£¨10·Ö£©ÔÚ³£ÎÂÏ£¬ÓÃÒ»¶¨Å¨¶ÈµÄCH3COOHÈÜÒºµÎ¶¨V mLͬŨ¶ÈNaOHÈÜҺʱµÃµ½µÄµÎ¶¨ÇúÏßÈçÏÂͼ£º

¾­²â¶¨Ä³ÈÜÒºÖÐÖ»º¬ÓÐNa+¡¢CHCOO£­¡¢H+¡¢OH£­ ËÄÖÖÀë×Ó£¬ÒÑÖªÕâÖÖÈÜÒºº¬ÓÐÒ»ÖÖ»òÁ½ÖÖÈÜÖÊ¡£²é×ÊÁϱíÃ÷µÈŨ¶ÈµÄCH3COOHºÍCH3COONaµÄ»ìºÏÒºÏÔËáÐÔ¡£ÊÔÍê³ÉÏÂÁи÷Ì⣺
£¨1£©ÊÔ·ÖÎöÉÏͼËù±íʾµÎ¶¨¹ý³ÌµÄb¡¢dÁ½µã¿ÉÄܵÄÈÜÖÊ×éºÏ£º
bµã_____________________£¬dµã____________________¡£
£¨2£©·Ö±ðÖ¸³öÉÏͼa¡¢cÁ½µãËù´æÔÚµÄ΢Á£µÄÀë×ÓŨ¶È´óС¹Øϵ£º
aµã£º_________________________________________________________________________
cµã£º_________________________________________________________________________
£¨3£©Ë®µÄµçÀë³Ì¶ÈÓëÈÜÒºÖÐËùÈܽâµÄµç½âÖÊÓйأ¬ÊÔ·ÖÎöÉÏͼa¡¢b¡¢c¡¢dµã£¬Ë®µÄµçÀë³Ì¶È×î´óµÄÊÇ______¡£
£¨4£©ÓйØÕâÖÖÈÜÒº£¬ÏÂÁеÄ˵·¨²»ÕýÈ·µÄÊÇ_________
A£®ÈôÈÜÒºÖÐÁ£×Ó¼äÂú×㣺c(Na+)>c(CH3COO£­)>c(OH£­)>c(H+)£¬ÔòÈÜÒºÖÐÈÜÖÊ¿ÉÄÜΪCH3COONaºÍNaOH
B£®ÈôÈÜÒºÖÐÁ£×Ó¼äÂú×ãc(CH3COO£­)>c(Na+)>c(H+)>c (OH£­)£¬ÔòÈÜÒºÖÐÈÜÖÊÒ»¶¨Ö»ÓÐCH3COONa
C£®ÈôÈÜÒºÖÐc(Na+)=c(CH3COO£­)£¬Ôò¸ÃÈÜÒºÒ»¶¨ÏÔÖÐÐÔ
D£®ÈôÈÜÒºÖÐc(CH3COOH)>c(Na+)£¬ÔòÈÜÒºÒ»¶¨ÏÔËáÐÔ
E£®ÈÜÒºÖÐÀë×Ó¼ä¿ÉÄÜÂú×ãc(Na+)>c(CH3COO£­)>c(H+)>c(OH£­)
£¨5£©ÈôÈÜÒºÊÇÓÉÌå»ýÏàµÈµÄCH3COOHÈÜÒººÍNaOHÈÜÒº»ìºÏ¶ø³É£¬ÇÒÇ¡ºÃ³ÊÖÐÐÔ£¬Ôò»ìºÏÇ°c(CH3COOH)____________c(NaOH)£¨Ìî¡°>¡±¡°<¡±»ò¡°=¡±£©¡£
£¨1£©bµã£ºCH3COONa(1·Ö)£¬dµã£ºCH3COONaºÍCH3COOH£¨1·Ö£©
£¨2£©aµã£ºC£¨Na+£©£¾C(OH_)£¾C(CH3COO-) £¾C(H+)£¨2·Ö£©
cµã£ºC£¨Na+£©=C(CH3COO-)£¾C(OH_)=C(H+)£»£¨2·Ö£©
£¨3£©C£¨1·Ö£©
£¨4£©B E(2·Ö)
£¨5£©£¾£¨1·Ö£©
ÂÔ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£º¼ÆËãÌâ

