(12·Ö)ijѧϰС×éÀûÓÃÏÂͼËùʾװÖýøÐС°ÌúÓëË®Æø·´Ó¦¡±ºÍÆäËûʵÑé(ÂÔÈ¥Á˼гÖÒÇÆ÷)¡£

(1)ΪÁË°²È«£¬¼ÓÈÈEÒÔÇ°±ØÐë½øÐеIJÙ×÷ÊÇ____________________________¡£
(2) BÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ                              _______________¡£
(3)ÒÑÖªÓз´Ó¦£ºCu2O+2H+Cu+Cu2++H2O£¬Ôò¿ÉÓÃÀ´¼ìÑé·´Ó¦ºóEÖеĺìÉ«¹ÌÌåÖгýCuÍâÊÇ·ñº¬Cu2O£¬¿ÉÓõÄÊÔ¼ÁÊÇ________(ÌîÐòºÅ)
a£®Ï¡ÏõËá    b£®Ï¡ÁòËá    c£®ÑÎËá    d£®Å¨ÁòËá  
(4)ÔÚEºóÈôÔÙ½Ó¶þ¸öÊ¢¼îʯ»ÒµÄ¸ÉÔï¹Ü(ÒÀ´Î³ÆΪFºÍG)£¬Ôò»¹¿ÉÓøÃ×°ÖòⶨˮµÄ×é³É¡£Èô·´Ó¦ºóÊ¢ÓÐÒ©Æ·µÄEµÄÖÊÁ¿¼õÇáÁËe g£¬FµÄÖÊÁ¿Ôö¼ÓÁËf g¡£Ë®ÖÐÔªËصÄÎïÖʵÄÁ¿Ö®±È¿É±íʾΪ£¨²»Óû¯¼ò£©n(H)£ºn(O)= ________£º_______£»Èô·´Ó¦ºóEÖгýCuÍ⻹º¬ÓÐÁíÒ»ÖÖ»¹Ô­²úÎïCu2O£¬Ôò¸Ã±ÈÖµ½«___________ (Ñ¡Ìî¡°Æ«´ó¡±¡°Æ«Ð¡¡±»ò¡°ÎÞÓ°Ï족)¡£
(5)ijѧÉúΪÁ˼ìÑé·´Ó¦ºó¹ÌÌåµÄ³É·Ö£¬·´Ó¦Ç°ÔÚE¹ÜÖмÓÈëÁËÑõ»¯Í­¹ÌÌå16g£¬·´Ó¦ºó³ÆÁ¿¹ÌÌåµÄÖÊÁ¿±äΪ13.6g£¬Ôò13.6gµÄ³É·ÖΪ£º___________£¨ÈôΪ»ìºÏÎÐè¼ÆËã³ö¸÷×ÔµÄÖÊÁ¿£©

(12·Ö)
¢ÅÔÚEµÄ³ö¿ÚÊÕ¼¯ÇâÆøÑé´¿£¨»ò¼ìÑé×°ÖÃÄÚÇâÆøµÄ´¿¶È£©£¨2·Ö£©
¢Æ3Fe£«4H2O£¨Æø£© Fe3O4£«4H2£¨2·Ö£©
¢Çb¡¢c£¨1·Ö£©
¢Èf-e£ºe/16£¨2·Ö£©£»ÎÞÓ°Ï죨1·Ö£©£»
£¨5£©Í­6.4g£¬Ñõ»¯ÑÇÍ­7.2g£¨4·Ö£©

½âÎö

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£ºÑ×µÂ?Ó¢²Å´óÁª¿¼ÈýÏæÃûУ2010½ì¸ßÈýÔ¿¼ÊÔ¾í£¨Ò»£© ÌâÐÍ£ºÊµÑéÌâ

£¨Ã¿¿Õ2·Ö£¬¹²12·Ö£©Ä³Ð£»¯Ñ§Ñо¿ÐÔѧϰС×éµÄͬѧÔÚѧϰÁ˽ðÊôµÄ֪ʶºó£¬ÎªÁ˽âCuµÄ³£¼û»¯ºÏÎïÐÔÖÊ£¬ÔËÓÃÀà±ÈѧϰµÄ˼ÏëÌá³öÈçϵÄÎÊÌ⣬̽¾¿¡£ÇëÄãЭÖú¸ÃС×éµÄͬѧÍê³ÉÏÂÁÐÑо¿¡£

