Ä¿Ç°²â¶¨¿ÕÆøÖÐSO2º¬Á¿Ö÷ÒªÓÃÑõ»¯»¹Ô­·´Ó¦£®ÒÑÖªSO2ÆøÌåÓëËáÐÔKMnO4ÈÜÒº·´Ó¦Ê±£¬MnO4- ±»»¹Ô­ÎªMn2+£¬SO2±»Ñõ»¯³ÉSO42-£®
Ϊ²â¶¨Ä³µØ·½µÄ¿ÕÆøÖÐSO2ºÍ¿ÉÎüÈë¿ÅÁ£µÄº¬Á¿£¬¼×ͬѧÉè¼ÆÁËÈçͼËùʾµÄʵÑé×°Öãº

¢ÙÆäÖУº»ò±íʾÃܱÕÈÝÆ÷£» ±íʾÆøÌåÁ÷Ëٹܣ¨µ¥Î»Ê±¼äÄÚͨ¹ýÆøÌåµÄÌå»ýºã¶¨£¬ÇÒÎÞ³ý³¾ºÍÎüÊÕÆøÌå×÷Óã©£»±íʾÃÞ»¨£»¿ÅÁ£Îü¸½¼Á¿ÉÒÔÎüÊÕ¿ÉÎüÈëµÄ¿ÅÁ££»¡ú±íʾÆøÌåµÄÁ÷Ïò£®
¢ÚËáÐÔKMnO4ÈÜÒºÌå»ýΪ200mL£¬Å¨¶ÈΪ0.1mol?L-1£®»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÅäÖÆ200mL0.1mol?L-1ËáÐÔKMnO4ÈÜÒº£¬ÐèÓõ½µÄÒÇÆ÷°´Ê¹ÓõÄÏȺó˳ÐòÒÀ´ÎÓÐ______¡¢²£Á§°ô¡¢______¡¢______¡¢______£®²£Á§°ôµÄ×÷ÓÃÊÇ______£®
£¨2£©Ð´³ö²¢Åäƽ²â¶¨SO2º¬Á¿µÄÀë×Ó·½³Ìʽ£º______
£¨3£©ÈôÆøÌåÁ÷ËÙ¹ÜÖÐÆøÌåÁ÷ËÙΪacm3/min£¬µ±tminʱËáÐÔKMnO4ÈÜҺǡºÃÍÊÉ«£¬Ôò¿ÕÆøÖÐSO2µÄº¬Á¿Îª______£¨g/cm3£©£®
£¨4£©ÊµÑéÖÐÃÞ»¨µÄ×÷ÓÃÊÇ______£»
ÈôÒª²â¶¨¿ÕÆøÖпÉÎüÈë¿ÅÁ£µÄº¬Á¿£¨g/L£©£¬»¹ÐèÒª²â³öµÄÊý¾ÝÊÇ______
£¨5£©ÒÒͬѧ°´ÕÕͬÑùµÄ·½·¨²âÁ¿¿ÕÆøÖÐSO2µÄº¬Á¿£¬Ëù²âµÃµÄÊýÖµ×ÜÊDZÈʵ¼Êº¬Á¿Æ«µÍ£¬×î¿ÉÄܵÄÔ­ÒòÊÇ£¨¼ÙÉèÈÜÒºÅäÖÆ¡¢³ÆÁ¿»òÁ¿È¡¼°¸÷ÖÖ¶ÁÊý¾ùÎÞ´íÎ󣩣º______£®

