£¨8·Ö£©ÒÑÖªCa(OH)2ÓëCl2·´Ó¦µÄÑõ»¯²úÎïÓëζÈÓйأ¬ÔÚÒ»¶¨Á¿µÄʯ»ÒÈéÖÐͨÈëÒ»¶¨Á¿µÄÂÈÆø£¬¶þÕßÇ¡ºÃÍêÈ«·´Ó¦£¨·¢ÉúµÄ·´Ó¦¾ùΪ·ÅÈÈ·´Ó¦£©¡£Éú³ÉÎïÖк¬ÓÐCl¡ª¡¢ClO¡ª¡¢ClO3¡ªÈýÖÖº¬ÂÈÔªËصÄÀë×Ó£¬ÆäÖÐClO¡ª¡¢ClO3¡ªÁ½ÖÖÀë×ÓµÄÎïÖʵÄÁ¿£¨n£©Ó뷴Ӧʱ¼ä£¨t£©µÄÇúÏßÈçͼËùʾ¡£

£¨1£©t1Ç°£¬Ñõ»¯²úÎïÊÇ________£¨Ìѧʽ£©¡£
£¨2£©t2ʱ£¬Ca(OH)2ÓëCl2·¢Éú·´Ó¦µÄ×ܵÄÀë×Ó·½³ÌʽΪ£º                                  ¡£
£¨3£©¸Ãʯ»ÒÈéÖк¬ÓÐCa£¨OH£©2µÄÎïÖʵÄÁ¿ÊÇ       mol¡£
£¨4£©NaClO2½ÏÎȶ¨£¬µ«¼ÓÈÈ»òÇû÷ÑÇÂÈËáÄƹÌÌåʱÁ¢¼´±¬Õ¨£¬Æ䱬ըºóµÄ²úÎï¿ÉÄÜÊÇ       ¡£

A£®NaCl¡¢Cl2B£®NaCl¡¢NaClOC£®NaClO3¡¢NaClO4D£®NaCl¡¢NaClO3

£¨1£©Ca(ClO)2  £¨2£©5Ca(OH)2+5Cl2=5Ca2++7Cl-+2ClO-+ClO3¡ª+5H2O £¨3£©5 £¨4£©D

½âÎö

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2013½ì½­Î÷Ê¡½­Î÷ʦ´ó¸½ÖС¢ÁÙ´¨Ò»ÖиßÈý12ÔÂÁª¿¼»¯Ñ§ÊÔ¾í£¨´ø½âÎö£© ÌâÐÍ£ºÌî¿ÕÌâ

£¨7·Ö£©ÒÑÖªCa(OH)2ÓëCl2·´Ó¦µÄÑõ»¯²úÎïÓëζÈÓйأ¬ÔÚÒ»¶¨Á¿µÄʯ»ÒÈéÖÐͨÈëÒ»¶¨Á¿µÄÂÈÆø£¬¶þÕßÇ¡ºÃÍêÈ«·´Ó¦(·¢ÉúµÄ·´Ó¦¾ùΪ·ÅÈÈ·´Ó¦)¡£Éú³ÉÎïÖк¬ÓÐCl¡¢ClO¡¢£»ÈýÖÖº¬ÂÈÔªËصÄÀë×Ó£¬ÆäÖÐC1O¡¢Á½ÖÖÀë×ÓµÄÎïÖʵÄÁ¿(n)Ó뷴Ӧʱ¼ä(t)µÄÇúÏßÈçÓÒͼËùʾ¡£

£¨1£©t1Ç°£¬Ñõ»¯²úÎïÊÇ         (Ìѧʽ)¡£
(2)t2ʱ£¬Ca(OH)2ÓëCl2·¢Éú·´Ó¦µÄ×ܵÄÀë×Ó·½³ÌʽΪ£º                         
(3)¸Ãʯ»ÒÈéÖк¬ÓÐCa(OH)2µÄÎïÖʵÄÁ¿ÊÇ                   mol
(4)NaClO2½ÏÎȶ¨£¬µ«¼ÓÈÈ»òÇû÷ÑÇÂÈËáÄƹÌÌåʱÁ¢¼´±¬Õ¨£¬Æ䱬ըºóµÄ²úÎï¿ÉÄÜÊÇ  (Ìî×Öĸ)¡£

