ÔÚÒ»¶¨Î¶ȺÍѹǿÏ£¬ÓÐÈçÏ·´Ó¦£º2SO2£¨g£©+O2£¨g£©2SO3£¨g£©£¬½«1.6molSO2ºÍ0.8molµÄO2·ÅÈëÒ»ÈÝ»ý¿É±äµÄÃܱÕÈÝÆ÷ÖУ¬²âµÃÈÝÆ÷µÄÆðʼÈÝ»ýΪ100L¡£¾­Ò»¶Îʱ¼äºó£¬·´Ó¦´ïµ½Æ½ºâ£¬²âµÃ»ìºÏÆøÌåµÄÃܶÈΪ1.6g/L¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©´ïµ½Æ½ºâʱ»ìºÏÆøÌåµÄÌå»ýΪ_______£¬SO2µÄת»¯ÂÊΪ______¡£
£¨2£©ÈôÆðʼʱ¼ÓÈëamolSO2¡¢bmolO2£¬ÇÒa¡Ãb=2¡Ã1£¬ÔÚͬÑùµÄζȺÍѹǿÏ£¬·´Ó¦´ïµ½Æ½ºâʱ£¬²âµÃ»ìºÏÆøÌåµÄÌå»ýΪ120L¡£Ôòa¡¢bµÄÖµ·Ö±ðΪ______¡¢______¡£
£¨3£©ÈôÈÝÆ÷ΪÈÝ»ý²»±äµÄÃܱÕÈÝÆ÷£¬ÆäÈÝ»ýΪ100L¡£Æðʼʱ¼ÓÈëxmolSO2¡¢ymolO2¡¢zmolSO3£¬·´Ó¦´ïƽºâʱ£¬Î¶ȺÍѹǿÓ루2£©ÍêÈ«Ïàͬ£¬ÈÝÆ÷ÄÚ¸÷ÆøÌåµÄÌå»ý·ÖÊýÒ²Ó루2£©´ïƽºâʱµÄÇé¿öÍêÈ«Ïàͬ¡£Ôòx¡¢yÓ¦¸ÃÂú×ãµÄ¹ØϵʽΪ______£¬x¡¢zÓ¦¸ÃÂú×ãµÄ¹ØϵʽΪ______¡£

£¨1£©80L£»60%
£¨2£©2.4£»1.2
£¨3£©x¡Ãy=2¡Ã1£»x+z=2
¡¾ÊÔÌâ·ÖÎö¡¿
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÔÚÒ»¶¨Î¶ȺÍѹǿÏ£¬2Ìå»ýX2ÆøÌåÓë3Ìå»ýY2ÆøÌåÇ¡ºÃÍêÈ«·´Ó¦£¬Éú³É2Ìå»ýÆøÌ廯ºÏÎïZ£¬ÔòZµÄ»¯Ñ§Ê½¿ÉÄÜÊÇ£¨¡¡¡¡£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨1£©ÔÚÒ»¶¨Î¶ȺÍѹǿÏ£¬5Ìå»ýÆøÌåA2¸ú15Ìå»ýµÄÆøÌåB2ÍêÈ«»¯ºÏÉú³É10Ìå»ýijÆøÌåC£¬Ôò¸ÃÆøÌåCµÄ»¯Ñ§Ê½Îª£¨ÓÃA¡¢B±íʾ£©
AB3
AB3
£®
£¨2£©4gNaOH¹ÌÌåÈܽâºóÅäÖƳÉ100mLÈÜÒº£¬ÆäÎïÖʵÄÁ¿Å¨¶ÈΪ
1mol/L
1mol/L
£¬È¡³ö10mL¸ÃÈÜÒº£¬ËüµÄÎïÖʵÄÁ¿Å¨¶ÈΪ
1mol/L
1mol/L
£¬½«È¡³öµÄ10mL¼ÓˮϡÊÍÖÁ100mL£¬ÆäÎïÖʵÄÁ¿Å¨¶È±äΪ
0.1mol/L
0.1mol/L
£®
£¨3£©
 
