(2009¹ã¶«¶«Ý¸µ÷ÑУ¬3)ÏÂÁÐʵÑéÄÜ´ïµ½Ô¤ÆÚÄ¿µÄµÄÊÇ(    )

¢ÙÓÃÒÒ´¼ºÍŨÁòËá³ýÈ¥ÒÒËáÒÒõ¥ÖеÄÉÙÁ¿ÒÒËá ¢ÚÓÃNaOHÈÜÒº³ýÈ¥±½ÖеÄÉÙÁ¿±½·Ó

¢ÛÓñ¥ºÍNaHCO3ÈÜÒº³ýÈ¥CO2ÖеÄÉÙÁ¿SO2 ¢ÜÓüÓÈȵķ½·¨ÌáÈ¡NH4Cl¹ÌÌåÖлìÓеÄÉÙÁ¿µâ

¢ÝÓô׺ͳÎÇåʯ»ÒË®ÑéÖ¤µ°¿ÇÖк¬ÓÐ̼ËáÑÎ ¢ÞÓÃÃ×ÌÀ¼ìÑéʳÓüӵâÑÎÖк¬µâ ¢ßÓõâ¾ÆÑéÖ¤ÆûÓÍÖк¬Óв»±¥ºÍÌþ

A.¢Ù¢Ú¢Ü¢Ý¢ß                                   B.¢Ú¢Û¢Ý

C.¢Ú¢Û¢Ü¢Ý                                     D.¢Ù¢Ú¢Û¢Ü¢Ý¢Þ¢ß

B


½âÎö:

Óñ¥ºÍ̼ËáÄÆÈÜÒº³ýÈ¥ÒÒËáÒÒõ¥ÖеÄÉÙÁ¿ÒÒËᣬ¢Ù²»ºÏÊÊ£»NH4Cl¹ÌÌåÊÜÈȷֽ⣬¢Ü²»ºÏÊÊ£»µâÑÎÖк¬£¬²»º¬I2£¬¢Þ²»ºÏÊÊ£»ÓÃäåË®ÑéÖ¤ÆûÓÍÖк¬Óв»±¥ºÍÌþ£¬¢ß²»ºÏÊÊ¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2009?¹ã¶«£©ÏÂÁÐÓйØʵÑé²Ù×÷µÄ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2009?¹ã¶«£©¿ÉÓÃÓڵ綯Æû³µµÄÂÁ-¿ÕÆøȼÁϵç³Ø£¬Í¨³£ÒÔNaClÈÜÒº»òNaOHÈÜҺΪµç½âÒº£¬ÂÁºÏ½ðΪ¸º¼«£¬¿ÕÆøµç¼«ÎªÕý¼«£®ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2009?¹ã¶«Ä£Ä⣩ͨ³£Çé¿öÏ¿ÕÆøÖÐCO2µÄÌå»ý·ÖÊýΪ0.030%£¬µ±¿ÕÆøÖÐCO2µÄÌå»ý·ÖÊý³¬¹ý0.050%ʱ£¬»áÒýÆðÃ÷ÏÔµÄÎÂÊÒЧӦ£®Îª¼õСºÍÏû³ýCO2¶Ô»·¾³µÄÓ°Ï죬һ·½ÃæÊÀ½ç¸÷¹ú¶¼ÔÚÏÞÖÆÆäÅÅ·ÅÁ¿£¬ÁíÒ»·½Ãæ¿Æѧ¼Ò¼ÓÇ¿Á˶ÔCO2´´ÐÂÀûÓõÄÑо¿£®
£¨1£©Ä¿Ç°£¬Óó¬ÁÙ½çCO2£¨Æä״̬½éÓÚÆø̬ºÍҺ̬֮¼ä£©´úÌæ·úÀû°º×÷ÖÂÀä¼ÁÒѳÉΪһÖÖÇ÷ÊÆ£¬ÕâÒ»×ö·¨¶Ô»·¾³µÄ»ý¼«ÒâÒåÔÚÓÚ
±£»¤³ôÑõ²ã
±£»¤³ôÑõ²ã
£®
£¨2£©×î½üÓпÆѧ¼ÒÌá³ö¡°ÂÌÉ«×ÔÓÉ¡±¹¹Ï룺°Ñ¿ÕÆø´µÈë̼Ëá¼ØÈÜÒº£¬È»ºóÔÙ°ÑCO2´ÓÈÜÒºÖÐÌáÈ¡³öÀ´£¬¾­»¯Ñ§·´Ó¦ºóʹ֮±äΪ¿ÉÔÙÉúȼÁϼ״¼£®¡°ÂÌÉ«×ÔÓÉ¡±¹¹Ïë¼¼ÊõÁ÷³ÌÈçÏ£º

