(7·Ö) Ϊ³ýÈ¥´ÖÑÎÖеÄCa2+¡¢Mg2+¡¢SO42£­ÒÔ¼°ÄàɳµÈÔÓÖÊ£¬Ä³Í¬Ñ§Éè¼ÆÁËÒ»ÖÖÖƱ¸¾«ÑεÄʵÑé·½°¸£¬²½ÖèÈçÏ£¨ÓÃÓÚ³ÁµíµÄÊÔ¼ÁÉÔ¹ýÁ¿£©£º




(1)ÅжÏBaCl2ÒѹýÁ¿µÄ·½·¨ÊÇ_________________________________¡£
(2)µÚ¢Ü²½ÖУ¬ÓйصÄÀë×Ó·½³ÌʽÊÇ_____________________________¡£
(3)ÈôÏÈÓÃÑÎËáµ÷pHÖµÔÙ¹ýÂË£¬½«¶ÔʵÑé½á¹û²úÉúÓ°Ï죬ÆäÔ­ÒòÊÇ
_____________________________                                         ¡£
(4)Ϊ¼ìÑ龫Ñδ¿¶È£¬ÐèÅäÖÆ1000mL.0.2 mol/L NaCl(¾«ÑÎ)ÈÜÒº£¬Èô¶¨ÈÝʱ¹Û²ìÒºÃæÑöÊÓ£¨ÈçÓÒͼËùʾ£©£¬»áÔì³ÉËùÅäÖƵÄÈÜҺŨ¶È£¨ÌîÆ«¸ß»òÆ«µÍ £©________________¡£
£¨1£©È¡µÚ¢Ú²½ºóµÄÉϲãÇåÒº1¡«2µÎÓÚµãµÎ°åÉÏ£¬ÔÙµÎÈë1¡«2µÎBaCl2ÈÜÒº£¬ÈôÈÜҺδ±ä»ë×Ç£¬Ôò±íÃ÷BaCl2ÒѹýÁ¿
£¨2£©¨T CaCO3¡ý£»¨T BaCO3¡ý
£¨3£©ÔÚ´ËËá¶ÈÌõ¼þÏ»áÓв¿·Ö³ÁµíÈçCaCO3¡¢BaCO3Èܽ⣬´Ó¶øÓ°ÏìÖƵþ«ÑεĴ¿¶È
£¨4£©Æ«Ð¡
ÂÔ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÏÂÁÐÎïÖÊ·ÖÀëµÄ·½·¨ÕýÈ·µÄÊÇ
A£®´ÓµâË®ÖÐÌáÈ¡µâ£ºÓþƾ«ÝÍÈ¡
B£®³ýÈ¥COÖÐÉÙÁ¿O2£ºÍ¨¹ý×ÆÈȵÄCuÍøºóÊÕ¼¯ÆøÌå
C£®³ýÈ¥KClÈÜÒºÖеÄÉÙÁ¿MgCl2£º¼ÓÈëÊÊÁ¿NaOHÈÜÒº£¬¹ýÂË
D£®³ýÈ¥CO2ÖеÄÉÙÁ¿HCl£ºÍ¨Èë±¥ºÍNaHCO3ÈÜÒº£¬ÊÕ¼¯ÆøÌå

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

£¨5·Ö£©³£ÎÂÏ£¬Ä³Î´ÖªËáÐÔÈÜÒºÖУ¬¿ÉÄܺ¬ÓдóÁ¿µÄCl-¡¢OH-¡¢CO32-¡¢H+¡¢Ag+¡¢Fe3+ µÈÀë×Ó¡£ÄãÈÏΪÆäÖÐÒ»¶¨º¬ÓеÄÀë×ÓÊÇ                   £¬Ò»¶¨²»º¬ÓеÄÀë×ÓÊÇ                  £¬»¹Ðè½øÒ»²½¼ìÑéµÄÀë×ÓÊÇ                 £¬ÎªÁ˽øÒ»²½È·ÈÏÊÇ·ñº¬¸ÃÀë×Ó£¬ÐèÒªµÄÊÔ¼ÁºÍÏÖÏóΪ                             ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

(9·Ö) Ñ¡ÓÃÒ»ÖÖÊÔ¼Á³ýÈ¥ÏÂÁи÷ÎïÖÊÖеÄÔÓÖÊ£¨À¨ºÅÄÚΪÔÓÖÊ£©£¬°ÑËùÑ¡ÊÔ¼ÁµÄ»¯Ñ§Ê½ÌîÔÚºáÏßÉÏ£¬²¢Ð´³öÀë×Ó·½³Ìʽ¡£
£¨1£©BaCl2(HCl)ÊÔ¼Á          £»Àë×Ó·½³ÌʽΪ                                 
£¨2£©CO(CO2)ÊÔ¼Á         £»Àë×Ó·½³ÌʽΪ                                     
£¨3£©Fe SO4 (Cu SO4)          £»Àë×Ó·½³ÌʽΪ                          

