Èý±½¼×´¼(C6H5)3C-OHÊÇÒ»ÖÖÖØÒªµÄ»¯¹¤ÔÁϺÍÒ½Ò©ÖмäÌ壮ʵÑéÊҺϳÉÈý±½¼×´¼µÄʵÑé×°ÖÃÈçͼËùʾ¡£
ÒÑÖª£º¢Ù¹ý³ÌÖÐÉú³ÉµÄÖмäÎïÖʸñÊÏÊÔ¼ÁÒ×·¢ÉúË®½â·´Ó¦£»
¢Ú²¿·ÖÏà¹ØÎïÖʵķеãÈçÏ£º
¢ÛÈý±½¼×´¼µÄÏà¶Ô·Ö×ÓÖÊÁ¿Îª260£®
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©×°ÖÃÖв£Á§ÒÇÆ÷BµÄÃû³ÆΪ____________£»×°ÓÐÎÞË®CaCl2µÄÒÇÆ÷AµÄ×÷ÓÃÊÇ____________£»
£¨2£©×°ÖÃÖеμÓÒºÌåδÓÃÆÕͨ·ÖҺ©¶·¶øÓõÎҺ©¶·µÄ×÷ÓÃÊÇ____________£»
£¨3£©ÖƵõÄÈý±½¼×´¼´Ö²úÆ·Öк¬ÓÐÒÒÃÑ¡¢äå±½¡¢ÂÈ»¯ï§µÈÔÓÖÊ£¬¿ÉÒÔÉè¼ÆÈçÏÂÌá´¿·½°¸£º
ÆäÖУ¬²Ù×÷¢ÙµÄÃû³ÆÊÇ____________£»Ï´µÓÒº×îºÃÑ¡ÓÃ____________(Ìî×ÖĸÐòºÅ)£®
a£®Ë® b£®ÒÒÃÑ c£®ÒÒ´¼ d£®±½
¼ìÑé²úÆ·ÒѾϴµÓ¸É¾»µÄ²Ù×÷Ϊ____________£»
£¨4£©´¿¶È²â¶¨£º³ÆÈ¡2.60g²úÆ·£¬Åä³ÉÒÒÃÑÈÜÒº£¬¼ÓÈë×ãÁ¿½ðÊôÄÆ(ÒÒÃÑÓëÄƲ»·´Ó¦)£¬³ä·Ö·´Ó¦ºó£¬²âµÃÉú³ÉµÄÆøÌåÔÚ±ê×¼×´¿öϵÄÌå»ýΪ100.80mL£®Ôò²úÆ·ÖÐÈý±½¼×´¼µÄÖÊÁ¿·ÖÊýΪ____________¡£
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2015-2016ѧÄê½Î÷Ê¡µÈËÄУ¸ßһϵڶþ´ÎÔ¿¼»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ
Á½ÖÖÆø̬Ìþ»ìºÏÆøÌå¹²1L , ÔÚ¿ÕÆøÖÐÍêȫȼÉյõ½1.5L CO2ºÍ2LË®ÕôÆø(ÆøÌåÌå»ý¾ùÔÚ150¡æÌõ¼þϲⶨ), ¹ØÓÚ´Ë»ìºÏÆøÌåµÄÅжϺÏÀíµÄÊÇ£¨ £©
A£®Ò»¶¨º¬Óм×Íé
B£®Ò»¶¨º¬ÓÐÒÒÏ©
C£®¿ÉÄÜÊÇÒÒÍéºÍ¼×ÍéµÄ»ìºÏÆøÌå
D£®Ò»¶¨º¬ÓÐÒÒÏ©£¬²»Ò»¶¨º¬Óм×Íé
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2016½ìÔÆÄÏÊ¡¸ßÈýÏÂѧÆÚµÚ°Ë´ÎÔ¿¼Àí×Û»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ
ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ
A£®PCl3ºÍBCl3·Ö×ÓÖÐËùÓÐÔ×ÓµÄ×îÍâ²ã¶¼´ïµ½8µç×ÓÎȶ¨½á¹¹
B£®ÎªÔöÇ¿ÂÈË®µÄƯ°×ÐÔ£¬¿ÉÒÔÏòÆäÖмÓÈë̼Ëá¸Æ
C£®NaHÓëÖØË®·´Ó¦µÄ·½³Ìʽ£ºNaH+D2O==NaOH+D2¡ü
D£®¾ùº¬ÓÐNA¸öµç×ÓµÄH2OºÍCH4¾ßÓÐÏàͬµÄÌå»ý
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2016½ìÉÂÎ÷Î÷²ØÃñ×åѧԺ¸½ÖиßÈýÏ¿¼Ç°ÈýÄ£Àí×Û»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ
