(1)ʹÓÃͺÍÏ¡ÁòËáÖƱ¸ÁòËá;§Ìå?
²½ÖèÈçÏ£º?
²½Öè¢Ù¹Û²ìµ½µÄÏÖÏóÊÇ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£?
²½Öè¢ÛµÄÖ÷Òª²Ù×÷°üÀ¨£º¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£
(2)ijÁòËá;§Ìå(CuSO4¡¤nH2O)Öк¬ÓÐÉÙÁ¿µÄÂÈ»¯ÄÆ£¬ÊµÑéÊÒÀï²â¶¨½á¾§Ë®nµÄÊýÖµ?
A.ÔÚʵÑé¹ý³ÌÖÐÒªÓõ½ÏÂÁÐÒÇÆ÷Öеġ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡(ÌîÐòºÅ£¬ÏÂͬ)¡£?
¢ÙÈÝÁ¿Æ¿¡¡¢ÚÍÐÅÌÌìƽ¡¡¢ÛÉÕ±¡¡¢Ü׶ÐÎÆ¿¡¡?¢Ý©¶·?¡¡¢Þ¸ÉÔïÆ÷¡¡¢ß³¤¾±Â©¶·¡¡¢àÊԹܡ¡¢áÊԹܼС¡?¢âÛáÛö?
B.ÔÚÏÂÁвÙ×÷ÖУ¬Ñ¡ÓñØÒªµÄ²½Ö裬°´²Ù×÷ÏȺó˳ÐòÅÅÁС¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£?
¢Ù³ÆÁ¿ÁòËá;§Ìå¡¡¢Ú¼ÓË®Èܽ⡡¢Û¹ýÂË¡¡¢Ü¼Ó¹ýÁ¿AgNO3ÈÜÒº¡¡¢Ý³Æ³ö¼ÓÈȺó¹ÌÌåÖÊÁ¿¡¡¢Þ¼ÓÈȢ߼ӹýÁ¿BaCl2ÈÜÒº¡¡¢à³ÆÁ¿³Áµí?
C.ÔÚÒÔÉϲÙ×÷ÖУ¬ÈôÁòËá;§ÌåÖÊÁ¿Îªa g£¬³ÁµíÖÊÁ¿Îªb g£¬¼ÓÈȺó¹ÌÌåÖÊÁ¿Îªc g£¬Ôòa gÁòËá;§ÌåÖнᾧˮnΪ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£?
(3)ÁòËáÍÈܽâ¶ÈµÄ²â¶¨?
ÓÃʯīµç¼«(Ïàͬ)µç½â±¥ºÍCuSO4ÈÜÒº£¬Òõ¼«µÄµç¼«·´Ó¦Ê½ÊÇ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£
ÒÑÖª±¥ºÍCuSO4ÈÜÒºµÄÖÊÁ¿Îª60 g£¬Í¨µç10 minºó£¬ÈÜҺǡºÃ±äΪÎÞÉ«¡£³ÆÁ¿·¢ÏÖÁ½µç¼«ÖÊÁ¿²îΪ4 g£¬´ËζÈÏÂCuSO4µÄÈܽâ¶ÈÊÇ ¡£?
(4)ÒÑÖªÍм·ÅÈëÏ¡ÁòËáÖв»·¢Éú·´Ó¦£¬ÈôÔÚÏ¡ÁòËáÖмÓÈëH2O2£¬Íм¿ÉÖð½¥Èܽ⡣Çëд³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£?
(1)ºìÉ«¹ÌÌå±äºÚ¼ÓÈÈŨËõ£¬ÀäÈ´½á¾§£¬¹ýÂË?
(2)A.¢Ú¢Û¢Ý¡¡B.¢Ù¢Þ¢Ý¢Ú¢ß¢Û¢à¡¡?C. ??
(3)Cu2++2e-Cu¡¡¡¡20g?
(4)Cu+H2O2+H2SO4CuSO4+2H2O?
½âÎö£º(1)Ϊ·ÀÖ¹ÎÛȾ£¬½ÚÔ¼ÔÁÏ£¬ÏȽ«Cuת»¯ÎªCuO£¬ÓÉCuSO4ÈÜÒº»ñÈ¡¾§ÌåµÄ·½·¨Í¨³£ÊÇŨËõºó½µÎÂÈ»ºó¹ýÂ˵þ§Ìå¡£?
(2)Òª²âCuSO4¡¤nH2O(NaCl)ÖеÄnÖµ£¬±ØÐëÒªÖªµÀH2OµÄÖÊÁ¿ºÍCuSO4µÄÖÊÁ¿»òCuSO4ÖÊÁ¿ºÍNaClÖÊÁ¿»òË®µÄÖÊÁ¿ºÍNaClµÄÖÊÁ¿£¬·½·¨½Ï¶à£¬²½ÖèºÍÒÇÆ÷Ó¦ÏàÆ¥Å䣬A¡¢B½áºÏ·ÖÎö¡£
C£ºa gΪ¾§ÌåÖÊÁ¿b gΪBaSO4ÖÊÁ¿(a-c) gΪH2OµÄÖÊÁ¿£¬
¹Ên(CuSO4)=£»n(H2O)=?£»ËùÒÔn=¡£?
(3)CuµÄÖÊÁ¿Îª4 g£¬¹ÊCuSO4ÖÊÁ¿Îª10 g£¬¹ÊÈܽâ¶ÈΪ20 g¡£?