½â£º£¨1£©ÅäÖÆ200mL0.1mol?L-1ËáÐÔKMnO4ÈÜÒº£¬ÓÉÓÚʵÑéÊÒûÓÐ200mLÈÝÁ¿Æ¿£¬Ó¦ÓÃ250mLÈÝÁ¿Æ¿ÅäÖÆ£¬ÐèÓÃÍÐÅÌÌìƽ³ÆÁ¿¸ßÃÌËá¼Ø¹ÌÌ壬ÔÚÉÕ±­ÖмÓË®ÈܽⲢÓò£Á§°ô½Á°è£¬ÀäÈ´ºóÓò£Á§°ôתÒÆÖÁÈÝÁ¿Æ¿ÖУ¬²£Á§°ôµÄ×÷ÓÃÊÇÒýÁ÷£¬¼ÓË®ÖÁÈÜÒºÀë¿Ì¶ÈÏß1¡«2cmʱ¸ÄÓýºÍ·µÎ¹ÜµÎ¼ÓÖÁ¿Ì¶ÈÏߣ¬
¹Ê´ð°¸Îª£ºÌìƽ£»ÉÕ±­£»250mLÈÝÁ¿Æ¿£»½ºÍ·µÎ¹Ü£»½Á°èºÍÒýÁ÷£»
£¨2£©SO2¾ßÓл¹Ô­ÐÔ£¬¸ßÃÌËá¼Ø¾ßÓÐÑõ»¯ÐÔ£¬¶þÕß·¢ÉúÑõ»¯»¹Ô­·´Ó¦Éú³ÉSO42-ºÍMn2+Àë×Ó£¬
·´Ó¦µÄ·½³ÌʽΪ5SO2+2MnO4-+2H2O¨T5SO42-+2Mn2++4H+£¬
¹Ê´ð°¸Îª£º5SO2+2MnO4-+2H2O¨T5SO42-+2Mn2++4H+£»
£¨3£©¸ßÃÌËá¼ØµÄÎïÖʵÄÁ¿Îª0.2L¡Á0.1moL/L=0.02moL£¬
¸ù¾Ý·´Ó¦·½³Ìʽ5SO2+2MnO4-+2H2O¨T5SO42-+2Mn2++4H+£¬
¿ÉÖªatml¿ÕÆøÖк¬ÓÐSO2µÄÎïÖʵÄÁ¿Îª=0.05mol£¬
ÖÊÁ¿Îª0.05mol¡Á64g/moL=3.2g£¬
ËùÒÔ¿ÕÆøÖÐSO2µÄº¬Á¿Îªg/cm3£¬
¹Ê´ð°¸Îª£º£»
£¨4£©ÃÞ»¨¾ßÓÐÎü¸½ÐÔ£¬¿ÉÎüÊÕÆøÁ÷ÖеĿÅÁ££¬·ÀÖ¹¿ÉÎüÈë¿ÅÁ£¶ÂÈûµ¼Æø¹Ü»ò½øÈëËáÐÔ¸ßÃÌËá¼ØÈÜÒºÖУ¬Ê¹²âÁ¿ÖÊÁ¿²»×¼£¬ÈôÒª²â¶¨¿ÕÆøÖпÉÎüÈë¿ÅÁ£µÄº¬Á¿£¨g/L£©£¬»¹ÐèÒª²â³öµÄÊý¾ÝÊÇÎüÊÕÇ°ºó¿ÅÁ£Îü¸½¼Á¡¢ÃÞ»¨¡¢Ê¢·ÅÈÝÆ÷µÄ×ÜÖÊÁ¿£¬