(9·Ö) ÒÑÖªÓйØÎïÖʵÄÑõ»¯ÐÔÇ¿Èõ˳ÐòΪ£ºÅ¨ÁòË᣾Fe3£«£¾H£«£¾Fe2£«¡£³ÆµÃ 60 g Ìú·ÛÓë100 mL ŨÁòËáÔÚ¼ÓÈȵÄÌõ¼þÏ·´Ó¦£¬·´Ó¦×îÖÕÓйÌÌåÊ£Ó࣬¹²ÊÕ¼¯µ½±ê×¼×´¿öÏÂÆøÌå22.4 L£¬ÆøÌåµÄÖÊÁ¿Îª39.2 g¡£ÊԻشðÒÔÏÂÎÊÌ⣺£¨ÓÖÖª£º2Fe 3£«+ Fe = 3Fe2£«£©
£¨1£©ÔÚ¼ÓÈȵÄÌõ¼þÏ¿ªÊ¼·´Ó¦µ½×îÖÕÓйÌÌåÊ£Ó࣬»¹Éæ¼°µ½µÄ»¯Ñ§·½³ÌʽÓУº
_______________________________________________________________________£»
£¨2£©ÇóŨÁòËáµÄÎïÖʵÄÁ¿Å¨¶È£»
£¨3£©·´Ó¦×îÖÕÊ£Óà¹ÌÌåµÄÖÊÁ¿¡££¨Ð´³ö¼òµ¥µÄ¼ÆËã¹ý³Ì£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

£¨10·Ö£©ÒûÓÃË®°²È«×´¿öÓëÈËÀཡ¿µÓÐ×ÅÃÜÇйØϵ¡£ÖؽðÊôÀë×Ó¶ÔºÓÁ÷¡¢º£Ñó»áÔì³ÉÑÏÖØÎÛȾ¡£³Áµí·¨ÊÇ´¦Àíº¬ÖؽðÊôÀë×ÓÎÛË®³£Óõķ½·¨¡£
ij¹¤³§·ÏË®£¨pH£½2.0£¬¦Ñ£½1.0 g¡¤mL-1£©Öк¬Ag+¡¢Pb2+µÈÖؽðÊôÀë×Ó£¬ÆäŨ¶È¸÷ԼΪ0.01mol¡¤L-1¡£ÅÅ·ÅÇ°ÄâÓóÁµí·¨³ýÈ¥ÕâÁ½ÖÖÀë×Ó£¬²éÕÒÓйØÊý¾ÝÈçÏ£º
ÄÑÈܵç½âÖÊ
AgCl
AgI
AgOH
Ag2S
PbI2
Pb(OH)2
PbS
Ksp
1.8¡Á10-10
8.3¡Á10-17
5.6¡Á10-18
6.3¡Á10-50
7.1¡Á10-9
1.2¡Á10-15
3.4¡Á10-28
£¨1£©ÄãÈÏΪÍù·ÏË®ÖÐͶ    £¨Ìî×ÖĸÐòºÅ£©£¬³ÁµíЧ¹û×îºÃ¡£
A£®NaOH B£®Na2SC£®KI D£®Ca(OH)2
£¨2£©Èç¹ûÓÃÉúʯ»Ò´¦ÀíÉÏÊö·ÏË®£¬Ê¹ÈÜÒºµÄpH£½8.0£¬´¦ÀíºóµÄ·ÏË®ÖÐc(Pb2+)£½       ¡£
£¨3£©Èç¹ûÓÃʳÑδ¦ÀíÆäÖ»º¬ÒøÀë×ӵķÏË®£¬²âµÃ´¦ÀíºóµÄ·ÏË®ÖÐNaClµÄÖÊÁ¿·ÖÊýΪ0.117%£¬Èô»·¾³ÒªÇóÅŷűê׼Ϊc(Ag+)µÍÓÚ1.0¡Á10-18mol¡¤L-1£¬Ôò¸Ã¹¤³§´¦ÀíºóµÄ·ÏË®ÊÇ·ñ·ûºÏÅŷűê×¼         ¡££¨Ìî¡°ÊÇ¡±»ò ¡°·ñ¡±£©Ð´³ö¼ÆËã¹ý³Ì¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÏÖÔÚÓÐÏàͬŨ¶ÈµÄCH3COONaºÍNaClOÈÜÒº£¬Á½ÈÜÒºÖÐÒõÀë×ÓŨ¶ÈµÄ´óС¹ØϵÕýÈ·µÄÊÇ
A£®Ç°Õß´óÓÚºóÕßB£®ºóÕß´óÓÚÇ°ÕßC£®Á½ÕßÏàµÈD£®ÎÞ·¨È·¶¨

