»¯·ÊÊÇÅ©ÒµÉú²ú×î»ù´¡¶øÇÒÊÇ×îÖØÒªµÄÎïÖÊͶÈ룮¹¤ÒµÉÏÀûÓÃN2ºÍH2ºÏ³É°±£¬Æ仯ѧ·½³ÌʽΪ£ºN2£¨g£©+3H2£¨g£©?2NH3£¨g£©¡÷H£¼0
£¨1£©Ï±íΪ²»Í¬Î¶Èϸ÷´Ó¦µÄƽºâ³£Êý£®ÓÉ´Ë¿ÉÍÆÖª£¬±íÖÐT1    573K£¨Ìî¡°£¾¡±¡¢¡°£¼¡±»ò¡°=¡±£©£®
T/KT1573T2
K1.00×1072.45×1051.88×103
£¨2£©½«Ò»¶¨Á¿µÄN2ºÍH2µÄ»ìºÏÆø·ÅÈëijÃܱÕÈÝÆ÷Öз¢ÉúÉÏÊö·´Ó¦£®
¢ÙÏÂÁдëÊ©ÖпÉÌá¸ßÇâÆøµÄת»¯ÂʵÄÓР   £¨Ìî×Öĸ£©£®
A£®Éý¸ßζȠ                       B£®Ê¹Óô߻¯¼Á
C£®Ôö´óѹǿ                        D£®Ñ­»·ÀûÓúͲ»¶Ï²¹³äµªÆø
¢ÚÔÚÒ»¶¨Î¶ȺÍѹǿÏ£¬½«H2ºÍN2°´Ìå»ý±È3£º1ÔÚÃܱÕÈÝÆ÷ÖлìºÏ£¬µ±¸Ã·´Ó¦´ïµ½Æ½ºâʱ£¬²âµÃƽºâ»ìºÏÆøÖÐNH3µÄÌå»ý·ÖÊýΪ£¬´ËʱN2µÄת»¯ÂÊΪ    £®
£¨3£©Ä³³§Ã¿Ìì²úÉú600m3º¬°±·ÏË®£®¸Ã³§´¦Àí·ÏË®µÄ·½·¨£º½«·ÏË®¼ÓÈȵõ½NH3£¬Ê¹·ÏË®ÖÐNH3µÄŨ¶È½µÎª17mg?L-1£®ÔÙ¶Ô¼ÓÈÈÕô·¢µÃµ½µÄNH3ÓÃÒ»¶¨Á¿¿ÕÆøÑõ»¯£®·¢ÉúµÄÖ÷·´Ó¦ÈçÏ£º
4NH3+5O24NO+6H2O      4NO+3O2+2H2O=4HNO3
¸±·´Ó¦Îª£º4NH3+3O2=2N2+6H2O
¢Ù¸Ã³§Ã¿Ììͨ¹ý¼ÓÈÈÕô·¢¿ÉµÃµ½NH3µÄÎïÖʵÄÁ¿ÊǶàÉÙ£¿
¢ÚÈôÑõ»¯¹ý³ÌÖÐ90% NH3ת»¯ÎªÏõËᣬ10% NH3·¢ÉúÁ˸±·´Ó¦£¬Ôò¸Ã³§Ã¿ÌìÏûºÄ±ê×¼×´¿öϵĿÕÆø¶àÉÙÁ¢·½Ã×£¿£¨¼ÙÉè·ÏË®¼ÓÈÈÇ°ºóµÄÌå»ýºÍÃܶȽüËÆÈÏΪ²»±ä£¬¿ÕÆøÖÐÑõÆøµÄÌå»ý·ÖÊý20%£®£©
¡¾´ð°¸¡¿·ÖÎö£º£¨1£©Õý·´Ó¦·ÅÈÈ£¬¸ù¾ÝζȶÔƽºâÒƶ¯µÄÓ°Ïì·ÖÎö£»
£¨2£©Ìá¸ßÇâÆøµÄת»¯ÂÊ£¬Ó¦Ê¹Æ½ºâÏòÕý·´Ó¦·½ÏòÒƶ¯£»ÀûÓÃÈý¶Îʽ·¨¼ÆËãת»¯ÂÊ£»
£¨3£©¢Ù¼ÆËã°±ÆøµÄŨ¶È±ä»¯£¬¸ù¾Ýn=cV¼ÆËãÎïÖʵÄÁ¿£»
¢Ú¸ù¾Ý·½³ÌʽµÃ³ö·´Ó¦µÄ¹Øϵʽ£¬¿É¸ù¾Ý¹Øϵʽ¼ÆË㣮
½â´ð£º½â£º£¨1£©¸Ã·´Ó¦µÄÕý·´Ó¦·ÅÈÈ£¬Î¶ÈÉý¸ßƽºâÏòÄæ·´Ó¦·½ÏòÒƶ¯£¬T1ʱƽºâ³£Êý´óÓÚ573KµÄƽºâ³£Êý£¬ËµÃ÷T1£¼573K£¬
