¢ñ.ÑéÖ¤ÒÒõ£Ë®ÑîËáÖоßÓÐôÈ»ùºÍõ¥µÄ½á¹¹(¡ªCOOR)¡£
¢Ù½«Ò»Æ¬°¢Ë¾Æ¥ÁÖÑÐËéºóÈÜÓÚË®£¬¾²Ö㬸÷È¡ÇåÒº2 mLÓÚÁ½Ö§½à¾»µÄÊÔ¹ÜÖУ»
¢ÚÏòÒ»Ö§ÊÔ¹ÜÖмÓÈë____________£¬Èô¹Û²ìµ½____________£¬¼´Ö¤Ã÷ÒÒõ£Ë®ÑîËáÖÐÓÐôÈ»ù£»
¢ÛÏòÁíÒ»Ö§ÊÔ¹ÜÖмÓÈëÊÊÁ¿NaOHÈÜÒº£¬¼ÓÈȼ¸·ÖÖÓ£¬ÀäÈ´ºóÖðµÎµÎÈëÏ¡H2SO4£¬ÔÙÏòÆäÖеÎÈëFeCl3ÈÜÒº£¬±ß¼Ó±ßÕñµ´£¬Èô¹Û²ìµ½ÈÜÒºÖð½¥±äΪ____________É«£¬¼´Ö¤Ã÷ÒÒõ£Ë®ÑîËáÖоßÓÐõ¥µÄ½á¹¹¡£
»Ø´ðÏÂÁÐÎÊÌ⣺
(1)½«ÉÏÊöÈý´¦¿Õ°×²¹³äÍêÕû¡£
(2)ʵÑéÖеμÓÏ¡H2SO4µÄ×÷ÓÃÊÇ_____________________________________________¡£
¢ò.¸ÃѧϰС×éÉè¼ÆÁËÈçÏÂʵÑé·½°¸²â¶¨ÒÒõ£Ë®ÑîËáÔÚҩƬÖеĺ¬Á¿¡£
¢Ù³ÆÈ¡°¢Ë¾Æ¥ÁÖÑùÆ·m g£»¢Ú½«ÑùÆ·ÑÐË飬ÈÜÓÚV1 mL a mol¡¤L-1 NaOHÈÜÒºÖÐ(¹ýÁ¿)²¢¼ÓÈÈ£¬³ýÈ¥¸¨ÁϵȲ»ÈÜÎ½«ËùµÃÈÜÒºÒÆÈë׶ÐÎÆ¿£»¢ÛÏò׶ÐÎÆ¿ÖеμӼ¸µÎָʾ¼Á£¬ÓÃŨ¶ÈΪb mol¡¤L-1µÄÑÎËáÀ´µÎ¶¨Î´·´Ó¦µÄNaOH£¬ÏûºÄÑÎËáµÄÌå»ýΪV2 mL¡£
»Ø´ðÏÂÁÐÎÊÌ⣺
(1)°¢Ë¾Æ¥ÁÖÖмÓÈë¹ýÁ¿NaOHÈÜÒº²¢¼ÓÈÈ·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ____________£»ÆäÖмÓÈÈÄ¿µÄÊÇ____________________________________________________________¡£
(2)²½Öè¢ÛÖÐÈôÓ÷Ó̪×÷ָʾ¼Á£¬ÈçºÎÅжϵζ¨Öյ㣿________________________________
____________________________________________________________________¡£
(3)¸ù¾ÝʵÑéÖмǼµÄÊý¾Ý£¬°¢Ë¾Æ¥ÁÖҩƬÖÐÒÒõ£Ë®ÑîËáÖÊÁ¿·ÖÊýµÄ±í´ïʽΪ___________
_____________________________________________________________________¡£
¢ñ.(1)ʯÈïÊÔÒº ÈÜÒº±äΪºìÉ« ×Ï
(2)ÖкÍNaOH£¬µ÷½ÚÈÜҺΪÈõËáÐÔ
¢ò.(1)
ʹÒÒõ£Ë®ÑîËá¿ìËÙ·´Ó¦
(2)׶ÐÎÆ¿ÄÚÈÜÒººìÉ«ÍÊÈ¥ÇÒ°ë·ÖÖÓÄÚ²»ÔÙ±äΪºìÉ«
(3)£Ûav1-bv2¡Á10-3¡Á60/m£Ý¡Á100%
½âÎö£º¢ñ.ôÈ»ùÏÔËáÐÔ£¬¿ÉÓÃʯÈïÊÔÒº¼ìÑ飻õ¥»ùË®½âºóÉú³É·ÓôÇ»ù£¬ÓöFeCl3ÈÜÒº³Ê×ÏÉ«¡£¢ò.ÒÒõ£Ë®ÑîËáÓëNaOH°´ÕÕ1¡Ã3µÄ±ÈÀý·´Ó¦£¬ÒÒõ£Ë®ÑîËáµÄÖÊÁ¿·ÖÊý¼ÆËãʽΪ
¡Á180¡Á100%=¡Á100%¡£
