£¨15·Ö£©ÏÂÁпòͼÖеÄA ~ KÎïÖʾùΪÖÐѧ³£¼ûÎïÖÊ¡£ÒÑÖªB¡¢D¡¢E¡¢L³£ÎÂÏÂΪÃܶȱȿÕÆø´óµÄÆøÌ壬D¡¢EΪµ¥ÖÊ£¬ÆäËüΪ»¯ºÏÎï¡£AºÍI¶¼Êdz£ÓõÄƯ°×¼Á£¬FµÄÑæÉ«·´Ó¦³Ê»ÆÉ«¡£F¡¢G¾ùÄÜÓëLµÄË®ÈÜÒº·´Ó¦·Å³öB¡£Çë¸ù¾Ýͼʾ¹Øϵ»Ø´ðÎÊÌ⣺
£¨1£©FµÄË×ÃûÊǣߣߣߣߣߣߣ»KµÄµç×Óʽ£ß£ß£ß£ß£ß£ß¡£
£¨2£©·´Ó¦¢Ù~¢ÝÖУ¬ÊôÓÚÑõ»¯£»¹Ô·´Ó¦µÄÊǣߣߣߣߣߣߡ£
£¨3£©·´Ó¦¢ÜµÄÀë×Ó·½³Ìʽ£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß¡£
·´Ó¦¢ÛµÄ»¯Ñ§·½³Ìʽ£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß¡£
£¨4£©Ä³µ¥ÖÊÄÜÓëH·´Ó¦Éú³ÉE£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß¡£
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
µãȼ |
µãȼ |
µãȼ |
µãȼ |
c |
22.4 |
c |
22.4 |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
(1)¸ù¾ÝÉÏͼģÐÍд³öÈøÂ޵Ľṹ¼òʽ£º________________________________________¡£
(2)ÈøÂ޾ˮ½â¡¢·ÖÀë¡¢Ìá´¿¿ÉµÃµ½´¿¾»µÄ±½·ÓºÍË®ÑîËá(ÁÚôÇ»ù±½¼×Ëá)¡£ÇëÉè¼ÆÒ»¸ö·½°¸£¬ËµÃ÷±½·Ó¡¢Ì¼ËᡢˮÑîËáµÄËáÐÔÒÀ´ÎÔöÇ¿(Óû¯Ñ§·½³Ìʽ±íʾ)¡£
(3)ͬʱ·ûºÏÏÂÁÐËĸöÒªÇóµÄË®ÑîËáµÄͬ·ÖÒì¹¹Ìå¹²ÓÐ_____________ÖÖ¡£
¢Ùº¬Óб½»·£»¢ÚÄÜ·¢ÉúÒø¾µ·´Ó¦£¬²»ÄÜ·¢ÉúË®½â·´Ó¦£»¢ÛÔÚÏ¡NaOHÈÜÒºÖУ¬1 mol¸Ãͬ·ÖÒì¹¹ÌåÄÜÓë2 mol NaOH·¢Éú·´Ó¦£»¢ÜÖ»ÄÜÉú³ÉÁ½ÖÖÒ»ÂÈ´ú²úÎï¡£
(4)´Ó(3)È·¶¨µÄͬ·ÖÒì¹¹ÌåÖÐÈÎÑ¡Ò»ÖÖ£¬Ö¸¶¨ÎªÏÂÁпòͼÖеÄA¡£
д³öÏÂÁÐÁ½¸ö·´Ó¦µÄ»¯Ñ§·½³Ìʽ(ÓлúÎïÓýṹ¼òʽ±íʾ)£¬²¢Ö¸³öÏàÓ¦µÄ·´Ó¦ÀàÐÍ¡£
¢ÙAB______________________________________________________¡£
·´Ó¦ÀàÐÍ£º____________________________¡£
¢ÚB+DE__________________________________________________¡£
·´Ó¦ÀàÐÍ£º___________________________¡£
(5)ÏÖÓÐË®ÑîËáºÍ±½·ÓµÄ»ìºÏÎËüÃǵÄÎïÖʵÄÁ¿Ö®ºÍΪn¡£¸Ã»ìºÏÎïÍêȫȼÉÕÏûºÄa L O2£¬²¢Éú³Éb g H2OºÍc L CO2(ÆøÌåÌå»ý¾ùΪ±ê×¼×´¿öϵÄÌå»ý)¡£
¢Ù·Ö±ðд³öË®ÑîËáºÍ±½·ÓÍêȫȼÉյĻ¯Ñ§·½³Ìʽ(ÓлúÎï¿ÉÓ÷Ö×Óʽ±íʾ)¡£
¢ÚÉè»ìºÏÎïÖÐË®ÑîËáµÄÎïÖʵÄÁ¿Îªx£¬ÁгöxµÄ¼ÆËãʽ¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
(1)¸ù¾ÝÉÏͼģÐÍд³öÈøÂ޵Ľṹ¼òʽ£º___________¡£
(2)ÈøÂ޾ˮ½â¡¢·ÖÀë¡¢Ìá´¿¿ÉµÃµ½´¿¾»µÄ±½·ÓºÍË®ÑîËá(ÁÚôÇ»ù±½¼×Ëá)¡£ÇëÉè¼ÆÒ»¸ö·½°¸£¬ËµÃ÷±½·Ó¡¢Ì¼ËᡢˮÑîËáµÄËáÐÔÒÀ´ÎÔöÇ¿(Óû¯Ñ§·½³Ìʽ±íʾ)