¹Ê´ð°¸Îª£º·ÀÖ¹¿ÉÎüÈë¿ÅÁ£¶ÂÈûµ¼Æø¹Ü»ò½øÈëËáÐÔ¸ßÃÌËá¼ØÈÜÒºÖУ¬Ê¹²âÁ¿ÖÊÁ¿²»×¼£»ÎüÊÕÇ°ºó¿ÅÁ£Îü¸½¼Á¡¢ÃÞ»¨¡¢Ê¢·ÅÈÝÆ÷µÄ×ÜÖÊÁ¿£¨»ò½«×°ÖÃÓñàºÅ±íʾ»Ø´ð£¬»ò´ð¿ÅÁ£Îü¸½¼Á¡¢ÃÞ»¨¡¢Ê¢·ÅÈÝÆ÷µÄ×ÜÖÊÁ¿µÄÔö¼ÓÖµ£©£»
£¨5£©Èç²âµÃµÄÊýÖµ×ÜÊDZÈʵ¼Êº¬Á¿Æ«µÍ£¬ËµÃ÷¶þÑõ»¯ÁòδºÍËáÐÔ¸ßÃÌËá¼ØÈÜÒº³ä·Ö·´Ó¦£¬¿ÉÄÜÔ­ÒòÊÇÆøÁ÷ËÙÂʹý¿ì£¬
¹Ê´ð°¸Îª£ºÍ¨ÈëÆøÁ÷ËÙÂʹý¿ì£¬¶þÑõ»¯ÁòδºÍËáÐÔ¸ßÃÌËá¼ØÈÜÒº³ä·Ö·´Ó¦¾ÍÒѾ­±»Åųö£»
·ÖÎö£º£¨1£©¸ù¾ÝÅäÖÆ200mL0.1mol?L-1ËáÐÔKMnO4ÈÜҺʱ£¬ÐèÒªµÄ²Ù×÷²½ÖèºÍÿһ²½²Ù×÷ËùÐèÒªµÄÒÇÆ÷·ÖÎö£»
£¨2£©SO2¾ßÓл¹Ô­ÐÔ£¬¸ßÃÌËá¼Ø¾ßÓÐÑõ»¯ÐÔ£¬¶þÕß·¢ÉúÑõ»¯»¹Ô­·´Ó¦Éú³ÉSO42-ºÍMn2+Àë×Ó£¬ÒÔ´ËÊéдÀë×Ó·½³Ìʽ£»
£¨3£©¸ù¾Ý·´Ó¦µÄÀë×Ó·½³Ìʽ¼ÆË㣻
£¨4£©ÃÞ»¨¾ßÓÐÎü¸½ÐÔ£¬¿ÉÎüÊÕÆøÁ÷ÖеĿÅÁ££»
£¨5£©Èç²âµÃµÄÊýÖµ×ÜÊDZÈʵ¼Êº¬Á¿Æ«µÍ£¬ËµÃ÷¶þÑõ»¯ÁòδºÍËáÐÔ¸ßÃÌËá¼ØÈÜÒº³ä·Ö·´Ó¦£®
µãÆÀ£º±¾Ì⿼²éÎïÖʵÄ×é³ÉºÍº¬Á¿µÄ²â¶¨£¬ÌâÄ¿½ÏÄÑ£¬±¾Ìâ×¢ÒâʵÑéµÄÔ­ÀíºÍ²Ù×÷·½·¨µÄ×¢ÒâÊÂÏ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â