¹Ê´ð°¸Îª£º£¼£»
£¨2£©¢ÙA£®Éý¸ßζȣ¬Æ½ºâÏòÄæ·´Ó¦·½ÏòÒƶ¯£¬Ôòת»¯ÂʼõС£¬¹ÊA´íÎó£»
B£®Ê¹Óô߻¯¼Áƽºâ²»Òƶ¯£¬×ª»¯Âʲ»±ä£¬¹ÊB´íÎó£»
C£®Ôö´óѹǿƽºâÏòÕý·´Ó¦·½ÏòÒƶ¯£¬×ª»¯ÂÊÔö´ó£¬¹ÊCÕýÈ·£»
D£®Ñ­»·ÀûÓúͲ»¶Ï²¹³äµªÆø£¬¿ÉʹƽºâÏòÕý·´Ó¦·½ÏòÒƶ¯£¬×ª»¯ÂÊÔö´ó£¬¹ÊDÕýÈ·£®
¹Ê´ð°¸Îª£ºCD£»
¢ÚÉèÆðʼʱH2µÄÎïÖʵÄÁ¿Îª3mol£¬N2Ϊ1mol£¬Æ½ºâʱN2ת»¯ÁËxmol£¬
          N2£¨g£©+3H2£¨g£©?2NH3£¨g£©
Æðʼ£º1mol     3mol       0
ת»¯£ºxmol     3xmol      2xmol
ƽºâ£º£¨1-x£©mol £¨3-3x£©mol 2xmol
Ôò=
x=0.25£¬
´ËʱN2µÄת»¯ÂÊΪ=25%£¬
¹Ê´ð°¸Îª£º25%£»
£¨3£©¢Ùn£¨NH3£©=×10-3g/mg×600m3×103L/m3=4800mol£¬
´ð£º¸Ã³§Ã¿Ììͨ¹ý¼ÓÈÈÕô·¢¿ÉµÃµ½NH3µÄÎïÖʵÄÁ¿ÊÇ4800mol£»
¢Ú¸ù¾ÝÏÂÁз¢ÉúµÄÖ÷·´Ó¦£º
4NH3+5O24NO+6H2O£¬4NO+3O2+2H2O=4HNO3
µÃÖ÷·´Ó¦Öа±ÆøÓëÑõÆøµÄÎïÖʵÄÁ¿ÓÐÈçϹØϵʽ£ºNH3¡«2O2
n£¨O2£©Ö÷·´Ó¦=4800 mol×90%×2=8640 mol
¸ù¾ÝÏÂÁи±·´Ó¦£º
4NH3+3O2=2N2+6H2O
n£¨O2£©¸±·´Ó¦=4800 mol×10%×3/4=360mol
V£¨¿ÕÆø£©=£¨8640+360£©mol×22.4L/mol×10-3m3/L÷20%=1008m3
´ð£º¸Ã³§Ã¿ÌìÏûºÄ±ê×¼×´¿öϵĿÕÆø1008m3£®
µãÆÀ£º±¾Ì⿼²é»¯Ñ§Æ½ºâµÄ¼ÆË㣬ÌâÄ¿½ÏΪ×ۺϣ¬ÇÒÄѶȽϴó£¬Ò×´íµãΪ£¨3£©£¬×¢Òâ¸ù¾ÝÖÊÁ¿ÊغãÀûÓùØϵ·¨¼ÆË㣮
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

»¯·ÊÊÇÅ©ÒµÉú²ú×î»ù´¡¶øÇÒÊÇ×îÖØÒªµÄÎïÖÊͶÈ룮¹¤ÒµÉÏÀûÓÃN2ºÍH2ºÏ³É°±£¬Æ仯ѧ·½³ÌʽΪ£ºN2£¨g£©+3H2£¨g£©?2NH3£¨g£©¡÷H£¼0
£¨1£©Ï±íΪ²»Í¬Î¶Èϸ÷´Ó¦µÄƽºâ³£Êý£®ÓÉ´Ë¿ÉÍÆÖª£¬±íÖÐT1
£¼
£¼
573K£¨Ìî¡°£¾¡±¡¢¡°£¼¡±»ò¡°=¡±£©£®
T/K T1 573 T2
