(6·Ö)ÏÂÃæÊÇÖÐѧ»¯Ñ§ÊµÑéÖг£¼ûµÄ¼¸ÖÖÒÇÆ÷£ºa£®Á¿Í² b£®ÈÝÁ¿Æ¿ c£®ÊԹܠ d£®Ô²µ×ÉÕÆ¿e£®ÍÐÅÌÌìƽ

 (1)ÆäÖÐÒÇÆ÷ÉÏÒª±ê³öʹÓÃζȵÄÊÇ             (ÌîÑ¡Ïî)

 (2)¿ÉÓÃ×÷·´Ó¦ÈÝÆ÷²¢ÄܽøÐмÓÈȵÄÊÇ             (ÌîÑ¡Ïî)

 (3)ÓÉÓÚ²Ù×÷´íÎó£¬Ê¹µÃʵÑé½á¹ûƫСµÄÊÇ            (ÌîÑ¡Ïî)

A£®³ÆÈ¡5.2 gNaCl¹ÌÌåʱ£¬½«íÀÂë·Åµ½×óÅÌ£¬NaCl¹ÌÌå·Åµ½ÓÒÅÌ

B£®ÅäÖÆÒ»¶¨ÎïÖʵÄÁ¿Å¨¶ÈµÄNaClÈÜÒº£¬¶¨ÈÝʱ£¬¸©ÊÓÈÝÁ¿Æ¿¿Ì¶ÈÏß¼ÓË®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÏÂÃæÊÇÖÐѧ»¯Ñ§Öг£Óò£Á§ÒÇÆ÷×é³ÉµÄʵÑé×°ÖÃͼ£¨¸ù¾ÝÐèÒª¿ÉÔÚÆäÖмÓÈëÒºÌå»ò¹ÌÌ壩£®
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÄÜÓÃ×÷¸ÉÔï°±ÆøµÄ×°ÖÃÓÐ
D¡¢E
D¡¢E
£¨Ìî×Öĸ£©£»
£¨2£©¼ÈÄÜÓÃÓÚÊÕ¼¯ÂÈÆøÓÖÄÜÓÃÓÚÊÕ¼¯Ò»Ñõ»¯µªÆøÌåµÄ×°ÖÃÓÐ
B
B
£¨Ìî×Öĸ£©£»
£¨3£©ÔÚÂÈÆøºÍÌú·´Ó¦ÊµÑéÖУ¬ÄÜÌí¼ÓÔÚÖÆÂÈÆøºÍ·´Ó¦×°ÖÃÖ®¼äÒÔ³ýÈ¥ÂÈÆøÖÐÂÈ»¯ÇâµÈÔÓÖÊÆøÌåµÄ×°ÖÃÓÐ
A
A
£¨Ìî×Öĸ£©£»
£¨4£©ÄÜÓÃÓÚÒÒÏ©ÓëäåË®·´Ó¦ÖƶþäåÒÒÍéµÄʵÑé×°ÖÃÓÐ
A
A
£¨Ìî×Öĸ£©£»
£¨5£©ÈôÓÃC×°ÖÃ×÷¶þÑõ»¯ÁòÓëÉÕ±­ÖÐÇâÑõ»¯ÄÆÈÜÒº·´Ó¦µÄʵÑ飬ÔòÆäÖйã¿ÚÆ¿µÄ×÷ÓÃÊÇ
·ÀÖ¹µ¹Îü
·ÀÖ¹µ¹Îü
£®
£¨6£©Îª±È½ÏFe3+ºÍCu2+¶ÔH2O2·Ö½âµÄ´ß»¯Ð§¹û£¬Ä³Í¬Ñ§Éè¼ÆÁËÏÂͼËùʾµÄʵÑ飮

¢Ù¿Éͨ¹ý¹Û²ì
¸ù¾Ý2H2O2
 ´ß»¯¼Á 
.
 
2H2O+O2¡ü¿ÉÖªÒÔÉú³ÉÆøÌåµÄ¿ìÂýÀ´ÅжϷ´Ó¦µÄ¿ìÂý
¸ù¾Ý2H2O2
 ´ß»¯¼Á 
.
 
