ÓÉʵÑéµÃÖª£¬Óõç½â·¨½«µç½âÒºÖеĽðÊôÀë×Ó»¹Ô­Îª½ðÊôµ¥ÖÊʱ£¬µç·ÖÐËùͨ¹ýµÄµçÁ¿QÕý±ÈÓÚ½ðÊôµÄÎïÖʵÄÁ¿nºÍ½ðÊôÀë×ӵĻ¯ºÏ¼ÛaµÄ³Ë»ý£¬Æä±ÈÀýϵÊýFÊÇÒ»¸öºãÁ¿£¬³ÆΪ·¨À­µÚ³£Êý£¬ËüÓë½ðÊôµÄÖÖÀàÎ޹أ®

(°¢·ü¼ÓµÂÂÞ³£ÊýNA£½6.02¡Á1023mol£­1£¬µç×ÓµçÁ¿e£½1.60¡Á10£­19C£¬AlµÄĦ¶ûÖÊÁ¿Îª27¡Á10£­3kg¡¤mol£­1)

(1)ÊÔÇó³ö·¨À­µÚ³£ÊýF(µçÁ¿ÒÔ¿âÂØΪµ¥Î»£¬±£ÁôÈýλÓÐЧÊý×Ö)£®

(2)Èç¹ûµç½âAl2O3»ñµÃ1kgµÄ½ðÊôÂÁ£¬Í¨¹ýµç½â²ÛµÄµçÁ¿ÊǶàÉÙ£¿

´ð°¸£º
½âÎö£º

¡¡¡¡½â£º(1)Q£½n¡ÁNA¡Áe¡Áa£½F¡¤a¡¤n£¬F£½NA¡Áe£½6.02¡Á1023¡Á1.60¡Á10£­19£½9.63¡Á104C/mol

¡¡¡¡(2)Al¡«3e£­

¡¡¡¡Q£½F¡Án¡Áa£½9.63¡Á104¡Á¡Á3£½1.07¡Á107C


Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£ºÎïÀí½ÌÑÐÊÒ ÌâÐÍ£º038

ÓÉʵÑéµÃÖª£¬Óõç½â·¨½«µç½âÒºÖеĽðÊôÀë×Ó»¹Ô­Îª½ðÊôµ¥ÖÊʱ£¬µç¼«Ëùͨ¹ýµÄµçÁ¿QÕý±ÈÓÚ½ðÊôµÄÎïÖʵÄÁ¿nºÍ½ðÊôÀë×Ó»¯ºÏ¼ÛaµÄ³Ë»ý£¬Æä±ÈÀýϵÊýFÊÇÒ»¸öºãÁ¿£¬³ÆΪ·¨À­µÚ³£Êý£¬ËüÓë½ðÊôµÄÖÖÀàÎ޹ء£°¢·ü¼ÓµÂÂÞ³£Êý£ºNA=6.02´1023mol-1£¬µç×ÓµçÁ¿£ºe=1.60´10-19C£¬CuµÄĦ¶ûÖÊÁ¿£º64´10-3kg/mol¡££¨1£©ÊÔÇó³ö·¨À­µÚ³£ÊýF£¨µçÁ¿ÒÔ¿âÂØΪµ¥Î»£¬±£ÁôÈýλÓÐЧÊý×Ö£©¡££¨2£©Èç¹ûµç½âÁòËáÍ­ÈÜÒº»ñµÃ1kgµÄ½ðÊôÍ­£¬Í¨¹ýµç½â²ÛµÄµçÁ¿ÊǶàÉÙ£¿£¨3£©Óõç¶ÆµÄ·½·¨Ôڰ뾶ΪRµÄÍ­¿Ç±íÃæÉϾùÔȶÆÉϺܱ¡µÄÒø²ã£¬ÔÚµç½â²ÛÖÐÍ­ÇòÊÇÑô¼«»¹ÊÇÒõ¼«£¿ÁíÒ»µç¼«ÊÇʲô²ÄÁÏ£¿£¨4£©ÈôµçÁ÷Ç¿¶ÈΪI£¬Í¨µçʱ¼äΪt£¬ÒøµÄÏà¶ÔÔ­×ÓÖÊÁ¿ÎªA£¬½ðÊôÒøµÄÃܶÈΪr£¬Çó¶Æ²ãµÄºñ¶Èd£¨ÓÃÌâÖеķûºÅ±íʾ£©¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º038