(4)Cu+H2O2+H2SO4CuSO4+2H2O
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ÆøÌå | A | B | C | D | E | F |
ÉÕÆ¿ºÍ ÆøÌåµÄ ×ÜÖÊÁ¿£¨g£© |
48.408 2 | 48.408 2 | 48.408 2 | 48.382 2 | 48.434 2 | 48.876 2 |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ÆøÌå | A | B | C | D | E | F |
ÉÕÆ¿ºÍÆøÌåµÄ×ÜÖÊÁ¿/g | 48.4082 | 48.4082 | 48.4082 | 48.3822 | 48.4342 | 48.8762 |
ÒÑÖª±ê×¼×´¿öÏ£¬ÉÕÆ¿µÄÈÝ»ýΪ0.293 L£¬ÉÕÆ¿ºÍ¿ÕÆøµÄ×ÜÖÊÁ¿ÊÇ48.4212 g¡£¿ÕÆøµÄƽ¾ùÏà¶Ô·Ö×ÓÖÊÁ¿Îª29¡£A¡¢B¡¢C¡¢D¡¢E¡¢FÊÇÖÐѧ³£¼ûµÄÆøÌå¡£
(1)ÉÏÊöÁùÖÖÆøÌåÖУ¬Äܹ»Ê¹Æ·ºìÈÜÒºÍÊÉ«µÄÊÇ(д»¯Ñ§Ê½)________________¡£
(2)EµÄÏà¶Ô·Ö×ÓÖÊÁ¿ÊÇ________¡£
(3)ʵÑéÊÒÖÆÈ¡ÉÙÁ¿DµÄ»¯Ñ§·½³ÌʽÊÇ______________________________¡£
(4)A¡¢B¡¢C¿ÉÄܵĻ¯Ñ§Ê½ÊÇ______________________________________________¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ÆøÌå | A | B | C | D | E | F |
ÉÕÆ¿ºÍÆøÌåµÄ×ÜÖÊÁ¿/g | 48.4082 | 48.4082 | 48.4082 | 48.3822 | 48.4342 | 48.8762 |
ÒÑÖª±ê×¼×´¿öÏ£¬ÉÕÆ¿µÄÈÝ»ýΪ0.293 L£¬ÉÕÆ¿ºÍ¿ÕÆøµÄ×ÜÖÊÁ¿ÊÇ48.4212 g¡£¿ÕÆøµÄƽ¾ùÏà¶Ô·Ö×ÓÖÊÁ¿Îª29¡£A¡¢B¡¢C¡¢D¡¢E¡¢FÊÇÖÐѧ³£¼ûµÄÆøÌå¡£
(1)ÉÏÊöÁùÖÖÆøÌåÖУ¬Äܹ»Ê¹Æ·ºìÈÜÒºÍÊÉ«µÄÊÇ(д»¯Ñ§Ê½)________________¡£
(2)EµÄÏà¶Ô·Ö×ÓÖÊÁ¿ÊÇ_________¡£
(3)ʵÑéÊÒÖÆÈ¡ÉÙÁ¿DµÄ»¯Ñ§·½³ÌʽÊÇ________________________________________¡£
(4)A¡¢B¡¢C¿ÉÄܵĻ¯Ñ§Ê½ÊÇ________________¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ijУ»¯Ñ§Ð¡×éѧÉú½øÐС°ÆøÌåÏà¶Ô·Ö×ÓÖÊÁ¿µÄ²â¶¨¡±µÄʵÑé¡£²Ù×÷ÈçÏ£ºÓÃÖÊÁ¿ºÍÈÝ»ý¶¼ÏàµÈµÄÉÕÆ¿ÊÕ¼¯ÆøÌ壬³ÆÁ¿ÊÕ¼¯ÂúÆøÌåµÄÉÕÆ¿ÖÊÁ¿¡£Êý¾Ý¼ûϱí(ÒÑ»»Ëã³É±ê×¼×´¿öϵÄÊýÖµ)¡£?
ÆøÌå | A | B | C | D | E | F |
ÉÕÆ¿ºÍÆøÌåµÄ×ÜÖÊÁ¿/g | 48.4082 | 48.408 2 | 48.4082 | 48.3822 | 48.4342 | 48.8762 |
ÒÑÖª±ê×¼×´¿öÏ£¬ÉÕÆ¿µÄÈÝ»ýΪ0.293 L£¬ÉÕÆ¿ºÍ¿ÕÆøµÄ×ÜÖÊÁ¿ÊÇ48.4212 g¡£¿ÕÆøµÄƽ¾ùÏà¶Ô·Ö×ÓÖÊÁ¿Îª29¡£A¡¢B¡¢C¡¢D¡¢E¡¢FÊÇÖÐѧ³£¼ûµÄÆøÌå¡£?
(1)ÉÏÊöÁùÖÖÆøÌåÖУ¬Äܹ»Ê¹Æ·ºìÈÜÒºÍÊÉ«µÄÊÇ(д»¯Ñ§Ê½)_______________¡£
(2)EµÄÏà¶Ô·Ö×ÓÖÊÁ¿ÊÇ____________¡£
(3)ʵÑéÊÒÖÆÈ¡ÉÙÁ¿DµÄ»¯Ñ§·½³ÌʽÊÇ____________________________________¡£
(4)A¡¢B¡¢C¿ÉÄܵĻ¯Ñ§Ê½ÊÇ__________________________________________________¡£
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com