ÓÐX¡¢Y¡¢ZÈýÖÖ³£¼ûÔªËØ£¬ÒÑÖª£º¢ÙX2£­¡¢Y£­¾ùÓëYµÄÆø̬Ç⻯Îï·Ö×Ó¾ßÓÐÏàͬµÄµç×ÓÊý£»¢ÚZÓëY¿É×é³É»¯ºÏÎïZY3£¬ZY3ÈÜÒºÓö±½·Ó³Ê×ÏÉ«¡£Çë»Ø´ð£º

£¨1£©YµÄ×î¸ß¼ÛÑõ»¯Îï¶ÔӦˮ»¯ÎïµÄ»¯Ñ§Ê½ÊÇ                  ¡£w.w.^w.k.&s.5*u.c.#om

£¨2£©½«ZY3ÈÜÒºµÎÈë·ÐË®¿ÉµÃºìºÖÉ«ÒºÌ壬

·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ                                                     £¬

´ËÒºÌå¾ßÓеÄÐÔÖÊÊÇ                   £¨ÌîдÐòºÅ×Öĸ£©¡£

a£®¹âÊøͨ¹ý¸ÃÒºÌåʱÐγɹâÁÁµÄ¡°Í¨Â·¡± w.w.^w.k.&s.5*u.c.#om

b£®²åÈëµç¼«Í¨Ö±Á÷µçºó£¬ÓÐÒ»¼«¸½½üÒºÌåÑÕÉ«¼ÓÉî

c£®Ïò¸ÃÒºÌåÖмÓÈëÏõËáÒøÈÜÒº£¬ÎÞ³Áµí²úÉúw.w.^w.k.&s.5*u.c.#om

d£®½«¸ÃÒºÌå¼ÓÈÈ¡¢Õô¸É¡¢×ÆÉÕºó£¬ÓÐÑõ»¯ÎïÉú³É

£¨3£©Xµ¥ÖÊÔÚ¿ÕÆøÖÐȼÉÕÉú³ÉÒ»ÖÖÎÞÉ«Óд̼¤ÐÔÆøζµÄÆøÌå¡£

¢ÙÒÑÖªÒ»¶¨Ìõ¼þÏ£¬Ã¿1mol¸ÃÆøÌå±»O2Ñõ»¯·ÅÈÈ98.0kJ¡£Èô2mol ¸ÃÆøÌåÓë1mol O2ÔÚ´ËÌõ¼þÏ·¢Éú·´Ó¦£¬´ïµ½Æ½ºâʱ·Å³öµÄÈÈÁ¿ÊÇ176.4kJ£¬Ôò¸ÃÆøÌåµÄת»¯ÂÊΪ              ¡£

¢Ú¸ÃÎÞÉ«Óд̼¤ÐÔÆøζµÄÆøÌåÓ뺬1.5molYµÄÒ»ÖÖº¬ÑõËᣨ¸ÃËáµÄijÑγ£ÓÃÓÚʵÑéÊÒÖÆÈ¡ÑõÆø£©µÄÈÜÒºÔÚÒ»¶¨Ìõ¼þÏ·´Ó¦£¬¿ÉÉú³ÉÒ»ÖÖÇ¿ËáºÍÒ»ÖÖÑõ»¯ÎÈôÓÐ1.5¡Á6.02¡Á1023¸öµç×ÓתÒÆʱ£¬Ð´³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ£¬²¢Óõ¥ÏßÇűê³öµç×ÓתÒƵķ½ÏòºÍÊýÄ¿