Ä¿Ç°²â¶¨¿ÕÆøÖÐSO2º¬Á¿Ö÷ÒªÓÃÑõ»¯»¹Ô­·´Ó¦£®ÒÑÖªSO2ÆøÌåÓëËáÐÔKMnO4ÈÜÒº·´Ó¦Ê±£¬MnO4- ±»»¹Ô­ÎªMn2+£¬SO2±»Ñõ»¯³ÉSO42-£®
Ϊ²â¶¨Ä³µØ·½µÄ¿ÕÆøÖÐSO2ºÍ¿ÉÎüÈë¿ÅÁ£µÄº¬Á¿£¬¼×ͬѧÉè¼ÆÁËÈçͼËùʾµÄʵÑé×°Öãº

¢ÙÆäÖУº»ò±íʾÃܱÕÈÝÆ÷£» ±íʾÆøÌåÁ÷Ëٹܣ¨µ¥Î»Ê±¼äÄÚͨ¹ýÆøÌåµÄÌå»ýºã¶¨£¬ÇÒÎÞ³ý³¾ºÍÎüÊÕÆøÌå×÷Óã©£»±íʾÃÞ»¨£»¿ÅÁ£Îü¸½¼Á¿ÉÒÔÎüÊÕ¿ÉÎüÈëµÄ¿ÅÁ££»¡ú±íʾÆøÌåµÄÁ÷Ïò£®
¢ÚËáÐÔKMnO4ÈÜÒºÌå»ýΪ200mL£¬Å¨¶ÈΪ0.1mol?L-1£®»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÅäÖÆ200mL0.1mol?L-1ËáÐÔKMnO4ÈÜÒº£¬ÐèÓõ½µÄÒÇÆ÷°´Ê¹ÓõÄÏȺó˳ÐòÒÀ´ÎÓÐ
Ììƽ
Ììƽ
¡¢²£Á§°ô¡¢
ÉÕ±­
ÉÕ±­
¡¢
250mLÈÝÁ¿Æ¿
250mLÈÝÁ¿Æ¿
¡¢
½ºÍ·µÎ¹Ü
½ºÍ·µÎ¹Ü
£®²£Á§°ôµÄ×÷ÓÃÊÇ
½Á°èºÍÒýÁ÷
½Á°èºÍÒýÁ÷
£®
£¨2£©Ð´³ö²¢Åäƽ²â¶¨SO2º¬Á¿µÄÀë×Ó·½³Ìʽ£º
5SO2+2MnO4-+2H2O¨T5SO42-+2Mn2++4H+
5SO2+2MnO4-+2H2O¨T5SO42-+2Mn2++4H+

£¨3£©ÈôÆøÌåÁ÷ËÙ¹ÜÖÐÆøÌåÁ÷ËÙΪacm3/min£¬µ±tminʱËáÐÔKMnO4ÈÜҺǡºÃÍÊÉ«£¬Ôò¿ÕÆøÖÐSO2µÄº¬Á¿Îª
3.2
at
3.2
at
£¨g/cm3£©£®
£¨4£©ÊµÑéÖÐÃÞ»¨µÄ×÷ÓÃÊÇ
·ÀÖ¹¿ÉÎüÈë¿ÅÁ£¶ÂÈûµ¼Æø¹Ü»ò½øÈëËáÐÔ¸ßÃÌËá¼ØÈÜÒºÖУ¬Ê¹²âÁ¿ÖÊÁ¿²»×¼
·ÀÖ¹¿ÉÎüÈë¿ÅÁ£¶ÂÈûµ¼Æø¹Ü»ò½øÈëËáÐÔ¸ßÃÌËá¼ØÈÜÒºÖУ¬Ê¹²âÁ¿ÖÊÁ¿²»×¼
£»
ÈôÒª²â¶¨¿ÕÆøÖпÉÎüÈë¿ÅÁ£µÄº¬Á¿£¨g/L£©£¬»¹ÐèÒª²â³öµÄÊý¾ÝÊÇ
ÎüÊÕÇ°ºó¿ÅÁ£Îü¸½¼Á¡¢ÃÞ»¨¡¢Ê¢·ÅÈÝÆ÷µÄ×ÜÖÊÁ¿£¨»ò½«×°ÖÃÓñàºÅ±íʾ»Ø´ð£¬»ò´ð¿ÅÁ£Îü¸½¼Á¡¢ÃÞ»¨¡¢Ê¢·ÅÈÝÆ÷µÄ×ÜÖÊÁ¿µÄÔö¼ÓÖµ£©£®
ÎüÊÕÇ°ºó¿ÅÁ£Îü¸½¼Á¡¢ÃÞ»¨¡¢Ê¢·ÅÈÝÆ÷µÄ×ÜÖÊÁ¿£¨»ò½«×°ÖÃÓñàºÅ±íʾ»Ø´ð£¬»ò´ð¿ÅÁ£Îü¸½¼Á¡¢ÃÞ»¨¡¢Ê¢·ÅÈÝÆ÷µÄ×ÜÖÊÁ¿µÄÔö¼ÓÖµ£©£®