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â
µÎ¶¨´ÎÊý | 0.1mol/LÑÎËá¶ÁÊý/mL | |
µÎ¶¨Ç° | µÎ¶¨ºó | |
1 | 0.00 | 17.98 |
2 | 1.56 | 16.58 |
3 | 0.22 | 15.20 |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â
ÒÑÖª£º¢Ù°¢Ë¾Æ¥ÁÖҩƬÖÐÒ»°ãÌí¼ÓÉÙÁ¿µÄ¸¨ÁÏ(¶¼²»ÈÜÓÚË®£¬Ò²²»ÓëNaOH·´Ó¦)£»¢Ú·ÓÀàÎïÖÊÓëFeCl3ÈÜÒºÔÚÈõËáÐÔÌõ¼þÏÂÄÜ·¢ÉúÏÔÉ«·´Ó¦¡£
ij¿ÎÍâѧϰС×éΪ¼ìÑ鰢˾ƥÁÖÓÐЧ³É·ÖÖеĹÙÄÜÍŲ¢²â¶¨ÒÒõ£Ë®ÑîËáÔÚҩƬÖеĺ¬Á¿£¬½øÐÐÁËÈçÏÂʵÑ飺
¢ñÑéÖ¤ÒÒõ£Ë®ÑîËáÖоßÓÐôÈ»ùºÍõ¥µÄ½á¹¹(¡ªCOOR)¡£
¢Ù½«Ò»Æ¬°¢Ë¾Æ¥ÁÖÑÐËéºóÈÜÓÚË®£¬¾²Ö㬸÷È¡ÇåÒº2mLÓÚÁ½Ö§½à¾»µÄÊÔ¹ÜÖУ»¢ÚÏòÒ»Ö§ÊÔ¹ÜÖмÓÈë___________£¬Èô¹Û²ìµ½___________£¬¼´Ö¤Ã÷ÒÒõ£Ë®ÑîËáÖÐÓÐôÈ»ù£»¢ÛÏòÁíÒ»Ö§ÊÔ¹ÜÖмÓÈëÊÊÁ¿NaOHÈÜÒº£¬¼ÓÈȼ¸·ÖÖÓ£¬ÀäÈ´ºóÖðµÎµÎÈëÏ¡H2SO4£¬ÔÙÏòÆäÖеÎÈëFeCl3ÈÜÒº£¬±ß¼Ó±ßÕñµ´£¬Èô¹Û²ìµ½ÈÜÒºÖð½¥±äΪ___________É«£¬¼´Ö¤Ã÷ÒÒõ£Ë®ÑîËáÖоßÓÐõ¥µÄ½á¹¹¡£
»Ø´ðÏÂÁÐÎÊÌ⣺
(1)½«ÉÏÊöÈý´¦¿Õ°×²¹³äÍêÕû¡£
(2)ʵÑéÖеμÓÏ¡H2SO4µÄ×÷ÓÃÊÇ_________________________________¡£
¢ò¸ÃѧϰС×éÉè¼ÆÁËÈçÏÂʵÑé·½°¸²â¶¨ÒÒõ£Ë®ÑîËáÔÚҩƬÖеĺ¬Á¿£º
¢Ù³ÆÈ¡°¢Ë¾Æ¥ÁÖÑùÆ·mg£»¢Ú½«ÑùÆ·ÑÐË飬ÈÜÓÚV1mLamol¡¤L-1NaOHÈÜÒº(¹ýÁ¿)²¢¼ÓÈÈ£¬³ýÈ¥¸¨ÁϵȲ»ÈÜÎ½«ËùµÃÈÜÒºÒÆÈë׶ÐÎÆ¿£»¢ÛÏò׶ÐÎÆ¿ÖеμӼ¸µÎָʾ¼Á£¬ÓÃŨ¶ÈΪbmol¡¤L-1µÄ±ê×¼ÑÎËá·´µÎδ·´Ó¦µÄNaOH£¬ÏûºÄÑÎËáµÄÌå»ýΪV2mL¡£
»Ø´ðÏÂÁÐÎÊÌ⣺
(1)°¢Ë¾Æ¥ÁÖÖмÓÈë¹ýÁ¿NaOHÈÜÒº²¢¼ÓÈÈ·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ___________________£»ÆäÖУ¬¼ÓÈȵÄÄ¿µÄÊÇ______________________¡£
(2)²»Äܽ«°¢Ë¾Æ¥ÁÖÈܽâÓÚË®ºóÖ±½ÓÓÃNaOHÈÜÒº½øÐе樵ÄÔÒòÊÇ__________________¡£
(3)¸ù¾ÝʵÑéÖмǼµÄÊý¾Ý£¬°¢Ë¾Æ¥ÁÖҩƬÖÐÒÒõ£Ë®ÑîËáÖÊÁ¿·ÖÊýµÄ±í´ïʽΪ£º____________________________________________¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ
µÎ¶¨´ÎÊý | 0.1mol/LÑÎËá¶ÁÊý/mL | |
µÎ¶¨Ç° | µÎ¶¨ºó | |
