·ÖÎö£ºAµÄϵͳÃüÃûΪ1£¬4-¶þäå-2-¶¡Ï©£¬ÔòAD½á¹¹¼òʽΪ£ºBrCH
2CH=CHCH
2Br£¬ÔòC
4H
6ΪCH
2=CH-CH
2=CH
2£»AÓëÇâÑõ»¯ÄƵÄË®ÈÜÒº¼ÓÈÈÉú³ÉB£¬ÔòBΪHOCH
2CH=CHCH
2OH£»BÓëHBrÉú³ÉC£¬ÔòCΪHOCH
2CH
2CHBrCH
2OH£»C±»ËáÐÔ¸ßÃÌËá¼ØÈÜÒºÑõ»¯³ÉD£ºHOOCCH
2CHBrCOOH£¬DÔÚÇâÑõ»¯ÄƵĴ¼ÈÜÒºÖмÓÈÈ·¢ÉúÏûÈ¥·´Ó¦Éú³ÉE£ºHOOCCH=CHCOOH£»·´Ó¦¢ÙΪȡ´ú·´Ó¦£¬Ôò½áºÏ·´Ó¦¢ÚµÄ²úÎï¿ÉÖª·Ö×ÓʽΪC
13H
9NO
4SµÄÎïÖʵĽṹ¼òʽΪ£º
£¬¾Ý´Ë½øÐнâ´ð£®
½â´ð£º
½â£ºAµÄϵͳÃüÃûΪ1£¬4-¶þäå-2-¶¡Ï©£¬ÔòA½á¹¹¼òʽΪ£ºBrCH
2CH=CHCH
2Br£¬ÔòC
4H
6ΪCH
2=CH-CH
2=CH
2£»AÓëÇâÑõ»¯ÄƵÄË®ÈÜÒº¼ÓÈÈÉú³ÉB£¬ÔòBΪHOCH
2CH=CHCH
2OH£»BÓëHBrÉú³ÉC£¬ÔòCΪHOCH
2CH
2CHBrCH
2OH£»C±»ËáÐÔ¸ßÃÌËá¼ØÈÜÒºÑõ»¯³ÉD£ºHOOCCH
2CHBrCOOH£¬DÔÚÇâÑõ»¯ÄƵĴ¼ÈÜÒºÖмÓÈÈ·¢ÉúÏûÈ¥·´Ó¦Éú³ÉE£ºHOOCCH=CHCOOH£»·´Ó¦¢ÙΪȡ´ú·´Ó¦£¬Ôò½áºÏ·´Ó¦¢ÚµÄ²úÎï¿ÉÖªµÄC
13H
9NO
4S½á¹¹¼òʽΪ£º
£¬
£¨1£©¸ù¾Ý·ÖÎö¿ÉÖª£¬·Ö×ÓʽΪC
13H
9NO
4SµÄ½á¹¹¼òʽΪ£º
£¬¹Ê´ð°¸Îª£º
£»
£¨2£©
·Ö×ÓÖк¬ÓйÙÄÜÍÅΪ£º-S-¡¢°±»ùºÍôÈ»ù£¬¹Ê´ð°¸Îª£º°±»ù¡¢ôÈ»ù£»
£¨3£©·´Ó¦¢ÜµÄ»¯Ñ§·½³ÌʽΪ£ºBrCH
2CH=CHCH
2Br+2NaOH
2NaBr+HOCH
2CH=CHCH
2OH£»ÓÉÓÚ̼̼˫¼üÈÝÒ×±»ËáÐÔ¸ßÃÌËá¼ØÈÜÒºÑõ»¯£¬ËùÒÔ·´Ó¦¢ÝµÄÄ¿µÄÊDZ£»¤Ì¼Ì¼Ë«¼ü£¬·ÀÖ¹±»ËáÐÔ¸ßÃÌËá¼ØÈÜÒºÑõ»¯£¬
¹Ê´ð°¸Îª£ºBrCH
2CH=CHCH
2Br+2NaOH
2NaBr+HOCH
2CH=CHCH
2OH£»±£»¤Ì¼Ì¼Ë«¼ü£¬·ÀÖ¹±»ËáÐÔ¸ßÃÌËá¼ØÈÜÒºÑõ»¯£»
£¨4£©BµÄ½á¹¹¼òʽΪ£ºHOCH
2CH=CHCH
2OH£»¢ÙÄÜ·¢ÉúÒø¾µ·´Ó¦£¬·Ö×ÓÖк¬ÓÐÈ©»ù£»¢ÚÓëNaOHÈÜÒºÄÜ·´Ó¦£¬ÓëNaHCO
3ÈÜÒº²»·´Ó¦£¬Æä·Ö×ÓÖк¬ÓÐõ¥»ù¡¢²»º¬ôÈ»ù£»¢ÛºË´Å¹²ÕñÇâÆ×Ö»ÓÐÈý×é·å£¬Æä·Ö×ÓÖÐÖ»º¬ÓÐ3ÖÖµÈЧHÔ×Ó£¬Âú×ãÌõ¼þµÄÓлúÎïµÄ½á¹¹¼òʽΪ£º
£¬
¹Ê´ð°¸Îª£º
£»
£¨5£©ÒÑÖª£ºÒ»SH£¨ÛÏ»ù£©µÄÐÔÖÊÓë-OHÏàËÆ£¬Ôò
ÔÚÒ»¶¨Ìõ¼þÏ·¢ÉúËõ¾Û·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º
£¬
¹Ê´ð°¸Îª£º
£»
£¨6£©ÒÑÖª·´Ó¦ÔÀí
£¬ÒÔÒÒ´¼ÎªÔÁÏÖÆÈ¡CH
2=CH-CH=CH
2£¬¿ÉÒÔÏȽ«ÒÒ´¼´ß»¯Ñõ»¯Éú³ÉCH
3CHO£¬È»ºó·¢Éú·´Ó¦
£¬Éú³ÉµÄ
ÓëÇâÆø·¢Éú¼Ó³É·´Ó¦Éú³É
£¬
ÔÚŨÁòËá×÷ÓÃϼÓÈÈ·¢ÉúÏûÈ¥·´Ó¦Éú³ÉCH
2=CH-CH=CH
2£¬ËùÒÔ·´Ó¦Á÷³ÌΪ£ºCH
3CH
2OH
CH
2=CH-CH=CH
2£¬
¹Ê´ð°¸Îª£ºCH
3CH
2OH
CH
2=CH-CH=CH
2£®