̼¼°Æ仯ºÏÎï¹ã·º´æÔÚÓÚ×ÔÈ»½çÖУ¬»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©´¦ÓÚÒ»¶¨¿Õ¼äÔ˶¯×´Ì¬µÄµç×ÓÔÚÔ×ÓºËÍâ³öÏֵĸÅÂÊÃܶȷֲ¼¿ÉÓÃÐÎÏó»¯ÃèÊö___________£»
£¨2£©Ì¼ÔÚÐγɻ¯ºÏÎïʱ£¬Æä¼üÐÍÒÔ¹²¼Û¼üΪÖ÷£¬ÔÒòÊÇ___________£»
£¨3£©C2H2 ·Ö×ÓÖУ¬¹²¼Û¼üµÄÀàÐÍÓÐ___________£¬C Ô×ÓµÄÔÓ»¯¹ìµÀÀàÐÍÊÇ___________£¬Ð´³öÁ½¸öÓëC2H2 ¾ßÓÐÏàͬ¿Õ¼ä¹¹Ðͺ¬Ì¼ÎÞ»úÎï·Ö×ӵķÖ×Óʽ___________£»
( 4 )CO ÄÜÓë½ðÊôFe¡¢Ni ·Ö±ðÐγÉFe(CO)5¡¢Ni(CO)4£¬Fe(CO)5 ÖÐFe ÔªËصÄÔ×ÓºËÍâµç×ÓÅŲ¼Îª______£¬Ni(CO)4 ÊÇÎÞÉ«ÒºÌ壬·Ðµã42.1¡æ£¬ÈÛµã-19.3¡æ£¬ÄÑÈÜÓÚË®£¬Ò×ÈÜÓÚÓлúÈܼÁÍƲâNi(CO)4 ÊÇ___________¾§Ìå¡£
£¨5£©Ì¼ÓжàÖÖͬËØÒìÐÎÌ壬ÆäÖÐʯīϩÓë½ð¸ÕʯµÄ¾§Ìå½á¹¹ÈçͼËùʾ£º
¢ÙÔÚʯīϩ¾§ÌåÖУ¬Ã¿¸öC Ô×ÓÁ¬½Ó___________¸öÁùÔª»·£¬Ã¿¸öÁùÔª»·Õ¼ÓÐ___________¸öC Ô×Ó£®
¢ÚÔÚ½ð¸Õʯ¾§ÌåÖУ¬C Ô×ÓËùÁ¬½ÓµÄ×îС»·Ò²ÎªÁùÔª»·£¬Ã¿¸öC Ô×ÓÁ¬½Ó___________¸öÁùÔª»·£¬ÁùÔª»·ÖÐ×î¶àÓÐ___________¸öC Ô×ÓÔÚͬһƽÃæ¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2016½ìÉÂÎ÷Î÷²ØÃñ×åѧԺ¸½ÖиßÈýÏ¿¼Ç°ÈýÄ£Àí×Û»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ
ijÓлúÎïµÄ½á¹¹¼òʽΪ£¬¹ØÓÚËüµÄ˵·¨ÕýÈ·µÄÊÇ( )
A£®¸ÃÎïÖÊÊôÓÚ·¼ÏãÌþ
B£®¸ÃÎïÖÊÒ×ÈÜÓÚË®
C£®1mol¸ÃÎïÖÊ×î¶àÄÜÓë2mol NaOH·´Ó¦
D£®¸ÃÎïÖÊÄÜ·¢ÉúµÄ·´Ó¦ÀàÐÍÓмӳɡ¢Ë®½â¡¢ÏûÈ¥¡¢Ñõ»¯
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2016½ìɽÎ÷Ê¡¸ßÈýµÚ¶þÂÖ¸´Ï°ÑµÁ·Áù»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ
ÏÂÁи÷ÏîÖÐʵÑéµÄÉè¼Æ»ò²Ù×÷ÄÜ´ïµ½Ô¤ÆÚʵÑéÄ¿µÄÊÇ( )
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2016½ì½ËÕÊ¡¸ßÈý¿¼Ç°ÖÜÁ·Ä£Ä⻯ѧÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ
µª¿ÉÒÔÐγɶàÖÖ»¯ºÏÎÈçNH3¡¢N2H4¡¢NH4NO3¡¢NF3µÈ¡£
£¨1£©ÒÑÖª£ºN2(g)+2H2(g)¨TN2H4(l)¡÷H=+50.6kJ•mol-1
2H2(g)+O2(g)¨T2H2O(l)¡÷H=-571.6kJ•mol-1
ÔòN2H4(l)+O2(g)¨TN2(g)+2H2O ¡÷H= _________kJ•mol-1£»
£¨2£©ÎÛË®ÖеÄNH4+¿ÉÒÔÓÃÑõ»¯Ã¾´¦Àí£¬·¢ÉúÈçÏ·´Ó¦£º
MgO+H2OMg(OH)2 Mg(OH)2+2NH4+Mg2++2NH3•H2O
¢ÙζȶԵª´¦ÀíÂʵÄÓ°ÏìÈçͼËùʾ£®ÔÚ25¡æÇ°£¬Éý¸ßζȵªÈ¥³ýÂÊÔö´óµÄÔÒòÊÇ________________£»
