(1)³£ÎÂÏÂÓÐŨ¶È¾ùΪ0.5mol¡¤L-1µÄËÄÖÖÈÜÒº£º
¢Ù̼ËáÄÆÈÜÒº£»¢Ú̼ËáÇâÄÆÈÜÒº£»¢ÛÑÎË᣻¢Ü°±Ë®¡£
Çë¸ù¾ÝÌâÄ¿ÒªÇó»Ø´ðÏÂÁÐÎÊÌâ¡£
¢ÙÉÏÊöÈÜÒºÖУ¬¿É·¢ÉúË®½â·´Ó¦µÄÊÇ__________ (ÌîÐòºÅ£¬ÏÂͬ)¡£
¢ÚÉÏÊöÈÜÒºÖУ¬¼ÈÄÜÓëÇâÑõ»¯ÄÆÈÜÒº·´Ó¦£¬ÓÖÄÜÓëÁòËáÈÜÒº·´Ó¦µÄÊÇ________ ¡£
¢ÛÈ¡ÊÊÁ¿ÈÜÒº¢Ü£¬¼ÓÈëÉÙÁ¿ÂÈ»¯ï§¹ÌÌ壬´ËʱÈÜÒºÖеÄÖµ_________(Ìî¡°Ôö´ó¡±»ò¡°¼õС¡±»ò¡°²»±ä¡±)¡£
¢Ü Èô¢ÛºÍ¢ÜµÄÈÜÒº»ìºÏºóÈÜҺǡºÃ³ÊÖÐÐÔ£¬Ôò»ìºÏÇ°¢ÛµÄÌå»ý(Ìî¡°´óÓÚ¡±¡¢¡°Ð¡ÓÚ¡±»ò¡°µÈÓÚ¡±£¬ÏÂͬ)___________ ¢ÜµÄÌå»ý¡£
¢ÝÈ¡10mLÈÜÒº¢Û£¬¼ÓˮϡÊ͵½500mL£¬Ôò¸ÃÈÜÒºÖÐÓÉË®µçÀë³öc(H+)£½____________¡£
(2)ζÈÏàͬ¡¢Å¨¶È¾ùΪ0.2mol/LµÄ
¢Ù(NH4)2SO4¡¢¢ÚNaNO3¡¢¢ÛNH4HSO4¡¢¢ÜNH4NO3¡¢¢Ý¡¢¢ÞCH3COONaÈÜÒº£¬
¢ÙËüÃǵÄpHÖµÓÉСµ½´óµÄÅÅÁÐ˳ÐòÊÇ____________
¢ÚÉÏÊöº¬ÓÐNH4+µÄÈÜÒºÖУ¬NH4+Ũ¶ÈÓÉ´óµ½Ð¡Ë³Ðò___________
(1)¢Ù¡¢ ¢Ù¢Ú £»¢Ú¡¢ ¢Ú £»¢Û¡¢¼õС £»¢Ü¡¢Ð¡ÓÚ £» ¢Ý10-12 mol/L
(2)¢Ù¡¢¢Û<¢Ù<¢Ü<¢Ú<¢Þ<¢Ý £»¢Ú¡¢¢Ù>¢Û>¢Ü
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