£¨5£©ÒÒͬѧ°´ÕÕͬÑùµÄ·½·¨²âÁ¿¿ÕÆøÖÐSO2µÄº¬Á¿£¬Ëù²âµÃµÄÊýÖµ×ÜÊDZÈʵ¼Êº¬Á¿Æ«µÍ£¬×î¿ÉÄܵÄÔ­ÒòÊÇ£¨¼ÙÉèÈÜÒºÅäÖÆ¡¢³ÆÁ¿»òÁ¿È¡¼°¸÷ÖÖ¶ÁÊý¾ùÎÞ´íÎ󣩣º
ͨÈëÆøÁ÷ËÙÂʹý¿ì£¬¶þÑõ»¯ÁòδºÍËáÐÔ¸ßÃÌËá¼ØÈÜÒº³ä·Ö·´Ó¦¾ÍÒѾ­±»Åųö
ͨÈëÆøÁ÷ËÙÂʹý¿ì£¬¶þÑõ»¯ÁòδºÍËáÐÔ¸ßÃÌËá¼ØÈÜÒº³ä·Ö·´Ó¦¾ÍÒѾ­±»Åųö
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

Ä¿Ç°²â¶¨¿ÕÆøÖÐSO2º¬Á¿Ö÷ÒªÓÃÑõ»¯»¹Ô­·´Ó¦£®ÒÑÖªSO2ÆøÌåÓëËáÐÔKMnO4ÈÜÒº·´Ó¦Ê±£¬MnO4- ±»»¹Ô­ÎªMn2+£¬SO2±»Ñõ»¯³ÉSO42-£®
Ϊ²â¶¨Ä³µØ·½µÄ¿ÕÆøÖÐSO2ºÍ¿ÉÎüÈë¿ÅÁ£µÄº¬Á¿£¬¼×ͬѧÉè¼ÆÁËÈçͼËùʾµÄʵÑé×°Öãº

¾«Ó¢¼Ò½ÌÍø

¢ÙÆäÖУº
¾«Ó¢¼Ò½ÌÍø
»ò
¾«Ó¢¼Ò½ÌÍø
±íʾÃܱÕÈÝÆ÷£»
¾«Ó¢¼Ò½ÌÍø
 ±íʾÆøÌåÁ÷Ëٹܣ¨µ¥Î»Ê±¼äÄÚͨ¹ýÆøÌåµÄÌå»ýºã¶¨£¬ÇÒÎÞ³ý³¾ºÍÎüÊÕÆøÌå×÷Óã©£»
¾«Ó¢¼Ò½ÌÍø
±íʾÃÞ»¨£»¿ÅÁ£Îü¸½¼Á¿ÉÒÔÎüÊÕ¿ÉÎüÈëµÄ¿ÅÁ££»¡ú±íʾÆøÌåµÄÁ÷Ïò£®
¢ÚËáÐÔKMnO4ÈÜÒºÌå»ýΪ200mL£¬Å¨¶ÈΪ0.1mol?L-1£®»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÅäÖÆ200mL0.1mol?L-1ËáÐÔKMnO4ÈÜÒº£¬ÐèÓõ½µÄÒÇÆ÷°´Ê¹ÓõÄÏȺó˳ÐòÒÀ´ÎÓÐ______¡¢²£Á§°ô¡¢______¡¢______¡¢______£®²£Á§°ôµÄ×÷ÓÃÊÇ______£®
£¨2£©Ð´³ö²¢Åäƽ²â¶¨SO2º¬Á¿µÄÀë×Ó·½³Ìʽ£º______
£¨3£©ÈôÆøÌåÁ÷ËÙ¹ÜÖÐÆøÌåÁ÷ËÙΪacm3/min£¬µ±tminʱËáÐÔKMnO4ÈÜҺǡºÃÍÊÉ«£¬Ôò¿ÕÆøÖÐSO2µÄº¬Á¿Îª______£¨g/cm3£©£®
£¨4£©ÊµÑéÖÐÃÞ»¨µÄ×÷ÓÃÊÇ______£»
ÈôÒª²â¶¨¿ÕÆøÖпÉÎüÈë¿ÅÁ£µÄº¬Á¿£¨g/L£©£¬»¹ÐèÒª²â³öµÄÊý¾ÝÊÇ______
£¨5£©ÒÒͬѧ°´ÕÕͬÑùµÄ·½·¨²âÁ¿¿ÕÆøÖÐSO2µÄº¬Á¿£¬Ëù²âµÃµÄÊýÖµ×ÜÊDZÈʵ¼Êº¬Á¿Æ«µÍ£¬×î¿ÉÄܵÄÔ­ÒòÊÇ£¨¼ÙÉèÈÜÒºÅäÖÆ¡¢³ÆÁ¿»òÁ¿È¡¼°¸÷ÖÖ¶ÁÊý¾ùÎÞ´íÎ󣩣º______£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2007-2008ѧÄêÔÆÄÏÊ¡Çú¾¸ÊÐÐûÍþ°ËÖиßÈý£¨ÉÏ£©»¯Ñ§ÊµÑé×ۺϼì²âÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ

Ä¿Ç°²â¶¨¿ÕÆøÖÐSO2º¬Á¿Ö÷ÒªÓÃÑõ»¯»¹Ô­·´Ó¦£®ÒÑÖªSO2ÆøÌåÓëËáÐÔKMnO4ÈÜÒº·´Ó¦Ê±£¬MnO4- ±»»¹Ô­ÎªMn2+£¬SO2±»Ñõ»¯³ÉSO42-£®
Ϊ²â¶¨Ä³µØ·½µÄ¿ÕÆøÖÐSO2ºÍ¿ÉÎüÈë¿ÅÁ£µÄº¬Á¿£¬¼×ͬѧÉè¼ÆÁËÈçͼËùʾµÄʵÑé×°Öãº

¢ÙÆäÖУº»ò±íʾÃܱÕÈÝÆ÷£» ±íʾÆøÌåÁ÷Ëٹܣ¨µ¥Î»Ê±¼äÄÚͨ¹ýÆøÌåµÄÌå»ýºã¶¨£¬ÇÒÎÞ³ý³¾ºÍÎüÊÕÆøÌå×÷Óã©£»±íʾÃÞ»¨£»¿ÅÁ£Îü¸½¼Á¿ÉÒÔÎüÊÕ¿ÉÎüÈëµÄ¿ÅÁ££»¡ú±íʾÆøÌåµÄÁ÷Ïò£®
¢ÚËáÐÔKMnO4ÈÜÒºÌå»ýΪ200mL£¬Å¨¶ÈΪ0.1mol?L-1£®»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÅäÖÆ200mL0.1mol?L-1ËáÐÔKMnO4ÈÜÒº£¬ÐèÓõ½µÄÒÇÆ÷°´Ê¹ÓõÄÏȺó˳ÐòÒÀ´ÎÓР   ¡¢²£Á§°ô¡¢    ¡¢    ¡¢    £®²£Á§°ôµÄ×÷ÓÃÊÇ    £®
£¨2£©Ð´³ö²¢Åäƽ²â¶¨SO2º¬Á¿µÄÀë×Ó·½³Ìʽ£º   
£¨3£©ÈôÆøÌåÁ÷ËÙ¹ÜÖÐÆøÌåÁ÷ËÙΪacm3/min£¬µ±tminʱËáÐÔKMnO4ÈÜҺǡºÃÍÊÉ«£¬Ôò¿ÕÆøÖÐSO2µÄº¬Á¿Îª    £¨g/cm3£©£®
£¨4£©ÊµÑéÖÐÃÞ»¨µÄ×÷ÓÃÊÇ    £»
ÈôÒª²â¶¨¿ÕÆøÖпÉÎüÈë¿ÅÁ£µÄº¬Á¿£¨g/L£©£¬»¹ÐèÒª²â³öµÄÊý¾ÝÊÇ   
