(8·Ö)ÈçͼËùʾ£¬ÔÚÒ»ÌõÓ㡢Ϻ¼¸ºõ¾ø¼£µÄºÓ±ß£¬´ÓÉÏÓε½ÏÂÓÎÒÀ´ÎÓмס¢ÒÒ¡¢±û¡¢¶¡ËÄ×ù¹¤³§£¬¸÷³§ÅŷŵķÏË®Àﶼֻº¬ÓÐNa2CO3¡¢FeCl3¡¢Ca(OH)2¡¢HClÖеÄÒ»ÖÖ¡£Ä³ÖÐѧ»·±£Ð¡×é¶ÔºÓË®¼ì²âʱ·¢ÏÖ£º¢Ù¼×´¦ºÓË®³ÊÈé°×É«£»¢ÚÒÒ´¦ºÓË®³ÊºìºÖÉ«£»¢Û±û´¦ºÓË®ÓÉ»ë±äÇ壻¢Ü¶¡´¦²úÉúÆøÅÝ£¬ºÓË®ÈÔ³ÎÇå¡£Çë»Ø´ð£º

£¨1£©ËÄ×ù¹¤³§ÅųöµÄ·ÏË®ÀﺬÓеÄÎÛȾÎï·Ö±ðΪ£º

      ¼×£º             ÒÒ£º              ±û£º              ¶¡£º            £¨Ìѧʽ£©

£¨2£©ÔÚ¶¡µÄÏÂÓÎM´¦È¡³öµÄºÓË®ÖУ¬¿Ï¶¨º¬ÓеÄÀë×ÓÊÇ                               ¡£

£¨3£©Ð´³öÓйط´Ó¦µÄÀë×Ó·½³Ìʽ£º                                                     

                                                                               ¡£

 

 

£¨1£©¼×£ºCa(OH)2                            ÒÒ£ºFeCl3             ±û£ºHCl        ¶¡£ºNa2CO3

£¨2£©Na+¡¢Cl£­¡¢Fe3+¡¢Ca2+

£¨3£©Fe3+£«3OH£­====Fe(OH)3¡ý       Fe(OH)3+3H+====Fe3+£«3H2O

  2H+£«CO====H2O£«CO2¡ü

½âÎö:

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2014½ìºÚÁú½­Ê¡¸ß¶þÉÏѧÆÚÆÚ³õ¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ

(8·Ö)ÓÐA¡¢B¡¢C¡¢DËÄÖÖ¶ÌÖÜÆÚÔªËØ£¬ÆäÔ­×ÓÐòÊýÒÀ´ÎÔö´ó¡£A¡¢B¿ÉÐγÉA2BºÍA2B2Á½ÖÖ»¯ºÏÎB¡¢CͬÖ÷×åÇÒ¿ÉÐγÉCB2ºÍCB3Á½ÖÖ»¯ºÏÎï¡£»Ø´ðÏÂÁÐÎÊÌâ¡£

(1)A2B2µÄµç×ÓʽΪ____________¡£

(2)CB2ͨÈëA2B2ÈÜÒºÖпɱ»Ñõ»¯ÎªW£¬ÓÃWµÄÈÜÒº(Ìå»ýΪ1 L£¬¼ÙÉè±ä»¯Ç°ºóÈÜÒºÌå»ý±ä»¯ºöÂÔ²»¼Æ)×é×°³ÉÔ­µç³Ø(ÈçͼËùʾ)¡£

ÔÚbµç¼«ÉÏ·¢ÉúµÄ·´Ó¦¿É±íʾΪ£ºPbO2£«4H£«£«SO£«2e£­£½PbSO4£«2H2O£¬ÔòÔÚaµç¼«ÉÏ·¢ÉúµÄ·´Ó¦¿É±íʾΪ_________________¡£Èôµç³Ø¹¤×÷Ò»¶Îʱ¼äºó£¬a¼«ÏûºÄ0.05 mol Pb£¬ÔòWµÄŨ¶ÈÓÉÖÊÁ¿·ÖÊý39 % (ÃܶÈ1.3 g / cm3)±äΪ______mol /L¡£

(3)½ðÊôÔªËØEÊÇÖÐѧ»¯Ñ§³£¼ûÔªËØ£¬Î»ÓÚÔªËØÖÜÆÚ±íµÄµÚËÄÖÜÆÚ¡£¸ÃÔªËØ¿ÉÓëDÐγÉED2ºÍED3Á½ÖÖ»¯ºÏÎï¡£½«EµÄµ¥ÖʽþÈëED3ÈÜÒºÖÐ(ÈçÏÂͼ¼×Ëùʾ)£¬ÈÜÒºÓÉ»ÆÉ«Öð½¥±äΪdzÂÌÉ«£¬¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽΪ____________________________________¡£

