´Óº¬Í­¡¢Òø¡¢½ðºÍ²¬µÄ¿é×´½ðÊô·ÏÁÏÖÐÌáÈ¡²¬¡¢½ð¡¢ÒøµÄÒ»ÖÖ¹¤ÒÕÈçÏ£º

[À´Ô´:ѧ#¿Æ#ÍøZ#X#X#K]

 

 

 

 

 

 

¸ù¾ÝÒÔÉϹ¤ÒջشðÏÂÁÐÎÊÌ⣺

£¨1£©µç½âʱ£¬ÒÔ_____________ΪÑô¼«£¬´¿Í­ÎªÒõ¼«£¬CuSO4ÈÜҺΪµç½âÒº£¬ÔòÒõ¼«µÄµç¼«·´Ó¦·½³ÌʽΪ                             

£¨2£©AgClÈÜÓÚ°±Ë®ºóËùµÃµÄÈÜÒºº¬ÓеÄÒ»ÖÖÑôÀë×Ó£¬ÔÚ¼îÐÔÌõ¼þÏ£¬Ò²¿ÉÓÃÆÏÌÑÌǽ«Æ仹ԭΪÒø£¬Ð´³ö¸Ã·´Ó¦µÄÀë×Ó·½³Ìʽ£º                                        

£¨3£©Ð´³ö²½Öè¢ÜµÄÀë×Ó·½³Ìʽ£º

                                                                  

£¨4£©½ðºÍŨÏõËá·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºAu +6HNO3(Ũ)Au(NO3)3+3NO2¡ü+ 3H2O£¬Òò¸Ã·´Ó¦ÕýÏò½øÐеij̶ȼ«Ð¡£¬ËùÒԽ𼸺õ²»ÈÜÓÚŨÏõËᣬµ«½ðÈ´¿ÉÒÔÈÜÓÚÍõË®£¬ÊÔ¼òÒª½âÊÍÖ®£º                                                                

                                                      

£¨5£©Ð´³ö·´Ó¦¢ÝµÄ»¯Ñ§·´Ó¦·½³Ìʽ

____________________________________________________________________________

 

¡¾´ð°¸¡¿

£¨¹²15·Ö£©

£¨1£©½ðÊô·ÏÁÏ£¨1·Ö£©¡¢Cu2+ + 2e¡ú Cu£¨2·Ö£©

£¨2£©2Ag(NH3)2+ + 2OH¡ª+CH2OH(CHOH)4CHO¡úCH2OH(CHOH)4COO+ NH4+ + 2Ag¡ý+ 3NH3 + H2O£¨Ë®Ô¡¼ÓÈÈ£©£¨3·Ö£©

£¨3£©2AuCl4+ 3SO2 + 6 H2O = 2Au + 8Cl+ 3SO42 + 12H+ £¨3·Ö£©

£¨4£©ÍõË®Öк¬ÓдóÁ¿µÄCl£¬Au3+ÓëCl¡ª¿ÉÉú³ÉAuCl4£¬Ê¹¸ÃƽºâÖÐAu3+Ũ¶È½µµÍ£¬Æ½ºâÕýÒÆ£¬½ð¼´¿ÉÈÜÓÚÍõË®¡££¨3·Ö£©

£¨5£©3(NH4)2 PtCl6 == 3Pt + 2N2 +18HCl + 2NH3£¨435¡æ£©£¨3·Ö£©

¡¾½âÎö¡¿

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

´Óº¬Òø¡¢Í­¡¢½ðºÍ²¬µÄ½ðÊô·ÏÁÏÖÐÌáÈ¡½ð¡¢Òø¡¢²¬µÄÒ»ÖÖ¹¤ÒÕÈçÏ£º
¾«Ó¢¼Ò½ÌÍø
¸ù¾ÝÒÔÉϹ¤ÒջشðÏÂÁÐÎÊÌ⣺
£¨1£©µç½âʱ£¬ÒÔ½ðÊô·ÏÁÏΪÑô¼«£¬´¿Í­ÎªÒõ¼«£¬CuSO4ÈÜҺΪµç½âÒº£¬Ð´³öµç¼«·´Ó¦Ê½£ºÑô¼«£º
 
£¬Òõ¼«£º
 
£»
Èô¹¤×÷Ò»¶Îʱ¼äºó²âµÃµ¼ÏßÉÏͨ¹ýÁË3.01¡Á1024¸öe-£¬ÔòÒõ¼«ÓÐ
 
gÍ­Îö³ö£®
£¨2£©²½Ö裨4£©ÖÐSO2±»Ñõ»¯³ÉH2SO4£¬ÊÔд³ö¸Ã²½ÖèµÄÀë×Ó·´Ó¦·½³Ìʽ£º
 
£»
£¨3£©½ðºÍŨÏõËá·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºAu+6HNO3£¨Å¨£©?Au£¨NO3£©3+3NO2¡ü+3H2O
µ«¸Ã·´Ó¦µÄƽºâ³£ÊýºÜС£¬ËùÒÔ½ðºÍŨÏõËἸºõ²»·´Ó¦£¬µ«½ðÈ´¿ÉÒÔÈÜÓÚÍõË®£¬ÊÔ¼òÒª½âÊÍÖ®£º
 
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

´Óº¬Í­¡¢Òø¡¢½ðºÍ²¬µÄ¿é×´½ðÊô·ÏÁÏÖÐÌáÈ¡²¬¡¢½ð¡¢ÒøµÄÒ»ÖÖ¹¤ÒÕÈçÏ£º

 

 

 

 

 

 

