ijÈÜÒºÖÐÖ»º¬ÓÐNa£«¡¢H£«¡¢OH£­¡¢X£­ËÄÖÖÀë×Ó£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ

A£®ÈÜÒºÖв»¿ÉÄÜ´æÔÚ£ºc(Na£«)>c (X£­)>c(OH£­)>c(H£«)

B£®Èôc(OH£­)>c(H£«)£¬ÈÜÒºÖв»¿ÉÄÜ´æÔÚ£ºc(Na£«)>c(OH£­)>c(X£­)>c(H£«)

C£®ÈôÈÜÒºÖÐc(X£­) = c(Na£«)£¬ÔòÈÜÒºÒ»¶¨³ÊÖÐÐÔ

D£®ÈôÈÜÖÊΪNaX¡¢HX£¬ÔòÒ»¶¨´æÔÚ£ºc(X£­)>c(Na£«)>c(H£«)>c(OH£­)

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2008?·ðɽ¶þÄ££©Ä³ÈÜÒºÖÐÖ»º¬ÓÐNa+¡¢H+¡¢OH-¡¢A-ËÄÖÖÀë×Ó£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2013?³ÐµÂÄ£Ä⣩ijÈÜÒºÖÐÖ»º¬ÓÐNa+¡¢Al3+¡¢Cl-¡¢SO42- ËÄÖÖÀë×Ó£¬ÒÑ֪ǰÈýÖÖÀë×ӵĸöÊý±ÈΪ3£º2£º1£¬ÔòÈÜÒºÖÐAl3+ºÍ SO42-µÄÀë×Ó¸öÊý±ÈΪ£¨¡¡¡¡£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ijÈÜÒºÖÐÖ»º¬ÓÐNa+¡¢Al3+¡¢Cl-¡¢SO42-ËÄÖÖÀë×Ó£¬ÒÑÖªC£¨Na+£©=0.2mol/L¡¢C£¨Al3+£©=0.4mol/L¡¢C£¨Cl-£©=0.6mol/L¡¢£¬ÔòÈÜÒºÖÐC£¨SO42-£©Îª
0.4mol/L
0.4mol/L
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ijÈÜÒºÖÐÖ»º¬ÓÐNa+¡¢Al3+¡¢Cl-¡¢SO42- ËÄÖÖÀë×Ó£¬ÒÑ֪ǰÈýÖÖÀë×ӵĸöÊý±ÈΪ3£º2£º1£¬ÔòÈÜÒºÖÐNa+ºÍSO42-µÄÀë×Ó¸öÊý±ÈΪ£¨¡¡¡¡£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¾­²â¶¨Ä³ÈÜÒºÖÐÖ»º¬ÓÐNa+¡¢CH3COO-¡¢H+¡¢OH-ËÄÖÖÀë×Ó£¬ÇÒÀë×ÓŨ¶È´óС˳ÐòΪc£¨CH3COO-£©£¾c£¨Na+£©£¾c£¨H+£©£¾c£¨OH-£©£¬Æä¿ÉÄܵÄÇéÐÎÊÇ£¨¡¡¡¡£©

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