ÑÎËá¡¢ÁòËáºÍÏõËáÊÇÖÐѧ½×¶Î³£¼ûµÄÈýÖÖÇ¿ËᣮÇë¾ÍÈýÕßÓë½ðÊôÍ­µÄ·´Ó¦Çé¿ö£¬»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©¢ÙÔÚ100mL 18mol?L-1µÄŨÁòËáÖмÓÈë¹ýÁ¿µÄͭƬ£¬¼ÓÈÈʹ֮³ä·Ö·´Ó¦£¬²úÉúµÄÆøÌåÔÚ±ê×¼×´¿öϵÄÌå»ý¿ÉÄÜÊÇ______
A£®40.32L    B£® 6.72L    C£®20.16L    D£®30.24L
¢ÚÈôʹÉÏÊö·´Ó¦¢ÙÖÐÊ£ÓàµÄͭƬ¼ÌÐøÈܽ⣬¿ÉÏòÆäÖмÓÈëÏõËáÄÆ£¬Ð´³ö·´Ó¦µÄÀë×Ó·½³Ìʽ______£®
£¨2£©Èô½«¹ýÁ¿Í­·ÛÓëÒ»¶¨Á¿Å¨ÏõËá·´Ó¦£¬µ±·´Ó¦Íêȫֹͣʱ£¬¹²ÊÕ¼¯µ½µÄÆøÌå1.12L£¨±ê×¼×´¿ö£©£¬Ôò¸ÃÆøÌåµÄ³É·ÖÊÇ______£¬·´Ó¦ÖÐËùÏûºÄµÄÏõËáµÄÎïÖʵÄÁ¿¿ÉÄÜΪ______£®
A£® 0.25mol        B£® 0.2mol        C£®0.15mol       D£®0.1mol
£¨3£©Ä³Í¬Ñ§Ïò½þÅÝͭƬµÄÏ¡ÑÎËáÖмÓÈëH2O2ºó£¬Í­Æ¬Èܽ⣬²¢ÇҸ÷´Ó¦µÄ²úÎïÖ»ÓÐÂÈ»¯Í­ºÍË®£®¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ______£®
£¨1£©¢ÙÍ­Ö»ÄܺÍŨÁòËá·´Ó¦ºÍÏ¡ÁòËá²»·´Ó¦£¬Cu+2H2SO4£¨Å¨£©
  ¡÷  
.
 
CuSO4+SO2¡ü+H2O£¬Å¨ÁòËáµÄÎïÖʵÄÁ¿Îª0.1L¡Á18mol/L=1.8mol£¬Èç±»»¹Ô­µÄÁòËáÊÇ0.9mol£¬ÔòÉú³Én£¨SO2£©=0.9mol£¬V£¨SO2£©=0.9mol¡Á22.4L/mol=20.16L£¬µ«Ëæ×ÅÍ­ºÍŨÁòËáµÄ·´Ó¦µÄ½øÐУ¬ËáµÄŨ¶ÈÔ½À´Ô½Ð¡£¬²»ÔÙ²úÉú¶þÑõ»¯Áò£¬ÔòÉú³É¶þÑõ»¯ÁòµÄÌå»ýСÓÚ20.16L£¬Ö»ÓÐB·ûºÏ£¬¹Ê´ð°¸Îª£ºB£»
¢ÚÈôʹÉÏÊö·´Ó¦¢ÙÖÐÊ£ÓàµÄͭƬ¼ÌÐøÈܽ⣬¿ÉÏòÆäÖмÓÈëÏõËáÄÆ£¬ÈÜÒºÖÐÐγÉÏ¡ÏõËá¿ÉÒÔ¼ÌÐøÈܽâÍ­£¬·´Ó¦µÄÀë×Ó·½³ÌʽΪ£º3Cu+8H++2NO3-=3Cu2++2NO¡ü+4H2O£¬
¹Ê´ð°¸Îª£º3Cu+8H++2NO3-=3Cu2++2NO¡ü+4H2O£»
