£¨6·Ö£©773 K¡¢¹Ì¶¨Ìå»ýµÄÈÝÆ÷ÖÐ,·´Ó¦CO£¨g£©£«2H2£¨g£©CH3OH£¨g£©¹ý³ÌÖÐÄÜÁ¿±ä»¯ÈçÏÂͼ¡£ÇúÏߢò±íʾʹÓô߻¯¼ÁʱµÄÄÜÁ¿±ä»¯¡£ÈôͶÈëamol CO¡¢2amol H2£¬Æ½ºâʱÄÜÉú³É0£®1amol CH3OH£¬·´Ó¦¾Í¾ß¹¤ÒµÓ¦ÓüÛÖµ¡£

¢Ù Èô°´ÉÏÊöͶÁϱÈʹ¸Ã·´Ó¦¾ßÓй¤ÒµÓ¦ÓüÛÖµ£¬COµÄƽºâת»¯ÂÊ×îСΪ             £»

¢Ú ÔÚÈÝÆ÷ÈÝ»ý²»±äµÄÇ°ÌáÏ£¬ÓûÌá¸ßH2µÄת»¯ÂÊ£¬¿É²ÉÈ¡µÄ´ëÊ©£¨´ðÁ½Ïî¼´¿É£©                           ¡¢                           £»

¢Û ÏÂÁÐÓë´ß»¯¼ÁÓйصÄ˵·¨ÖУ¬ÕýÈ·µÄÊÇ        £¨Ìî×ÖĸÐòºÅ£©¡£

a£® ʹÓô߻¯¼Á£¬Ê¹·´Ó¦CO£¨g£©£«2H2£¨g£©CH3OH£¨g£©£»¦¤H>£­91kJ¡¤mol£­1

b£® ʹÓô߻¯¼Á, Äܹ»Ìá¸ß·´Ó¦Îïת»¯ÂÊ

c£® ʹÓô߻¯¼Á£¬²»Äܸı䷴ӦµÄƽºâ³£ÊýK

 

 ¢Ù £¨2·Ö£©10%

¢Ú £¨2·Ö£©Ôö´óCOŨ¶È¡¢Êʵ±½µµÍζȡ¢¼°Ê±·ÖÀëÉú³ÉµÄCH3OH £¨»Ø´ðÆäÖÐÁ½Ïî¼´¿ÉµÃ·Ö2·Ö£¬Ö»»Ø´ðÒ»ÏîµÃ1·Ö£©   ¢Û £¨2·Ö£©c

½âÎö:ÂÔ

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

773 K¡¢¹Ì¶¨Ìå»ýµÄÈÝÆ÷ÖÐ,·´Ó¦CO£¨g£©£«2H2£¨g£©CH3OH£¨g£©¹ý³ÌÖÐÄÜÁ¿±ä»¯ÈçÏÂͼ¡£ÇúÏߢò±íʾʹÓô߻¯¼ÁʱµÄÄÜÁ¿±ä»¯¡£ÈôͶÈëa mol CO¡¢2a mol H2£¬Æ½ºâʱÄÜÉú³É0£®1a mol CH3OH£¬·´Ó¦¾Í¾ß¹¤ÒµÓ¦ÓüÛÖµ¡£

¢Ù Èô°´ÉÏÊöͶÁϱÈʹ¸Ã·´Ó¦¾ßÓй¤ÒµÓ¦ÓüÛÖµ£¬COµÄƽºâת»¯ÂÊ×îСΪ              £»

¢Ú ÔÚÈÝÆ÷ÈÝ»ý²»±äµÄÇ°ÌáÏ£¬ÓûÌá¸ßH2µÄת»¯ÂÊ£¬¿É²ÉÈ¡µÄ´ëÊ©£¨´ðÁ½Ïî¼´¿É£©                            ¡¢                            £»