34
16
S2-΢Á£ÖеÄÖÊ×ÓÊýÊÇ
16
16
£¬ÖÐ×ÓÊýÊÇ
18
18
£¬ºËÍâµç×ÓÊýÊÇ
18
18
£®±ê×¼×´¿öÏÂ11.2LµÄ34SO2ÆøÌåµÄÖÊÁ¿ÊÇ
33¸ö
33¸ö
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÔÚÒ»¶¨Î¶ȺÍѹǿϵÄÀíÏëÆøÌ壬ӰÏìÆäËùÕ¼Ìå»ý´óСµÄÖ÷ÒªÒòËØÊÇ£¨¡¡¡¡£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨1£©SO2µÄĦ¶ûÖÊÁ¿ÊÇ
64g/mol
64g/mol
£» 0.1molCO2µÄÖÊÁ¿ÊÇ
4.4
4.4
g£¬ËüÔÚ±ê×¼×´¿öÊǵÄÌå»ýԼΪ
2.24
2.24
L£»ÔÚ0.5L 0.2mol/LµÄ Ba£¨NO3£©2ÈÜÒºÖÐNO3-µÄÎïÖʵÄÁ¿Å¨¶ÈΪ
0.4mol/L
0.4mol/L
£®
£¨2£©Îª·ÀÖ¹ÂÈÆøβÆøÎÛȾ¿ÕÆø£¬¸ù¾ÝÂÈÆøµÄÐÔÖÊ£¬¿ÉÓÃ
ÇâÑõ»¯ÄÆ
ÇâÑõ»¯ÄÆ
ÈÜÒºÎüÊÕ¶àÓàµÄÂÈÆø£¬Ô­ÀíÊÇ£¨Óû¯Ñ§·½³Ìʽ±íʾ£©
2NaOH+Cl2=NaClO+NaCl+H2O
2NaOH+Cl2=NaClO+NaCl+H2O
£®   ¸ù¾ÝÕâÒ»Ô­Àí£¬¹¤ÒµÉϳ£ÓÃÁ®¼ÛµÄʯ»ÒÈéÎüÊÕ¹¤ÒµÂÈÆøβÆøÖƵÃƯ°×·Û£¬Æ¯°×·ÛµÄÓÐЧ³É·ÖÊÇ
Ca£¨ClO£©2
Ca£¨ClO£©2
£¨Ìѧʽ£©£¬³¤ÆÚ¶ÖÃÓÚ¿ÕÆøÖеÄƯ°×·Û»áʧЧµÄÔ­Òò£¬Óû¯Ñ§·´Ó¦·½³Ìʽ¿É±íʾΪ
Ca£¨ClO£©2+CO2+H2O=CaCO3¡ý+2HClO
Ca£¨ClO£©2+CO2+H2O=CaCO3¡ý+2HClO
£®
£¨3£©½«Ò»Ð¡¿é½ðÊôÄÆͶÈëË®ÖУ¬·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ
2Na+2H2O=2NaOH+H2¡ü
2Na+2H2O=2NaOH+H2¡ü
£»¿É¹Û²ìµ½µÄʵÑéÏÖÏóÊÇ
bc
bc
£¨ÌîÐòºÅ£©£®
a£®ÄƳÁµ½Ë®µ×    b£®ÄÆÈÛ³ÉСÇò    c£®Ð¡ÇòËÄ´¦Óζ¯
£¨4£©1.5mol CO2Öк¬
1.5
1.5
 mol̼ԭ×Ó£¬
3NA
3NA
¸öÑõÔ­×Ó£¨ÒÔNAΪ°¢·ü¼ÓµÂÂÞ³£ÊýµÄÖµ£©£¬±ê×¼×´¿öϵÄÌå»ýΪ
33.6
33.6
L£®
£¨5£©ÔÚÒ»¶¨Î¶ȺÍѹǿÏ£¬5Ìå»ýÆøÌåA2¸ú15Ìå»ýµÄÆøÌåB2ÍêÈ«»¯ºÏÉú³É10Ìå»ýijÆøÌåC£¬Ôò¸ÃÆøÌåCµÄ»¯Ñ§Ê½Îª£¨ÓÃA¡¢B±íʾ£©
AB3»òB3A
AB3»òB3A
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÏòÒ»¸öÈÝ»ýΪ4LµÄÃܱÕÈÝÆ÷ÖгäÈë7molSO2ºÍ4molO2£¬ÔÚÒ»¶¨Î¶ȺÍѹǿÏ£¬·¢ÉúÈçÏ·´Ó¦£º2SO2£¨g£©+O2£¨g£© 2SO3£¨g£©£¬¾­4sºó´ïµ½Æ½ºâ״̬£¬²âµÃSO2µÄÎïÖʵÄÁ¿ÊÇ3mol£¬¼ÆË㣺
£¨1£©ÒÔO2±íʾµÄ¸Ã·´Ó¦µÄËÙÂÊ
v£¨O2£©=0.125mol?L-1?s-1
v£¨O2£©=0.125mol?L-1?s-1

£¨2£©Æ½ºâʱSO3µÄÎïÖʵÄÁ¿Å¨¶È
c£¨SO3£©=4mol/L
c£¨SO3£©=4mol/L
£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