K 1.00¡Á107 2.45¡Á105 1.88¡Á103
£¨2£©½«Ò»¶¨Á¿µÄN2ºÍH2µÄ»ìºÏÆø·ÅÈëijÃܱÕÈÝÆ÷Öз¢ÉúÉÏÊö·´Ó¦£®
¢ÙÏÂÁдëÊ©ÖпÉÌá¸ßÇâÆøµÄת»¯ÂʵÄÓÐ
CD
CD
£¨Ìî×Öĸ£©£®
A£®Éý¸ßζȠ                       B£®Ê¹Óô߻¯¼Á
C£®Ôö´óѹǿ                        D£®Ñ­»·ÀûÓúͲ»¶Ï²¹³äµªÆø
¢ÚÔÚÒ»¶¨Î¶ȺÍѹǿÏ£¬½«H2ºÍN2°´Ìå»ý±È3£º1ÔÚÃܱÕÈÝÆ÷ÖлìºÏ£¬µ±¸Ã·´Ó¦´ïµ½Æ½ºâʱ£¬²âµÃƽºâ»ìºÏÆøÖÐNH3µÄÌå»ý·ÖÊýΪ
1
7
£¬´ËʱN2µÄת»¯ÂÊΪ
25%
25%
£®
£¨3£©Ä³³§Ã¿Ìì²úÉú600m3º¬°±·ÏË®£¨NH3 µÄŨ¶ÈΪ153mg?L-1£¬·Ï°±Ë®ÃܶÈΪ1g?cm-3£©£®¸Ã³§´¦Àí·ÏË®µÄ·½·¨£º½«·ÏË®¼ÓÈȵõ½NH3£¬Ê¹·ÏË®ÖÐNH3µÄŨ¶È½µÎª17mg?L-1£®ÔÙ¶Ô¼ÓÈÈÕô·¢µÃµ½µÄNH3ÓÃÒ»¶¨Á¿¿ÕÆøÑõ»¯£®·¢ÉúµÄÖ÷·´Ó¦ÈçÏ£º
4NH3+5O2
 Ò»¶¨Ìõ¼þ 
.
 
4NO+6H2O      4NO+3O2+2H2O=4HNO3
¸±·´Ó¦Îª£º4NH3+3O2=2N2+6H2O
¢Ù¸Ã³§Ã¿Ììͨ¹ý¼ÓÈÈÕô·¢¿ÉµÃµ½NH3µÄÎïÖʵÄÁ¿ÊǶàÉÙ£¿
¢ÚÈôÑõ»¯¹ý³ÌÖÐ90% NH3ת»¯ÎªÏõËᣬ10% NH3·¢ÉúÁ˸±·´Ó¦£¬Ôò¸Ã³§Ã¿ÌìÏûºÄ±ê×¼×´¿öϵĿÕÆø¶àÉÙÁ¢·½Ã×£¿£¨¼ÙÉè·ÏË®¼ÓÈÈÇ°ºóµÄÌå»ýºÍÃܶȽüËÆÈÏΪ²»±ä£¬¿ÕÆøÖÐÑõÆøµÄÌå»ý·ÖÊý20%£®£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

Ëæ×ÅÊÀ½çÁ¸Ê³ÐèÇóÁ¿µÄÔö³¤£¬Å©Òµ¶Ô»¯Ñ§·ÊÁϵÄÐèÇóÁ¿Ô½À´Ô½´ó£¬ÆäÖеª·ÊÊÇÐèÇóÁ¿×î´óµÄÒ»ÖÖ»¯·Ê£®¶ø°±µÄºÏ³ÉΪµª·ÊµÄÉú²ú¹¤Òµµì¶¨ÁË»ù´¡£¬ÆäÔ­ÀíΪ£ºN2+3H2?2NH3
£¨1£©ÔÚN2+3H2?2NH3µÄ·´Ó¦ÖУ¬Ò»¶Îʱ¼äºó£¬NH3µÄŨ¶ÈÔö¼ÓÁË0.9mol?L-1£®ÓÃN2±íʾÆä·´Ó¦ËÙÂÊΪ0.15mol?L-1?s-1£¬ÔòËù¾­¹ýµÄʱ¼äΪ
B
B
£»
A£®2s          B£®3s        C£®4s         D£®6s
£¨2£©ÏÂÁÐ4¸öÊý¾ÝÊÇÔÚ²»Í¬Ìõ¼þϲâµÃµÄºÏ³É°±·´Ó¦µÄËÙÂÊ£¬ÆäÖз´Ó¦×î¿ìµÄÊÇ