_____________________________________________________________
(3)ͬʱ·ûºÏÏÂÁÐÒªÇóµÄË®ÑîËáµÄͬ·ÖÒì¹¹Ìå¹²ÓÐÖÖ¡£
¢Ùº¬Óб½»·£»¢ÚÄÜ·¢ÉúÒø¾µ·´Ó¦£»¢ÛÔÚÏ¡NaOHÈÜÒºÖУ¬1mol¸Ãͬ·ÖÒì¹¹ÌåÄÜÓë2molNaOH·´Ó¦;¢ÜÖ»ÄÜÉú³ÉÁ½ÖÖÒ»ÂÈ´úÎï¡£
(4)´Ó(3)È·¶¨µÄͬ·ÖÒì¹¹ÌåÖÐÈÎÑ¡Ò»ÖÖ£¬Ö¸¶¨ÎªÏÂÁпòͼÖеÄA¡£
д³öÏÂÁÐÁ½¸ö·´Ó¦µÄ»¯Ñ§·½³Ìʽ(Ë®ÑîËáÓýṹ¼òʽ±íʾ)£¬²¢Ö¸³öÏàÓ¦µÄ·´Ó¦ÀàÐÍ¡£
¢ÙA¡úB___________________________________________________
·´Ó¦ÀàÐÍ_________¡£
¢ÚB+D¡úE_________________________________________________
·´Ó¦ÀàÐÍ_________¡£
(5)ÏÖÓÐË®ÑîËáÓë±½·ÓµÄ»ìºÏÎËüÃǵÄÎïÖʵÄÁ¿Ö®ºÍΪnmol¡£¸Ã»ìºÏÎïÍêȫȼÉÕÏûºÄO2aL£¬²¢Éú³ÉbgH2O,cLCO2(ÆøÌåÌå»ý¾ùΪ±ê×¼×´¿öϵÄÌå»ý)
¢Ù·Ö±ðд³öË®ÑîËáºÍ±½·ÓÍêȫȼÉյĻ¯Ñ§·½³Ìʽ(ÓлúÎï¿ÉÓ÷Ö×Óʽ±íʾ)
___________________________________________________________
___________________________________________________________
¢ÚÉè»ìºÏÎïÖÐË®ÑîËáµÄÎïÖʵÄÁ¿Îªxmol£¬ÁгöxµÄ¼ÆËãʽ¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
(1)¸ù¾ÝÉÏͼģÐÍд³öÈøÂ޵Ľṹ¼òʽ£º_________________________________¡£
(2)ÈøÂ޾ˮ½â¡¢·ÖÀë¡¢Ìá´¿¿ÉµÃµ½´¿¾»µÄ±½·ÓºÍË®ÑîËá(ÁÚôÇ»ù±½¼×Ëá)¡£ÇëÉè¼ÆÒ»¸ö·½°¸£¬ËµÃ÷±½·Ó¡¢Ì¼ËᡢˮÑîËáµÄËáÐÔÒÀ´ÎÔöÇ¿(Óû¯Ñ§·½³Ìʽ±íʾ)¡£
(3)ͬʱ·ûºÏÏÂÁÐËĸöÒªÇóµÄË®ÑîËáµÄͬ·ÖÒì¹¹Ìå¹²ÓÐ___________ÖÖ¡£¢Ùº¬Óб½»·£»¢ÚÄÜ·¢ÉúÒø¾µ·´Ó¦£¬²»ÄÜ·¢ÉúË®½â·´Ó¦£»¢ÛÔÚÏ¡NaOHÈÜÒºÖУ¬1 mol¸Ãͬ·ÖÒì¹¹ÌåÄÜÓë2 mol NaOH·¢Éú·´Ó¦£»¢ÜÖ»ÄÜÉú³ÉÁ½ÖÖÒ»ÂÈ´úÎï¡£
(4)´Ó(3)È·¶¨µÄͬ·ÖÒì¹¹ÌåÖÐÈÎÑ¡Ò»ÖÖ£¬Ö¸¶¨ÎªÏÂÁпòͼÖеÄA¡£
д³öÏÂÁÐÁ½¸ö·´Ó¦µÄ»¯Ñ§·½³Ìʽ(ÓлúÎïÓýṹ¼òʽ±íʾ)£¬²¢Ö¸³öÏàÓ¦µÄ·´Ó¦ÀàÐÍ¡£
¢ÙAB__________________¡£·´Ó¦ÀàÐÍ£º_________¡£
¢ÚB+DE__________________¡£·´Ó¦ÀàÐÍ£º_________¡£
(5)ÏÖÓÐË®ÑîËáºÍ±½·ÓµÄ»ìºÏÎËüÃǵÄÎïÖʵÄÁ¿Ö®ºÍΪn mol¡£¸Ã»ìºÏÎïÍêȫȼÉÕÏûºÄa L O2£¬²¢Éú³Éb g H2OºÍc L CO2(ÆøÌåÌå»ý¾ùΪ±ê×¼×´¿öϵÄÌå»ý)¡£
¢Ù·Ö±ðд³öË®ÑîËáºÍ±½·ÓÍêȫȼÉյĻ¯Ñ§·½³Ìʽ(ÓлúÎï¿ÉÓ÷Ö×Óʽ±íʾ)£º__________________,__________________¡£
¢ÚÉè»ìºÏÎïÖÐË®ÑîËáµÄÎïÖʵÄÁ¿Îªx mol£¬ÁгöxµÄ¼ÆËãʽ£º___________________________¡£
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com