£¨2£©¹ýÁ¿Í­·ÛÓëÒ»¶¨Á¿Å¨ÏõËá·´Ó¦£¬·´Ó¦¿ªÊ¼ÊÇÉú³ÉNO2£¬·¢Éú£ºCu+4HNO3=Cu£¨NO3£©2+2NO2¡ü+2H2O£»Ëæ×Å·´Ó¦µÄ½øÐУ¬ÏõËáŨ¶È½µµÍ£¬Ï¡ÏõËáÓëÍ­·´Ó¦Éú³ÉNO£¬·¢Éú£º3Cu+8HNO3=3Cu£¨NO3£©2+2NO¡ü+4H2O£»ÆøÌåµÄÎïÖʵÄÁ¿Îª
1.12L
22£¬4L/mol
=0.05mol£¬µ±Éú³ÉÆøÌåÈ«²¿ÎªNO2ʱ£¬ÏûºÄµÄÏõËáµÄÎïÖʵÄÁ¿Îª0.05mol¡Á2=0.10mol£¬µ±Éú³ÉÆøÌåÈ«²¿ÎªNOʱ£¬ÏûºÄµÄÏõËáµÄÎïÖʵÄÁ¿Îª0.05mol¡Á4=0.20mol£¬ËùÒÔÏûºÄµÄÏõËáµÄÎïÖʵÄÁ¿½éÓÚ0.10molºÍ0.20molÖ®¼ä£¬Ö»ÓÐC·ûºÏ£¬¹Ê´ð°¸Îª£ºNO2¡¢NO£»C£»
£¨3£©ÑÎËá²»ÄÜÓë½ðÊôÍ­·´Ó¦£¬µ«¿ÉÒÔÓëÑõ»¯Í­·´Ó¦£¬ËùÒÔË«ÑõË®µÄ×÷ÓÃÊǽ«½ðÊôÍ­Ñõ»¯ÎªCuO£¬È»ºóÑõ»¯Í­ÈÜÓÚÑÎËᣬ·´Ó¦µÄ·½³ÌʽΪCu+H2O2+2HCl=CuCl2+2H2O£»
¹Ê´ð°¸Îª£ºCu+H2O2+2HCl=CuCl2+2H2O£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÑÎËá¡¢ÁòËáºÍÏõËáÊÇÖÐѧ½×¶Î³£¼ûµÄ¡°Èý´óËᡱ£®ÏÖ¾ÍÈý´óËáÓë½ðÊôÍ­·´Ó¦µÄÇé¿ö£¬»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©Ï¡ÑÎËá²»ÓëCu·´Ó¦£¬ÈôÔÚÏ¡ÑÎËáÖмÓÈëH2O2£¨³£¼ûÑõ»¯¼Á£¬×÷Ñõ»¯¼Áʱ»¹Ô­²úÎïΪˮ£©ºó£¬Ôò¿Éʹͭ˳ÀûÈܽ⣮¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º
Cu+H2O2+2HCl=2H2O+CuCl2
Cu+H2O2+2HCl=2H2O+CuCl2
£®
£¨2£©ÔÚÒ»¶¨Ìå»ýµÄ10mol?L-1µÄŨÁòËáÖмÓÈë¹ýÁ¿Í­Æ¬£¬¼ÓÈÈʹ֮·´Ó¦£¬±»»¹Ô­µÄÁòËáΪ0.9mol£®ÔòŨÁòËáµÄʵ¼ÊÌå»ý
´óÓÚ
´óÓÚ
£¨Ìî¡°´óÓÚ¡±¡¢¡°µÈÓÚ¡±»ò¡°Ð¡ÓÚ¡±£©180mL£®ÈôʹʣÓàµÄͭƬ¼ÌÐøÈܽ⣬¿ÉÔÚÆäÖмÓÈëÏõËáÑÎÈÜÒº£¨ÈçKNO3ÈÜÒº£©£¬Ôò¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽΪ
3Cu+2NO3-+8H+=3Cu2++2NO¡ü+4H2O
3Cu+2NO3-+8H+=3Cu2++2NO¡ü+4H2O
£®
£¨3£©¸ù¾ÝÏÂͼ²Ù×÷¼°ÏÖÏóÍƶÏËáXΪ
b
b
£¨ÌîÐòºÅ£©£®