 (4)ÒÀ¾Ý(3)Öеķ´Ó¦£¬¿ÉÓõ¥ÖÊEºÍʯīΪµç¼«Éè¼ÆÒ»¸öÔ­µç³Ø£¨Í¼ÒÒ£©£¬ÔòÔÚ¸ÃÔ­µç³Ø¹¤×÷ʱ£¬Ê¯Ä«Ò»¼«·¢ÉúµÄ·´Ó¦¿ÉÒÔ±íʾΪ______________________________¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄêÕã½­Ê¡Í©ÏçÊиßÈýÉÏѧÆÚ10Ô·ÝÔ¿¼»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÊµÑéÌâ

£¨±¾Ìâ8·Ö£©ÈçͼËùʾ£¬½«¼×¡¢ÒÒÁ½¸ö×°Óв»Í¬ÎïÖʵÄÕëͲÓõ¼¹ÜÁ¬½ÓÆðÀ´£¬½«ÒÒÕëͲÄÚµÄÎïÖÊѹµ½¼×ÕëͲÄÚ£¬½øÐÐϱíËùÁеIJ»ËÅʵÑ飨ÆøÌåÔÚͬÎÂͬѹϲⶨ£©¡£

ÊԻشðÏÂÁÐÎÊÌ⣺

£¨1£©ÊµÑé1ÖУ¬³Áµí×îÖÕ±äΪ£º            É«£¬Ð´³ö³Áµí±äÉ«µÄ»¯Ñ§·½³Ìʽ         ¡£

£¨2£©ÊµÑé2ÖУ¬ÒÑÖª£º3Cl2+2NH3=N2+6HCl¡£¼×ÕëͲ³ý»îÈûÓÐÒƶ¯, ÕëͲÄÚÓа×Ñ̲úÉúÍ⣬ÆøÌåµÄÑÕÉ«±ä»¯Îª      £¬×îºóÁ½¸öÕëͲÖй²Ê£ÓàÆøÌåµÄÌå»ýԼΪ      mL¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨±¾Ìâ8·Ö£©ÈçͼËùʾ£¬½«¼×¡¢ÒÒÁ½¸ö×°Óв»Í¬ÎïÖʵÄÕëͲÓõ¼¹ÜÁ¬½ÓÆðÀ´£¬½«ÒÒÕëͲÄÚµÄÎïÖÊѹµ½¼×ÕëͲÄÚ£¬½øÐÐϱíËùÁеIJ»ËÅʵÑ飨ÆøÌåÔÚͬÎÂͬѹϲⶨ£©¡£

ÊԻشðÏÂÁÐÎÊÌ⣺

£¨1£©ÊµÑé1ÖУ¬³Áµí×îÖÕ±äΪ£º           É«£¬Ð´³ö³Áµí±äÉ«µÄ»¯Ñ§·½³Ìʽ         ¡£

£¨2£©ÊµÑé2ÖУ¬ÒÑÖª£º3Cl2+2NH3=N2+6HCl¡£¼×ÕëͲ³ý»îÈûÓÐÒƶ¯, ÕëͲÄÚÓа×Ñ̲úÉúÍ⣬ÆøÌåµÄÑÕÉ«±ä»¯Îª     £¬×îºóÁ½¸öÕëͲÖй²Ê£ÓàÆøÌåµÄÌå»ýԼΪ      mL¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012½ìÕã½­Ê¡Í©ÏçÊи߼¶ÖÐѧ¸ßÈýÉÏѧÆÚ10Ô·ÝÔ¿¼»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÊµÑéÌâ

£¨±¾Ìâ8·Ö£©ÈçͼËùʾ£¬½«¼×¡¢ÒÒÁ½¸ö×°Óв»Í¬ÎïÖʵÄÕëͲÓõ¼¹ÜÁ¬½ÓÆðÀ´£¬½«ÒÒÕëͲÄÚµÄÎïÖÊѹµ½¼×ÕëͲÄÚ£¬½øÐÐϱíËùÁеIJ»ËÅʵÑ飨ÆøÌåÔÚͬÎÂͬѹϲⶨ£©¡£

ÊԻشðÏÂÁÐÎÊÌ⣺

£¨1£©ÊµÑé1ÖУ¬³Áµí×îÖÕ±äΪ£º           É«£¬Ð´³ö³Áµí±äÉ«µÄ»¯Ñ§·½³Ìʽ        ¡£
£¨2£©ÊµÑé2ÖУ¬ÒÑÖª£º3Cl2+2NH3=N2+6HCl¡£¼×ÕëͲ³ý»îÈûÓÐÒƶ¯, ÕëͲÄÚÓа×Ñ̲úÉúÍ⣬ÆøÌåµÄÑÕÉ«±ä»¯Îª     £¬×îºóÁ½¸öÕëͲÖй²Ê£ÓàÆøÌåµÄÌå»ýԼΪ     mL¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