ʵÑéÊÒÓûÅäÖÆ
480 mL¡¡0.1 mol/L¡¡Na2CO3ÈÜÒº£®(1)Ó¦¸ÃÓÃÍÐÅÌÌìƽ³ÆÈ¡ÎÞˮ̼ËáÄÆ·ÛÄ©________g£®
(2)ÈôÔÚ³ÆÁ¿ÑùƷʱ£¬Ò©Æ··ÅÔÚÌìƽµÄÓÒÅÌ£¬íÀÂë·ÅÔÚÌìƽµÄ×óÅÌ£¬Ììƽƽºâʱ£¬Êµ¼Ê³ÆÁ¿µÄ̼ËáÄÆ·ÛÄ©ÊÇ________g(1 gÒÔÏÂÓÃÓÎÂë)£®
(3)ÅäÖÆNa2CO3ÈÜҺʱÐèҪʹÓõÄÖ÷ÒªÒÇÆ÷ÓÐ________________£®
(4)ÏÂÁÐÇé¿ö»áʹËùÅäÈÜҺŨ¶ÈÆ«µÍµÄÊÇ________£®
¢Ù³ÆÈ¡µÄ̼ËáÄÆÖдøÓв¿·Ö½á¾§Ë®
¢ÚÈÜҺתÒƵ½ÈÝÁ¿Æ¿ºó£¬ÉÕ±¼°²£Á§°ôδÓÃÕôÁóˮϴµÓ
¢ÛתÒÆÈÜҺǰÈÝÁ¿Æ¿ÄÚÓÐÉÙÁ¿ÕôÁóË®
¢Ü¶¨ÈÝʱ£¬¸©ÊÓÈÝÁ¿Æ¿µÄ¿Ì¶ÈÏß
¢Ý¶¨ÈݺóÒ¡ÔÈ£¬·¢ÏÖÒºÃæ½µµÍ£¬ÓÖ²¹¼ÓÉÙÁ¿Ë®£¬ÖØдﵽ¿Ì¶ÈÏß
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£ººÓ±±Ê¡Þ»³ÇÒ»ÖÐ2010£2011ѧÄê¸ßÒ»ÉÏѧÆÚµÚÒ»´ÎÔ¿¼Àí¿Æ»¯Ñ§ÊÔÌâ ÌâÐÍ£º058
ijѧÉúÔÚʵÑéÊÒÖÐÓû
ÅäÖÆ480 mL¡¡0.26 mol/L¡¡NaOHÈÜÒº£¬Çë°ïÖú¸ÃÉúÍê³ÉÏÂÁÐʵÑé¹ý³Ì²¢»Ø´ðÎÊÌ⣺¢Ù³ÆÁ¿£ºÓÃÍÐÅÌÌìƽ³ÆÁ¿
NaOH¹ÌÌå________g£¬³ÆÁ¿Ê±Ó¦½«NaOH¹ÌÌå·ÅÔÚ________(ÌîʵÑéÓÃÆ·)ÖУ¬²¢ÖÃÓÚÌìƽµÄ________(Ìî¡°×ó¡±»ò¡°ÓÒ¡±)ÅÌ£®¢Ú
Èܽ⣺¼ÓÉÙÁ¿Ë®Óò£Á§°ô½Á°èÈܽ⣬²¢________£®¢Û
תÒÆ£º½«ÉÕ±ÖеÄÇâÑõ»¯ÄÆÈÜÒºÓò£Á§°ôÒýÁ÷תÒƵ½________ÖУ®¢Ü
¶¨ÈÝ£º¼ÓË®ÖÁÀë¿Ì¶ÈÏß1£2 cmʱ£¬¸ÄÓýºÍ·µÎ¹ÜµÎ¼ÓÖÁ¿Ì¶ÈÏߣ®¢ÝÒ¡ÔÈ¡¢×°Æ¿¡¢Ìù±êÇ©£®
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
(1)¸ÃÉúÔÚÅäÖƹý³ÌÖÐȱÉÙÒ»¸öʵÑé²½Ö裬ÕâһʵÑé²½ÖèµÄλÖú;ßÌå²Ù×÷ÊÇ________________£®
(2)ÏÂÁвÙ×÷»áʹʵ¼ÊÅäÖƵÄÈÜҺŨ¶ÈÆ«¸ßµÄÊÇ________£®
A£®³ÆÁ¿Ç°£¬ÇâÑõ»¯ÄƹÌÌåÒѳ±½â
B£®³ÆÁ¿Ê±£¬íÀÂëºÍÎïÆ··Å·´ÁË
C£®×ªÒÆʱÓÐÈÜÒº½¦³ö
D£®¶ÁÊýʱ¸©Êӿ̶È
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£ººÓ±±Ê¡Þ»³ÇÒ»ÖÐ2010£2011ѧÄê¸ßÒ»ÉÏѧÆÚµÚÒ»´ÎÔ¿¼ÎÄ¿Æ»¯Ñ§ÊÔÌâ ÌâÐÍ£º058
ijѧÉúÔÚʵÑéÊÒÖÐÓû
