ijͬѧÓûÓÃÒÑÖªÎïÖʵÄÁ¿Å¨¶ÈΪ0.100 0 mol¡¤L-1µÄÑÎËá²â¶¨Î´ÖªÎïÖʵÄÁ¿Å¨¶ÈµÄÇâÑõ»¯ÄÆÈÜҺʱ£¬Ñ¡Ôñ·Ó̪×÷ָʾ¼Á¡£ÇëÌîдÏÂÁпհףº

(1)Óñê×¼µÄÑÎËáµÎ¶¨´ý²âµÄÇâÑõ»¯ÄÆÈÜҺʱ£¬×óÊÖ°ÑÎÕËáʽµÎ¶¨¹ÜµÄ»îÈû£¬ÓÒÊÖÒ¡¶¯×¶ÐÎÆ¿£¬ÑÛ¾¦×¢ÊÓ׶ÐÎÆ¿ÖÐÈÜÒºÑÕÉ«µÄ±ä»¯£¬ÈçºÎÅжϵζ¨Öյ㣺 ¡£

(2)ÏÂÁвÙ×÷ÖпÉÄÜʹËù²âÇâÑõ»¯ÄÆÈÜÒºµÄŨ¶ÈÊýֵƫµÍµÄÊÇ (ÌîÐòºÅ)¡£

A£®ËáʽµÎ¶¨¹ÜδÓñê×¼ÑÎËáÈóÏ´¾ÍÖ±½Ó×¢Èë±ê×¼ÑÎËá

B£®µÎ¶¨Ç°Ê¢·ÅÇâÑõ»¯ÄÆÈÜÒºµÄ׶ÐÎÆ¿ÓÃÕôÁóˮϴ¾»ºóûÓиÉÔï

C£®ËáʽµÎ¶¨¹ÜÔڵζ¨Ç°ÓÐÆøÅÝ£¬µÎ¶¨ºóÆøÅÝÏûʧ

D£®¶ÁÈ¡ÑÎËáÌå»ýʱ£¬¿ªÊ¼ÑöÊÓ¶ÁÊý£¬µÎ¶¨½áÊøʱ¸©ÊÓ¶ÁÊý

E£®µÎ¶¨¹ý³ÌÖУ¬×¶ÐÎÆ¿µÄÕñµ´¹ýÓÚ¼¤ÁÒ£¬Ê¹ÉÙÁ¿ÈÜÒº½¦³ö

(3)ÈôµÚÒ»´ÎµÎ¶¨¿ªÊ¼ºÍ½áÊøʱ£¬ËáʽµÎ¶¨¹ÜÖеÄÒºÃæÈçÏÂͼËùʾ¡£ÔòÆðʼ¶ÁÊýΪV1= mL£¬ÖÕµã¶ÁÊýV2= mL¡£

(4)ÔÙ½áºÏϱíÊý¾Ý£¬¼ÆËã±»²âÇâÑõ»¯ÄÆÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶ÈÊÇ mol¡¤L-1¡£

µÎ¶¨´ÎÊý

´ý²âÈÜÒºÌå»ý/mL

±ê×¼ËáÌå»ý

µÎ¶¨Ç°µÄ¿Ì¶È/mL

µÎ¶¨ºóµÄ¿Ì¶È/mL

µÚÒ»´Î

10.00

V1

V2

µÚ¶þ´Î

10.00

4.10

21.10

µÚÈý´Î

10.00

0.40

17.60

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2016-2017ѧÄ꺣ÄÏÊ¡¸ß¶þÉÏÆÚÖÐÎÄ»¯Ñ§¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ

£¨1£©Õý³£ÉÅʳÖÐÓ¦µ±º¬ÓеÄÓªÑøËØ°üÀ¨ÌÇÀà¡¢________¡¢µ°°×ÖÊ¡¢________¡¢Ë®ºÍ¿óÎïÖʵȡ£

£¨2£©µí·ÛË®½â×îÖÕ²úÎïÊÇ________µ°°×ÖÊË®½â×îÖÕË®½â²úÎïÊÇ__________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2016-2017ѧÄê¹ãÎ÷ÁøÖÝÌú·һÖи߶þÉ϶ο¼ÎÄ»¯Ñ§¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

ÏÂÁйØÓÚÒÒÏ©µÄ˵·¨ÕýÈ·µÄÊÇ

A£®ÊÇÌìÈ»ÆøµÄÖ÷Òª³É·Ö B£®ÄÜʹäåµÄËÄÂÈ»¯Ì¼ÈÜÒºÍÊÉ«

C£®²»ÄÜ·¢ÉúȼÉÕ·´Ó¦ D£®²»ÄÜ·¢Éú¼Ó¾Û·´Ó¦

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2016-2017ѧÄê¹ãÎ÷ÁøÖÝÌú·һÖи߶þÉ϶ο¼ÎÄ»¯Ñ§¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