¢ÚÊ£ÓàµÄÑõ»¯Ã¾£¬²»»á¶Ô·ÏË®Ðγɶþ´ÎÎÛȾ£¬ÀíÓÉÊÇ________________£»
£¨3£©ÎÛË®Öе嬵ª»¯ºÏÎͨ³£ÏÈÓÃÉúÎïĤÍѵª¹¤ÒÕ½øÐд¦ÀíÔÚÏõ»¯Ï¸¾úµÄ×÷ÓÃϽ«NH4+Ñõ»¯ÎªNO3-(2NH4++3O2¨T2HNO2+2H2O+2H+£»2HNO2+O2=2HNO3)£®È»ºó¼ÓÈë¼×´¼£¬¼×´¼ºÍNO3-·´Ó¦×ª»¯ÎªÁ½ÖÖÎÞ¶¾ÆøÌ壮
¢ÙÉÏÊö·½·¨ÖУ¬14gï§Ì¬µªÔªËØת»¯ÎªÏõ̬µªÔªËØʱÐèÑõµÄÖÊÁ¿Îª_______g¡£
¢Úд³ö¼ÓÈë¼×´¼ºó·´Ó¦µÄÀë×Ó·½³Ìʽ________________£»
£¨4£©Ê¹ÓÃNaBH4ΪÓÕµ¼¼Á£¬¿ÉʹCo2+ÓëëÂÔÚ¼îÐÔÌõ¼þÏ·¢Éú·´Ó¦£¬ÖƵøߴ¿¶ÈÄÉÃ×îÜ£¬¸Ã¹ý³Ì²»²úÉúÓж¾ÆøÌå¡£
¢Ùд³ö¸Ã·´Ó¦µÄÀë×Ó·½³Ìʽ________________£»
¢ÚÔÚÄÉÃ×îܵĴ߻¯×÷ÓÃÏ£¬ë¿ɷֽâÉú³ÉÁ½ÖÖÆøÌ壬ÆäÖÐÒ»ÖÖÄÜʹʪÈóµÄºìɫʯÈïÊÔÖ½±äÀ¶£®Èô·´Ó¦ÔÚ²»Í¬Î¶ÈÏ´ﵽƽºâʱ£¬»ìºÏÆøÌåÖи÷×é·ÖµÄÌå»ý·ÖÊýÈçÏÂͼ1Ëùʾ£¬ÔòN2H4·¢Éú·Ö½â·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ________________£»
£¨5£©ÔÚ΢µç×Ó¹¤ÒµÖÐNF3³£ÓÃ×÷µª»¯¹èµÄÊ´¿Ì¼Á£¬¹¤ÒµÉÏͨ¹ýµç½âº¬NH4FµÈµÄÎÞË®ÈÛÈÚÎïÉú²úNF3£¬Æäµç½âÔÀíÈçÉÏͼ2Ëùʾ¡£Ð´³öaµç¼«µÄµç¼«·´Ó¦Ê½__________________¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2016½ì½ËÕÊ¡¸ßÈý¿¼Ç°ÖÜÁ·Ä£Ä⻯ѧÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ
»¯Ñ§ÓëÈËÀàÉú»î¡¢Éç»á¿É³ÖÐø·¢Õ¹ÃÜÇÐÏà¹Ø¡£ÏÂÁÐ˵·¨²»ÕýÈ·µÄÊÇ
A£®ÀûÓÃÌ«ÑôÄܵÈÇå½àÄÜÔ´´úÌ滯ʯȼÁÏ£¬ÓÐÀûÓÚ½ÚÔ¼×ÊÔ´¡¢±£»¤»·¾³
B£®´ß»¯×ª»¯»ú¶¯³µÎ²ÆøΪÎÞº¦ÆøÌ壬ÄÜÏû³ýËáÓêºÍÎíö²µÄ·¢Éú
C£®Ñз¢¸ßЧµÍ¶¾µÄÅ©Ò©£¬½µµÍÊ߲˵ÄÅ©Ò©²ÐÁôÁ¿
D£®»ý¼«¿ª·¢·Ïµç³ØµÄ×ÛºÏÀûÓü¼Êõ£¬·ÀÖ¹µç³ØÖеÄÖؽðÊôµÈÎÛȾÍÁÈÀºÍË®Ìå
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2015-2016ѧÄêÄþÏÄÓý²ÅÖÐѧ¿×µÂУÇø¸ßÒ»ÏÂ6Ô¿¼»¯Ñ§¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ
NAΪ°¢·ü¼ÓµÂÂÞ³£ÊýµÄÖµ£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ( )
A£®±ê×¼×´¿öÏ£¬11.2LµÄÎìÍéËùº¬µÄ·Ö×ÓÊýΪ0.5NA
B£®0.5mol C3H8·Ö×ÓÖк¬C¡ªH¹²¼Û¼ü2NA
C£®11.2 L¶þÂȼ×ÍéËùº¬·Ö×ÓÊýΪ0.5NA
D£®ÏÖÓÐÒÒÏ©¡¢±ûÏ©¡¢¶¡Ï©µÄ»ìºÏÆøÌå¹²14 g£¬ÆäÔ×ÓÊýΪ3NA
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com