a¡¢Å¨ÑÎËá          b¡¢Å¨ÁòËá            c¡¢Å¨ÏõËᣮ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÑÎËá¡¢ÁòËáºÍÏõËáÊÇÖÐѧ½×¶Î³£¼ûµÄ¡°Èý´óËᡱ£®ÏÖ¾ÍÈý´óËáÓë½ðÊôÍ­·´Ó¦µÄÇé¿ö£¬»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©Ï¡ÑÎËá²»ÓëCu·´Ó¦£¬ÈôÔÚÏ¡ÑÎËáÖмÓÈëH2O2£¨³£¼ûÑõ»¯¼Á£¬×÷Ñõ»¯¼Áʱ»¹Ô­²úÎïΪˮ£©ºó£¬Ôò¿Éʹͭ˳ÀûÈܽ⣮¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º
Cu+H2O2+2HCl=CuCl2+2H2O
Cu+H2O2+2HCl=CuCl2+2H2O
£®
£¨2£©ÔÚÒ»¶¨Ìå»ýµÄ10mol?l-1µÄŨÁòËáÖмÓÈë¹ýÁ¿Í­Æ¬£¬¼ÓÈÈʹ֮·´Ó¦£¬±»»¹Ô­µÄÁòËáΪ0.9mol£®ÔòŨÁòËáµÄʵ¼ÊÌå»ý
´óÓÚ
´óÓÚ
£¨Ìî¡°´óÓÚ¡±¡¢¡°µÈÓÚ¡±»ò¡°Ð¡ÓÚ¡±£©100ml£®ÈôʹʣÓàµÄͭƬ¼ÌÐøÈܽ⣬¿ÉÔÚÆäÖмÓÈëÏõËáÑÎÈÜÒº£¨ÈçKNO3ÈÜÒº£©£¬Ôò¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽΪ
3Cu+8H++2NO3-=3Cu2++2NO¡ü+4H2O
3Cu+8H++2NO3-=3Cu2++2NO¡ü+4H2O
£®
£¨3£©¸ù¾ÝÏÂͼ²Ù×÷¼°ÏÖÏóÍƶÏËáXΪ
b
b
£¨ÌîÐòºÅ£©£®
a¡¢Å¨ÑÎËá          b¡¢Å¨ÁòËá            c¡¢Å¨ÏõËᣮ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÑÎËá¡¢ÁòËáºÍÏõËáÊÇÈýÖÖÖØÒªµÄËᣮ
£¨1£©¹¤ÒµÉÏÉú²úÑÎËáÓëÏõËáʱ£¬¶¼ÒªÓõ½µÄÆø̬·´Ó¦ÎïÊÇ
¶¼ÒªÓõ½H2
¶¼ÒªÓõ½H2
£»
£¨2£©¹¤ÒµÉÏÉú²úÁòËáÓëÏõËáʱ£¬Óõ½µÄÏàͬµÄÖØÒªÉ豸ÊÇ
ÎüÊÕËþ£¬´ß»¯Ñõ»¯ÔÚ½Ó´¥ÊÒ»òÑõ»¯Â¯ÖÐ
ÎüÊÕËþ£¬´ß»¯Ñõ»¯ÔÚ½Ó´¥ÊÒ»òÑõ»¯Â¯ÖÐ
£»
£¨3£©¹¤ÒµÉú²úÖÐÓûÖƵøßŨ¶ÈµÄÁòËáÓëÏõËᣬ¿ÉʹÓõÄÏàͬÎïÖÊÊÇ
ŨH2SO4
ŨH2SO4
£»
£¨4£©Å¨ÑÎËáÓëŨÏõËᱩ¶ÔÚ¿ÕÆøÖУ¬ÏàͬµÄÏÖÏóÊÇ
²úÉú°×Îí
²úÉú°×Îí
£»
£¨5£©Å¨ÁòËáÓëŨÏõËᶼ¿ÉÓÃÌú¡¢ÂÁÈÝÆ÷Öü´æµÄÏàͬԭÀíÊÇ