¸ù¾ÝÒÔÉϹ¤ÒջشðÏÂÁÐÎÊÌ⣺

£¨1£©µç½âʱ£¬ÒÔ_____________ΪÑô¼«£¬´¿Í­ÎªÒõ¼«£¬CuSO4ÈÜҺΪµç½âÒº£¬ÔòÒõ¼«µÄµç¼«·´Ó¦·½³ÌʽΪ                             

£¨2£©AgClÈÜÓÚ°±Ë®ºóËùµÃµÄÈÜÒºº¬ÓеÄÒ»ÖÖÑôÀë×Ó£¬ÔÚ¼îÐÔÌõ¼þÏ£¬Ò²¿ÉÓÃÆÏÌÑÌǽ«Æ仹ԭΪÒø£¬Ð´³ö¸Ã·´Ó¦µÄÀë×Ó·½³Ìʽ£º                                        

£¨3£©Ð´³ö²½Öè¢ÜµÄÀë×Ó·½³Ìʽ£º

                                                                  

£¨4£©½ðºÍŨÏõËá·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºAu +6HNO3(Ũ)Au(NO3)3+3NO2¡ü+ 3H2O£¬Òò¸Ã·´Ó¦ÕýÏò½øÐеij̶ȼ«Ð¡£¬ËùÒԽ𼸺õ²»ÈÜÓÚŨÏõËᣬµ«½ðÈ´¿ÉÒÔÈÜÓÚÍõË®£¬ÊÔ¼òÒª½âÊÍÖ®£º                                                                

                                                      

£¨5£©Ð´³ö·´Ó¦¢ÝµÄ»¯Ñ§·´Ó¦·½³Ìʽ

____________________________________________________________________________

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£ºÖØÇìÒ»ÖÐ2010¼¶¸ßÈýÏÂѧÆÚ¿¼Ç°Ä£ÄâÀí×Û»¯Ñ§ ÌâÐÍ£ºÌî¿ÕÌâ

´Óº¬Í­¡¢Òø¡¢½ðºÍ²¬µÄ¿é×´½ðÊô·ÏÁÏÖÐÌáÈ¡²¬¡¢½ð¡¢ÒøµÄÒ»ÖÖ¹¤ÒÕÈçÏ£º

¸ù¾ÝÒÔÉϹ¤ÒջشðÏÂÁÐÎÊÌ⣺
£¨1£©µç½âʱ£¬ÒÔ_____________ΪÑô¼«£¬´¿Í­ÎªÒõ¼«£¬CuSO4ÈÜҺΪµç½âÒº£¬ÔòÒõ¼«µÄµç¼«·´Ó¦·½³ÌʽΪ                             
£¨2£©AgClÈÜÓÚ°±Ë®ºóËùµÃµÄÈÜÒºº¬ÓеÄÒ»ÖÖÑôÀë×Ó£¬ÔÚ¼îÐÔÌõ¼þÏ£¬Ò²¿ÉÓÃÆÏÌÑÌǽ«Æ仹ԭΪÒø£¬Ð´³ö¸Ã·´Ó¦µÄÀë×Ó·½³Ìʽ£º                                        
£¨3£©Ð´³ö²½Öè¢ÜµÄÀë×Ó·½³Ìʽ£º
                                                                  
£¨4£©½ðºÍŨÏõËá·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºAu +6HNO3(Ũ)Au(NO3)3+3NO2¡ü+ 3H2O£¬Òò¸Ã·´Ó¦ÕýÏò½øÐеij̶ȼ«Ð¡£¬ËùÒԽ𼸺õ²»ÈÜÓÚŨÏõËᣬµ«½ðÈ´¿ÉÒÔÈÜÓÚÍõË®£¬ÊÔ¼òÒª½âÊÍÖ®£º                                                                
                                                      
£¨5£©Ð´³ö·´Ó¦¢ÝµÄ»¯Ñ§·´Ó¦·½³Ìʽ
____________________________________________________________________________

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

´Óº¬Í­¡¢Òø¡¢½ðºÍ²¬µÄ¿é×´½ðÊô·ÏÁÏÖÐÌáÈ¡²¬¡¢½ð¡¢ÒøµÄÒ»ÖÖ¹¤ÒÕÈçÏ£º

¸ù¾ÝÒÔÉϹ¤ÒջشðÏÂÁÐÎÊÌ⣺

£¨1£©µç½âʱ£¬ÒÔ_____________ΪÑô¼«£¬´¿Í­ÎªÒõ¼«£¬CuSO4ÈÜҺΪµç½âÒº£¬ÔòÒõ¼«µÄµç¼«·´Ó¦·½³ÌʽΪ                             

£¨2£©AgClÈÜÓÚ°±Ë®ºóËùµÃµÄÈÜÒºº¬ÓеÄÒ»ÖÖÑôÀë×Ó£¬ÔÚ¼îÐÔÌõ¼þÏ£¬Ò²¿ÉÓÃÆÏÌÑÌǽ«Æ仹ԭΪÒø£¬Ð´³ö¸Ã·´Ó¦µÄÀë×Ó·½³Ìʽ£º                                        

£¨3£©Ð´³ö²½Öè¢ÜµÄÀë×Ó·½³Ìʽ£º

                                                                  

£¨4£©½ðºÍŨÏõËá·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºAu +6HNO3(Ũ)Au(NO3)3+3NO2¡ü+ 3H2O£¬Òò¸Ã·´Ó¦ÕýÏò½øÐеij̶ȼ«Ð¡£¬ËùÒԽ𼸺õ²»ÈÜÓÚŨÏõËᣬµ«½ðÈ´¿ÉÒÔÈÜÓÚÍõË®£¬ÊÔ¼òÒª½âÊÍÖ®£º                                                                

                                                      

£¨5£©Ð´³ö·´Ó¦¢ÝµÄ»¯Ñ§·´Ó¦·½³Ìʽ

____________________________________________________________________________

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