                                                   ¡£

£¨1£©HClO4£¨1·Ö£©

£¨2£©Fe3++3H2OFe(OH)3(½ºÌå)+3H+£¨2·Ö£©  abd£¨3·Ö£©

£¨3£©¢Ù90% £¨1·Ö£©     ¢Ú S O2+2HClO3==H2SO4+2ClO2£¨3·Ö£©


½âÎö:
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2007?µÂÑôÄ£Ä⣩ÓРX¡¢Y¡¢Z ÈýÖÖ³£¼ûÔªËØ£®ÒÑÖª£ºX2Ò»¡¢YÒ»¾ùÓë Y µÄÆø̬Ç⻯Îï·Ö×Ó¾ßÓÐÏàͬµÄµç×ÓÊý£» Y Ô­×ӵĵç×Ó²ãÊýΪ n£¬×îÍâ²ãµç×ÓÊýΪ 2n+1£¬Ô­×ÓºËÄÚÖÊ×ÓÊýΪ2n2-1£» ZÓë Y ¿ÉÐγɻ¯ºÏÎï ZY3£®Çë»Ø´ð£º
£¨1£©Y ÔªËØÔÚÖÜÆÚ±íÖеÄλÖÃÊÇ
µÚÈýÖÜÆÚµÚ¢÷A×å
µÚÈýÖÜÆÚµÚ¢÷A×å
X2һˮ½âµÄÀë×Ó·½³ÌʽÊÇ
S2-+H2O?HS-+OH-
S2-+H2O?HS-+OH-
£®
£¨2£©½« ZY3 ÈÜÒºµÎÈë·ÐË®¿ÉµÃºìºÖÉ«ÒºÌ壬¹âÊøͨ¹ý¸ÃÒºÌåʱÐγɹâÁÁµÄ¡°Í¨Â·¡±£¬Ôò¸ÃÒºÌå²åÈëµç¼«Í¨ÒÔÖ±Á÷µçºó£¬ÓëµçÔ´
¸º
¸º
£¨Ìî¡°Õý¡±»ò¡°¸º¡±£©¼«ÏàÁ¬µÄÒ»¼«¸½½üÒºÌåÑÕÉ«¼ÓÉZY3ÈÜÒºµÎÈë·ÐË®Öз´Ó¦µÄÀë×Ó·½³ÌʽÊÇ
Fe3++3H2O
  ¡÷  
.
 
Fe£¨OH£©3£¨½ºÌ壩+3H+
Fe3++3H2O
  ¡÷  
.
 
Fe£¨OH£©3£¨½ºÌ壩+3H+
£®
£¨3£©Èô½«22.4g Í­ºÍZ 2O3µÄ»ìºÏÎï·ÛÄ©¼ÓÈëµ½¹ýÁ¿µÄ l mol?L-1H2SO4ÖУ¬Ê¹Ö®³ä·Ö·´Ó¦£®Éè·´Ó¦ºóÈÜÒºÌå»ýΪ 1 L£¬²¢²âµÃ´ËÈÜÒºÖÐZ2+µÄŨ¶ÈΪ 0.1mol?L-1£¬ÔòÔ­»ìºÏÎïÖк¬ÓÐÍ­µÄÖÊÁ¿ÊÇ
3.2g»ò14.4g
3.2g»ò14.4g
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÓÐX¡¢Y¡¢ZÈýÖÖ³£¼ûÔªËØ£¬ÒÑÖª£º¢ÙX2£­¡¢Y£­¾ùÓëYµÄÆø̬Ç⻯Îï·Ö×Ó¾ßÓÐÏàͬµÄµç×ÓÊý£»¢ÚZÓëY¿É×é³É»¯ºÏÎïZY3£¬ZY3ÈÜÒºÓö±½·Ó³Ê×ÏÉ«¡£Çë»Ø´ð£º

¢ÅYµÄ×î¸ß¼ÛÑõ»¯Îï¶ÔӦˮ»¯ÎïµÄ»¯Ñ§Ê½ÊÇ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡ ¡£

¢Æ½«ZY3ÈÜÒºµÎÈë·ÐË®¿ÉµÃºìºÖÉ«ÒºÌ壬

·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡ £¬

´ËÒºÌå¾ßÓеÄÐÔÖÊÊÇ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡ £¨ÌîдÐòºÅ×Öĸ£©¡£