¡¾Ìá³öÎÊÌâ¡¿
¢ÙCuµÄ½ðÊô»îÆÃÐÔСÓÚAl£¬Al(OH)3¾ßÓÐÁ½ÐÔ£¬Cu(OH)2Ò²¾ßÓÐÁ½ÐÔÂð£¿
¢Úͨ³£Çé¿öÏ£¬£«2¼ÛFeµÄÎȶ¨ÐÔСÓÚ£«3¼ÛFe£¬£«1¼ÛCuµÄÎȶ¨ÐÔҲСÓÚ£«2¼ÛCuÂ𣿢ÛCuOÄܱ»H2¡¢COµÈ»¹Ô­£¬Ò²Äܱ»NH3»¹Ô­Âð£¿
¡¾ÊµÑé·½°¸¡¿
£¨1£©½â¾öÎÊÌâ¢ÙÐèÓõ½µÄÒ©Æ·ÓУºCuSO4ÈÜÒº¡¢£ß£ß£ß£ß£ß£ß£ß£ß£ß£¨ÌîÊÔ¼Á£©£¬Í¬Ê±½øÐÐÏà¹ØʵÑé¡£
£¨2£©½â¾öÎÊÌâ¢ÚµÄʵÑé²½ÖèºÍÏÖÏóÈçÏ£ºÈ¡98g Cu(OH)2¹ÌÌ壬¼ÓÈÈÖÁ80¡æ¡«100¡æʱ£¬µÃµ½ºÚÉ«¹ÌÌå·ÛÄ©£¬¼ÌÐø¼ÓÈȵ½1000¡æÒÔÉÏ£¬ºÚÉ«·ÛÄ©È«²¿±ä³ÉºìÉ«·ÛÄ©A¡£ÀäÈ´ºó³ÆÁ¿AµÄÖÊÁ¿Îª72g¡£ÏòAÖмÓÈëÊÊÁ¿µÄÏ¡ÁòËᣬµÃµ½À¶É«ÈÜÒº£¬Í¬Ê±¹Û²ìµ½ÈÝÆ÷»¹ÓкìÉ«¹ÌÌå´æÔÚ¡£¾ÝЩ¿ÉÍƵã¬AµÄ»¯Ñ§Ê½Îª£ß£ß£ß£ß£ß¡£
£¨3£©Îª½â¾öÎÊÌâ¢Û£¬Éè¼ÆµÄʵÑé×°ÖÃΪ£¨¼Ð³Ö¼°Î²Æø´¦Àí×°ÖÃδ»­³ö£©£º
ʵÑéÖй۲쵽CuO±äΪºìÉ«ÎïÖÊ£¬ÎÞË®CuSO4±ä£ß£ß£ß£ßÉ«¡£Í¬Ê±Éú³ÉÒ»ÖÖ¶Ô´óÆøÎÞÎÛȾµÄÆøÌå¡£
¡¾ÊµÑé½áÂÛ¡¿
£¨1£©Cu(OH)2¾ßÓÐÁ½ÐÔ£¬Ö¤Ã÷Cu(OH)2¾ßÓÐÁ½ÐÔµÄʵÑéÏÖÏóÓ¦Êǣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߡ£
£¨2£©¸ù¾Ý¡°ÊµÑé·½°¸£¨2£©¡±£¬µÃ³öµÄ£«1¼ÛCuºÍ£«2¼ÛCuÎȶ¨ÐÔ´óСµÄ½áÂÛÊǣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߡ£
¡¾ÎÊÌâÌÖÂÛ¡¿
£¨1£©ÓÐͬѧÈÏΪNH3ÓëCuO·´Ó¦Éú³ÉµÄºìÉ«ÎïÖÊÊÇCu£¬Ò²ÓÐͬѧÈÏΪNH3ÓëCuO·´Ó¦Éú³ÉµÄºìÉ«ÎïÖÊÊÇCuºÍAµÄ»ìºÏÎï¡£ÇëÄãÉè¼ÆÒ»¸ö¼òµ¥µÄʵÑé¼ìÑéNH3ÓëCuO·´Ó¦ÖÐÉú³ÉµÄºìÉ«ÎïÖÊÖÐÊÇ·ñº¬ÓÐA£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012½ìɽ¶«Ê¡Î«·»ÊÐÈýÏØÊиßÈýÉÏѧÆÚÆÚÖÐÁªºÏ¿¼ÊÔ»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÊµÑéÌâ

( 14·Ö)ΪÁË̽¾¿Å¨¶È¶ÔÁòËáÑõ»¯ÐÔµÄÓ°Ï죬ijѧϰС×é½øÐÐÁËÒÔÏÂ̽¾¿»î¶¯£º
[̽¾¿Ò»]³ÆÈ¡ÎÞÐâÌú¶¤£¨Ì¼Ëظ֣©12.0g·ÅÈë30.0mLŨÁòËáÖУ¬¼ÓÈÈ£¬³ä·Ö·´Ó¦ºóµÃµ½ÈÜÒºX²¢ÊÕ¼¯µ½ÆøÌåY¡£
£¨1£©¼×ͬѧÈÏΪXÖгýFe3+Í⻹¿ÉÄܺ¬ÓÐFe2+¡£ÈôҪȷÈÏÆäÖеÄFe2+£¬ÇëÑ¡ÔñÏÂÁÐÊÔ¼Á£¬Éè¼Æ¼òµ¥µÄʵÑé·½°¸£¨¼òÊö²Ù×÷¹ý³Ì¡¢ÏÖÏóºÍ½áÂÛ£©                              
                                                           ¡£
¹©Ñ¡ÓÃÊÔ¼Á£ºa.KSCNÈÜÒººÍÂÈË®     b.Ìú·ÛºÍKSCNÈÜÒº   
c.Ũ°±Ë®         d.ËáÐÔKMnO4ÈÜÒº
£¨2£©ÒÒͬѧΪÁ˲ⶨÆøÌåYÖÐSO2µÄº¬Á¿£¬Éè¼ÆÈçÏÂÈýÖÖ·½°¸£º
·½°¸I.È¡672mL£¨±ê×¼×´¿ö£©ÆøÌåYͨÈë×ãÁ¿äåË®ÖУ¬È»ºó¼ÓÈë×ãÁ¿BaCl2ÈÜÒº£¬¾­Êʵ±²Ù×÷ºóµÃ¸ÉÔï¹ÌÌå4.66g¡£
·½°¸II.ÏòVmL c mol¡¤L-1ËáÐÔ¸ßÃÍËá¼ØÈÜÒºÖлºÂýͨÈëYÆøÌåaL£¨±ê×¼×´¿ö£©£¬ÈÜҺǡºÃÍêÈ«ÍÊÉ«¡£
·½°¸III£¬È¡VL£¨±ê×¼×´¿ö£©ÆøÌåY»ºÂýͨÈë×ãÁ¿µÄÇâÑõ»¯±µÈÜÒºÖУ¬³ä·Ö·´Ó¦ºó£¬¹ýÂË¡¢Ï´µÓ¡¢ºæ¸É£¬³ÆµÃ¹ÌÌåÖÊÁ¿Îªmg¡£
¢ÙÆäÖв»ºÏÀíµÄ·½°¸ÊÇ                    £¬ÀíÓÉÊÇ                                                   ¡£
¢ÚÑ¡ÔñºÏÀí·½°¸µÄÊý¾Ý¼ÆËãÆøÌåYÖÐSO2µÄÌå»ý·ÖÊý
£¨Óú¬Î´ÖªÊýµÄ´úÊýʽ±íʾ£©                                             ¡£
[̽¾¿¶þ]·ÖÎöÉÏÊöʵÑéÖÐSO2Ìå»ý·ÖÊýµÄ½á¹û£¬±ûͬѧÈÏΪÆøÌåYÖл¹¿ÉÄܺ¬Á¿ÓÐH2ºÍCO2ÆøÌ塣Ϊ´ËÉè¼ÆÁËÏÂÁÐ̽¾¿ÊµÑé×°Öã¨Í¼ÖмгÖ×°ÖÃÒÑÊ¡ÂÔ£©¡£

£¨3£©×°ÖÃAÖÐÊÔ¼ÁµÄ×÷ÓÃÊÇ                                                              ¡£
£¨4£©¼òÊöÈ·ÈÏÆøÌåYÖк¬ÓÐCO2µÄʵÑéÏÖÏ󣺠                                                                                  ¡£
£¨5£©ÓÐͬѧ¸ù¾Ý¡°F¸ÉÔï¹ÜÎÞË®ÁòËáÍ­ÊÇ·ñ±äÀ¶É«¡±È·ÈÏYÆøÌåÖÐÊÇ·ñÓÐÇâÆø£¬ÄãÈÏΪÊÇ·ñ¿É¿¿£¿                          £¨Ìî¡°¿É¿¿¡±»ò¡°²»¿É¿¿¡±£©£¬¼òÊöÀíÓÉ£º                   
                                                                                   ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012½ìºÓÄÏÊ¡Ö£ÖÝÊиßÈýµÚÒ»´ÎÖÊÁ¿Ô¤²â»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÊµÑéÌâ

(12·Ö¡µÄ³Ñо¿ÐÔѧϰС×éÓû̽¾¿SO2ÄÜ·ñÓëBaCl2ÈÜÒº·´Ó¦Éú³ÉBaSO3³Áµí¡£²éÔÄ×ÊÁϵÃÖª³£ÎÂÏÂBaSO3µÄKSPΪ£¬±¥ºÍÑÇÁòËáÖС£
(1) ½«0.1 mol ? L¡ª1µÄBaCl2ÈÜÒºµÎÈë±¥ºÍÑÇÁòËáÖУ¬_______ (Ìî¡°ÄÜ¡±»ò¡°²»ÄÜ¡±£©Éú³ÉBaSO3³Áµí£¬Ô­ÒòÊÇ______________ (Çëд³ö±ØÒªµÄÍƶϹý³Ì£©¡£
(2) ŨÁòËáµÄ·ÐµãΪ338¡ãC£¬¾Æ¾«µÆ»ðÑæµÄζÈΪ400?5000C£¬¼×ͬѧÓÃ×°ÖÃI½øÐÐʵÑ飬·¢ÏÖBaCl2ÈÜÒºÖгöÏÖ°×É«³Áµí£¬ÇÒ°×É«³Áµí²»ÈÜÓÚÑÎËá¡£
¢Ùд³ö¼ÓÈÈÊÔ¹ÜÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º_____________________
¢Ú°×É«³ÁµíµÄ»¯Ñ§Ê½ÊÇ_______£¬ÇëÓÃÀë×Ó·½³Ìʽ±íʾÉú³É¸Ã°×É«³ÁµíµÄ¿ÉÄÜÔ­Òò___________________________________
(3) ÒÒͬѧÈÏΪ¼×ͬѧµÄ×°Öò»ÍêÉÆ£¬Éè¼ÆÁ˸Ľø×°ÖÃII½øÐÐʵÑ飨¼Ð³Ö×°ÖúÍAÖмÓÈÈ×°ÖÃÒÑÂÔ£¬ÆøÃÜÐÔÒѼìÑ飩¡£

¢Ù´ò¿ªµ¯»É¼Ð£¬Í¨ÈëN2¡ª¶Îʱ¼äºó¹Ø±Õµ¯»É¼Ð
¢ÚµÎ¼ÓÒ»¶¨Á¿Å¨ÁòËᣬ¼ÓÈÈA£¬Ò»¶Îʱ¼äºóCÖÐδ¼û³ÁµíÉú³É¡£
²Ù×÷¢ÙµÄÄ¿µÄÊÇ_______£¬Ï´ÆøÆ¿BÖеÄÊÔ¼ÁÊÇ______________¡£
(4) ±ûͬѧȡÒÒʵÑéºóµÄCÖÐÈÜÒºÉÙÐí£¬µÎ¼ÓÒ»ÖÖÎÞÉ«ÈÜÒº£¬Ò²²úÉú²»ÈÜÓÚÑÎËáµÄ°×É«³Áµí£¬±ûµÎ¼ÓµÄÊÔ¼Á¿ÉÄÜÊÇ______________¡£

A£®NaOHÈÜÒºB£®Na[Al(OH)4]ÈÜÒºC£®H2O2ÈÜÒºD£®ËáÐÔ KMnO4ÈÜÒº

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄêºÓ±±Ê¡¸ßÈýÉÏѧÆÚµÚ¶þ´ÎÔ¿¼»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÊµÑéÌâ

(12·Ö)ijѧϰС×éÀûÓÃÏÂͼËùʾװÖýøÐС°ÌúÓëË®Æø·´Ó¦¡±ºÍÆäËûʵÑé(ÂÔÈ¥Á˼гÖÒÇÆ÷)¡£

(1)ΪÁË°²È«£¬¼ÓÈÈEÒÔÇ°±ØÐë½øÐеIJÙ×÷ÊÇ____________________________¡£

(2) BÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ                               _______________¡£