ÅäÖÆ480 mL¡¡0.26 mol/L¡¡NaOHÈÜÒº£¬Çë°ïÖú¸ÃÉúÍê³ÉÏÂÁÐʵÑé¹ý³Ì²¢»Ø´ðÎÊÌ⣺¢Ù³ÆÁ¿£ºÓÃÍÐÅÌÌìƽ³ÆÁ¿
NaOH¹ÌÌå________g£¬³ÆÁ¿Ê±Ó¦½«NaOH¹ÌÌå·ÅÔÚ________(ÌîʵÑéÓÃÆ·)ÖУ¬²¢ÖÃÓÚÌìƽµÄ________(Ìî¡°×ó¡±»ò¡°ÓÒ¡±)ÅÌ£®¢Ú
Èܽ⣺¼ÓÉÙÁ¿Ë®Óò£Á§°ô½Á°èÈܽ⣬²¢________£®¢Û
תÒÆ£º½«ÉÕ±ÖеÄÇâÑõ»¯ÄÆÈÜÒºÓò£Á§°ôÒýÁ÷תÒƵ½________ÖУ®¢Ü
¶¨ÈÝ£º¼ÓË®ÖÁÀë¿Ì¶ÈÏß1£2 cmʱ£¬¸ÄÓýºÍ·µÎ¹ÜµÎ¼ÓÖÁ¿Ì¶ÈÏߣ®¢ÝÒ¡ÔÈ¡¢×°Æ¿¡¢Ìù±êÇ©£®
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
¸ÃÉúÔÚÅäÖƹý³ÌÖÐȱÉÙÒ»¸öʵÑé²½Ö裬ÕâһʵÑé²½ÖèµÄλÖú;ßÌå²Ù________£®
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2013½ìɽ¶«Ê¡Ì©°²ÊÐÄþÑô¶þÖиßÈýµÚÒ»´ÎÔ¿¼»¯Ñ§ÊÔ¾í£¨´ø½âÎö£© ÌâÐÍ£ºÊµÑéÌâ
(11·Ö)ijѧÉúÓûÅäÖÆ6.0 mol/LµÄH2SO4 1 000 mL£¬ÊµÑéÊÒÓÐÈýÖÖ²»Í¬Å¨¶ÈµÄÁòË᣺
¢Ù480 mL 0.5 mol/L µÄÁòË᣻¢Ú150 mL 25%µÄÁòËá(¦Ñ£½1.18 g/mL)£»¢Û×ãÁ¿µÄ18 mol/LµÄÁòËá¡£ÓÐÈýÖÖ¹æ¸ñµÄÈÝÁ¿Æ¿£º250 mL¡¢500 mL¡¢1 000 mL¡£ÀÏʦҪÇó°Ñ¢Ù¢ÚÁ½ÖÖÁòËáÈ«²¿ÓÃÍ꣬²»×ãµÄ²¿·ÖÓÉ¢ÛÀ´²¹³ä¡£
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
(1)ʵÑéËùÓÃ25%µÄÁòËáµÄÎïÖʵÄÁ¿Å¨¶ÈΪ______mol/L(±£Áô1λСÊý)¡£
(2)ÅäÖƸÃÁòËáÈÜҺӦѡÓÃÈÝÁ¿Æ¿µÄ¹æ¸ñΪ______mL¡£
(3)ÅäÖÆʱ£¬¸ÃͬѧµÄ²Ù×÷˳ÐòÈçÏ£¬Ç뽫²Ù×÷²½ÖèB¡¢D²¹³äÍêÕû¡£
A£®½«¢Ù¢ÚÁ½ÈÜҺȫ²¿ÔÚÉÕ±ÖлìºÏ¾ùÔÈ£»
B£®ÓÃÁ¿Í²×¼È·Á¿È¡ËùÐèµÄ18 mol/LµÄŨÁòËá____mL£¬Ñز£Á§°ôµ¹ÈëÉÏÊö»ìºÏÒºÖС£²¢Óò£Á§°ô½Á°è£¬Ê¹Æä»ìºÏ¾ùÔÈ£»
C£®½«»ìºÏ¾ùÔȵÄÁòËáÑز£Á§°ô×¢ÈëËùÑ¡µÄÈÝÁ¿Æ¿ÖУ»
D£®_________________________________________________________________
_________________________________________________________________
E£®Õñµ´£¬¼ÌÐøÏòÈÝÁ¿Æ¿ÖмÓË®£¬Ö±µ½ÒºÃæ½Ó½ü¿Ì¶ÈÏß1¡«2 cm ´¦£»