a£®¹âÊøͨ¹ý¸ÃÒºÌåʱÐγɹâÁÁµÄ¡°Í¨Â·¡±

b£®²åÈëµç¼«Í¨Ö±Á÷µçºó£¬ÓÐÒ»¼«¸½½üÒºÌåÑÕÉ«¼ÓÉî

c£®Ïò¸ÃÒºÌåÖмÓÈëÏõËáÒøÈÜÒº£¬ÎÞ³Áµí²úÉú

d£®½«¸ÃÒºÌå¼ÓÈÈ¡¢Õô¸É¡¢×ÆÉÕºó£¬ÓÐÑõ»¯ÎïÉú³É

¢ÇXµ¥ÖÊÔÚ¿ÕÆøÖÐȼÉÕÉú³ÉÒ»ÖÖÎÞÉ«Óд̼¤ÐÔÆøζµÄÆøÌå¡£

¢ÙÒÑÖªÒ»¶¨Ìõ¼þÏ£¬Ã¿1mol¸ÃÆøÌå±»O2Ñõ»¯·ÅÈÈ98.0kJ¡£Èô2mol ¸ÃÆøÌåÓë1mol O2ÔÚ´ËÌõ¼þÏ·¢Éú·´Ó¦£¬´ïµ½Æ½ºâʱ·Å³öµÄÈÈÁ¿ÊÇ176.4kJ£¬Ôò¸ÃÆøÌåµÄת»¯ÂÊΪ¡¡¡¡¡¡¡¡¡¡¡¡ ¡£

¢Ú¸ÃÎÞÉ«Óд̼¤ÐÔÆøζµÄÆøÌåÓ뺬1.5molYµÄÒ»ÖÖº¬ÑõËᣨ¸ÃËáµÄijÑγ£ÓÃÓÚʵÑéÊÒÖÆÈ¡ÑõÆø£©µÄÈÜÒºÔÚÒ»¶¨Ìõ¼þÏ·´Ó¦£¬¿ÉÉú³ÉÒ»ÖÖÇ¿ËáºÍÒ»ÖÖÑõ»¯ÎÈôÓÐ1.5¡Á6.02¡Á1023¸öµç×ÓתÒÆʱ£¬Ð´³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ£¬²¢Óõ¥ÏßÇűê³öµç×ÓתÒƵķ½ÏòºÍÊýÄ¿

¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡ ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

 ÓÐX¡¢Y¡¢ZÈýÖÖ³£¼ûÔªËØ£¬ÒÑÖª£º¢ÙX2£­¡¢Y£­¾ùÓëYµÄÆø̬Ç⻯Îï·Ö×Ó¾ßÓÐÏàͬµÄµç×ÓÊý£»¢ÚZÓëY¿É×é³É»¯ºÏÎïZY3£¬ZY3ÈÜÒºÓö±½·Ó³Ê×ÏÉ«¡£Çë»Ø´ð£º

¢ÅYµÄ×î¸ß¼ÛÑõ»¯Îï¶ÔӦˮ»¯ÎïµÄ»¯Ñ§Ê½ÊÇ                  ¡£

¢Æ½«ZY3ÈÜÒºµÎÈë·ÐË®¿ÉµÃºìºÖÉ«ÒºÌ壬

·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ                                                    £¬

´ËÒºÌå¾ßÓеÄÐÔÖÊÊÇ                  £¨ÌîдÐòºÅ×Öĸ£©¡£

a£®¹âÊøͨ¹ý¸ÃÒºÌåʱÐγɹâÁÁµÄ¡°Í¨Â·¡±

b£®²åÈëµç¼«Í¨Ö±Á÷µçºó£¬ÓÐÒ»¼«¸½½üÒºÌåÑÕÉ«¼ÓÉî

c£®Ïò¸ÃÒºÌåÖмÓÈëÏõËáÒøÈÜÒº£¬ÎÞ³Áµí²úÉú

d£®½«¸ÃÒºÌå¼ÓÈÈ¡¢Õô¸É¡¢×ÆÉÕºó£¬ÓÐÑõ»¯ÎïÉú³É

¢ÇXµ¥ÖÊÔÚ¿ÕÆøÖÐȼÉÕÉú³ÉÒ»ÖÖÎÞÉ«Óд̼¤ÐÔÆøζµÄÆøÌå¡£

¢ÙÒÑÖªÒ»¶¨Ìõ¼þÏ£¬Ã¿1mol¸ÃÆøÌå±»O2Ñõ»¯·ÅÈÈ98.0kJ¡£Èô2mol ¸ÃÆøÌåÓë1mol O2ÔÚ´ËÌõ¼þÏ·¢Éú·´Ó¦£¬´ïµ½Æ½ºâʱ·Å³öµÄÈÈÁ¿ÊÇ176.4kJ£¬Ôò¸ÃÆøÌåµÄת»¯ÂÊΪ             ¡£