Ư°×·ÛµÄÓÐЧ³É·ÖÊÇ

A£®Ca(ClO)2 B£®CaCl2 C£®Ca(OH)2 D£®CaCO3

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2016-2017ѧÄê¹ãÎ÷ÁøÖÝÌú·һÖи߶þÉ϶ο¼ÎÄ»¯Ñ§¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

ÏÂÁгÉÓï»òË×ÓïÉæ¼°»¯Ñ§±ä»¯µÄÊÇ

A£®µÎË®³É±ù B£®¾Ûɳ³ÉËþ C£®»ðÉϽ½ÓÍ D£®ÌúèÆÄ¥³ÉÕë

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2016-2017ѧÄê¹ãÎ÷ÁøÖÝÌú·һÖи߶þÉ϶ο¼Àí»¯Ñ§¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

²¿·ÖÈõËáµÄµçÀëƽºâ³£ÊýÈçÏÂ±í£º

ÈõËá

HCOOH

HCN

H2CO3

µçÀëƽºâ³£Êý(25 ¡æ)

Ki=1.77¡Á10-4

Ki=4.9¡Á10-10

Ki1=4.3¡Á10-7

Ki2=5.6¡Á10-11

ÏÂÁÐÑ¡Ïî´íÎóµÄÊÇ( )

A£®2CN-+H2O+CO2=2HCN+ CO32-

B£®2HCOOH+ CO32-=2HCOO-+H2O+CO2¡ü

C£®Öк͵ÈÌå»ý¡¢µÈc(H+)µÄHCOOHºÍHCNÏûºÄNaOHµÄÁ¿Ç°ÕßСÓÚºóÕß

D£®ÏàͬÎïÖʵÄÁ¿Å¨¶ÈµÄHCOOHºÍHCNÈÜÒºÖУ¬c(HCOO-)<c(CN-)

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2016-2017ѧÄê¹ãÎ÷ÁøÖÝÌú·һÖи߶þÉ϶ο¼Àí»¯Ñ§¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

25¡æ¡¢101 kPaÏ£¬Ì¼¡¢ÇâÆø¡¢¼×ÍéºÍÆÏÌÑÌǵÄȼÉÕÈÈÒÀ´ÎÊÇ393.5 kJ/mol¡¢285.8 kJ/mol¡¢890.3kJ/mol¡¢2800 kJ/mol¡£ÔòÏÂÁÐÈÈ»¯Ñ§·½³ÌʽÕýÈ·µÄÊÇ ( )

A£®C(s)+1/2O2(g)=CO(g)£»¡÷H= - 393.5 kJ/mol

B£®2H2(g)+O2(g)=2H2O(l)£»¡÷H=+571.6 kJ/mol

C£®CH4(g)+2O2(g)=CO2(g)+2H2O(g)£»¡÷H=-890.3 kJ/mol

D£®1/2C6H12O6(s)+3O2(g)=3CO2(g)+3H2O(l)£»¡÷H=-1400 kJ/mol

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2016-2017ѧÄê¸ÊËàÊ¡¸ßÒ»ÉÏÆÚÖл¯Ñ§¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

ÏÂÁг£¼ûÏÖÏóÓ뽺ÌåÎ޹صÄÊÇ

A£®Ç峿ÔÚÃÜÁÖÖп´µ½Ò»ÂÆÂƵĹâÊø

B£®Ïò¶¹½¬ÖмÓÈëÁòËá¸Æʹµ°°×ÖʵȾ۳Á£¬ÖƳɿɿڵĶ¹¸¯

C£®FeCl3ÈÜÒº¼ÓÈëNaOHÈÜÒº²úÉúºìºÖÉ«³Áµí

D£®ÀûÓõçÓ¾½«ÓÍÆá¡¢È齺¡¢Ï𽺵È΢Á£¾ùÔȵسÁ»ýÔڶƼþÉÏ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2017½ìÔÆÄÏʦ´ó¸½ÖиßÈýÉÏÔ¿¼Èý»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ

A£®¼×Íé·Ö×ÓÖÐÁ½¸öÇâÔ­×Ó±»ÂÈÔ­×ÓÈ¡´úºó£¬ÓÐÁ½ÖÖ²»Í¬½á¹¹·Ö×Ó

B£®¼×È©ÄÜʹµ°°×ÖʱäÐÔ£¬¿ÉÓÃÓÚʳƷ·À¸¯¼Á

C£®¼×´¼·Ö×ÓÓëË®·Ö×ÓÖ®¼ä´æÔÚÇâ¼ü£¬Ê¹¼×´¼µÄË®ÈÜÐÔÏÔÖøÔöÇ¿

D£®¼×±½Óë±½»¥ÎªÍ¬ÏµÎ¾ùÄÜʹKMnO4ËáÐÔÈÜÒºÍÊÉ«

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