ÏÂÁÐÊÇijµ°°×ÖʵĽṹƬ¶Î£º

(1)ÉÏÊöµ°°×ÖʵĽṹƬ¶ÎµÄË®½â²úÎïÖв»ÊôÓÚ¦Á-°±»ùËáµÄ½á¹¹¼òʽÊÇ________£®

(2)ÉÏÊöµ°°×ÖʵĽṹƬ¶ÎË®½âºóµÄ°±»ùËáÖУ¬Ä³°±»ùËá̼ÇâÔ­×ÓÊý±ÈÖµ×î´ó£®

¢Ù¸Ã°±»ùËáÓëNaOH·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º________£®

¢Ú¸Ã°±»ùËáÁ½·Ö×ÓËõºÏÐγɵĻ·×´ÎïÖʵķÖ×ÓʽΪ________£®

¢Û¸Ã°±»ùËáµÄͬ·ÖÒì¹¹ÌåÖУ¬ÊôÓÚÏõ»ù»¯ºÏÎïÇÒ±½»·ÉÏÖ»Óм׻ùµÄÒì¹¹ÌåÓÐ________ÖÖ£®

(3)ÒÑÖªÉÏÊöµ°°×ÖʽṹƬ¶ÎµÄ»¯Ñ§Ê½Á¿Îª364£¬ÔòË®½âÉú³ÉµÄ¸÷ÖÖ°±»ùËáµÄʽÁ¿Ö®ºÍΪ________£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â