¢Ú¸ÃÎÞÉ«Óд̼¤ÐÔÆøζµÄÆøÌåÓ뺬1.5molYµÄÒ»ÖÖº¬ÑõËᣨ¸ÃËáµÄijÑγ£ÓÃÓÚʵÑéÊÒÖÆÈ¡ÑõÆø£©µÄÈÜÒºÔÚÒ»¶¨Ìõ¼þÏ·´Ó¦£¬¿ÉÉú³ÉÒ»ÖÖÇ¿ËáºÍÒ»ÖÖÑõ»¯ÎÈôÓÐ1.5¡Á6.02¡Á1023¸öµç×ÓתÒÆʱ£¬Ð´³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ£¬²¢Óõ¥ÏßÇűê³öµç×ÓתÒƵķ½ÏòºÍÊýÄ¿

 

                                                  ¡£

 

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£ººÓ±±Ê¡ºâË®ÖÐѧ09-10ѧÄê¸ß¶þµÚ¶þѧÆÚÆÚÖп¼ÊÔ ÌâÐÍ£ºÌî¿ÕÌâ

 ÓÐX¡¢Y¡¢ZÈýÖÖ³£¼ûÔªËØ£¬ÒÑÖª£º¢ÙX2£­¡¢Y£­¾ùÓëYµÄÆø̬Ç⻯Îï·Ö×Ó¾ßÓÐÏàͬµÄµç×ÓÊý£»¢ÚZÓëY¿É×é³É»¯ºÏÎïZY3£¬ZY3ÈÜÒºÓö±½·Ó³Ê×ÏÉ«¡£Çë»Ø´ð£º

¢ÅYµÄ×î¸ß¼ÛÑõ»¯Îï¶ÔӦˮ»¯ÎïµÄ»¯Ñ§Ê½ÊÇ                   ¡£

¢Æ½«ZY3ÈÜÒºµÎÈë·ÐË®¿ÉµÃºìºÖÉ«ÒºÌ壬

·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ                                                     £¬

´ËÒºÌå¾ßÓеÄÐÔÖÊÊÇ                   £¨ÌîдÐòºÅ×Öĸ£©¡£

a£®¹âÊøͨ¹ý¸ÃÒºÌåʱÐγɹâÁÁµÄ¡°Í¨Â·¡±

b£®²åÈëµç¼«Í¨Ö±Á÷µçºó£¬ÓÐÒ»¼«¸½½üÒºÌåÑÕÉ«¼ÓÉî

c£®Ïò¸ÃÒºÌåÖмÓÈëÏõËáÒøÈÜÒº£¬ÎÞ³Áµí²úÉú

d£®½«¸ÃÒºÌå¼ÓÈÈ¡¢Õô¸É¡¢×ÆÉÕºó£¬ÓÐÑõ»¯ÎïÉú³É

¢ÇXµ¥ÖÊÔÚ¿ÕÆøÖÐȼÉÕÉú³ÉÒ»ÖÖÎÞÉ«Óд̼¤ÐÔÆøζµÄÆøÌå¡£

¢ÙÒÑÖªÒ»¶¨Ìõ¼þÏ£¬Ã¿1mol¸ÃÆøÌå±»O2Ñõ»¯·ÅÈÈ98.0kJ¡£Èô2mol ¸ÃÆøÌåÓë1mol O2ÔÚ´ËÌõ¼þÏ·¢Éú·´Ó¦£¬´ïµ½Æ½ºâʱ·Å³öµÄÈÈÁ¿ÊÇ176.4kJ£¬Ôò¸ÃÆøÌåµÄת»¯ÂÊΪ              ¡£

¢Ú¸ÃÎÞÉ«Óд̼¤ÐÔÆøζµÄÆøÌåÓ뺬1.5molYµÄÒ»ÖÖº¬ÑõËᣨ¸ÃËáµÄijÑγ£ÓÃÓÚʵÑéÊÒÖÆÈ¡ÑõÆø£©µÄÈÜÒºÔÚÒ»¶¨Ìõ¼þÏ·´Ó¦£¬¿ÉÉú³ÉÒ»ÖÖÇ¿ËáºÍÒ»ÖÖÑõ»¯ÎÈôÓÐ1.5¡Á6.02¡Á1023¸öµç×ÓתÒÆʱ£¬Ð´³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ£¬²¢Óõ¥ÏßÇűê³öµç×ÓתÒƵķ½ÏòºÍÊýÄ¿

 

                                                   ¡£

 

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