ÔÚÓÒÏÂͼ¾ùÓÃʯī×÷µç¼«µÄµç½â³ØÖУ¬¼×³ØÖÐΪ500mLº¬Ä³Ò»ÈÜÖʵÄÀ¶É«ÈÜÒº£¬ÒÒ³ØÖÐΪ500mLÏ¡ÁòËᣬ±ÕºÏK1£¬¶Ï¿ªK2½øÐеç½â£¬¹Û²ìµ½Aµç¼«±íÃæÓкìÉ«µÄ¹Ì̬ÎïÖÊÉú³É£¬Bµç¼«ÓÐÎÞÉ«ÆøÌåÉú³É£»µ±ÈÜÒºÖеÄÔ­ÓÐÈÜÖÊÍêÈ«µç½âºó£¬Í£Ö¹µç½â£¬È¡³öAµç¼«£¬Ï´µÓ¡¢¸ÉÔï¡¢³ÆÁ¿£¬µç¼«ÔöÖØ6.4g¡£

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©Bµç¼«·¢Éú·´Ó¦µÄµç¼«·´Ó¦Ê½                                        ¡£

     Cµç¼«·¢Éú·´Ó¦µÄµç¼«·´Ó¦Ê½                                       .

£¨2£©¼×³Øµç½âʱ·´Ó¦µÄÀë×Ó·½³Ìʽ                                       ¡£

£¨3£©¼×³Øµç½âºóÈÜÒºµÄc(H+)Ϊ           £¬ÒªÊ¹µç½âºóÈÜÒº»Ö¸´µ½µç½âÇ°µÄ״̬£¬ÔòÐè¼ÓÈë         £¬ÆäÖÊÁ¿Îª         g¡££¨¼ÙÉèµç½âÇ°ºóÈÜÒºµÄÌå»ý²»±ä£©

£¨4£©ÇëÄãÉè¼ÆʵÑéÈ·¶¨¼×³ØÔ­ÈÜÒºÖпÉÄܺ¬ÓеÄËá¸ùÀë×Ó£¬ÒªÇó£ºÌá³öÁ½ÖÖ¿ÉÄܵļÙÉ裬·Ö±ðд³öÂÛÖ¤ÕâÁ½ÖÖ¼ÙÉèµÄ²Ù×÷²½Ö衢ʵÑéÏÖÏóºÍʵÑé½áÂÛ

¢Ù¼ÙÉèÒ»£º                                                 £»

¢Ú¼ÙÉè¶þ£º                                                 ¡£

£¨5£©ÈôÔÙ½«K1¶Ï¿ª£¬±ÕºÏK2£¬ÁéÃôµçÁ÷¼Æ   ÖÐÖ¸ÕëÊÇ·ñ»á·¢Éúƫת£¿ÀíÓÉÊÇʲô£¿

£¨1£©4OH¡ª-4e¡ª     2H2O+O2¡ü    2H++2e¡ª      H2¡ü

£¨2£©2Cu2++2H2O      2Cu+O2¡ü+4H+

£¨3£©0.4mol/L      CuO        8

£¨4£©¢Ù¼ÙÉèÔ­ÈÜÒºÖеÄËá¸ùÀë×ÓΪSO42¡ª¡£È¡µç½âºóµÄÈÜÒº£¬ÏòÆäÖмÓÈëBaCl2ÈÜÒº£¬ÈôÓа×É«³Áµí²úÉú£¬ÔòÔ­ÈÜÒºÖк¬SO42¡ª  ¢Ú¼ÙÉèÔ­ÈÜÒºÖеÄËá¸ùÀë×ÓΪNO3¡ª¡£È¡µç½âºóµÄÈÜÒº£¬ÏòÆäÖмÓÈëCu΢ÈÈ£¬ÈôCuÈܽ⣬²¢ÓÐÎÞÉ«ÆøÌåÉú³É£¬ÔÚ¿ÕÆøÖбäΪºì×ØÉ«£¬Ôòº¬ÓÐNO3¡ª

£¨5£©Æ«×ª   ´ò¿ªK1£¬¹Ø±ÕK2£¬   ÖÐÖ¸Õë»áƫת£¬ÒòÓÖÐγÉH2¡¢O2ȼÁϵç³Ø¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÔÚÈçͼÓÃʯī×÷µç¼«µÄµç½â³ØÖУ¬·ÅÈë500mLº¬Ò»ÖÖÈÜÖʵÄijÀ¶É«ÁòËáÑÎÈÜÒº½øÐеç½â£¬¹Û²ìµ½Aµç¼«±íÃæÓкìÉ«µÄ¹Ì̬ÎïÖÊÉú³É£¬Bµç¼«ÓÐÎÞÉ«ÆøÌåÉú³É£®Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©Çëд³öB¼«°åµÄÃû³Æ£º
Ñô¼«
Ñô¼«
 µç¼«·´Ó¦Ê½
4OH--4e-=2H2O+O2¡ü
4OH--4e-=2H2O+O2¡ü

д³öµç½âʱ·´Ó¦µÄ×ÜÀë×Ó·½³Ìʽ
2Cu2++2H2O
 µç½â 
.
 