2H2O+O2¡ü¿ÉÖªÒÔÉú³ÉÆøÌåµÄ¿ìÂýÀ´ÅжϷ´Ó¦µÄ¿ìÂý
ÏÖÏóÀ´¶¨ÐԱȽϵóö½áÂÛ£®
¢ÚÓÐͬѧÌá³ö½«CuSO4¸ÄΪCuCl2¸üΪºÏÀí£¬ÆäÀíÓÉÊÇ
ÓÉÓÚCuSO4¡¢FeCl3ÖеÄÒõÀë×Ó²»Í¬£¬²»ÄÜÅųýÒõÀë×ÓµÄÒòËØ
ÓÉÓÚCuSO4¡¢FeCl3ÖеÄÒõÀë×Ó²»Í¬£¬²»ÄÜÅųýÒõÀë×ÓµÄÒòËØ
£¬ÄãÈÏΪ»¹¿ÉÒÔ×÷ºÎ¸Ä½ø£¿
½«FeCl3¸ÄΪFe2£¨SO4£©3
½«FeCl3¸ÄΪFe2£¨SO4£©3
©q

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨¢ñ£©ÆøÌåÖƱ¸Ê±ÐëÏȼì²é×°ÖõÄÆøÃÜÐÔ£¬ÏÂÁи÷ͼËùʾװÖ㬿϶¨²»·ûºÏÆøÃÜÐÔ¼ì²éÒªÇóµÄÊÇ
D
D
£®

£¨¢ò£©ÏÂÃæÊÇÖÐѧ»¯Ñ§ÊµÑéÖг£¼ûµÄ¼¸ÖÖÒÇÆ÷£º
a£®Á¿Í²    b£®ÈÝÁ¿Æ¿    c£®·ÖҺ©¶·    d£®ÍÐÅÌÌìƽ   e£®Î¶ȼÆ
£¨1£©ÆäÖбêʾ³öÒÇÆ÷ʹÓÃζȵÄÊÇ
ab
ab
£¨Ìî±àºÅ£©£®
£¨2£©³ÆÈ¡10.5g¹ÌÌåÑùÆ·£¨1gÒÔÏÂʹÓÃÓÎÂ룩ʱ£¬½«ÑùÆ··ÅÔÚÁËÌìƽµÄÓÒÅÌ£¬ÔòËù³ÆÑùÆ·µÄʵ¼ÊÖÊÁ¿Îª
9.5
9.5
g£®
£¨3£©Ê¹ÓÃÇ°Òª¼ì²éÒÇÆ÷ÊÇ·ñ©ҺµÄÊÇ
bc
bc
£¨Ìî±àºÅ£©£®
£¨¢ó£©ÊµÑéÊÒÐèÒª95mL 1.0mol?L-1Ï¡ÁòËᣬÏÖÓÃ98%µÄŨÁòËᣨÆäÃܶÈΪ1.84g/mL£©À´½øÐÐÅäÖÆ£®ÈôʵÑéÒÇÆ÷ÓУº
A£®100mLÁ¿Í²       B£®ÍÐÅÌÌìƽ          C£®²£Á§°ô         D£®250mLÈÝÁ¿Æ¿
E£®10mLÁ¿Í²         F£®½ºÍ·µÎ¹Ü        G£®50mLÉÕ±­    H£®100mLÈÝÁ¿Æ¿
£¨1£©ÐèÁ¿È¡Å¨ÁòËáµÄÌå»ýΪ
5.4
5.4
mL£®
£¨2£©ÊµÑéʱѡÓõÄÒÇÆ÷ÓУ¨ÌîÐòºÅ£©
C¡¢E¡¢F¡¢G¡¢H
C¡¢E¡¢F¡¢G¡¢H

