ij¶þÔªËᣨH2A£©°´ÏÂʽ·¢ÉúµçÀ룺H2A£½H++HA££»HA£H++A2£¡£ÏÖÓÐÏÂÁÐËÄÖÖÈÜÒº£º
¢Ù 0.01mol?L1µÄH2AÈÜÒº
¢Ú 0.01mol?L1µÄNaHAÈÜÒº
¢Û 0.02mol?L1µÄHClÈÜÒºÓë0.04mol?L1µÄNaHAÈÜÒºµÈÌå»ý»ìºÏ
¢Ü 0.02mol?L1µÄNaOHÈÜÒºÓë0.02mol?L1µÄNaHAÈÜÒºµÈÌå»ý»ìºÏ
ÏÂÁйØÓÚÉÏÊöËÄÖÖÈÜÒºµÄ˵·¨ÕýÈ·µÄÊÇ£¨ £©
A£®ÈÜÒº¢ÚÖдæÔÚË®½âƽºâ£ºHA¨D+H2O H2A+OH¨D
B£®ÈÜÒº¢ÛÖÐÓУºc(HA£)+2c(A2£)=c(Na+)
C£®ÈÜÒº¢ÜÖÐÓУºc(OH£)=c(H+)+c(HA£)
D£®ËÄÖÖÈÜÒºÖÐc(HA£)Ũ¶È´óС£º¢Û£¾¢Ù£¾¢Ú£¾¢Ü
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012-2013ѧÄêºÓ±±Ê¡¸ßÈý3ÔÂÔ¿¼»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ
ij¶þÔªËᣨH2A£©°´ÏÂʽ·¢ÉúµçÀ룺H2A£½H++HA££»HA£H++A2£¡£ÏÖÓÐÏÂÁÐËÄÖÖÈÜÒº£º
¢Ù 0.01mol?L1µÄH2AÈÜÒº
¢Ú 0.01mol?L1µÄNaHAÈÜÒº
¢Û 0.02mol?L1µÄHClÈÜÒºÓë0.04mol?L1µÄNaHAÈÜÒºµÈÌå»ý»ìºÏ
¢Ü 0.02mol?L1µÄNaOHÈÜÒºÓë0.02mol?L1µÄNaHAÈÜÒºµÈÌå»ý»ìºÏ
ÏÂÁйØÓÚÉÏÊöËÄÖÖÈÜÒºµÄ˵·¨ÕýÈ·µÄÊÇ£¨ £©
A£®ÈÜÒº¢ÚÖдæÔÚË®½âƽºâ£ºHA¨D+H2O H2A+OH¨D
B£®ÈÜÒº¢ÛÖÐÓУºc(HA£)+2c(A2£)=c(Na+)
C£®ÈÜÒº¢ÜÖÐÓУºc(OH£)=c(H+)+c(HA£)
D£®ËÄÖÖÈÜÒºÖÐc (HA£)Ũ¶È´óС£º¢Û£¾¢Ù£¾¢Ú£¾¢Ü
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄêÁÉÄþÊ¡¸ßÈýÉÏѧÆÚµÚÈý´ÎÔ¿¼»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÑ¡ÔñÌâ
ij¶þÔªËᣨH2A£©°´ÏÂʽ·¢ÉúµçÀ룺H2A£½H++HA-£»HA-H++A2-¡£ÏÖÓÐÏÂÁÐËÄÖÖÈÜÒº¢Ù0£®0lmol/LµÄH2AÈÜÒº¢Ú0£®0lmol/LµÄNaHAÈÜÒº ¢Û0£®02mol/LµÄHC1ÈÜÒºÓë0£®04mol/LµÄNaHAÈÜÒºµÈÌå»ý»ìºÏ¢Ü0£®02mol/LµÄNaOHÈÜÒºÓë0£®02mol/LµÄNaHAÈÜÒºµÈÌå»ý»ìºÏ
ÏÂÁйØÓÚÉÏÊöËÄÖÖÈÜÒºµÄ˵·¨ÕýÈ·µÄÊÇ £¨ £©