Ìú¡¢ÂÁ±»Å¨H2SO4»òŨHNO3¶Û»¯
Ìú¡¢ÂÁ±»Å¨H2SO4»òŨHNO3¶Û»¯
£»
£¨6£©ÊµÑéÊÒÖƱ¸H2¡¢CO2¡¢H2S¡¢SO2ʱ£¬ÓÃÑÎËáºÍŨÁòËá¿ÉÖƱ¸µÄÏàͬÆøÌåÊÇ
SO2
SO2
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÑÎËá¡¢ÁòËáºÍÏõËáÊÇÖÐѧ½×¶Î³£¼ûµÄ¡°Èý´óËᡱ£¬Çë¾Í¡°Èý´óËᡱµÄÐÔÖÊ£¬»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©Ï¡ÑÎËáÓëÍ­²»·´Ó¦£¬µ«ÏòÏ¡ÑÎËáÖмÓÈëH2O2ºó£¬Ôò¿ÉʹͭÈܽ⣮¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ
Cu+H2O2+2HCl¨TCuCl2+2H2O
Cu+H2O2+2HCl¨TCuCl2+2H2O
£®
£¨2£©Ä³¿ÎÍâ»î¶¯Ð¡×éÉè¼ÆÁËÒÔÏÂʵÑé·½°¸ÑéÖ¤CuÓëŨÏõËá·´Ó¦µÄ¹ý³ÌÖпÉÄܲúÉúNO£®ÆäʵÑéÁ÷³ÌͼÈçÏ£º

¢ÙÈôÒª²â¶¨NOµÄÌå»ý£¬´ÓͼËùʾµÄ×°ÖÃÖУ¬ÄãÈÏΪӦѡÓÃ
A
A
×°ÖýøÐÐCuÓëŨÏõËᷴӦʵÑ飬ѡÓõÄÀíÓÉÊÇ
ÒòΪA×°ÖÿÉÒÔͨN2½«×°ÖÃÖеĿÕÆøÅž¡£¬·ÀÖ¹NO±»¿ÕÆøÖÐO2Ñõ»¯
ÒòΪA×°ÖÿÉÒÔͨN2½«×°ÖÃÖеĿÕÆøÅž¡£¬·ÀÖ¹NO±»¿ÕÆøÖÐO2Ñõ»¯
£®
¢ÚÑ¡ÓÃÈçͼËùʾÒÇÆ÷×éºÏÒ»Ì׿ÉÓÃÀ´²â¶¨Éú³ÉNOÌå»ýµÄ×°Öã¬ÆäºÏÀíµÄÁ¬½Ó˳ÐòÊÇ
123547
123547
£¨Ìî¸÷µ¼¹Ü¿Ú±àºÅ£©£®
123547
123547

¢ÛÔڲⶨNOµÄÌå»ýʱ£¬ÈôÁ¿Í²ÖÐË®µÄÒºÃæ±È¼¯ÆøÆ¿µÄÒºÃæÒªµÍ£¬´ËʱӦ½«Á¿Í²µÄλÖÃ
Éý¸ß
Éý¸ß
£¨¡°Ï½µ¡±»ò¡°Éý¸ß¡±£©£¬ÒÔ±£Ö¤Á¿Í²ÖеÄÒºÃæÓ뼯ÆøÆ¿ÖеÄÒºÃæ³Öƽ£®
£¨3£©¹¤ÒµÖÆÁòËáʱ£¬ÁòÌú¿ó£¨FeS2£©¸ßÎÂÏ¿ÕÆøÑõ»¯²úÉú¶þÑõ»¯Áò£º4FeS2+11O2=8SO2+2Fe2O3£¬Éè¿ÕÆøÖÐN2¡¢O2µÄº¬Á¿·Ö±ðΪ0.800ºÍ0.200£¨Ìå»ý·ÖÊý£©£¬4.8t FeS2ÍêÈ«ÖƳÉÁòËᣬÐèÒª¿ÕÆøµÄÌå»ý£¨±ê×¼×´¿ö£©Îª
1.68¡Á107
1.68¡Á107
L£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÑÎËá¡¢ÁòËáºÍÏõËáÊÇÖÐѧ½×¶Î³£¼ûµÄÈýÖÖÇ¿Ëᣮ