¢Û ÏÂÁÐÓë´ß»¯¼ÁÓйصÄ˵·¨ÖУ¬ÕýÈ·µÄÊÇ        £¨Ìî×ÖĸÐòºÅ£©¡£

a£® ʹÓô߻¯¼Á£¬Ê¹·´Ó¦CO£¨g£©£«2H2£¨g£©CH3OH£¨g£©£»¦¤H>£­91 kJ¡¤mol£­1

b£® ʹÓô߻¯¼Á, Äܹ»Ìá¸ß·´Ó¦Îïת»¯ÂÊ

c£® ʹÓô߻¯¼Á£¬²»Äܸı䷴ӦµÄƽºâ³£ÊýK

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

Ó¦Óû¯Ñ§·´Ó¦ÐèÒªÑо¿»¯Ñ§·´Ó¦µÄÌõ¼þ¡¢Ï޶ȺÍËÙÂÊ¡£

£¨1£©773 K¡¢¹Ì¶¨Ìå»ýµÄÈÝÆ÷ÖÐ,·´Ó¦CO£¨g£©£«2H2£¨g£©CH3OH£¨g£©¹ý³ÌÖÐ

ÄÜÁ¿±ä»¯ÈçÏÂͼ¡£ÇúÏߢò±íʾʹÓô߻¯¼ÁʱµÄÄÜÁ¿±ä»¯¡£ÈôͶÈëamol CO¡¢2amol H2£¬Æ½ºâʱÄÜÉú³É0.1a mol CH3OH£¬·´Ó¦¾Í¾ß¹¤ÒµÓ¦ÓüÛÖµ¡£

Èô°´ÉÏÊöͶÁϱÈʹ¸Ã·´Ó¦¾ßÓй¤ÒµÓ¦ÓüÛÖµ£¬COµÄƽºâת»¯ÂÊ×îСΪ¡¡           £»

 ¢ÚÔÚÈÝÆ÷ÈÝ»ý²»±äµÄÇ°ÌáÏ£¬ÓûÌá¸ßH2µÄת»¯ÂÊ£¬¿É²ÉÈ¡µÄ´ëÊ©£¨´ðÁ½Ïî¼´¿É£©                   ¡¢¡¡¡¡¡¡¡¡                           £»

¡¡  ¢ÛÏÂÁÐÓë´ß»¯¼ÁÓйصÄ˵·¨ÖУ¬ÕýÈ·µÄÊÇ¡¡         £¨Ìî×ÖĸÐòºÅ£©¡£

 a£®Ê¹Óô߻¯¼Á£¬Ê¹·´Ó¦ CO(g)£«2H2£¨g£©CH3OH£¨g£© ¦¤H>£­91 kJ¡¤mol£­1

 b£®Ê¹Óô߻¯¼Á£¬Äܹ»Ìá¸ß·´Ó¦Îïת»¯ÂÊ

c£®Ê¹Óô߻¯¼Á£¬²»Äܸı䷴ӦµÄƽºâ³£ÊýK

   £¨2£©¸ßÌúËáÑÎÔÚÄÜÔ´»·±£ÁìÓòÓй㷺ÓÃ;¡£ÎÒ¹úѧÕßÌá³öÓÃÄø£¨Ni£©¡¢Ìú×÷µç¼«µç½âŨNaOHÈÜÒºÖƱ¸¸ßÌúËáÑÎNa2FeO4µÄ·½°¸£¬×°ÖÃÈçÏÂͼIËùʾ¡£

¢ÙFeµç¼«×÷¡¡              ¼«£¨Ìî¡°Òõ¡±»ò¡°Ñô¡±£©£»

¢ÚNiµç¼«µÄµç¼«·´Ó¦Ê½Îª£º¡¡¡¡                                          ¡£

£¨3£©ÓûÓÃÏÂͼII×°ÖÃͨ¹ý²â¶¨ÆøÌåÉú³ÉÁ¿²âËãÏõËá±»»¹Ô­µÄËÙÂÊ£¬µ±·´Ó¦ÎïµÄŨ¶È¡¢ÓÃÁ¿¼°ÆäËûÓ°ÏìËÙÂʵÄÌõ¼þÈ·¶¨Ö®ºó£¬¿ÉÒÔͨ¹ý²â¶¨                   