F£®¸ÄÓýºÍ·µÎ¹Ü¼ÓË®£¬Ê¹ÈÜÒºµÄ°¼ÒºÃæÇ¡ºÃÓë¿Ì¶ÈÏßÏàÇУ»
G£®½«ÈÝÁ¿Æ¿¸Ç½ô£¬Õñµ´£¬Ò¡ÔÈ¡£
(4)Èç¹ûÊ¡ÂÔ²Ù×÷D£¬¶ÔËùÅäÈÜҺŨ¶ÈÓкÎÓ°Ï죿________(Ìî¡°Æ«´ó¡±¡¢¡°Æ«Ð¡¡±»ò¡°ÎÞÓ°Ï족)¡£
(5)½øÐвÙ×÷CÇ°»¹Ðè×¢Òâ
¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012-2013ѧÄêɽ¶«Ê¡Ì©°²ÊиßÈýµÚÒ»´ÎÔ¿¼»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÊµÑéÌâ
ijѧÉúÓûÅäÖÆ6.0 mol/LµÄH2SO4 1 000 mL£¬ÊµÑéÊÒÓÐÈýÖÖ²»Í¬Å¨¶ÈµÄÁòË᣺
¢Ù480 mL 0.5 mol/L µÄÁòË᣻¢Ú150 mL 25%µÄÁòËá(¦Ñ£½1.18 g/mL)£»¢Û×ãÁ¿µÄ18 mol/LµÄÁòËá¡£ÓÐÈýÖÖ¹æ¸ñµÄÈÝÁ¿Æ¿£º250 mL¡¢500 mL¡¢1 000 mL¡£ÀÏʦҪÇó°Ñ¢Ù¢ÚÁ½ÖÖÁòËáÈ«²¿ÓÃÍ꣬²»×ãµÄ²¿·ÖÓÉ¢ÛÀ´²¹³ä¡£
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
(1)ʵÑéËùÓÃ25%µÄÁòËáµÄÎïÖʵÄÁ¿Å¨¶ÈΪ______mol/L(±£Áô1λСÊý)¡£
(2)ÅäÖƸÃÁòËáÈÜҺӦѡÓÃÈÝÁ¿Æ¿µÄ¹æ¸ñΪ______mL¡£
(3)ÅäÖÆʱ£¬¸ÃͬѧµÄ²Ù×÷˳ÐòÈçÏ£¬Ç뽫²Ù×÷²½ÖèB¡¢D²¹³äÍêÕû¡£
A£®½«¢Ù¢ÚÁ½ÈÜҺȫ²¿ÔÚÉÕ±ÖлìºÏ¾ùÔÈ£»
B£®ÓÃÁ¿Í²×¼È·Á¿È¡ËùÐèµÄ18 mol/LµÄŨÁòËá____mL£¬Ñز£Á§°ôµ¹ÈëÉÏÊö»ìºÏÒºÖС£²¢Óò£Á§°ô½Á°è£¬Ê¹Æä»ìºÏ¾ùÔÈ£»
C£®½«»ìºÏ¾ùÔȵÄÁòËáÑز£Á§°ô×¢ÈëËùÑ¡µÄÈÝÁ¿Æ¿ÖУ»
D£®_________________________________________________________________
_________________________________________________________________
E£®Õñµ´£¬¼ÌÐøÏòÈÝÁ¿Æ¿ÖмÓË®£¬Ö±µ½ÒºÃæ½Ó½ü¿Ì¶ÈÏß1¡«2 cm ´¦£»
F£®¸ÄÓýºÍ·µÎ¹Ü¼ÓË®£¬Ê¹ÈÜÒºµÄ°¼ÒºÃæÇ¡ºÃÓë¿Ì¶ÈÏßÏàÇУ»
G£®½«ÈÝÁ¿Æ¿¸Ç½ô£¬Õñµ´£¬Ò¡ÔÈ¡£
(4)Èç¹ûÊ¡ÂÔ²Ù×÷D£¬¶ÔËùÅäÈÜҺŨ¶ÈÓкÎÓ°Ï죿________(Ìî¡°Æ«´ó¡±¡¢¡°Æ«Ð¡¡±»ò¡°ÎÞÓ°Ï족)¡£
(5)½øÐвÙ×÷CÇ°»¹Ðè×¢Òâ
¡£
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com