2Cu+O2¡ü+4H+
2Cu2++2H2O
 µç½â 
.
 
2Cu+O2¡ü+4H+

£¨2£©Èôµ±ÈÜÒºÖеÄÔ­ÓÐÈÜÖÊÍêÈ«µç½âºó£¬Í£Ö¹µç½â£¬È¡³öAµç¼«£¬Ï´µÓ¡¢¸ÉÔï¡¢³ÆÁ¿¡¢µç¼«ÔöÖØ1.6g£®µç½âºóÈÜÒºµÄpHΪ
PH=1
PH=1
£»ÒªÊ¹µç½âºóÈÜÒº»Ö¸´µ½µç½âÇ°µÄ״̬£¬ÔòÐè¼ÓÈë
CuO
CuO
£¬ÆäÖÊÁ¿Îª
2
2
g£®£¨¼ÙÉèµç½âÇ°ºóÈÜÒºµÄÌå»ý²»±ä£©
£¨3£©ÈôÔ­ÈÜҺΪ1L  K2SO4¡¢CuSO4µÄ»ìºÏÈÜÒº£¬ÇÒc£¨SO42-£©=2.0mol/L£»ÈçͼװÖõç½â£¬µ±Á½¼«¶¼ÊÕ¼¯µ½22.4LÆøÌ壨±ê×¼×´¿ö£©Ê±£¬Í£Ö¹µç½â£®ÔòÔ­ÈÜÒºÖеÄc£¨K+£©=
2mol/L
2mol/L
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¾«Ó¢¼Ò½ÌÍøÔÚÈçͼÓÃʯī×÷µç¼«µÄµç½â³ØÖУ¬·ÅÈë500mLº¬Ò»ÖÖÈÜÖʵÄijÀ¶É«ÈÜÒº½øÐеç½â£¬¹Û²ìµ½Aµç¼«±íÃæÓкìÉ«µÄ¹Ì̬ÎïÖÊÉú³É£¬Bµç¼«ÓÐÎÞÉ«ÆøÌåÉú³É£®Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©Çëд³öB¼«°åµÄÃû³Æ¼°·´Ó¦Ê½£º
 
£®
£¨2£©Ð´³öµç½âʱ·´Ó¦µÄ×ÜÀë×Ó·½³Ìʽ
 
£®
£¨3£©Èôµ±ÈÜÒºÖеÄÔ­ÓÐÈÜÖÊÍêÈ«µç½âºó£¬Í£Ö¹µç½â£¬È¡³öAµç¼«£¬Ï´µÓ¡¢¸ÉÔï¡¢³ÆÁ¿¡¢µç¼«ÔöÖØ1.6g£®µç½âºóÈÜÒºµÄpHΪ
 
£»ÒªÊ¹µç½âºóÈÜÒº»Ö¸´µ½µç½âÇ°µÄ״̬£¬ÔòÐè¼ÓÈë
 
£¬ÆäÖÊÁ¿Îª
 
£®£¨¼ÙÉèµç½âÇ°ºóÈÜÒºµÄÌå»ý²»±ä£©
£¨4£©ÈôÔ­ÈÜҺΪ1L K2SO4¡¢CuSO4µÄ»ìºÏÈÜÒº£¬ÇÒc£¨SO42-£©=2.0mol/L£»ÈçͼװÖõç½â£¬µ±Á½¼«¶¼ÊÕ¼¯µ½22.4LÆøÌ壨±ê×¼×´¿ö£©Ê±£¬Í£Ö¹µç½â£®ÔòÔ­ÈÜÒºÖеÄc£¨K+£©Îª¶àÉÙ£¿£¨Çë¼òµ¥±íʾ¼ÆËã¹ý³Ì£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010ÄêÕã½­Ê¡áÓÖÝÒ»ÖиßÈýÉÏѧÆÚÆÚÖп¼ÊÔÀí×Û£¨»¯Ñ§£© ÌâÐÍ£ºÌî¿ÕÌâ

£¨20·Ö£©ÔÚÓÒÏÂͼ¾ùÓÃʯī×÷µç¼«µÄµç½â³ØÖУ¬¼×³ØÖÐΪ500mLº¬Ä³Ò»ÈÜÖʵÄÀ¶É«ÈÜÒº£¬ÒÒ³ØÖÐΪ500mLÏ¡ÁòËᣬ±ÕºÏK1£¬¶Ï¿ªK2½øÐеç½â£¬¹Û²ìµ½Aµç¼«±íÃæÓкìÉ«µÄ¹Ì̬ÎïÖÊÉú³É£¬Bµç¼«ÓÐÎÞÉ«ÆøÌåÉú³É£»µ±ÈÜÒºÖеÄÔ­ÓÐÈÜÖÊÍêÈ«µç½âºó£¬Í£Ö¹µç½â£¬È¡³öAµç¼«£¬Ï´µÓ¡¢¸ÉÔï¡¢³ÆÁ¿£¬µç¼«ÔöÖØ6.4g¡£

Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©Bµç¼«·¢Éú·´Ó¦µÄµç¼«·´Ó¦Ê½                                       ¡£
Cµç¼«·¢Éú·´Ó¦µÄµç¼«·´Ó¦Ê½                                      .
£¨2£©¼×³Øµç½âʱ·´Ó¦µÄÀë×Ó·½³Ìʽ                                      ¡£
£¨3£©¼×³Øµç½âºóÈÜÒºµÄc(H+)Ϊ          £¬ÒªÊ¹µç½âºóÈÜÒº»Ö¸´µ½µç½âÇ°µÄ״̬£¬ÔòÐè¼ÓÈë        £¬ÆäÖÊÁ¿Îª        g¡££¨¼ÙÉèµç½âÇ°ºóÈÜÒºµÄÌå»ý²»±ä£©
£¨4£©ÇëÄãÉè¼ÆʵÑéÈ·¶¨¼×³ØÔ­ÈÜÒºÖпÉÄܺ¬ÓеÄËá¸ùÀë×Ó£¬ÒªÇó£ºÌá³öÁ½ÖÖ¿ÉÄܵļÙÉ裬·Ö±ðд³öÂÛÖ¤ÕâÁ½ÖÖ¼ÙÉèµÄ²Ù×÷²½Ö衢ʵÑéÏÖÏóºÍʵÑé½áÂÛ
¢Ù¼ÙÉèÒ»£º                                                £»
¢Ú¼ÙÉè¶þ£º                                                ¡£
£¨5£©ÈôÔÙ½«K1¶Ï¿ª£¬±ÕºÏK2£¬ÁéÃôµçÁ÷¼Æ  ÖÐÖ¸ÕëÊÇ·ñ»á·¢Éúƫת£¿ÀíÓÉÊÇʲô£¿

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÔÚÓÒÏÂͼ¾ùÓÃʯī×÷µç¼«µÄµç½â³ØÖУ¬¼×³ØÖÐΪ500mLº¬Ä³Ò»ÈÜÖʵÄÀ¶É«ÈÜÒº£¬ÒÒ³ØÖÐΪ500mLÏ¡ÁòËᣬ±ÕºÏK1£¬¶Ï¿ªK2½øÐеç½â£¬¹Û²ìµ½Aµç¼«±íÃæÓкìÉ«µÄ¹Ì̬ÎïÖÊÉú³É£¬Bµç¼«ÓÐÎÞÉ«ÆøÌåÉú³É£»µ±ÈÜÒºÖеÄÔ­ÓÐÈÜÖÊÍêÈ«µç½âºó£¬Í£Ö¹µç½â£¬È¡³öAµç¼«£¬Ï´µÓ¡¢¸ÉÔï¡¢³ÆÁ¿£¬µç¼«ÔöÖØ6.4g¡£

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©Bµç¼«·¢Éú·´Ó¦µÄµç¼«·´Ó¦Ê½                                        ¡£

     Cµç¼«·¢Éú·´Ó¦µÄµç¼«·´Ó¦Ê½                                       .

£¨2£©¼×³Øµç½âʱ·´Ó¦µÄÀë×Ó·½³Ìʽ                                       ¡£

£¨3£©¼×³Øµç½âºóÈÜÒºµÄc(H+)Ϊ           £¬ÒªÊ¹µç½âºóÈÜÒº»Ö¸´µ½µç½âÇ°µÄ״̬£¬ÔòÐè¼ÓÈë         £¬ÆäÖÊÁ¿Îª         g¡££¨¼ÙÉèµç½âÇ°ºóÈÜÒºµÄÌå»ý²»±ä£©

£¨4£©ÇëÄãÉè¼ÆʵÑéÈ·¶¨¼×³ØÔ­ÈÜÒºÖпÉÄܺ¬ÓеÄËá¸ùÀë×Ó£¬ÒªÇó£ºÌá³öÁ½ÖÖ¿ÉÄܵļÙÉ裬·Ö±ðд³öÂÛÖ¤ÕâÁ½ÖÖ¼ÙÉèµÄ²Ù×÷²½Ö衢ʵÑéÏÖÏóºÍʵÑé½áÂÛ

¢Ù¼ÙÉèÒ»£º                                                 £»

¢Ú¼ÙÉè¶þ£º                                                 ¡£

£¨5£©ÈôÔÙ½«K1¶Ï¿ª£¬±ÕºÏK2£¬ÁéÃôµçÁ÷¼Æ   ÖÐÖ¸ÕëÊÇ·ñ»á·¢Éúƫת£¿ÀíÓÉÊÇʲô£¿

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