B
B
£»
A£®v£¨H2£©=0.1mol?L-1?min-1          B£®v£¨N2£©=0.1mol?L-1?min-1
C£®v£¨NH3£©=0.15mol?L-1?min-1        D£®v£¨N2£©=0.002mol?L-1?min-1
£¨3£©ÔÚÒ»¸ö¾øÈÈ¡¢ÈÝ»ý²»±äµÄÃܱÕÈÝÆ÷Öз¢Éú¿ÉÄæ·´Ó¦£ºN2£¨g£©+3H2£¨g£©?2NH3£¨g£©¡÷H£¼0£®ÏÂÁи÷ÏîÄÜ˵Ã÷¸Ã·´Ó¦ÒѾ­´ïµ½Æ½ºâ״̬µÄÊÇ
BC
BC
£®
A£®ÈÝÆ÷ÄÚÆøÌåÃܶȱ£³Ö²»±ä                     
B£®ÈÝÆ÷ÄÚζȲ»Ôٱ仯
C£®¶ÏÁÑ1mol N¡ÔN¼üµÄͬʱ£¬¶ÏÁÑ6mol N-H¼ü
D£®·´Ó¦ÏûºÄN2¡¢H2Óë²úÉúNH3µÄËÙÂÊÖ®±È1£º3£º2£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄêÄÚÃɹŰÍÊÐÒ»ÖиßÒ»ÏÂѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨´ø½âÎö£© ÌâÐÍ£ºÌî¿ÕÌâ

£¨6·Ö£©Ëæ×ÅÊÀ½çÁ¸Ê³ÐèÇóÁ¿µÄÔö³¤£¬Å©Òµ¶Ô»¯Ñ§·ÊÁϵÄÐèÇóÁ¿Ô½À´Ô½´ó£¬ÆäÖеª·ÊÊÇÐèÇóÁ¿×î´óµÄÒ»ÖÖ»¯·Ê¡£¶ø°±µÄºÏ³ÉΪµª·ÊµÄÉú²ú¹¤Òµµì¶¨ÁË»ù´¡£¬ÆäÔ­ÀíΪ£ºN2£«3H22NH3
£¨1£©ÔÚN2£«3H22NH3µÄ·´Ó¦ÖУ¬Ò»¶Îʱ¼äºó£¬NH3µÄŨ¶ÈÔö¼ÓÁË0.9mol¡¤L£­1¡£ÓÃN2±íʾÆä·´Ó¦ËÙÂÊΪ0.15 mol¡¤L£­1¡¤s£­1£¬ÔòËù¾­¹ýµÄʱ¼äΪ         £»
A£®2 s          B£®3 s        C£®4 s         D£®6 s
£¨2£©ÏÂÁÐ4¸öÊý¾ÝÊÇÔÚ²»Í¬Ìõ¼þϲâµÃµÄºÏ³É°±·´Ó¦µÄËÙÂÊ£¬ÆäÖз´Ó¦×î¿ìµÄÊÇ        £»
A£®v(H2)£½0.1 mol¡¤L£­1¡¤min£­1    B£®v(N2)£½0.1 mol¡¤L£­1¡¤min£­1
C£®v(NH3)£½0.15 mol¡¤L£­1¡¤min£­ D£®v(N2)£½0.002mol¡¤L£­1¡¤min£­1
£¨3£©ÔÚÒ»¸ö¾øÈÈ¡¢ÈÝ»ý²»±äµÄÃܱÕÈÝÆ÷Öз¢Éú¿ÉÄæ·´Ó¦£º
N2(g)£«3H2(g)2NH3(g) ¡÷H£¼0¡£ÏÂÁи÷ÏîÄÜ˵Ã÷¸Ã·´Ó¦ÒѾ­´ïµ½Æ½ºâ״̬µÄÊÇ            ¡£
A£®ÈÝÆ÷ÄÚÆøÌåÃܶȱ£³Ö²»±ä
