·ÖÎö £¨1£©¸ù¾ÝÍÔÚÔªËØÖÜÆÚ±íÖеÄλÖÃÀ´Êéд»ù̬Ô×Óµç×ÓÅŲ¼Ê½ºÍÈ·¶¨·ÖÇø£»
£¨2£©Cu2OºÍCu2SͬÊôÓÚÀë×Ó¾§Ì壬Àë×Ó¾§ÌåÈÛµãµÄ¸ßµÍҪͨ¹ý¾§¸ñÄܵĴóСÀ´Åжϣ»
£¨3£©¶ÏÁÑÅäλ¼üºó£¬ÅäÌå±äΪCO£¬ÖÐÐÄÔ×Ó½áºÏ³É½ðÊô¾§Ì壻
£¨4£©ÖÐÐÄÔ×ÓÌṩ¿Õ¹ìµÀ£¬Í¨¹ý¼ÆËãAl¼Û²ãµç×Ó¶ÔÊýÇóÔÓ»¯ÀàÐÍ£»
£¨5£©¸ù¾ÝͼÒÒ¿ÉÍÆËã¶Ñ»ý·½Ê½ÎªABCABC¡£¬¿Éͨ¹ýÇóÿ¸ö¾§°ûµÄÖÊÁ¿ºÍÌå»ý¼ÆËãÃܶȣ»
£¨6£©Õâ5ÖÖÔªËØÐγɵÄÒ»ÖÖ1£º1ÐÍÀë×Ó»¯ºÏÎïÖУ¬ÒõÀë×Ó³ÊËÄÃæÌå½á¹¹£¬ËµÃ÷¸ÃÒõÀë×Ó¼Û²ãµç×Ó¶Ô¸öÊýÊÇ4ÇÒ²»º¬¹Âµç×Ó¶Ô£»ÑôÀë×Ó³ÊÖáÏòÏÁ³¤µÄ°ËÃæÌå½á¹¹£¬¸ù¾Ýͼ֪£¬ÆäÑôÀë×ÓÖÐÍÀë×ÓÅäλÊýÊÇ8£¬ÔÚ°ËÃæÌåÉÏ϶¥µãÉÏ·Ö×Óº¬ÓÐÁ½¸ö¹²¼Û¼üÇÒº¬ÓÐÁ½¸ö¹Âµç×Ó¶Ô£¬ÎªË®·Ö×Ó£¬ÓÐÁ½¸ö£¬Õý·½ÐÎƽÃæÉÏËĸö¶¥µãÉÏ·Ö×Óº¬ÓÐ3¸ö¹²¼Û¼üÇÒº¬ÓÐÒ»¸ö¹Âµç×Ó¶Ô£¬ËùÒÔΪ°±Æø·Ö×Ó£¬ÓÐ4¸ö£»ÑôÀë×ÓÖдæÔÚ¹²¼Û¼üºÍÅäλ¼ü£»H2OºÍCu2+µÄÅäλ¼ü±ÈNH3ÓëCu2+µÄÈõ£¬ËùÒԸû¯ºÏÎï¼ÓÈÈʱÊ×ÏÈʧȥµÄ×é·ÖÊÇH2O£®
½â´ð ½â£º£¨1£©ÍÊÇ29ºÅÔªËØ£¬Î»ÓÚµÚËÄÖÜÆÚ¢ñB×壬ÍâΧµç×ÓÅŲ¼Òª×ñѺéÌعæÔòÌØÀýΪ3d104s1£¬¹Ê´¦ÓÚdsÇø£¬µç×ÓÅŲ¼Îª1s22s22p63s23 p63d104s1»ò[Ar]3d104s1£¬
¹Ê´ð°¸Îª£ºds£»1s22 s22p63 s23 p63d104s1»ò[Ar]3d104s1£»
£¨2£©Cu2OºÍCu2SͬÊôÓÚÀë×Ó¾§Ì壬ÆäÑôÀë×ÓÏàͬ¡¢ÒõÀë×ÓËù´øµÄµçºÉÒ²Ïàͬ£¬ÓÉÓÚÀë×ӵİ뾶СÓÚÁòÀë×ÓµÄÀë×Ӱ뾶£¬ËùÒÔCu2OµÄ¾§¸ñÄÜ´ó£¬ÈÛµã¸ß£¬