±¾ÌâΪѡ×öÌ⣬°üÀ¨A¡¢BÁ½Ì⣮ѡѧ¡¶»¯Ñ§ÓëÉú»î¡·Ä£¿éµÄ¿¼Éú´ðAÌ⣬ѡѧ¡¶Óлú»¯Ñ§»ù´¡¡·Ä£¿éµÄ¿¼Éú´ðBÌ⣬ÿλ¿¼ÉúÖ»¿ÉÑ¡×ö1Ì⣮ÈôÁ½Ìⶼ×÷´ð£¬ÔòÒÔAÌâ¼Æ·Ö£®
A£®¡¶»¯Ñ§ÓëÉú»î¡·
£¨1£©²ÄÁÏÊÇÈËÀàÀµÒÔÉú´æºÍ·¢Õ¹µÄÖØÒªÎïÖÊ»ù´¡£®
¢ÙÉú²úË®ÄàµÄÖ÷ÒªÔ­ÁÏÊÇð¤ÍÁºÍ
ʯ»Òʯ
ʯ»Òʯ
£¨ÌîÃû³Æ£©£®
¢ÚÓлú²£Á§£¨¾Û¼×»ù±ûÏ©Ëá¼×õ¥£©Êµ¼ÊÉϲ»ÊǹèËáÑβÄÁÏ£¬¶øÊÇÒ»ÖÖ
ËÜÁÏ
ËÜÁÏ
£®£¨Ñ¡Ìî¡°Ï𽺡±»ò¡°ÏËά¡±»ò¡°ËÜÁÏ¡±£©
¢ÛÉϺ£ÊÀ²©»áÖйú¹ÝÓõ½Ò»ÖÖÍ¿ÁÏ-·ú̼Ϳ²ã¾Ûõ¥£¨FEP£©£¬ËüµÄµ¥ÌåΪCF3-CF=CF2£¬ÕâÖÖÍ¿ÁϾßÓÐ
ÈÈËÜÐÔ
ÈÈËÜÐÔ
£¨Ñ¡Ìî¡°ÈÈËÜÐÔ¡±»ò¡°ÈȹÌÐÔ¡±£©£®
¢Ü²£Á§¸Ö¾ßÓÐÄ͸¯Ê´¡¢ÖÊÁ¿Çᡢǿ¶È¸ßµÄÐÔÄÜ£¬ËüÊôÓÚ
¸´ºÏ
¸´ºÏ
²ÄÁÏ£¨Ñ¡Ìî¡°ºÏ½ð¡±»ò¡°¸´ºÏ¡±£©£®
£¨2£©ÈËÌ彡¿µÓëʳƷ¡¢Ò©ÎïµÈ¹ØϵÃÜÇУ®
¢ÙÓÐЩѧÉú´ÓСƫʳ£¬²»°®³ÔË®¹û¡¢Ê߲ˣ¬½á¹ûÓªÑøȱ·¦¡¢·¢Óý²»Á¼£¬ÕâÖ÷ÒªÊÇÓÉÓÚÉãÈ¡
άÉúËØ
άÉúËØ
£¨Ñ¡Ìî¡°Ö¬·¾¡±¡¢¡°Î¬ÉúËØ¡±»ò¡°µ°°×ÖÊ¡±£©²»×ãÒýÆðµÄ£®
¢ÚÉú»îÖÐÓ¦ºÏÀíµØÉãÈ¡ÈËÌå±ØÐèµÄÔªËØ£¬ÌåÄÚ
µâ
µâ
º¬Á¿¹ý¸ß£¬»áÒýÆð¼××´ÏÙ¼²²¡£®
¢ÛÌÇÀà¡¢ÓÍÖ¬¡¢µ°°×Öʶ¼ÊÇÈËÌå±ØÐèµÄÓªÑøÎïÖÊ£®ÆäÖе°°×Öʱ»ÉãÈëÈËÌåºó£¬ÔÚøµÄ×÷ÓÃÏÂË®½âΪ
°±»ùËá
°±»ùËá
£¨Ð´Ãû³Æ£©£®
¢ÜСËÕ´ò¿ÉÓÃÀ´ÖÎÁÆθËá¹ý¶à£¬Çëд³ö¸Ã·´Ó¦µÄÀë×Ó·½³Ìʽ
HCO3-+H+=CO2¡ü+H2O
HCO3-+H+=CO2¡ü+H2O
£®
¢Ý¿ÉÒÔ°ïÖúÁ÷¸Ð²¡È˽âÈÈÕòÍ´µÄÒ©ÎïÊÇ
°¢Ë¾Æ¥ÁÖ
°¢Ë¾Æ¥ÁÖ
£¨Ñ¡Ìî¡°ÇàùËØ¡±»ò¡°°¢Ë¾Æ¥ÁÖ¡±£©£®
£¨3£©½à¾»°²È«µÄÉú´æ»·¾³¸üÊǽ¡¿µµÄ±£ÕÏ£®
¢ÙΪȷ±£ÉϺ£ÊÀ²©»áÆÚ¼ä³ÇÊпÕÆøÖÊÁ¿ÓÅÁ¼ÂÊ´ïµ½95%ÒÔÉÏ£¬ÊÀ²©»áÆÚ¼äµÄ¿ÕÆøÖÊÁ¿×´¿ö¼à²âÖУ¬²»ÐèÒª¼à²âµÄÖ¸±êÊÇ
d
d
£®
a£®¿ÉÎüÈë¿ÅÁ£ÎPM10£©   b£®NO2Ũ¶È     c£®SO2Ũ¶È    d£®CO2Ũ¶È
¢Ú×ÔÀ´Ë®¿ÉÀûÓÃƯ°×·ÛÀ´É±¾úÏû¶¾£¬ÆäÄÜɱ¾úÏû¶¾µÄÔ­Òò£¨Óû¯Ñ§·´Ó¦·½³Ìʽ±íʾ£©ÊÇ
Ca£¨ClO£©2+CO2+H2O=CaCO3+2HClO
Ca£¨ClO£©2+CO2+H2O=CaCO3+2HClO
£®
¢ÛÀ¬»øµÄÎÞº¦»¯´¦Àí³£Óõķ½·¨°üÀ¨ÎÀÉúÌîÂñºÍ
·â±Õʽ
·â±Õʽ
·ÙÉÕ£®
¢ÜÈËÃÇΪ׷ÇóʱÉжø°ÑÍ··¢È¾³É¸÷ÖÖ¸÷ÑùµÄÑÕÉ«£¬³£¼ûµÄȾ·¢¼ÁÓÐÖ²ÎïȾ·¢¼Á¡¢ÎÞ»úȾ·¢¼ÁºÍ
ºÏ³É
ºÏ³É
Ⱦ·¢¼Á£¨Ñ¡Ìî¡°Óлú¡±¡°ºÏ³É¡±»ò¡°¸´ºÏ¡±£©£®
B£®£¨1£©¾ßÓÐÃ÷ÏÔÏÖÏóµÄ¹ÙÄÜÍÅÌØÕ÷·´Ó¦³£±»ÓÃÀ´¼ø¶¨»¯ºÏÎ
¢ÙÓûÇø·ÖCH2=CH2ºÍCH3CH3£¬Ó¦Ñ¡ÓÃ
b
b
£¨Ìî×Öĸ£©£®
a£®NaOHÈÜÒº       b£®äåË®    c£®Òø°±ÈÜÒº
¢ÚÓûÇø·ÖHCHOºÍHCOOH£¬Ó¦Ñ¡ÓÃ
c
c
 £¨Ìî×Öĸ£©£®
a£®KMnO4ÈÜÒº    b£®Òø°±ÈÜÒº    c£®Na2CO3ÈÜÒº
¢ÛÓûÇø·ÖºÍ£¬Ó¦Ñ¡ÓÃ
a
a
 £¨Ìî×Öĸ£©£®
a£®FeCl3ÈÜÒº     b£®NaOHÈÜÒº    c£®AgNO3ÈÜÒº
£¨2£©ÔÚÓлú»¯Ñ§ÖУ¬Í¬·ÖÒì¹¹ÊÇÆÕ±é´æÔÚÏÖÏó£®·Ö×ÓʽΪC4H9OHµÄÓлúÎï¹²ÓÐ
4
4