B£®ÈÝÆ÷ÄÚζȲ»Ôٱ仯
C£®¶ÏÁÑ1mol N¡ÔN¼üµÄͬʱ£¬¶ÏÁÑ6 mol N¡ªH¼ü
D£®·´Ó¦ÏûºÄN2¡¢H2Óë²úÉúNH3µÄËÙÂÊÖ®±È1©U3©U2

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

»¯·ÊÊÇÅ©ÒµÉú²ú×î»ù´¡¶øÇÒÊÇ×îÖØÒªµÄÎïÖÊͶÈ룮¹¤ÒµÉÏÀûÓÃN2ºÍH2ºÏ³É°±£¬Æ仯ѧ·½³ÌʽΪ£ºN2£¨g£©+3H2£¨g£©?2NH3£¨g£©¡÷H£¼0
£¨1£©Ï±íΪ²»Í¬Î¶Èϸ÷´Ó¦µÄƽºâ³£Êý£®ÓÉ´Ë¿ÉÍÆÖª£¬±íÖÐT1______573K£¨Ìî¡°£¾¡±¡¢¡°£¼¡±»ò¡°=¡±£©£®
T/K T1 573 T2
K 1.00¡Á107 2.45¡Á105 1.88¡Á103
£¨2£©½«Ò»¶¨Á¿µÄN2ºÍH2µÄ»ìºÏÆø·ÅÈëijÃܱÕÈÝÆ÷Öз¢ÉúÉÏÊö·´Ó¦£®
¢ÙÏÂÁдëÊ©ÖпÉÌá¸ßÇâÆøµÄת»¯ÂʵÄÓÐ______£¨Ìî×Öĸ£©£®
A£®Éý¸ßζȠ                       B£®Ê¹Óô߻¯¼Á
C£®Ôö´óѹǿ                        D£®Ñ­»·ÀûÓúͲ»¶Ï²¹³äµªÆø
¢ÚÔÚÒ»¶¨Î¶ȺÍѹǿÏ£¬½«H2ºÍN2°´Ìå»ý±È3£º1ÔÚÃܱÕÈÝÆ÷ÖлìºÏ£¬µ±¸Ã·´Ó¦´ïµ½Æ½ºâʱ£¬²âµÃƽºâ»ìºÏÆøÖÐNH3µÄÌå»ý·ÖÊýΪ
1
7
£¬´ËʱN2µÄת»¯ÂÊΪ______£®
£¨3£©Ä³³§Ã¿Ìì²úÉú600m3º¬°±·ÏË®£¨NH3 µÄŨ¶ÈΪ153mg?L-1£¬·Ï°±Ë®ÃܶÈΪ1g?cm-3£©£®¸Ã³§´¦Àí·ÏË®µÄ·½·¨£º½«·ÏË®¼ÓÈȵõ½NH3£¬Ê¹·ÏË®ÖÐNH3µÄŨ¶È½µÎª17mg?L-1£®ÔÙ¶Ô¼ÓÈÈÕô·¢µÃµ½µÄNH3ÓÃÒ»¶¨Á¿¿ÕÆøÑõ»¯£®·¢ÉúµÄÖ÷·´Ó¦ÈçÏ£º
4NH3+5O2
 Ò»¶¨Ìõ¼þ 
.
 
4NO+6H2O      4NO+3O2+2H2O=4HNO3
¸±·´Ó¦Îª£º4NH3+3O2=2N2+6H2O
¢Ù¸Ã³§Ã¿Ììͨ¹ý¼ÓÈÈÕô·¢¿ÉµÃµ½NH3µÄÎïÖʵÄÁ¿ÊǶàÉÙ£¿
¢ÚÈôÑõ»¯¹ý³ÌÖÐ90% NH3ת»¯ÎªÏõËᣬ10% NH3·¢ÉúÁ˸±·´Ó¦£¬Ôò¸Ã³§Ã¿ÌìÏûºÄ±ê×¼×´¿öϵĿÕÆø¶àÉÙÁ¢·½Ã×£¿£¨¼ÙÉè·ÏË®¼ÓÈÈÇ°ºóµÄÌå»ýºÍÃܶȽüËÆÈÏΪ²»±ä£¬¿ÕÆøÖÐÑõÆøµÄÌå»ý·ÖÊý20%£®£©

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