                                                        ÍÆËã·´Ó¦ËÙÂÊ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â

(16·Ö)Ó¦Óû¯Ñ§·´Ó¦ÐèÒªÑо¿»¯Ñ§·´Ó¦µÄÌõ¼þ¡¢Ï޶ȺÍËÙÂÊ¡£

£¨1£©ÒÑÖª·´Ó¦£ºBr2£«2Fe2£«£½2Br£­£«2Fe3£« £¬Ïò10mL 0.1 mol¡¤L£­1µÄFeBr2ÈÜÒºÖÐͨÈë0.001 mol Cl2£¬·´Ó¦ºó£¬ÈÜÒºÖгýº¬ÓÐCl-Í⣬»¹Ò»¶¨ÓР         (ÌîÐòºÅ)¡£

¢Ùº¬Fe2+£¬²»º¬Fe3+¢Ú º¬Fe3+£¬²»º¬Br-¢Û º¬Fe3+£¬»¹º¬ÓÐBr-

£¨2£©773 K¡¢¹Ì¶¨Ìå»ýµÄÈÝÆ÷ÖÐ,·´Ó¦CO(g)£«2H2(g)CH3OH(g)¹ý³ÌÖÐÄÜÁ¿±ä»¯ÈçÏÂͼ¡£ÇúÏߢò±íʾʹÓô߻¯¼ÁʱµÄÄÜÁ¿±ä»¯¡£ÈôͶÈëamol CO¡¢2a mol H2£¬Æ½ºâʱÄÜÉú³É0.1a mol CH3OH£¬·´Ó¦¾Í¾ß¹¤ÒµÓ¦ÓüÛÖµ¡£

¢ÙÈô°´ÉÏÊöͶÁϱÈʹ¸Ã·´Ó¦¾ßÓй¤ÒµÓ¦ÓüÛÖµ£¬COµÄƽºâת»¯ÂÊ×îСΪ          £»

¢ÚÔÚÈÝÆ÷ÈÝ»ý²»±äµÄÇ°ÌáÏ£¬ÓûÌá¸ßH2µÄת»¯ÂÊ£¬¿É²ÉÈ¡µÄ´ëÊ©(´ðÁ½Ïî¼´¿É)                           ¡¢                           £»

¢ÛÏÂÁÐÓë´ß»¯¼ÁÓйصÄ˵·¨ÖУ¬ÕýÈ·µÄÊÇ        (Ìî×ÖĸÐòºÅ)¡£

a. ʹÓô߻¯¼Á£¬Ê¹·´Ó¦CO(g)£«2H2(g)CH3OH(g)  ¦¤H>£­91kJ¡¤mol£­1

b. ʹÓô߻¯¼Á, Äܹ»Ìá¸ß·´Ó¦Îïת»¯ÂÊ

c. ʹÓô߻¯¼Á£¬²»Äܸı䷴ӦµÄƽºâ³£ÊýK

£¨3£©¸ßÌúËáÑÎÔÚÄÜÔ´»·±£ÁìÓòÓй㷺ÓÃ;¡£ÎÒ¹úѧÕßÌá³öÓÃÄø(Ni)¡¢Ìú×÷µç¼«µç½âŨNaOHÈÜÒºÖƱ¸¸ßÌúËáÑÎNa2FeO4µÄ·½°¸£¬×°ÖÃÈçÓÒͼËùʾ¡£

¢Ù Ni×÷           (Ìî¡°Òõ¡±»ò¡°Ñô¡±)¼«£»

¢ÚNiµç¼«µÄµç¼«·´Ó¦Ê½Îª£º                                ¡£

£¨4£©Ñõ»¯»¹Ô­·´Ó¦ÖÐʵ¼ÊÉÏ°üº¬Ñõ»¯ºÍ»¹Ô­Á½¸ö¹ý³Ì¡£ÏÂÃæÊÇHNO3·¢ÉúµÄÒ»¸ö»¹Ô­¹ý³ÌµÄ·´Ó¦Ê½£ºNO-3£«4H£«£«3e£­¡úNO£«2H2O

¢ÙKMnO4¡¢HCl¡¢Fe(NO3)2¡¢CuO¡¢KIÎåÖÖÎïÖÊÖеĠ          (Ìѧʽ)ÄÜʹÉÏÊö»¹Ô­¹ý³Ì·¢Éú¡£

¢ÚÓûÓÃÏÂͼװÖÃͨ¹ý²â¶¨ÆøÌåÉú³ÉÁ¿²âËãÏõËá±»»¹Ô­µÄËÙÂÊ£¬µ±·´Ó¦ÎïµÄŨ¶È¡¢ÓÃÁ¿¼°ÆäËûÓ°ÏìËÙÂʵÄÌõ¼þÈ·¶¨Ö®ºó£¬¿ÉÒÔͨ¹ý²â¶¨                     ÍÆ(¼Æ)Ëã·´Ó¦ËÙÂÊ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010Ä긣½¨Ê¡¸ß¶þÉÏѧÆÚÆÚÖп¼ÊÔ»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÌî¿ÕÌâ