ÖÖ£®ÆäÖУ¬Ò»ÖÖÓлúÎïͨ¹ýÏûÈ¥·´Ó¦¿Éת±äΪ2-¶¡Ï©£¬Çëд³ö¸ÃÏûÈ¥·´Ó¦µÄ»¯Ñ§·½³Ìʽ
H3CCH2CH£¨OH£©CH3
 Å¨ÁòËá 
.
¡÷
CH3CH=CHCH3+H2O
H3CCH2CH£¨OH£©CH3
 Å¨ÁòËá 
.
¡÷
CH3CH=CHCH3+H2O
£»ÁíÒ»ÖÖÓлúÎïµÄºË´Å¹²ÕñÇâÆ×ͼ£¨1HºË´Å¹²ÕñÆ×ͼ£©ÖÐÏÔʾһ¸ö·å£¬Çëд³ö¸ÃÓлúÎïµÄ½á¹¹¼òʽÈçÏ£º
£®
£¨3£©AÊÇʯÓÍÁѽâÆøµÄ³É·ÖÖ®Ò»£¬AµÄijһͬϵÎïEµÄ²úÁ¿Í¨³£ÓÃÀ´ºâÁ¿Ò»¸ö¹ú¼ÒµÄʯÓÍ»¯¹¤Ë®Æ½£®ÏÖÒÔAΪÖ÷ÒªÔ­ÁϺϳÉC6H12O2£¬ÆäºÏ³É·ÏßÈçͼËùʾ£º