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

£¨8·Ö£©¸ù¾Ý»ìºÏÎïµÄÌص㣬·ÖÀë·½·¨Ò»°ãÓйýÂË¡¢Õô·¢¡¢ÕôÁó¡­¡­£¬Óû°Ñµâ´ÓµâË®ÖзÖÀë³öÀ´£¬¿ÉÔÚÈÜÒºÖмÓÈëËÄÂÈ»¯Ì¼³ä·ÖÕñµ´ºó¾²Ö㬿ɹ۲쵽ÏÖÏó                                        £¬ÄÜÓÃËÄÂÈ»¯Ì¼´ÓµâË®ÖÐÝÍÈ¡µâµÄÔ­ÒòÊÇ                             £¬½Ó×Å¿ÉÓà         ·½·¨½«Á½²ãÒºÌå·Ö¿ª£¬²Ù×÷ʱÓõ½µÄ»¯Ñ§ÒÇÆ÷½Ð            ¡£ËÄÂÈ»¯Ì¼ÝÍÈ¡µâºó£¬ÈçºÎ·ÖÀë³öµâ                    ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

£¨5·Ö£©Ñ¡ÔñÏÂÁÐʵÑé·½·¨·ÖÀëÎïÖÊ£¬½«·ÖÀë·½·¨µÄÐòºÅÌîÔÚºáÏßÉÏ¡£
A£®·ÖÒºB£®Éý»ªC£®½á¾§D£®Õô·¢ E£®ÕôÁó F£®¹ýÂË
£¨1£©______·ÖÀ붹½¬Ó붹ÔüµÄ»ìºÏÎï¡£
£¨2£©______´ÓÏõËá¼ØºÍÂÈ»¯ÄƵĻìºÏÒºÖлñµÃÏõËá¼Ø¡£
£¨3£©______·ÖÀëË®ºÍʳÓõ÷ºÍÓ͵ĻìºÏÎï¡£
£¨4£©______·ÖÀëCCl4£¨·ÐµãΪ76.75¡æ£©ºÍ¼×±½£¨·ÐµãΪ110.6¡æ£©µÄ»ìºÏÎï¡£
£¨5£©______Óú£Ë®É¹ÑΡ£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÏÂÁÐ˵·¨ÖÐÕýÈ·µÄÊÇ£¨  £©
A£®Ä³ÈÜÒºÓëNaOHÈÜÒº¹²ÈÈ£¬²úÉúÄÜʹʪÈóµÄÀ¶É«Ê¯ÈïÊÔÖ½±äºìµÄÆøÌ壬˵Ã÷Ô­ÈÜÒºÖдæÔÚ笠ùÀë×Ó
B£®Ä³ÈÜÒºÖмÓÈëÏõËáÒøÈÜҺʱ£¬²úÉú°×É«³Áµí£¬¼ÓÏ¡ÏõËá³Áµí²»Èܽ⣬˵Ã÷Ô­ÈÜÒºÖк¬Cl-
C£®Óò¬Ë¿ÕºÈ¡Ä³ÈÜÒºÔھƾ«µÆµÄ»ðÑæÉÏ×ÆÉÕʱ£¬»ðÑæ³Ê»ÆÉ«£¬ËµÃ÷Ô­ÈÜÒºÖÐÖ»º¬ÓÐNa+£¬
²»º¬ÓÐK+¡£
D£®Ä³ÈÜÒºÖмÓÈëBaCl2ÈÜҺʱ£¬²úÉú°×É«³Áµí£¬¼ÓÏ¡ÏõËá³Áµí²»Èܽ⣬˵Ã÷Ô­ÈÜÒºÖдæÔÚSO42-

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÏÂÁÐÌá´¿·½·¨²»ÕýÈ·µÄÊÇ
A£®³ýÈ¥KNO3ÖеÄNaClÔÓÖÊ-------½á¾§¡¢ÖؽᾧB£®³ýȥʳÑÎÖеÄÄàɳ---Èܽ⡢¹ýÂË
C£®³ýÈ¥KClÖеÄK2CO3--------¼ÓÊÊÁ¿ÁòËáD£®³ýÈ¥µâË®ÖеÄË®-------ÓÃCCl4ÝÍÈ¡

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÏÂÁгýÔÓÖʵķ½·¨ÕýÈ·µÄÊÇ                                        £¨   £©
A£®ÓùýÁ¿µÄ¼îÒº³ýÈ¥CO2ÖлìÓеÄÉÙÁ¿HClÆøÌå
B£®Óñ¥ºÍʳÑÎË®³ýÈ¥ÂÈÆøÖлìÓеÄSO2ÆøÌå
C£®ÓÃÉý»ªµÄ·½·¨³ýȥʳÑÎÖÐÉÙÁ¿µÄI2
D£®ÓùýÁ¿µÄÂÈ»¯±µÈÜÒº³ýÈ¥ÑÇÁòËáÄÆÈÜÒºÖеÄÉÙÁ¿SO42£­

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