A£®ÈÜÒº¢ÚÖдæÔÚË®½âƽºâ£ºHA-+H2OH2A+OH-
B£®ÈÜÒº¢ÛÖÐÓУºc£¨HA-£©+c£¨A2Ò»£©=c£¨Na+£©
C£®ÈÜÒº¢ÜÖÐÓУºc£¨OHÒ»£©=c£¨H+£© +c£¨HA-£© +2c£¨H2A£©
D£®ËÄÖÖÈÜÒºÖÐc£¨HA-£©Å¨¶È´óС£º¢Û>¢Ú>¢Ù>¢Ü
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010-2011ѧÄêºþÄÏÊ¡¸ßÈýÉÏѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÑ¡ÔñÌâ
ij¶þÔªËᣨH2A£©°´ÏÂʽ·¢ÉúµçÀ룺H2A=H++HA££»HA£H++A2£¡£¹ØÓÚÏÂÁÐËÄÖÖÈÜÒºµÄ˵·¨ÕýÈ·µÄÊÇ
¢Ù0.01mol/LµÄH2AÈÜÒº£»¢Ú0.01mol/LµÄNaHAÈÜÒº£»¢Û0.02mol/LµÄHClÈÜÒºÓë0.04mol/LµÄNaHAÈÜÒºµÈÌå»ý»ìºÏ£»¢Ü0.02mol/LµÄNaOHÈÜÒºÓë0.02mol/LµÄNaHAÈÜÒºµÈÌå»ý»ìºÏ£»
A£®ËÄÖÖÈÜÒºÖÐc(HA£)Ũ¶È´óС£º¢Û£¾¢Ú£¾¢Ù£¾¢Ü
B£®ÈÜÒº¢ÙÖÐÒ»¶¨²»´æÔÚOH£
C£®ÈÜÒº¢ÚÖдæÔÚË®½âƽºâ£ºHA£+H2OH2A+OH£
D£®ÈÜÒº¢ÛÖÐÓйØÀë×ÓŨ¶È¹Øϵ£ºc(HA£)+c(A2£)=c(Na+)
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010ÄêÕã½Ê¡Õ㶫±±ÈýУ¸ß¶þµÚ¶þѧÆÚÆÚÖÐÁª¿¼»¯Ñ§ÊÔÌâ ÌâÐÍ£ºÑ¡ÔñÌâ
ij¶þÔªËᣨH2A£©°´ÏÂʽ·¢ÉúµçÀ룺H2A £½ H++HA££»HA£H++A2£¡£¹ØÓÚÏÂÁÐËÄÖÖÈÜÒºµÄ˵·¨ÕýÈ·µÄÊÇ ( )
¢Ù0.01mol/LµÄH2AÈÜÒº ¢Ú0.01mol/LµÄNaHAÈÜÒº
¢Û0.02mol/LµÄHClÈÜÒºÓë0.04mol/LµÄNaHAÈÜÒºµÈÌå»ý»ìºÏ
¢Ü0.02mol/LµÄNaOHÈÜÒºÓë0.02mol/LµÄNaHAÈÜÒºµÈÌå»ý»ìºÏ
A£®ÈÜÒº¢ÙÖÐÁ£×ÓŨ¶È´óС˳ÐòÊÇ£ºc(H2A)£¾c(H£«)£¾c(HA¡ª)£¾c(A2¡ª)£¾c(OH£)
B£®ÈÜÒº¢ÚÖÐÓйØÀë×ÓŨ¶È¹Øϵ£ºc(HA¡ª)£«2c(A2£)£«c(H2A)£½c(Na+)
C£®ËÄÖÖÈÜÒºÖÐc(HA£)Ũ¶È´óС£º¢Û£¾¢Ù£¾¢Ú£¾¢Ü
D£®ÈÜÒº¢ÛÖÐÓйØÀë×ÓŨ¶È¹Øϵ£ºc(HA£)£«c(A2£)£«c(OH£)=c(Na+)£«c(H£«)
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com