»Ø´ðÏÂÁÐÎÊÌ⣺
¢ÙAµÄ½á¹¹¼òʽΪ£º
CH3CH=CH2
CH3CH=CH2
£®
¢ÚB¡¢D·Ö×ÓÖеĹÙÄÜÍÅÃû³Æ·Ö±ðΪ
ôÇ»ù
ôÇ»ù
¡¢
ôÈ»ù
ôÈ»ù
£®
¢Ûд³öBµÄͬÀà±ðµÄͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽ£º
£® 
¢Üд³öB¡úCµÄ»¯Ñ§·½³Ìʽ£º
2CH3CH2CH2OH+O2
´ß»¯¼Á
.
¡÷
2CH3CH2CHO+2H2O
2CH3CH2CH2OH+O2
´ß»¯¼Á
.
¡÷
2CH3CH2CHO+2H2O
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ϱíÊÇÔªËØÖÜÆÚ±íµÄÒ»²¿·Ö£®
×å
ÖÜÆÚ
II A IV A VII A
1 ¢Ù
2 ¢Ú ¢Û ¢Ü ¢Ý
¢Þ ¢ß ¢à ¢á
¢â £¨11£©
£¨1£©±íÖÐËùÁÐÔªËØÖУ¬×îÎȶ¨µÄÆø̬Ç⻯ÎïµÄ»¯Ñ§Ê½
HF
HF
£¬Ô­×Ӱ뾶×îСµÄÔªËصÄÔªËØ·ûºÅÊÇ
H
H
£®
£¨2£©Ä³ÔªËØÔ­×ӵĺËÍâM²ãµç×ÓÊýÊÇÔªËØ¢Ú×îÍâ²ãµç×ÓÊýµÄ1/2£¬Ôò¸ÃÔªËصÄÔªËØ·ûºÅÊÇ
Mg
Mg
£¬ÆäÔªËØÔ­×ӽṹʾÒâͼΪ
£®
£¨3£©Ä³ÔªËØÊÇ×é³Éµ°°×ÖʵÄÖØÒª³É·Ö£¬µ°°×ÖÊÓÖÊÇÉúÃüµÄ´æÔÚÐÎʽ£¬Òò´Ë´ËÔªËر»³ÆΪ¡°ÉúÃüÔªËØ¡±£¬´ËÔªËصÄÃû³ÆΪ
µª
µª
£¬Æäµ¥Öʵĵç×ÓʽΪ
£¬Óû¯Ñ§·½³Ìʽ±íʾÆäµ¥ÖʵÄÒ»ÖÖÖØÒªµÄ¹¤ÒµÓÃ;£º
N2+3H2
¸ßθßѹ
´ß»¯¼Á
2NH3
N2+3H2
¸ßθßѹ
´ß»¯¼Á
2NH3
£®
£¨4£©¢ÜÓë¢ÞÐγÉÔ­×Ó¸öÊýÖ®±ÈΪ1£º1µÄ»¯ºÏÎïµÄµç×ÓʽΪ
£¬Óõç×Óʽ±íʾ¢ÝºÍ¢âÐγɻ¯ºÏÎïµÄ¹ý³Ì

£¨5£©Ð´³öÏÂÁл¯Ñ§·½³Ìʽ
¢ÝµÄµ¥ÖÊͨÈë¢ÞºÍ¢áÐγɻ¯ºÏÎïµÄË®ÈÜÒºÖÐ
2F2+2H2O=4HF+O2
2F2+2H2O=4HF+O2

¢áµÄµ¥ÖÊͨÈë¢ÞºÍ£¨11£©Ðγɻ¯ºÏÎïµÄË®ÈÜÒºÖÐ
Cl2+2NaBr=2NaCl+Br2
Cl2+2NaBr=2NaCl+Br2
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ijµ°°×ÖʵĽṹƬ¶ÏΪ£º

¸Ãµ°°×ÖÊÔÚθÖе°°×øµÄ×÷ÓÃÏ·¢ÉúË®½âʱ£¬²»ÄܲúÉúµÄ°±»ùËáÊÇÏÂÁÐÖеÄ(    )

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÏÂÁÐÊÇijµ°°×ÖʵĽṹƬ¶Î£º

£¨1£©ÉÏÊöµ°°×ÖʽṹƬ¶ÎµÄË®½â²úÎïÖв»ÊôÓÚ¦Á£­°±»ùËáµÄÊÇ_________________£¨Ìî½á¹¹¼òʽ£©¡£
£¨2£©ÉÏÊöµ°°×ÖʽṹƬ¶ÎË®½âºóµÄ°±»ùËáÖУ¬Ä³°±»ùËá̼ÇâÔ­×ÓÊý±ÈÖµ×î´ó¡£
¢Ù¸Ã°±»ùËáÓëNaOHÈÜÒº·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ_________________________________¡£
¢Ú¸Ã°±»ùËá¶þ·Ö×ÓËõºÏÐγɻ·×´ÎïÖʵķÖ×ÓʽΪ_____________¡£
¢Û¸Ã°±»ùËáµÄÒì¹¹ÌåÖУ¬ÊôÓÚÏõ»ù»¯ºÏÎïÇÒ±½»·ÉÏÖ»Óм׻ùµÄÒì¹¹ÌåÓÐ_______ÖÖ¡£
£¨3£©ÒÑÖªÉÏÊöµ°°×ÖʽṹƬ¶ÎµÄ»¯Ñ§Ê½Á¿Îª364£¬ÔòË®½âÉú³ÉµÄ¸÷ÖÖ°±»ùËáµÄÏà¶Ô·Ö×ÓÖÊÁ¿Ö®ºÍΪ_______________¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