¢Ù·Ö½â³ØÖз´Ó¦µÄ»¯Ñ§·½³ÌʽΪ
2KHCO3
  ¡÷  
.
 
K2CO3+CO2¡ü+H2O
2KHCO3
  ¡÷  
.
 
K2CO3+CO2¡ü+H2O
£®
¢ÚÔںϳÉËþÖУ¬ÈôÓÐ4.4kg CO2Óë×ãÁ¿H2Ç¡ºÃÍêÈ«·´Ó¦£¬Éú³ÉÆø̬µÄË®ºÍ¼×´¼£¬¿É·Å³ö4947kJµÄÈÈÁ¿£¬ÊÔд³öºÏ³ÉËþÖз¢Éú·´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ
CO2£¨g£©+3H2£¨g£©¨TCH3OH£¨g£©+H2O£¨g£©¡÷H=-49.47kJ/mol
CO2£¨g£©+3H2£¨g£©¨TCH3OH£¨g£©+H2O£¨g£©¡÷H=-49.47kJ/mol
£®
£¨3£©Ð¡ÀîͬѧÄâÓóÁµí·¨²â¶¨¿ÕÆøÖÐCO2µÄÌå»ý·ÖÊý£¬Ëû²éµÃCaCO3¡¢BaCO3µÄÈܶȻý£¨Ksp£©·Ö±ðΪ4.96¡Á10-9¡¢2.58¡Á10-11£®
СÀîÓ¦¸ÃÑ¡ÓõÄÊÔ¼ÁÊÇ
Ba£¨OH£©2£¨»òNaOHÈÜÒººÍBaCl2ÈÜÒº£©
Ba£¨OH£©2£¨»òNaOHÈÜÒººÍBaCl2ÈÜÒº£©
£¬ÊµÑéʱ²â¶¨µÄÊý¾Ý³ý¿ÕÆøµÄÌå»ýÍ⣬»¹ÐèÒª²â¶¨
ʵÑéʱµÄζȡ¢Ñ¹Ç¿¡¢³ÁµíµÄÖÊÁ¿
ʵÑéʱµÄζȡ¢Ñ¹Ç¿¡¢³ÁµíµÄÖÊÁ¿
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â