Ó¦Óû¯Ñ§·´Ó¦ÐèÒªÑо¿»¯Ñ§·´Ó¦µÄÌõ¼þ¡¢Ï޶ȺÍËÙÂÊ¡£

£¨1£©773 K¡¢¹Ì¶¨Ìå»ýµÄÈÝÆ÷ÖÐ,·´Ó¦CO£¨g£©£«2H2£¨g£©CH3OH£¨g£©¹ý³ÌÖÐ

ÄÜÁ¿±ä»¯ÈçÏÂͼ¡£ÇúÏߢò±íʾʹÓô߻¯¼ÁʱµÄÄÜÁ¿±ä»¯¡£ÈôͶÈëamol CO¡¢2amol H2£¬Æ½ºâʱÄÜÉú³É0.1a mol CH3OH£¬·´Ó¦¾Í¾ß¹¤ÒµÓ¦ÓüÛÖµ¡£

¢Ù         Èô°´ÉÏÊöͶÁϱÈʹ¸Ã·´Ó¦¾ßÓй¤ÒµÓ¦ÓüÛÖµ£¬COµÄƽºâת»¯ÂÊ×îСΪ¡¡           £»

¢Ú          ¢ÚÔÚÈÝÆ÷ÈÝ»ý²»±äµÄÇ°ÌáÏ£¬ÓûÌá¸ßH2µÄת»¯ÂÊ£¬¿É²ÉÈ¡µÄ´ëÊ©£¨´ðÁ½Ïî¼´¿É£©                   ¡¢¡¡¡¡¡¡¡¡                           £»

¢Û         ¡¡  ¢ÛÏÂÁÐÓë´ß»¯¼ÁÓйصÄ˵·¨ÖУ¬ÕýÈ·µÄÊÇ¡¡         £¨Ìî×ÖĸÐòºÅ£©¡£

¢Ü          a£®Ê¹Óô߻¯¼Á£¬Ê¹·´Ó¦ CO(g)£«2H2£¨g£©CH3OH£¨g£© ¦¤H>£­91 kJ¡¤mol£­1

¢Ý          b£®Ê¹Óô߻¯¼Á£¬Äܹ»Ìá¸ß·´Ó¦Îïת»¯ÂÊ

c£®Ê¹Óô߻¯¼Á£¬²»Äܸı䷴ӦµÄƽºâ³£ÊýK

   £¨2£©¸ßÌúËáÑÎÔÚÄÜÔ´»·±£ÁìÓòÓй㷺ÓÃ;¡£ÎÒ¹úѧÕßÌá³öÓÃÄø£¨Ni£©¡¢Ìú×÷µç¼«µç½âŨNaOHÈÜÒºÖƱ¸¸ßÌúËáÑÎNa2FeO4µÄ·½°¸£¬×°ÖÃÈçÏÂͼIËùʾ¡£

¢ÙFeµç¼«×÷¡¡              ¼«£¨Ìî¡°Òõ¡±»ò¡°Ñô¡±£©£»

¢ÚNiµç¼«µÄµç¼«·´Ó¦Ê½Îª£º¡¡¡¡                                          ¡£

£¨3£©ÓûÓÃÏÂͼII×°ÖÃͨ¹ý²â¶¨ÆøÌåÉú³ÉÁ¿²âËãÏõËá±»»¹Ô­µÄËÙÂÊ£¬µ±·´Ó¦ÎïµÄŨ¶È¡¢ÓÃÁ¿¼°ÆäËûÓ°ÏìËÙÂʵÄÌõ¼þÈ·¶¨Ö®ºó£¬¿ÉÒÔͨ¹ý²â¶¨                   

                                                        ÍÆËã·´Ó¦ËÙÂÊ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