(3)ÒÑÖªÓз´Ó¦£ºCu2O+2H+Cu+Cu2++H2O£¬Ôò¿ÉÓÃÀ´¼ìÑé·´Ó¦ºóEÖеĺìÉ«¹ÌÌåÖгýCuÍâÊÇ·ñº¬Cu2O£¬¿ÉÓõÄÊÔ¼ÁÊÇ________(ÌîÐòºÅ)

a£®Ï¡ÏõËá    b£®Ï¡ÁòËá    c£®ÑÎËá    d£®Å¨ÁòËá  

(4)ÔÚEºóÈôÔÙ½Ó¶þ¸öÊ¢¼îʯ»ÒµÄ¸ÉÔï¹Ü(ÒÀ´Î³ÆΪFºÍG)£¬Ôò»¹¿ÉÓøÃ×°ÖòⶨˮµÄ×é³É¡£Èô·´Ó¦ºóÊ¢ÓÐÒ©Æ·µÄEµÄÖÊÁ¿¼õÇáÁËe g£¬FµÄÖÊÁ¿Ôö¼ÓÁËf g¡£Ë®ÖÐÔªËصÄÎïÖʵÄÁ¿Ö®±È¿É±íʾΪ£¨²»Óû¯¼ò£©n(H)£ºn(O)= ________£º_______£»Èô·´Ó¦ºóEÖгýCuÍ⻹º¬ÓÐÁíÒ»ÖÖ»¹Ô­²úÎïCu2O£¬Ôò¸Ã±ÈÖµ½«___________ (Ñ¡Ìî¡°Æ«´ó¡±¡°Æ«Ð¡¡±»ò¡°ÎÞÓ°Ï족)¡£

(5)ijѧÉúΪÁ˼ìÑé·´Ó¦ºó¹ÌÌåµÄ³É·Ö£¬·´Ó¦Ç°ÔÚE¹ÜÖмÓÈëÁËÑõ»¯Í­¹ÌÌå16g£¬·´Ó¦ºó³ÆÁ¿¹ÌÌåµÄÖÊÁ¿±äΪ13.6g£¬Ôò13.6gµÄ³É·ÖΪ£º___________£¨ÈôΪ»ìºÏÎÐè¼ÆËã³ö¸÷×ÔµÄÖÊÁ¿£©

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨08ïÃûÊжþÄ££©£¨±¾Ìâ12·Ö£©Ä³Ñ§Ï°Ð¡×éΪ̽¾¿SºÍCl2ÄÜ·ñ·´Ó¦£¬¾­²é×ÊÁÏ»ñµÃÐÅÏ¢£¬¸ÉÔïµÄCl2ÔÚ110¡æ¡«140¡æÓëS·´Ó¦£¬¿ÉµÃS2Cl2´ÖÆ·£¬ÓÉ´ËÉè¼ÆÈçÏÂÊÔÑé×°Ö㨼гÖ×°ÖÃδ»­³ö£©£¬Çë»Ø´ðºóÃæÎÊÌâ¡£

(1)ʵÑé¹ý³ÌÖУ¬Ê¹Ó÷ÖҺ©¶·µÎ¼ÓŨÑÎËáµÄ²Ù×÷ÊÇ                             £¨2·Ö£©£¨2£©Ó÷´Ó¦·½³Ìʽ±íʾH×°ÖõÄ×÷Óà                                       £¨2·Ö£©£¨3£©Ð´³öBÖз´Ó¦µÄÀë×Ó·½³Ìʽ                                                 £¨2·Ö£©£¨4£©C¡¢DÖеÄÊÔ¼Á·Ö±ðÊÇ                          £¬                   £¨2·Ö£©£¨5£©¾­¼ì²â´ÖÆ·Öк¬ÓÐSCl2£¬Îª¼õÉÙSCl2µÄÉú³É£¬¹Ø¼üµÄ²Ù×÷ÊÇ                 £¨2·Ö£©£¨6£©Fµ¼¹Ü¿ÉÄܻᷢÉú¶ÂÈû£¬ÇëÔÚC¡¢DÖ®¼äÉè¼ÆÒ»¸ö·À¶ÂÈû×°ÖÃÒÔÃâ·¢ÉúΣÏÕ¡££¨ÒªÇó»­³ö×°ÖÃͼ£¬±ê³öÊÔ¼ÁÃû³Æ£¬¼Ð³Ö×°Öò»Ðè»­³ö£©                              £¨2·Ö£©

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