¹Ê´ð°¸Îª£ºCu2OÓëCu2SÏà±È½Ï£¬ÆäÑôÀë×ÓÏàͬ¡¢ÒõÀë×ÓËù´øµÄµçºÉÒ²Ïàͬ£¬µ«ÓÉÓÚÑõÀë×ӵİ뾶СÓÚÁòÀë×ÓµÄÀë×Ӱ뾶£¬Cu2OµÄ¾§¸ñÄܸü´ó£¨»òÑÇÍÀë×ÓÓëÑõÀë×ÓÐγɵÄÀë×Ó¼üÇ¿ÓÚÑÇÍÀë×ÓÓëÁòÀë×ÓÐγɵÄÀë×Ó¼ü£©£¬ËùÒÔCu2OµÄÈÛµã±ÈCu2SµÄ¸ß£»
£¨3£©´ËÅäÌåµÄÖÐÐÄÔ×ÓΪ½ðÊôÔ×Ó£¬ÓÉÓÚ¶ÏÁѵÄÊÇÖÐÐÄÔ×ÓºÍÅäÌåÖ®¼äµÄÅäλ¼ü£¬ËùÒÔ¶ÏÁѺóÅäÌåÐγÉCO£¬ÖÐÐÄÔ×Ó¼äÐγɽðÊô¼ü³ÉΪ½ðÊô¾§Ì壬
¹Ê´ð°¸Îª£º½ðÊô¼ü£»
£¨4£©AlCl3•NH3ÖÐAlΪÖÐÐÄÔ×Ó£¬NH3ºÍCl-ΪÅäÌ壬ÖÐÐÄÔ×ÓÌṩ¿Õ¹ìµÀ£¬AlCl4-µÄ¼Û²ãµç×Ó¶Ô=4+$\frac{1}{2}$£¨3+1-4¡Á1£©=4£¬¹ÊAl²ÉÓÃsp3ÔÓ»¯£¬
¹Ê´ð°¸Îª£ºAl£»sp3£»
£¨5£©½áºÏͼÒҺ;§°û½á¹¹¿ÉÖª£¬½ðÊôÂÁÖÐAlµÄ¶Ñ»ý·½Ê½ÎªABCABCABC¡£¬ÊôÓÚÃæÐÄÁ¢·½×îÃܶѻý£¬
ÂÁÔ×Ӱ뾶Ϊd cm£¬Ôò¾§°ûµÄ±ßÉÏΪ2$\sqrt{2}$dcm£¬¾§°ûµÄÌå»ýV=£¨2$\sqrt{2}$dcm£©3=16$\sqrt{2}$d3cm3£¬Ò»¸ö¾§°ûº¬ÓÐAlÔ×Ó¸öÊýΪ£º8¡Á$\frac{1}{8}$+6¡Á$\frac{1}{2}$=4£¬Ò»¸ö¾§°ûµÄÖÊÁ¿m=$\frac{4}{{N}_{A}}$¡ÁMg£¬¹ÊÃܶÈ$¦Ñ=\frac{m}{V}$=$\frac{\frac{4M}{{N}_{A}}}{16\sqrt{2}{d}^{3}}$g/cm3=$\frac{M}{4\sqrt{2}{N}_{A}{d}^{3}}$g/cm3£¬
¹Ê´ð°¸Îª£ºÃæÐÄÁ¢·½×îÃܶѻý£»$\frac{M}{4\sqrt{2}{N}_{A}{d}^{3}}$g/cm3£®
£¨6£©Õâ5ÖÖÔªËØÐγɵÄÒ»ÖÖ1£º1ÐÍÀë×Ó»¯ºÏÎïÖУ¬ÒõÀë×Ó³ÊËÄÃæÌå½á¹¹£¬ËµÃ÷¸ÃÒõÀë×Ó¼Û²ãµç×Ó¶Ô¸öÊýÊÇ4ÇÒ²»º¬¹Âµç×Ó¶Ô£¬Ó¦ÎªSO42-£»