£¨2009?¹ã¶«Ä£Ä⣩ÆßË®ÁòËáþ£¨MgSO4?7H2O£©ÔÚӡȾ¡¢ÔìÖ½ºÍÒ½Ò©µÈ¹¤ÒµÉ϶¼Óй㷺µÄÓ¦Óã¬ÀûÓû¯¹¤³§Éú²úÅðÉ°µÄ·ÏÔü-ÅðþÄà¿ÉÖÆÈ¡ÆßË®ÁòËáþ£®ÅðþÄàµÄÖ÷Òª³É·ÖÊÇMgCO3£¬»¹º¬ÓÐÆäËûÔÓÖÊ£¨MgO¡¢SiO2¡¢Fe2O3¡¢FeO¡¢CaO¡¢Al2O3¡¢MnOµÈ£©£®
±í1  ²¿·ÖÑôÀë×ÓÒÔÇâÑõ»¯ÎïÐÎʽÍêÈ«³ÁµíʱÈÜÒºµÄpH
³ÁµíÎï Al£¨OH£©3 Fe£¨OH£©3 Fe£¨OH£©2 Mn£¨OH£©2 Mg£¨OH£©2
pHÖµ 5.2 3.2 9.7 10.4 11.2
±í2  Á½ÖÖÑεÄÈܽâ¶È£¨µ¥Î»Îªg/100gË®£©
ζÈ/¡æ 10 30 40 50 60
CaSO4 0.19 0.21 0.21 0.20 0.19
MgSO4?7H2O 30.9 35.5 40.8 45.6 /
ÅðþÄàÖÆÈ¡ÆßË®ÁòËáþµÄ¹¤ÒÕÁ÷³ÌÈçÏ£º

¸ù¾ÝÒÔÉÏÁ÷³Ìͼ²¢²Î¿¼±í¸ñpHÊý¾ÝºÍÈܽâ¶ÈÊý¾Ý£¬ÊԻشðÏÂÁÐÎÊÌ⣺
£¨1£©¹ýÂËIµÄÂËÒºÖмÓÈëÅðþÄ࣬µ÷½ÚÈÜÒºµÄpH=5¡«6£¬ÔÙ¼ÓÈëNaClOÈÜÒº¼ÓÈÈÖó·Ð£¬½«ÈÜÒºÖеÄMn2+Ñõ»¯³ÉMnO2£¬·´Ó¦µÄÀë×Ó·´Ó¦·½³ÌʽΪ
Mn2++ClO-+H2O=MnO2¡ý+2H++Cl-
Mn2++ClO-+H2O=MnO2¡ý+2H++Cl-
£®¼ÓÈÈÖó·ÐµÄÖ÷ҪĿµÄÊÇ
´Ù½øAl3+¡¢Fe3+Ë®½â¼°Mn2+Ñõ»¯³ÉMnO2
´Ù½øAl3+¡¢Fe3+Ë®½â¼°Mn2+Ñõ»¯³ÉMnO2
£®
£¨2£©³ÁµíBÖгýMnO2¡¢SiO2Í⻹º¬ÓÐ
Fe£¨OH£©3¡¢Al£¨OH£©3
Fe£¨OH£©3¡¢Al£¨OH£©3
£¨Ìѧʽ£©µÈÎïÖÊ£®
£¨3£©¼ìÑé¹ýÂË¢òºóµÄÂËÒºÖÐÊÇ·ñº¬ÓÐFe3+µÄʵÑé·½·¨ÊÇ
È¡¹ýÂËIIºóµÄÂËÒº1¡«2mlÓÚÊÔ¹ÜÖУ¬¼ÓÈëÉÙÁ¿KSCNÈÜÒº£¬Èç¹ûÈÜÒº²»ÏÔºìÉ«£¬Ö¤Ã÷ÂËÒºÖÐÎÞFe3+
È¡¹ýÂËIIºóµÄÂËÒº1¡«2mlÓÚÊÔ¹ÜÖУ¬¼ÓÈëÉÙÁ¿KSCNÈÜÒº£¬Èç¹ûÈÜÒº²»ÏÔºìÉ«£¬Ö¤Ã÷ÂËÒºÖÐÎÞFe3+
£»
£¨4£©³ÁµíCµÄ»¯Ñ§Ê½ÊÇ
CaSO4?2H2O»òCaSO4
CaSO4?2H2O»òCaSO4
£®¹ýÂË¢óÐè³ÃÈȹýÂ˵ÄÀíÓÉÊÇ
ÒÔ·ÀMgSO4ÔÚζȵÍʱ½á¾§Îö³ö
ÒÔ·ÀMgSO4ÔÚζȵÍʱ½á¾§Îö³ö
£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