¢ñ£®Çë¾ÍÈýÕßÓë½ðÊôÍ­µÄ·´Ó¦Çé¿ö£¬»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÔÚ100mL¡¢18mol?L-1 µÄŨÁòËáÖмÓÈë¹ýÁ¿µÄͭƬ£¬¼ÓÈÈʹ֮³ä·Ö·´Ó¦£¬²úÉúµÄÆøÌåÔÚ±ê×¼Çé¿öϵÄÌå»ý¿ÉÄÜÊÇ
D
D

A.40.32L              B.30.24L          C.20.16L          D.6.72L
£¨2£©Èô½«¹ýÁ¿Í­·ÛÓëÒ»¶¨Á¿Å¨ÏõËá·´Ó¦£¬µ±·´Ó¦Íêȫֹͣʱ£¬¹²ÊÕ¼¯µ½µÄÆøÌå1.12L£¨±ê×¼×´¿ö£©£¬Ôò¸ÃÆøÌåµÄ³É·ÖÊÇ
NO2¡¢NO
NO2¡¢NO
£¬·´Ó¦ÖÐËùÏûºÄµÄÏõËáµÄÎïÖʵÄÁ¿¿ÉÄÜΪ
B
B
£®
A.0.1mol              B.0.15mol              C.0.2mol              D.0.25mol
£¨3£©Ä³Í¬Ñ§Ïò½þÅÝͭƬµÄÏ¡ÑÎËáÖмÓÈëH2O2ºó£¬Í­Æ¬Èܽ⣬²¢ÇҸ÷´Ó¦µÄ²úÎïÖ»ÓÐÂÈ»¯Í­ºÍË®£®¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ
Cu+H2O2+2HCl=CuCl2+2H2O
Cu+H2O2+2HCl=CuCl2+2H2O
£®
¢ò£®ÓÃÈçÏÂ×°ÖÿÉÒÔÍê³ÉHClµÄÖÆÈ¡¼°ºóÐøһϵÁеÄÐÔÖÊʵÑ飨ͼÖмгÖ×°ÖÃÒÑÂÔÈ¥£©£®
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©×°ÖÃAÑ¡ÓÃŨÁòËáºÍŨÑÎËá»ìºÏÖÆÈ¡HClÆøÌ壬pÖÐÊ¢×°ÊÔ¼ÁΪ
ŨÁòËá
ŨÁòËá
£®
£¨2£©×°ÖÃBÖеÄËÄ´¦ÃÞ»¨ÒÀ´Î×öÁËÈçÏ´¦Àí£º¢Ù°üÓÐij³±ÊªµÄ¹ÌÌåÎïÖÊ  ¢ÚÕºÓÐKIÈÜÒº¢ÛÕºÓÐʯÈïÈÜÒº  ¢ÜÕºÓÐŨNaOHÈÜÒº£®·´Ó¦¿ªÊ¼ºó£¬¹Û²ìµ½¢Ú´¦ÓÐ×Ø»ÆÉ«ÎïÖʲúÉú£¬Ð´³ö¢Ú´¦·¢Éú·´Ó¦µÄÀë×Ó·½³Ìʽ
CI2+2I-=2Cl-+I2
CI2+2I-=2Cl-+I2
£®ÔÚ¢Ù´¦°üÓеĹÌÌåÎïÖÊ¿ÉÄÜÊÇ
a£®MnO2        b£®KmnO4       C£®KCl              d£®Cu
£¨3£©ÔÚÕû¸öʵÑé¹ý³ÌÖУ¬ÔÚ¢Û´¦Äܹ۲쵽µÄÏÖÏóÊÇ
ÏȱäºìºóÍÊÉ«
ÏȱäºìºóÍÊÉ«
£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