú¶þÑõ»¯Áò£º4FeS2+11O2=8SO2+2Fe2O3£¬Éè¿ÕÆøÖÐN2¡¢O2µÄº¬Á¿·Ö±ðΪ0.800ºÍ0.200£¨Ìå»ý·ÖÊý£©£¬4.8t FeS2ÍêÈ«ÖƳÉÁòËᣬÐèÒª¿ÕÆøµÄÌå»ý£¨±ê×¼×´¿ö£©Îª
1.68¡Á107
1.68¡Á107
L£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÑÎËá¡¢ÁòËáºÍÏõËáÊÇÖÐѧ½×¶Î³£¼ûµÄÈýÖÖÇ¿Ëᣮ
¢ñ£®Çë¾ÍÈýÕßÓë½ðÊôÍ­µÄ·´Ó¦Çé¿ö£¬»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÔÚ100mL¡¢18mol?L-1 µÄŨÁòËáÖмÓÈë¹ýÁ¿µÄͭƬ£¬¼ÓÈÈʹ֮³ä·Ö·´Ó¦£¬²úÉúµÄÆøÌåÔÚ±ê×¼Çé¿öϵÄÌå»ý¿ÉÄÜÊÇ
D
D

A.40.32L              B.30.24L          C.20.16L          D.6.72L
£¨2£©Èô½«¹ýÁ¿Í­·ÛÓëÒ»¶¨Á¿Å¨ÏõËá·´Ó¦£¬µ±·´Ó¦Íêȫֹͣʱ£¬¹²ÊÕ¼¯µ½µÄÆøÌå1.12L£¨±ê×¼×´¿ö£©£¬Ôò¸ÃÆøÌåµÄ³É·ÖÊÇ
NO2¡¢NO
NO2¡¢NO
£¬·´Ó¦ÖÐËùÏûºÄµÄÏõËáµÄÎïÖʵÄÁ¿¿ÉÄÜΪ
B
B
£®
A.0.1mol              B.0.15mol              C.0.2mol              D.0.25mol
£¨3£©Ä³Í¬Ñ§Ïò½þÅÝͭƬµÄÏ¡ÑÎËáÖмÓÈëH2O2ºó£¬Í­Æ¬Èܽ⣬²¢ÇҸ÷´Ó¦µÄ²úÎïÖ»ÓÐÂÈ»¯Í­ºÍË®£®¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ
Cu+H2O2+2HCl=CuCl2+2H2O
Cu+H2O2+2HCl=CuCl2+2H2O
£®
¢ò£®ÓÃÈçÏÂ×°ÖÿÉÒÔÍê³ÉHClµÄÖÆÈ¡¼°ºóÐøһϵÁеÄÐÔÖÊʵÑ飨ͼÖмгÖ×°ÖÃÒÑÂÔÈ¥£©£®
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©×°ÖÃAÑ¡ÓÃŨÁòËáºÍŨÑÎËá»ìºÏÖÆÈ¡HClÆøÌ壬pÖÐÊ¢×°ÊÔ¼ÁΪ
ŨÁòËá
ŨÁòËá
£®
£¨2£©×°ÖÃBÖеÄËÄ´¦ÃÞ»¨ÒÀ´Î×öÁËÈçÏ´¦Àí£º¢Ù°üÓÐij³±ÊªµÄ¹ÌÌåÎïÖÊ  ¢ÚÕºÓÐKIÈÜÒº¢ÛÕºÓÐʯÈïÈÜÒº  ¢ÜÕºÓÐŨNaOHÈÜÒº£®·´Ó¦¿ªÊ¼ºó£¬¹Û²ìµ½¢Ú´¦ÓÐ×Ø»ÆÉ«ÎïÖʲúÉú£¬Ð´³ö¢Ú´¦·¢Éú·´Ó¦µÄÀë×Ó·½³Ìʽ
CI2+2I-=2Cl-+I2
CI2+2I-=2Cl-+I2
£®ÔÚ¢Ù´¦°üÓеĹÌÌåÎïÖÊ¿ÉÄÜÊÇ
a£®MnO2        b£®KmnO4       C£®KCl              d£®Cu
£¨3£©ÔÚÕû¸öʵÑé¹ý³ÌÖУ¬ÔÚ¢Û´¦Äܹ۲쵽µÄÏÖÏóÊÇ
ÏȱäºìºóÍÊÉ«
ÏȱäºìºóÍÊÉ«
£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