³£ÎÂÏÂÓÐŨ¶È¾ùΪ0.5mol?L-1µÄËÄÖÖÈÜÒº£º¢Ù̼ËáÄÆÈÜÒº ¢Ú̼ËáÇâÄÆÈÜÒº ¢ÛÑÎËᠢܰ±Ë®£®Çë¸ù¾ÝÌâÄ¿ÒªÇó»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÉÏÊöÈÜÒºÖУ¬¿É·¢ÉúË®½â·´Ó¦µÄÊÇ
¢Ù¢Ú
¢Ù¢Ú
£¨ÌîÐòºÅ£¬ÏÂͬ£©
£¨2£©ÉÏÊöÈÜÒºÖУ¬¼ÈÄÜÓëÇâÑõ»¯ÄÆÈÜÒº·´Ó¦£¬ÓÖÄÜÓëÁòËáÈÜÒº·´Ó¦µÄÈÜÒºÖÐÀë×ÓŨ¶È´óµ½Ð¡µÄ˳ÐòÊÇ
c£¨Na+£©£¾c£¨HCO3-£©£¾c£¨OH-£©£¾c£¨H+£©£¾c£¨CO32-£©
c£¨Na+£©£¾c£¨HCO3-£©£¾c£¨OH-£©£¾c£¨H+£©£¾c£¨CO32-£©
£®
£¨3£©È¡ÊÊÁ¿ÈÜÒº¢Ü£¬¼ÓÈëÉÙÁ¿ÂÈ»¯ï§¹ÌÌ壬´ËʱÈÜÒºÖÐ
c(NH4+)c(OH-)
µÄÖµ
Ôö´ó
Ôö´ó
£¨Ìî¡°Ôö´ó¡±»ò¡°¼õС¡±»ò¡°²»±ä¡±£©
£¨4£©Èô½«¢ÛºÍ¢ÜµÄÈÜÒº»ìºÏºóÈÜҺǡºÃ³ÊÖÐÐÔ£¬Ôò»ìºÏÇ°¢ÛµÄÌå»ý
СÓÚ
СÓÚ
¢ÜµÄÌå»ý £¨Ìî´óÓÚ¡¢Ð¡ÓÚ¡¢µÈÓÚ£©£¬´ËʱÈÜÒºÖÐÀë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ
c£¨NH4+£©=c£¨Cl-£©£¾c£¨OH-£©=c£¨H+£©
c£¨NH4+£©=c£¨Cl-£©£¾c£¨OH-£©=c£¨H+£©
£®
£¨5£©È¡10mLÈÜÒº¢Û£¬¼ÓˮϡÊ͵½500mL£¬Ôò¸ÃÈÜÒºÖÐÓÉË®µçÀë³öµÄc£¨H+£©=
10-12mol?L-1
10-12mol?L-1
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÖÐѧ»¯Ñ§ÖеÄƽºâÀíÂÛÖ÷Òª°üÀ¨£º»¯Ñ§Æ½ºâ¡¢µçÀëƽºâ¡¢Ë®½âƽºâºÍÈܽâƽºâ4ÖÖ£¬ÇÒ¾ù·ûºÏƽºâÒƶ¯Ô­Àí£®Çë»Ø´ðÏÂÁÐÎÊÌ⣺
¢ñ£®³£ÎÂÏÂÓÐŨ¶È¾ùΪ0.1mol?L-1µÄËÄÖÖÈÜÒº£º¢ÙNaHCO3¡¢¢ÚNa2CO3¡¢¢ÛHCl¡¢¢ÜNH3?H2O£®
£¨1£©ÈÜÒº¢Ù¡¢¢Ú¡¢¢ÛpHÖµÓÉСµ½´óµÄ˳ÐòΪ
¢Û£¼¢Ù£¼¢Ú
¢Û£¼¢Ù£¼¢Ú
£®£¨ÌîÐòºÅ£©
£¨2£©Ïò¢ÜÖмÓÈëÉÙÁ¿ÂÈ»¯ï§¹ÌÌ壬´Ëʱc£¨NH4+£©/c£¨OH-£©µÄÖµ
Ôö´ó
Ôö´ó
 £¨Ìî¡°Ôö´ó¡±¡¢¡°¼õС¡±»ò¡°²»±ä¡±£©£®
£¨3£©È¡10mLÈÜÒº¢Û£¬¼ÓˮϡÊ͵½100mL£¬Ôò´ËʱÈÜÒºÖÐÓÉË®µçÀë³öµÄc£¨H+£©=
10-12 mol?L-1
10-12 mol?L-1
£®
£¨4£©ÉÏÊöÈÜÒºÖУ¬¼ÈÄÜÓëÇâÑõ»¯ÄÆÈÜÒº·´Ó¦£¬ÓÖÄܺÍÁòËá·´Ó¦µÄÈÜÒºÖÐÀë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòΪ
c£¨Na+£©£¾c£¨HCO3-£©£¾c£¨OH-£©£¾c£¨H+£©£¾c£¨CO32-£©
c£¨Na+£©£¾c£¨HCO3-£©£¾c£¨OH-£©£¾c£¨H+£©£¾c£¨CO32-£©
£®
£¨5£©Èô½«¢ÛºÍ¢ÜµÄÈÜÒº»ìºÏºóÈÜҺǡºÃ³ÊÖÐÐÔ£¬Ôò»ìºÏÇ°¢ÛµÄÌå»ý
СÓÚ
СÓÚ
¢ÜµÄÌå»ý£¨Ìî¡°´óÓÚ¡±¡¢¡°Ð¡ÓÚ¡±»ò¡°µÈÓÚ¡±£©£®
¢ò£®ÄÑÈܵç½âÖÊÔÚË®ÈÜÒºÖдæÔÚÈܽâƽºâ£®ÔÚ³£ÎÂÏ£¬ÈÜÒºÖи÷Àë×ÓŨ¶ÈÒÔËüÃÇ»¯Ñ§¼ÆÁ¿ÊýΪָÊýµÄ³Ë»ýÊÇÒ»¸ö³£Êý£¬½ÐÈܶȻý³£Êý£¨Ksp£©£®µ±ÈÜÒºÖи÷Àë×ÓŨ¶ÈÖ¸ÊýµÄ³Ë»ý´óÓÚÈܶȻýʱ£¬Ôò²úÉú³Áµí£¬·´Ö®¹ÌÌåÈܽ⣮ÈôijCuSO4ÈÜÒºÖÐc£¨Cu2+£©=0.02mol?L-1£¬Èç¹ûÉú³ÉCu£¨OH£©2³Áµí£¬Ó¦µ÷ÕûÈÜÒºpH£¬Ê¹Ö®´óÓÚ
5
5
 £¨ÒÑÖªKsp=2.0¡Á10-20£©£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨Ò»£©ÇëÍê³ÉÏÂÁи÷¿Õ£º
£¨1£©pH=aµÄCH3COOHÈÜҺϡÊÍ100±¶ºóËùµÃÈÜÒºpH
£¼
£¼
a+2£¨Ìî¡°£¾¡±»ò¡°£¼¡±£©
£¨2£©0.01mol?L-1CH3COOHÈÜÒºµÄpH
£¾
£¾
2£¨Ìî¡°£¾¡±»ò¡°£¼¡±£©
£¨3£©0.1mol?L-1CH3COONaÈÜÒºµÄpH
£¾
£¾
7£¨Ìî¡°£¾¡±»ò¡°£¼¡±£©
£¨¶þ£©³£ÎÂÏÂÓÐŨ¶È¾ùΪ0.05mol/LµÄËÄÖÖÈÜÒº£º¢ÙNa2CO3 ¢ÚNaHCO3 ¢ÛHCl ¢ÜNH3?H2O£¬»Ø´ðÏà¹ØÎÊÌ⣺
£¨1£©ÉÏÊöÈÜÒºÖУ¬¿É·¢ÉúË®½âµÄÊÇ
¢Ù¢Ú
¢Ù¢Ú
£¨ÌîÐòºÅ£©
£¨2£©ÔÚNaHCO3ÈÜÒºÖУ¬Àë×ÓŨ¶È´óСµÄ¹ØϵÕýÈ·µÄÊÇ
CD
CD
£¨Ìî×Öĸ£©
A¡¢c£¨Na+£©£¾c£¨HCO3-£©£¾c£¨H+£©£¾c£¨OH-£©
B¡¢c£¨Na+£©=c£¨HCO3-£©£¾c£¨H+£©£¾c£¨OH-£©
C¡¢c£¨Na+£©=c£¨HCO3-£©+c£¨H2CO3£©+c£¨CO32-£©
D¡¢c£¨Na+£©+c£¨H+£©=c£¨HCO3-£©+c£¨OH-£©+2c£¨CO32-£©
£¨3£©Ïò¢ÜÖмÓÈëÉÙÁ¿NH4Cl¹ÌÌ壬´Ëʱc£¨NH4+/OH-£©µÄÖµ
Ôö´ó
Ôö´ó
£¨¡°Ôö´ó¡±¡¢¡°¼õС¡±»ò¡°²»±ä¡±£©
£¨4£©Èô½«¢ÛºÍ¢ÜµÄÈÜÒº»ìºÏºó£¬ÈÜҺǡºÃ³ÊÖÐÐÔ£¬Ôò»ìºÏÇ°¢ÛµÄÌå»ý
СÓÚ
СÓÚ
¢ÜµÄÌå»ý£¨¡°´óÓÚ¡±¡¢¡°Ð¡ÓÚ¡±»ò¡°µÈÓÚ¡±£©
£¨5£©È¡10mLµÄ¢ÛÈÜÒº¼ÓˮϡÊ͵½500mL£¬Ôò´ËÈÜÒºÖÐÓÉË®µçÀë³öµÄc£¨H+£©=
10-11
10-11
mol/L£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