£¨5£©ÒÒͬѧ°´ÕÕͬÑùµÄ·½·¨²âÁ¿¿ÕÆøÖÐSO2µÄº¬Á¿£¬Ëù²âµÃµÄÊýÖµ×ÜÊDZÈʵ¼Êº¬Á¿Æ«µÍ£¬×î¿ÉÄܵÄÔ­ÒòÊÇ£¨¼ÙÉèÈÜÒºÅäÖÆ¡¢³ÆÁ¿»òÁ¿È¡¼°¸÷ÖÖ¶ÁÊý¾ùÎÞ´íÎ󣩣º    £®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÖÐÑëµçÊǪ́´Ó2001Äê6ÔÂ5ÈÕÆðÿÌ춼Ҫ±¨µÀ47¸öÖصã³ÇÊеĿÕÆøÖÊÁ¿Ô¤±¨¡£°üÀ¨SO2ºÍ¿ÉÎüÈë¿ÅÁ£µÄº¬Á¿¡£Ä¿Ç°²â¶¨¿ÕÆøÖÐSO2º¬Á¿Ö÷ÒªÓÃÑõ»¯»¹Ô­·´Ó¦·¨¡£¼ÙÈç¸øÄãÆøÌåÁ÷Ëٹܣ¨µ¥Î»Ê±¼äÄÚͨ¹ýÆøÌåµÄÌå»ýºã¶¨µ«ÎÞ³ý³¾ºÍÎüÊÕÆøÌåµÄ×÷Óã©¡°¡è¡±¡¢ÃܱÕÈÝÆ÷¡°¡õ¡±¡¢³¨¿ÚÒÇÆ÷¡°¡È¡±¡¢µ¼¹Ü¡°-»ò¡¢0.0001mol?L-1µÄËáÐÔ¸ßÃÌËá¼ØÈÜÒº¡¢¿ÅÁ£Îü¸½¼Á¡¢Æ·ºìÊÔÒº¡¢pHÊÔÖ½µÈÒÇÆ÷ºÍÒ©Æ·£¬ÇëÉè¼ÆÒ»¸öʵÑé×°Ö㬲ⶨÄãËùÔÚµØÇø¿ÕÆøÖÐSO2ºÍ¿ÉÎüÈë¿ÅÁ£µÄº¬Á¿¡£ÒÑÖª5SO2+2H2O+2MnO4-£¨×ÏÉ«£©=5SO42-+2Mn2+£¨ÎÞÉ«£©+4H+¡£»·¾³¿ÕÆøÖÊÁ¿±ê×¼ÈçÏ£º

£¨1£©»­³ö²â¶¨¿ÕÆøÖÐSO2ºÍ¿ÉÎüÈë¿ÅÁ£µÄº¬Á¿µÄʵÑé×°ÖÃͼ£¨²¢Ö¸³öÒÇÆ÷ÖеÄÒ©Æ·£©¡£

 

£¨2£©ÈôÆøÌåÁ÷ËÙ¹ÜÖÐÆøÌåÁ÷ËÙΪ5000cm3?min-1£¬µ±140minʱ20mL0.0001mol?L-1µÄËáÐÔ¸ßÃÌËá¼ØÈÜҺǡºÃÍËÉ«£¬Ôò¸ù¾ÝÎÒ¹ú¿ÕÆøÖÊÁ¿±ê×¼ºÍ²â¶¨½á¹ûÅжÏËù²â¶¨µØµãµÄ¿ÕÆøÖÐSO2µÄº¬Á¿ÊôÓÚ_________£¨ÌîÊý×Ö£©¼¶±ê×¼£¨»·¾³£©¡£
£¨3£©ÈôÒª²â¶¨¿ÕÆøÖпÉÎüÈë¿ÅÁ£µÄº¬Á¿£¬ÐèÒª²â³öµÄÊý¾ÝÓÐ__________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