ÑôÀë×Ó³ÊÖáÏòÏÁ³¤µÄ°ËÃæÌå½á¹¹£¨Èçͼ2Ëùʾ£©£¬ÑôÀë×ÓΪCu2+£¬ÅäλÊýÊÇ6£¬ÔÚ°ËÃæÌåÉÏ϶¥µãÉÏ·Ö×Óº¬ÓÐÁ½¸ö¹²¼Û¼üÇÒº¬ÓÐÁ½¸ö¹Âµç×Ó¶Ô£¬ÎªH2O·Ö×Ó£¬ÓÐ2¸ö£¬Õý·½ÐÎƽÃæÉÏËĸö¶¥µãÉÏ·Ö×Óº¬ÓÐ3¸ö¹²¼Û¼üÇÒº¬ÓÐÒ»¸ö¹Âµç×Ó¶Ô£¬ËùÒÔΪNH3·Ö×Ó£¬ÓÐ4¸ö£¬Æ仯ѧʽΪ[Cu£¨NH3£©4£¨H2O£©2]SO4£¬H2OºÍCu2+µÄÅäλ¼ü±ÈNH3ÓëCu2+µÄÈõ£¬ËùÒԸû¯ºÏÎï¼ÓÈÈʱÊ×ÏÈʧȥµÄ×é·ÖÊÇH2O£¬
¹Ê´ð°¸Îª£ºSO42-£»H2O£»H2OºÍCu2+µÄÅäλ¼ü±ÈNH3ÓëCu2+µÄÈõ£®
µãÆÀ ±¾Ì⿼²éÎïÖʽṹºÍÐÔÖÊ£¬²àÖØ¿¼²éѧÉú¿Õ¼äÏëÏóÄÜÁ¦¡¢ÖªÊ¶ÔËÓÃÄÜÁ¦£¬Éæ¼°»ù̬µç×ÓÅŲ¼Ê½¡¢ÈÛµã±È½Ï¡¢¾§°û¼ÆËã¡¢ÅäºÏÎï¡¢Ô×ӽṹµÈ֪ʶµã£¬×ÛºÏÐÔ½ÏÇ¿£¬²ÉÓþù̯·¨¡¢¼Û²ãµç×Ó¶Ô»¥³âÀíÂÛµÈÀíÂÛ·ÖÎö½â´ð£¬ÌâÄ¿ÄѶÈÖеȣ¬×¢Ò⣺Åäλ¼üÒ²ÊôÓÚ¹²¼Û¼ü£®
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
A£® | Ũ¶È¾ùΪ0.1mol/LµÄHCNÈÜÒººÍNaCNÈÜÒºµÈÌå»ý»ìºÏºóÈÜÒº³Ê¼îÐÔc£¨CN-£©£¾c£¨Na+£©£¾c£¨HCN£©£¾c£¨OH-£©£¾c£¨H+£© | |
B£® | pH=aµÄ´×ËáÈÜÒº£¬Ï¡ÊÍ100±¶ºó£¬ÆäpH=b£¬Ôòa+2£¼b | |
C£® | c£¨NH4+£©ÏàͬµÄ¢ÙÂÈ»¯ï§¢ÚÁòËáÇâ梨۴ÎÂÈËá梨Ü̼Ëáï§ËÄÖÖÈÜÒºÖÐpH£º¢Ü£¾¢Ú£¾¢Ù£¾¢Û | |
D£® | pH=5µÄH2SÈÜÒºÖУºc£¨HS-£©£¼c£¨H+£©=1¡Á10-5mol/L |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
A£® | »¯Ñ§·´Ó¦³ýÁËÉú³ÉеÄÎïÖÊÍ⣬»¹°éËæ×ÅÄÜÁ¿µÄ±ä»¯ | |
B£® | ÎïÖʵÄȼÉÕÒ»¶¨ÊÇ·ÅÈÈ·´Ó¦ | |
C£® | ·ÅÈȵĻ¯Ñ§·´Ó¦²»ÐèÒª¼ÓÈȾÍÄÜ·¢Éú | |
D£® | »¯Ñ§ÄÜÓë¹âÄÜÖ®¼ä¿ÉÒÔÏ໥ת»¯ |
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com