1 | 0.00 | 17.98 |
2 | 1.56 | 16.58 |
3 | 0.22 | 15.20 |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â
ÒÑÖª£º¢Ù°¢Ë¾Æ¥ÁÖҩƬÖÐÒ»°ãÌí¼ÓÉÙÁ¿µÄ¸¨ÁÏ(¶¼²»ÈÜÓÚË®£¬Ò²²»ÓëNaOH·´Ó¦)£»¢Ú·ÓÀàÎïÖÊÓëFeCl3ÈÜÒºÔÚÈõËáÐÔÌõ¼þÏÂÄÜ·¢ÉúÏÔÉ«·´Ó¦¡£
ij¿ÎÍâѧϰС×éΪ¼ìÑ鰢˾ƥÁÖÓÐЧ³É·ÖÖеĹÙÄÜÍŲ¢²â¶¨ÒÒõ£Ë®ÑîËáÔÚҩƬÖеĺ¬Á¿£¬½øÐÐÁËÈçÏÂʵÑ飺
¢ñ.ÑéÖ¤ÒÒõ£Ë®ÑîËáÖоßÓÐôÈ»ùºÍõ¥µÄ½á¹¹(¡ªCOOR)¡£
¢Ù½«Ò»Æ¬°¢Ë¾Æ¥ÁÖÑÐËéºóÈÜÓÚË®£¬¾²Ö㬸÷È¡ÇåÒº2 mLÓÚÁ½Ö§½à¾»µÄÊÔ¹ÜÖУ»
¢ÚÏòÒ»Ö§ÊÔ¹ÜÖмÓÈë_________£¬Èô¹Û²ìµ½__________________£¬¼´Ö¤Ã÷ÒÒõ£Ë®ÑîËáÖÐÓÐôÈ»ù£»
¢ÛÏòÁíÒ»Ö§ÊÔ¹ÜÖмÓÈëÊÊÁ¿NaOHÈÜÒº£¬¼ÓÈȼ¸·ÖÖÓ£¬ÀäÈ´ºóÖðµÎÈëÏ¡H2SO4£¬ÔÙÏòÆäÖеÎÈëFeCl3ÈÜÒº£¬±ß¼Ó±ßÕñµ´£¬Èô¹Û²ìµ½ÈÜÒºÖð½¥±äΪ_________É«£¬¼´Ö¤Ã÷ÒÒõ£Ë®ÑîËáÖоßÓÐõ¥µÄ½á¹¹¡£
»Ø´ðÏÂÁÐÎÊÌ⣺
(1)½«ÉÏÊöÈý´¦¿Õ°×²¹³äÍêÕû¡£
(2)ʵÑéÖеμÓÏ¡H2SO4µÄ×÷ÓÃÊÇ__________________¡£
¢ò.¸ÃѧϰС×éÉè¼ÆÁËÈçÏÂʵÑé·½°¸²â¶¨ÒÒõ£Ë®ÑîËáÔÚҩƬÖеĺ¬Á¿£º
¢Ù³ÆÈ¡°¢Ë¾Æ¥ÁÖÑùÆ·m g£»
¢Ú½«ÑùÆ·ÑÐË飬ÈÜÓÚV1 mL a mol¡¤L-1 NaOHÈÜÒº(¹ýÁ¿)²¢¼ÓÈÈ£¬³ýÈ¥¸¨ÁϵȲ»ÈÜÎ½«ËùµÃÈÜÒºÒÆÈë׶ÐÎÆ¿£»
¢ÛÏò׶ÐÎÆ¿ÖеμӼ¸µÎָʾ¼Á£¬ÓÃŨ¶ÈΪb mol¡¤L-1µÄ±ê×¼ÑÎËá·µµÎδ·´Ó¦µÄNaOH£¬ÏûºÄÑÎËáµÄÌå»ýΪV2 mL¡£
»Ø´ðÏÂÁÐÎÊÌ⣺
(1)°¢Ë¾Æ¥ÁÖÖмÓÈë¹ýÁ¿NaOHÈÜÒº²¢¼ÓÈÈʱ·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ__________________;ÆäÖУ¬¼ÓÈȵÄÄ¿µÄÊÇ__________________________________________¡£
(2)²»Äܽ«°¢Ë¾Æ¥ÁÖÈܽâÓÚË®ºóÖ±½ÓÓÃNaOHÈÜÒº½øÐе樵ÄÔÒòÊÇ_____________________
____________________________________________________________________¡£
(3)¸ù¾ÝʵÑéÖмǼµÄÊý¾Ý£¬°¢Ë¾Æ¥ÁÖҩƬÖÐÒÒõ£Ë®ÑîËáÖÊÁ¿·ÖÊýµÄ±í´ïʽΪ_____________
_____________________________________________________________________¡£
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com