³£ÎÂÏÂÓÐŨ¶È¾ùΪ0.5mol/LµÄËÄÖÖÈÜÒº£º¢Ù̼ËáÄÆÈÜÒº ¢Ú̼ËáÇâÄÆÈÜÒº ¢ÛÑÎËᠢܰ±Ë®£®Çë¸ù¾ÝÌâÄ¿ÒªÇó»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÉÏÊöÈÜÒºÖУ¬¿É·¢ÉúË®½â·´Ó¦µÄ
 
£¨ÌîÐòºÅ£¬ÏÂͬ£©£¬ÔÚ·¢ÉúË®½â·´Ó¦µÄÈÜÒºÖÐpH×î´óµÄÊÇ
 
£®
£¨2£©ÉÏÊöÈÜÒºÖУ¬¼ÈÄÜÓëÇâÑõ»¯ÄÆÈÜÒº·´Ó¦£¬ÓÖÄÜÓëÁòËáÈÜÒº·´Ó¦µÄÊÇ
 
£®
£¨3£©È¡ÊÊÁ¿ÈÜÒº¢Ü£¬¼ÓÈëÉÙÁ¿ÂÈ»¯ï§¹ÌÌ壬´ËʱÈÜÒºÖÐ
c(OH-)c(NH3?H2O)
µÄÖµ
 
£¨Ìî¡°Ôö´ó¡±»ò¡°¼õС¡±»ò¡°²»±ä¡±£©
£¨4£©½«µÈÌå»ýµÄ¢ÛºÍ¢ÜµÄÈÜÒº»ìºÏºó£¬ËùµÃÈÜÒºÖÐÀë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ
 
£®
£¨5£©È¡10mLÈÜÒº¢Û£¬¼ÓˮϡÊ͵½500mL£¬Ôò¸ÃÈÜÒºÖÐÓÉË®µçÀë³öµÄc£¨H+£©=
 
mol/L£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