£¨3£©ÅäÖƹý³ÌÖУ¬ÏÂÁÐÇé¿ö»áʹÅäÖƽá¹ûÆ«¸ßµÄÊÇ£¨ÌîÐòºÅ£©
CD
CD

A£®½«Ï¡Ê͵ÄÁòËáҺתÒÆÖÁÈÝÁ¿Æ¿ºó£¬Î´Ï´µÓÉÕ±­ºÍ²£Á§°ô£®
B£®½«ÉÕ±­ÄÚµÄÏ¡ÁòËáÏòÈÝÁ¿Æ¿ÖÐתÒÆʱ£¬Òò²Ù×÷²»µ±Ê¹²¿·ÖÏ¡ÁòËὦ³öÆ¿Í⣮
C£®Î´ÀäÈ´ÖÁÊÒξͶ¨ÈÝ£®
D£®ÓýºÍ·µÎ¹Ü¼Óˮʱ£¬¸©ÊÓ¹Û²ìÈÜÒº°¼ÒºÃæÓëÈÝÁ¿Æ¿¿Ì¶ÈÏàÇУ®
E£®ÈÝÁ¿Æ¿Ê¹ÓÃʱδ¸ÉÔï
F£®¶¨Èݺó¾­Õñµ´¡¢Ò¡ÔÈ¡¢¾²Ö㬷¢ÏÖÒºÃæµÍÓڿ̶ÈÏߣ¬ÔÙ¼ÓÕôÁóË®²¹ÖÁ¿Ì¶ÈÏߣ®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012-2013Äê°²»ÕÊæ³ÇÏþÌìÖÐѧ¸ßÈýÉÏѧÆÚÖصã°à°ëÔ¿¼»¯Ñ§ÊÔ¾í£¨´ø½âÎö£© ÌâÐÍ£ºÊµÑéÌâ

(8·Ö)ÏÂÃæÊÇÖÐѧ»¯Ñ§ÊµÑéÖг£¼ûµÄ¼¸ÖÖ¶¨Á¿ÒÇÆ÷£º
a¡¢Á¿Í²b¡¢ÈÝÁ¿Æ¿c¡¢µÎ¶¨¹Üd¡¢ÍÐÅÌÌìƽe¡¢Î¶ȼÆ
(1)ÆäÖбêʾ³öÒÇÆ÷ʹÓÃζȵÄÊÇ_____________(Ìîд±àºÅ)£»
(2)ʵÑéʱÓÃÀ´¾«È·Á¿È¡ÒºÌåÌå»ýµÄÊÇ__________(Ìîд±àºÅ)£»
(3)ʹÓÃÇ°Òª¼ì²éÒÇÆ÷ÊÇ·ñ©ҺµÄÊÇ____________________(Ìîд±àºÅ)£»
(4)³ÆÈ¡10.5g¹ÌÌåÑùÆ·(1gÒÔÏÂʹÓÃÓÎÂë)ʱ£¬½«ÑùÆ··ÅÔÚÁËÌìƽµÄÓÒÅÌ£¬ÔòËù³ÆÑùÆ·µÄʵ¼ÊÖÊÁ¿Îª_______________g¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2013½ì°²»ÕÊæ³ÇÏþÌìÖÐѧ¸ßÈýÉÏѧÆÚÖصã°à°ëÔ¿¼»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÊµÑéÌâ

(8·Ö)ÏÂÃæÊÇÖÐѧ»¯Ñ§ÊµÑéÖг£¼ûµÄ¼¸ÖÖ¶¨Á¿ÒÇÆ÷£º

a¡¢Á¿Í²b¡¢ÈÝÁ¿Æ¿c¡¢µÎ¶¨¹Üd¡¢ÍÐÅÌÌìƽe¡¢Î¶ȼÆ

(1)ÆäÖбêʾ³öÒÇÆ÷ʹÓÃζȵÄÊÇ_____________(Ìîд±àºÅ)£»

(2)ʵÑéʱÓÃÀ´¾«È·Á¿È¡ÒºÌåÌå»ýµÄÊÇ__________(Ìîд±àºÅ)£»

(3)ʹÓÃÇ°Òª¼ì²éÒÇÆ÷ÊÇ·ñ©ҺµÄÊÇ____________________(Ìîд±àºÅ)£»

(4)³ÆÈ¡10.5g¹ÌÌåÑùÆ·(1gÒÔÏÂʹÓÃÓÎÂë)ʱ£¬½«ÑùÆ··ÅÔÚÁËÌìƽµÄÓÒÅÌ£¬ÔòËù³ÆÑùÆ·µÄʵ¼ÊÖÊÁ¿Îª_______________g¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