A£®NaCl¡¢Cl2B£®NaCl¡¢NaClO
C£®NaClO3¡¢NaClO4D£®NaCl¡¢NaClO3
(5)ÅäƽÏÂÁÐÀë×Ó·½³Ìʽ£º  Fe(OH)3+   ClO+   OH¡ª¡ª¡ª¡ª    
         

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2013-2014ѧÄêËÄ´¨Ê¡¸ßÈý¡°Áª²â´Ù¸Ä¡±»î¶¯Àí×Û»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÊµÑéÌâ

ijÑо¿ÐÔѧϰС×é¶Ô»¹Ô­Ìú·ÛÓëË®ÕôÆøµÄ·´Ó¦²úÎï½øÐпÆѧ̽¾¿¡£ÒÑÖªCa(OH)2µÄ·Ö½âζÈΪ580¡æ£¬Ìú·ÛÓëË®ÕôÆø·´Ó¦µÄζÈΪ900¡æ£º¸ù¾ÝÏÂͼËùʾʵÑé×°Ö㬽øÐÐÁË»¹Ô­Ìú·ÛÓëË®ÕôÆøµÄ·´Ó¦ÊµÑ飬ʵÑéÖй۲쵽·ÊÔíÒºÖвúÉúÁË´óÁ¿µÄÆøÅÝ¡£

£¨1£©ÊµÑéÖÐCa(OH)2µÄ×÷ÓÃÊÇ             ¡£ÊµÑéÖвúÉúµÄÆøÌå²úÎïÊÇ        ¡£

£¨2£©Îª½øÒ»²½Ì½¾¿»¹Ô­Ìú·ÛÓëË®ÕôÆø·´Ó¦¹ÌÌå²úÎïµÄ³É·Ö£¬Ñо¿ÐÔѧϰС×齫·´Ó¦ºóµÄ¹ÌÌå¾­´¦ÀíºóµÃµ½ºÚÉ«Ñõ»¯Îï¹ÌÌ壬Õë¶ÔºÚÉ«Ñõ»¯Îï¹ÌÌ壬¸ÃС×éÌá³öÈçϵļÙÉè²¢½øÐÐÁËÏà¹ØµÄʵÑ飺

¼ÙÉèÒ»£º¹ÌÌåΪFeO

¼ÙÉè¶þ£º¹ÌÌåΪFe3O4

¼ÙÉèÈý£º                       

¢ÙÏÞÑ¡ÓÃÏÂÁÐÊÔ¼Á£ºÑÎËá¡¢KSCNÈÜÒº¡¢K3Fe(CN)6 ÈÜÒº¡¢ÂÈË®£¬Ö¤Ã÷¼ÙÉèÒ»²»³ÉÁ¢

²Ù×÷

ÏÖÏó

½áÂÛ

 

 

¼ÙÉèÒ»²»³ÉÁ¢

 

¢ÚΪÁ˽øÒ»²½È·¶¨²úÎïµÄ³É·Ö£¬ÓúÚÉ«¹ÌÌå½øÐÐÁËÏÂÁÐʵÑé:

¼ÓÈë×ãÁ¿ÂÈË®Ëù·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ                          £»¼ìÑéºìºÖÉ«¹ÌÌåÊÇ·ñÏ´µÓ¸É¾»µÄ²Ù×÷ÊÇ                                             £»×ÆÉÕʱʢ·Å¹ÌÌåµÄÒÇÆ÷ÊÇ          £»Èô¼ÙÉè¶þ³ÉÁ¢£¬ºÚÉ«¹ÌÌå×îÖÕÈ«²¿×ª»¯³ÉµÄºì×ØÉ«·ÛÄ©µÄÖÊÁ¿ÊÇ     g

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012-2013ѧÄê½­Î÷Ê¡¡¢ÁÙ´¨Ò»ÖиßÈý12ÔÂÁª¿¼»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ

£¨7·Ö£©ÒÑÖªCa(OH)2ÓëCl2·´Ó¦µÄÑõ»¯²úÎïÓëζÈÓйأ¬ÔÚÒ»¶¨Á¿µÄʯ»ÒÈéÖÐͨÈëÒ»¶¨Á¿µÄÂÈÆø£¬¶þÕßÇ¡ºÃÍêÈ«·´Ó¦(·¢ÉúµÄ·´Ó¦¾ùΪ·ÅÈÈ·´Ó¦)¡£Éú³ÉÎïÖк¬ÓÐCl¡¢ClO¡¢£»ÈýÖÖº¬ÂÈÔªËصÄÀë×Ó£¬ÆäÖÐC1O¡¢Á½ÖÖÀë×ÓµÄÎïÖʵÄÁ¿(n)Ó뷴Ӧʱ¼ä(t)µÄÇúÏßÈçÓÒͼËùʾ¡£

£¨1£©t1Ç°£¬Ñõ»¯²úÎïÊÇ          (Ìѧʽ)¡£

(2)t2ʱ£¬Ca(OH)2ÓëCl2·¢Éú·´Ó¦µÄ×ܵÄÀë×Ó·½³ÌʽΪ£º                         

(3)¸Ãʯ»ÒÈéÖк¬ÓÐCa(OH)2µÄÎïÖʵÄÁ¿ÊÇ                    mol

(4)NaClO2½ÏÎȶ¨£¬µ«¼ÓÈÈ»òÇû÷ÑÇÂÈËáÄƹÌÌåʱÁ¢¼´±¬Õ¨£¬Æ䱬ըºóµÄ²úÎï¿ÉÄÜÊÇ   (Ìî×Öĸ)¡£

A£®NaCl¡¢Cl2                              B£®NaCl¡¢NaClO

C£®NaClO3¡¢NaClO4                          D£®NaCl¡¢NaClO3

(5)ÅäƽÏÂÁÐÀë×Ó·½³Ìʽ£º   Fe(OH)3+    ClO+    OH¡ª¡ª¡ª¡ª    

          

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012-2013ѧÄê°²»ÕÊ¡¸ßÈýµÚÒ»´ÎÔ¿¼»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ

£¨8·Ö£©ÒÑÖªCa(OH)2ÓëCl2·´Ó¦µÄÑõ»¯²úÎïÓëζÈÓйأ¬ÔÚÒ»¶¨Á¿µÄʯ»ÒÈéÖÐͨÈëÒ»¶¨Á¿µÄÂÈÆø£¬¶þÕßÇ¡ºÃÍêÈ«·´Ó¦£¨·¢ÉúµÄ·´Ó¦¾ùΪ·ÅÈÈ·´Ó¦£©¡£Éú³ÉÎïÖк¬ÓÐCl¡ª¡¢ClO¡ª¡¢ClO3¡ªÈýÖÖº¬ÂÈÔªËصÄÀë×Ó£¬ÆäÖÐClO¡ª¡¢ClO3¡ªÁ½ÖÖÀë×ÓµÄÎïÖʵÄÁ¿£¨n£©Ó뷴Ӧʱ¼ä£¨t£©µÄÇúÏßÈçͼËùʾ¡£

£¨1£©t1Ç°£¬Ñõ»¯²úÎïÊÇ________£¨Ìѧʽ£©¡£

£¨2£©t2ʱ£¬Ca(OH)2ÓëCl2·¢Éú·´Ó¦µÄ×ܵÄÀë×Ó·½³ÌʽΪ£º                                   ¡£

£¨3£©¸Ãʯ»ÒÈéÖк¬ÓÐCa£¨OH£©2µÄÎïÖʵÄÁ¿ÊÇ        mol¡£

£¨4£©NaClO2½ÏÎȶ¨£¬µ«¼ÓÈÈ»òÇû÷ÑÇÂÈËáÄƹÌÌåʱÁ¢¼´±¬Õ¨£¬Æ䱬ըºóµÄ²úÎï¿ÉÄÜÊÇ        ¡£

A£®NaCl¡¢Cl2    B£® NaCl¡¢NaClO    C£®NaClO3¡¢NaClO4    D£® NaCl¡¢NaClO3

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