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÄÜÕýÈ·±íʾÏÂÁз´Ó¦µÄÀë×Ó·½³ÌʽµÄÊÇ(    )
A£®¼×ËáÄÆÈÜÒººÍÑÎËá·´Ó¦ HCOO-+H+====HCOOH
B£®Áò»¯ÄƵÚÒ»²½Ë®½âS2-+2H2OH2S+2OH-
C£®´×Ëá±µÈÜÒººÍÁòËá·´Ó¦Ba2++SO====BaSO4¡ý
D£®ÇâÑõ»¯¸ÆÈÜÒººÍ̼ËáÇâþ·´Ó¦Ca2++OH-+HCO====CaCO3¡ý+H2O

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÏÂÁÐÐðÊö²»ÕýÈ·µÄÊÇ£¨   £©
A£®25¡æʱ£¬ÔÚMg£¨OH£©2µÄÐü×ÇÒºÖмÓÈëÉÙÁ¿µÄNH4Cl¹ÌÌ壬c£¨Mg2+£©Ôö´ó
B£®Ò»¶¨Î¶ÈÏ£¬IL 1mol£¯LµÄ°±Ë®Óë2L 0£®5mol£¯LµÄ°±Ë®ÖУ¬n£¨NH4+£©Ç°Õ߶à
C£®ÏàͬÌå»ý¡¢ÏàͬÎïÖʵÄÁ¿Å¨¶ÈµÄÑÎËá¡¢´×ËᣬϡÊÍÏàͬ±¶Êýºó£¬ÈÜÒºµÄpH£ºÑÎËá<´×Ëá
D£®0£®2mol£¯LµÄÒ»ÔªËáHXÓë0£®1mol£¯LµÄKOHÈÜÒºµÈÌå»ý»ìºÏËùµÃÈÜÒºÖУ¬Ò»¶¨ÓУºa£¨H+£©+c£¨K+£©=c£¨OH-£©+c£¨X-£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÔÚÏÂÁи÷×éÀë×ÓÔÚÒ»¶¨Ìõ¼þÏÂÄܹ»´óÁ¿¹²´æµÄÊÇ                      
A£®ÎÞÉ«ÈÜÒº£ºCu2£«¡¢K£«¡¢MnO4£­¡¢SO42£­
B£®ÄÜÈܽâAl2O3µÄÈÜÒº£ºNa£«¡¢Ca2£«¡¢HCO3£­¡¢NO3£­
C£®c(OH£­)£½1¡Á10£­13mol¡¤L£­1µÄÈÜÒº£ºNH4£«¡¢Al3£«¡¢SO42£­¡¢Cl£­
D£®º¬0.1 mol¡¤L£­1 NO3£­µÄÈÜÒº£ºH£«¡¢Fe2£«¡¢Mg2£«¡¢Br£­

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÏÂÁÐ˵·¨Öв»ÕýÈ·µÄÊÇ                                                                     £¨   £©
A£®½«´¿Ë®¼ÓÈÈÖÁ½Ï¸ßζȣ¬Ë®µÄÀë×Ó»ý±ä´ó£¬pH±äС£¬³ÊÖÐÐÔ
B£®°±Ë®ºÍÑÎËá»ìºÏºóÈÜÒº³ÊËáÐÔ£¬ÈÜÒºÖÐÀë×ÓŨ¶È´óС¹Øϵһ¶¨´æÔÚ£ºc£¨NH4+£©>c£¨H+£©
C£®ÏàͬζÈÏ£¬pH=2µÄ´×ËáÈÜÒºÓëpH=2µÄÑÎËáÖÐc£¨H+£©Ö®±ÈΪ1£ºl
D£®ÏòÊ¢ÓÐÉÙÁ¿Mg£¨OH£©2³ÁµíµÄÊÔ¹ÜÖмÓÈëNH4ClŨÈÜÒº£¬Õñµ´£¬³Áµí»áÖð½¥Èܽâ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÔÚÏàͬζÈÏ£¬µÈÌå»ý¡¢µÈÎïÖʵÄÁ¿Å¨¶ÈµÄÏÂÁÐÈÜÒº¢ÙNa2SO4¡¢¢ÚH2SO3¡¢¢ÛNaHSO3¡¢¢ÜNa2SÖУ¬Ëùº¬´øµç΢Á£ÊýÓɶൽÉÙµÄ˳ÐòΪ£¨     £©
A ¢Ü£¾¢Ù£¾¢Û£¾¢Ú           B ¢Ù£¾¢Ü£¾¢Û£¾¢Ú
C ¢Ù£½¢Ü£¾¢Ú£½¢Û           D ¢Ü£½¢Ù£¾¢Û£¾¢Ú

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