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D£®ÔÚDµã£ºc(CH3COO£­) + c(CH3COOH) = 2c(Na+)

 

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D£®ÔÚDµã£ºc(CH3COO£­) + c(CH3COOH) = 2c(Na+)

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  c(Na+) > c(CH3COO£­) > c(OH£­) > c(H+)

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D£®ÔÚDµã£ºc(CH3COO£­) + c(CH3COOH) = 2c(Na+)

 

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