ÓÉʵÑéµÃÖª£¬Óõç½â·¨½«µç½âÒºÖеĽðÊôÀë×Ó»¹Ô­Îª½ðÊôµ¥ÖÊʱ£¬µç¼«Ëùͨ¹ýµÄµçÁ¿QÕý±ÈÓÚ½ðÊôµÄÎïÖʵÄÁ¿nºÍ½ðÊôÀë×Ó»¯ºÏ¼ÛaµÄ³Ë»ý£¬Æä±ÈÀýϵÊýFÊÇÒ»¸öºãÁ¿£¬³ÆΪ·¨À­µÚ³£Êý£¬ËüÓë½ðÊôµÄÖÖÀàÎ޹ء£°¢·ü¼ÓµÂÂÞ³£Êý£ºNA=6.02´1023mol-1£¬µç×ÓµçÁ¿£ºe=1.60´10-19C£¬CuµÄĦ¶ûÖÊÁ¿£º64´10-3kg/mol¡££¨1£©ÊÔÇó³ö·¨À­µÚ³£ÊýF£¨µçÁ¿ÒÔ¿âÂØΪµ¥Î»£¬±£ÁôÈýλÓÐЧÊý×Ö£©¡££¨2£©Èç¹ûµç½âÁòËáÍ­ÈÜÒº»ñµÃ1kgµÄ½ðÊôÍ­£¬Í¨¹ýµç½â²ÛµÄµçÁ¿ÊǶàÉÙ£¿£¨3£©Óõç¶ÆµÄ·½·¨Ôڰ뾶ΪRµÄÍ­¿Ç±íÃæÉϾùÔȶÆÉϺܱ¡µÄÒø²ã£¬ÔÚµç½â²ÛÖÐÍ­ÇòÊÇÑô¼«»¹ÊÇÒõ¼«£¿ÁíÒ»µç¼«ÊÇʲô²ÄÁÏ£¿£¨4£©ÈôµçÁ÷Ç¿¶ÈΪI£¬Í¨µçʱ¼äΪt£¬ÒøµÄÏà¶ÔÔ­×ÓÖÊÁ¿ÎªA£¬½ðÊôÒøµÄÃܶÈΪr£¬Çó¶Æ²ãµÄºñ¶Èd£¨ÓÃÌâÖеķûºÅ±íʾ£©¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÓÉʵÑéµÃÖª£¬Óõç½â·¨½«µç½âÒºÖеĽðÊôÀë×Ó»¹Ô­Îª½ðÊôµ¥ÖÊʱ£¬µç¼«Ëùͨ¹ýµÄµçºÉÁ¿QÕý±ÈÓÚ½ðÊôµÄÎïÖʵÄÁ¿nºÍ½ðÊôÀë×Ó»¯ºÏ¼ÛaµÄ³Ë»ý£¬Q=F¡¤na£¬ÆäÖÐFÊÇÒ»ºãÁ¿£¬³ÆΪ·¨À­µÚ³£Êý£¬ËüÓë½ðÊôµÄÖÖÀàÎ޹أ¨°¢·ü¼ÓµÂÂÞ³£ÊýNA=6.023¡Á1023 mol£­1£¬µç×ÓµçºÉÁ¿e=1.6¡Á10£­19 C£¬CuµÄĦ¶ûÖÊÁ¿£º64¡Á10£­3 kg¡¤mol£­1£©¡£

£¨1£©ÊÔÇó³ö·¨À­µÚ³£ÊýF£¨µçÁ¿ÒÔ¿âÂØΪµ¥Î»£¬±£ÁôÈýλÓÐЧÊý×Ö£©¡£

£¨2£©Èç¹ûµç½âÁòËáÍ­ÈÜÒº»ñµÃ1 kgµÄ½ðÊôÍ­£¬Í¨¹ýµç½â²ÛµÄµçºÉÁ¿ÊǶàÉÙ£¿

£¨3£©Óõç¶ÆµÄ·½·¨Ôڰ뾶ΪRµÄÍ­Çò±íÃæ¾ùÔȵضÆÉϺܱ¡µÄÒø²ã£¬ÔÚµç¶Æ²ÛÖÐÍ­ÇòÊÇÑô¼«»¹ÊÇÒõ¼«£¿ÁíÒ»µç¼«ÊÇʲô²ÄÁÏ£¿ÈôµçÁ÷ΪI£¬Í¨µçʱ¼äΪt£¬ÒøµÄÏà¶ÔÔ­×ÓÖÊÁ¿ÎªA£¬½ðÊôÒøµÄÃܶÈΪ¦Ñ£¬Çó¶Æ²ãµÄºñ¶Èd¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â

