Ϊ³ýȥϱíËùÁÐÎïÖʺ¬ÓеÄÉÙÁ¿ÔÓÖÊ£¨À¨ºÅÄÚΪÔÓÖÊ£©£¬ÔÚAÏîÖÐÑ¡ÔñÊÔ¼Á£¬ÔÚBÏîÖÐÑ¡Ôñ²Ù×÷µÄ·½·¨£¬½«Æä´úºÅÌîÈë±íÖУº
A£º£¨1£©NaClϸ¿ÅÁ££» £¨2£©NaOHÈÜÒº£» £¨3£©Ë®£» £¨4£©CaO£»
£¨5£©±¥ºÍNa2CO3£» £¨6£©äåË®£» £¨7£©KMnO4ÈÜÒº¡£
B£º£¨1£©¹ýÂË£» £¨2£©ÑÎÎö£» £¨3£©ÕôÁó£» £¨4£©·ÖÒº£» £¨5£©½á¾§£»
£¨6£©Ï´Æø£» £¨7£©ÉøÎö
ÎïÖÊ |
µ° °× ÖÊÈÜÒº £¨ÂÈ»¯ÄÆÈÜÒº£© |
ÒÒ Íé £¨ÒÒÏ©£© |
·Ê Ôí £¨¸ÊÓÍ£© |
ÒÒ´¼£¨Ë®£© |
ÒÒËáÒÒõ¥£¨ÒÒËᣩ |
äå±½£¨ä壩 |
¼ÓÈëÊÔ¼Á |
|
|
|
|
|
|
²Ù×÷·½·¨ |
|
|
|
|
|
|
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ÎïÖÊ | ³ýÔÓ·½·¨(»òÊÔ¼Á) | »¯Ñ§·½³Ìʽ |
CO(CO2) |
|
|
Na2CO3¹ÌÌå(NaHCO3) |
|
|
(2)ij¿ÎÍâ»î¶¯Ð¡×é×¼±¸ÓÃÈçÏÂͼËùʾµÄ×°ÖýøÐÐʵÑé¡£ÏÖÓмס¢ÒÒ¡¢±ûÈýλͬѧ·Ö±ðÑ¡ÔñÁËÈçϵ缫²ÄÁϺ͵ç½âÖÊÈÜÒº:
| Aµç¼« | Bµç¼« | XÈÜÒº |
¼× | Cu | Zn | H2SO4 |
ÒÒ | Pt | Pt | CuCl2 |
±û | Fe | Cu | £¿ |
¢Ù¼×ͬѧÔÚʵÑéÖн«µç¼üK5±ÕºÏ,Znµç¼«Éϵĵ缫·´Ó¦Ê½Îª___________________________¡£
¢ÚÒÒͬѧ׼±¸½øÐеç½âCuCl2ÈÜÒºµÄʵÑé,Ôòµç½âʱµÄ×Ü·´Ó¦·½³ÌʽΪ:__________________¡£
ʵÑéʱӦ±ÕºÏµÄµç¼üµÄ×éºÏÊÇ:____________________¡£(´ÓÏÂÁÐÎåÏîÖÐÑ¡ÔñËùÓпÉÄÜ×éºÏ,µÚÈýСÌâÒ²ÔÚÕâÎåÏîÖÐÑ¡Ôñ)
A.K1ºÍK2 B.K1ºÍK
¢Û±ûͬѧ׼±¸ÔÚFeÉ϶ÆCu,Ñ¡ÔñÁËijÖÖÑÎÀ´ÅäÖƵç¶ÆÒº,Ôò¸ÃÑÎÖÐÓ¦º¬µÄÑôÀë×ӵĻ¯Ñ§Ê½Îª________,ʵÑéʱ,Ó¦±ÕºÏµÄµç¼üµÄ×éºÏÊÇ________(Ñ¡ÏîÈçÉÏ)¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
£¨16·Ö£©ÍÔÚ×ÔÈ»½çÖдæÔÚÓÚ¶àÖÖ¿óʯÖУ¬Èç
¿óʯÃû³Æ | »ÆÍ¿ó | °ßÍ¿ó | »ÔÍ¿ó | ¿×ȸʯ |
Ö÷Òª³É·Ö |
|
|
|
|
Çë»Ø´ðÒÔÏÂÎÊÌ⣺
(1)ÉϱíËùÁÐ͵Ļ¯ºÏÎïÖУ¬ÍµÄÖÊÁ¿·ÖÊý×î¸ßµÄÊÇ______________£¨Ìѧʽ£©¡£
(2)¹¤ÒµÉÏÒÔ»ÆÍ¿óΪÔÁÏ£¬²ÉÈ¡»ð·¨ÈÛÁ¶¹¤ÒÕÉú²úÍ¡£¸Ã¹ý³ÌÖÐÓÐÈçÏ·´Ó¦£º
£¬¸Ã·´Ó¦µÄ»¹Ô¼ÁÊÇ____________£»ÈôÔÚ±ê×¼×´¿öÏ·ųöÆøÌå56L£¬ÔòתÒƵç×ÓµÄÎïÖʵÄÁ¿Îª_____________¡£
(3)ijͬѧ²É¼¯ËáÓêÑùÆ·²¢²âÆäpH£¬·¢ÏÖÔÚÒ»¶Îʱ¼äÄÚÆäpHÖð½¥¼õС¡£ÇëÓñØÒªµÄÎÄ×ֺͻ¯Ñ§·½³Ìʽ˵Ã÷ÆäÔÒò______________________________________________
________________________________________________________¡£
(4)ÍÖÆÆ·³¤ÆÚÖÃÓÚ³±ÊªµÄ»·¾³ÖУ¬±íÃæ»á²úÉúÒ»²ãÍÂÌ£¬ÆäÖ÷Òª³É·ÖÓë¿×ȸʯÏàͬ¡£
Çëд³ö²ÉÓû¯Ñ§·½·¨³ýÈ¥ÍÆ÷±íÃæÍÂ̵ÄÓйط´Ó¦µÄÀë×Ó·½³Ìʽ£º_____________
_______________________________________________¡£
(5)Ó붼ÊǺìÉ«·ÛÄ©¡£ÈÜÓÚÏ¡»áÉú³ÉºÍ¡£Ò»Í¬Ñ§Îª¼ø¶¨Ä³ÑùÆ·ÖÐÊÇ·ñ»ìÓжàÉÙÁ¿µÄ£¬Éè¼ÆÁËÈçÏÂʵÑ飺ȡÉÙÁ¿·ÛÄ©·ÅÈë×ãÁ¿Ï¡ÖУ¬ÏòËùµÃÈÜÒºÖеμÓÊÔ¼Á¡£¸Ãͬѧͨ¹ýʵÑéÈÏΪ£ºÈôµÎ¼ÓKSCNÊÔ¼ÁºóÈÜÒº²»±äºìÉ«£¬ÔòÖ¤Ã÷Ô¹ÌÌå·ÛÄ©ÖÐÒ»¶¨²»º¬¡£ÄãÈÏΪÕâÖÖ˵·¨ÊÇ·ñÕýÈ·___________£º¼òÊöÄãµÄÀíÓÉ£¨ÓÃÀë×Ó·½³Ìʽ±íʾ£©:______________£¬
Èç¹ûÒªµÃµ½×¼È·µÄ½áÂÛ£¬»¹Ðè¼ÓÈëµÄÒ»ÖÖÊÔ¼ÁÊÇ_________________¡£
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com