Ëæ×Å¿Æѧ¼¼ÊõµÄ·¢Õ¹£¬°¢·ü¼ÓµÂÂÞ³£ÊýµÄ²â¶¨ÊÖ¶ÎÔ½À´Ô½¶à£¬²â¶¨µÄ¾«È·¶ÈÒ²Ô½À´Ô½¸ß¡£ÏÖÓÐÒ»ÖÖ¼òµ¥¿ÉÐеIJⶨ·½·¨£¬¾ßÌå²½ÖèΪ£º

NaCl¾§Ìå½á¹¹Ê¾Òâͼ

ͼ1-1-1

(1)½«¹ÌÌåNaClϸÁ£¸ÉÔïºó£¬×¼È·³ÆÈ¡m g NaCl¹ÌÌ岢תÒƵ½¶¨ÈÝÒÇÆ÷AÖУ»

(2)Óõζ¨¹ÜÏòAÒÇÆ÷Öмӱ½£¬²»¶ÏÕñµ´£¬¼ÌÐø¼Ó±½ÖÁAÒÇÆ÷µÄ¿Ì¶È£¬¼ÆËã³öNaCl¹ÌÌåµÄÌå»ýV cm3¡£

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

¢Ù²½Öè(1)ÖÐAÒÇÆ÷×îºÃʹÓÃ__________ (ÌîÐòºÅ)¡£

A.Á¿Í²                   B.ÉÕ±­               C.ÈÝÁ¿Æ¿              D.ÊÔ¹Ü

¢Ú²½Öè(2)ÖÐÓÃËáʽµÎ¶¨¹Ü»¹ÊÇÓüîʽµÎ¶¨¹Ü__________£¬ÀíÓÉÊÇ____________________¡£

¢ÛÄÜ·ñÓÃË®´úÌæ±½__________£¬ÀíÓÉÊÇ___________________________________________¡£

¢ÜÒÑÖªNaCl¾§ÌåÖУ¬¿¿µÃ×î½üµÄNa+ÓëCl-¼äµÄƽ¾ù¾àÀëΪa cm(Èçͼ1-1-1)£¬ÓÃÉÏÊö²â¶¨·½·¨²âµÃµÄ°¢·ü¼ÓµÂÂÞ³£ÊýNAµÄ±í´ïʽΪ_________________________________________¡£

(3)ÁíÒ»ÖÖ·½·¨Êǵç½â·¨£¬·½·¨ÊÇ£ºÓò¬µç¼«µç½âCuCl2ÈÜҺʱ£¬µ±µçÁ÷ΪI£¬Í¨µçʱ¼äΪt(µ¥Î»£º·ÖÖÓ)ʱ£¬Òõ¼«Ôö¼ÓµÄÖÊÁ¿Îªm£¬ÔÚÑô¼«ÊÕ¼¯µ½ÆøÌåÌå»ý(±ê×¼×´¿ö)ΪV¡£ÓÖÖª1¸öµç×ӵĵçºÉÁ¿ÎªQ£¬Í­µÄĦ¶ûÖÊÁ¿ÎªM£¬Ôò¼ÆËã°¢·ü¼ÓµÂÂÞ³£ÊýNAµÄËãʽΪ(    )

A.It/QV                B.32It/mQ             C.672It/QV             D.30MIt/mQ

(4)ÓÉʵÑéµÃÖª£¬Óõç½â·¨½«µç½âÒºÖеĽðÊôÀë×Ó»¹Ô­Îª½ðÊôµ¥ÖÊʱ£¬µç¼«Ëùͨ¹ýµÄµçÁ¿QÕý±ÈÓÚ½ðÊôµÄÎïÖʵÄÁ¿nºÍ½ðÊôÀë×ӵĻ¯ºÏ¼ÛaµÄ³Ë»ý£¬Æä±ÈÀýϵÊýFÊÇÒ»ºãÁ¿£¬³ÆΪ·¨À­µÚ³£Êý¡£ËüÓë½ðÊôµÄÖÖÀàÎ޹ء£

Óõç¶Æ·¨Ôڰ뾶ΪRµÄÍ­Çò±íÃæ¾ùÔȶÆÉϺܱ¡µÄÒø²ã£¬ÔÚµç½â²ÛÖÐÍ­Çò×÷__________¼«£¬ÁíÒ»µç¼«²ÄÁÏÊÇ__________¡£ÈôµçÁ÷ΪI£¬Í¨µçʱ¼äΪt£¬ÒøµÄÏà¶ÔÔ­×ÓÖÊÁ¿ÎªA£¬½ðÊôÒøµÄÃܶÈΪ¦Ñ,Çó¶Æ²ãµÄºñ¶Èd(Óñ¾ÌâÖеķûºÅ±íʾ)¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