ÒÑÖª¼×¡¢ÒÒ¡¢±ûΪ³£¼ûµ¥ÖÊ£¬A¡¢B¡¢C¡¢D¡¢X¡¢Y¡¢ZΪ³£¼ûµÄ»¯ºÏÎYµÄĦ¶ûÖÊÁ¿ÊýÖµ±ÈZµÄС16£¬ÒÒ¡¢±ûµÄĦ¶ûÖÊÁ¿Ïàͬ£¬BµÄĦ¶ûÖÊÁ¿±ÈDµÄС2£¬B¡¢XµÄĦ¶ûÖÊÁ¿Ïàͬ£®¸÷ÎïÖÊת»¯¹ØϵÈçÏ£º
¾«Ó¢¼Ò½ÌÍø
£¨1£©Ð´³ö±ûµÄ»¯Ñ§Ê½
 
£»BµÄµç×Óʽ
 
£®
£¨2£©Ð´³öY¡úZµÄ»¯Ñ§·½³Ìʽ£º
 

£¨3£©ÊµÑéÊÒÖü´æYÈÜҺʱÒ×±äÖÊ£¬Çëд³ö¼ìÑéYÈÜÒºÊÇ·ñ±äÖÊËùÐèÊÔ¼ÁÊÇ
 
£®
·ÖÎö£ºÓÉYµÄĦ¶ûÖÊÁ¿ÊýÖµ±ÈZµÄС16µÄÊý¾Ý¿ÉÖª£¬±ûΪO2£¬ÒÒ¡¢±ûµÄĦ¶ûÖÊÁ¿Ïàͬ£¬ÔòÒÒΪS£¬¸ù¾Ýת»¯¹Øϵ¿ÉÖª£¬CΪSO2£¬DΪSO3£®¼×ÓëÑõÆøÉú³ÉA£¬AÓëÑõÆøÉú³ÉB£¬BµÄĦ¶ûÖÊÁ¿±ÈDµÄС2£¬B¡¢XµÄĦ¶ûÖÊÁ¿Ïàͬ£¬ÔòB¡¢XµÄĦ¶ûÖÊÁ¿Îª78g/mol£¬¿¼ÂÇ¿ÉÄܼ×ΪNa¡¢AΪNa2O¡¢BΪNa2O2£¬ÔòXΪNa2S£¬ÆäĦ¶ûÖÊÁ¿Îª78g/mol£¬AÓëC·´Ó¦Éú³ÉYΪNa2SO3£¬ÔòZΪNa2SO4£¬·ûºÏת»¯¹Øϵ£¬¾Ý´Ë½â´ð£®
½â´ð£º½â£ºÓÉYµÄĦ¶ûÖÊÁ¿ÊýÖµ±ÈZµÄС16µÄÊý¾Ý¿ÉÖª£¬±ûΪO2£¬ÒÒ¡¢±ûµÄĦ¶ûÖÊÁ¿Ïàͬ£¬ÔòÒÒΪS£¬¸ù¾Ýת»¯¹Øϵ¿ÉÖª£¬CΪSO2£¬DΪSO3£®¼×ÓëÑõÆøÉú³ÉA£¬AÓëÑõÆøÉú³ÉB£¬BµÄĦ¶ûÖÊÁ¿±ÈDµÄС2£¬B¡¢XµÄĦ¶ûÖÊÁ¿Ïàͬ£¬ÔòB¡¢XµÄĦ¶ûÖÊÁ¿Îª78g/mol£¬¿¼ÂÇ¿ÉÄܼ×ΪNa¡¢AΪNa2O¡¢BΪNa2O2£¬ÔòXΪNa2S£¬ÆäĦ¶ûÖÊÁ¿Îª78g/mol£¬AÓëC·´Ó¦Éú³ÉYΪNa2SO3£¬ÔòZΪNa2SO4£¬·ûºÏת»¯¹Øϵ£¬
£¨1£©ÓÉÉÏÊö·ÖÎö¿ÉÖª£¬±ûΪO2£¬BΪNa2O2£¬Æäµç×ÓʽΪ¾«Ó¢¼Ò½ÌÍø£¬
¹Ê´ð°¸Îª£ºO2£»¾«Ó¢¼Ò½ÌÍø£»
£¨2£©Y¡úZÊÇÑÇÁòËáÄƱÈÑõÆøÑõ»¯Éú³ÉÁòËáÄÆ£¬»¯Ñ§·½³ÌʽΪ£º2Na2SO3+O2¨T2Na2SO4£¬
¹Ê´ð°¸Îª£º2Na2SO3+O2¨T2Na2SO4£»
£¨3£©ÊµÑéÊÒÖü´æNa2SO3ÈÜҺʱÒ×±äÖÊ£¬Éú³ÉNa2SO4£¬Í¨¹ý¼ìÑéÊÇ·ñº¬ÓÐÁòËá¸ùÅжÏÊÇ·ñ±äÖÊ£¬ËùÐèÊÔ¼ÁÊÇ£ºÏ¡ÑÎËáºÍÂÈ»¯±µÈÜÒº£¬
¹Ê´ð°¸Îª£ºÏ¡ÑÎËáºÍÂÈ»¯±µÈÜÒº£®
µãÆÀ£º±¾Ì⿼²éÎÞ»úÎïÍƶϣ¬ÐèÒª³ä·ÖÀûÓø÷ÎïÖʵÄĦ¶ûÖÊÁ¿¹Øϵ£¬ÍƶϱûΪÑõÆøÊǹؼü£¬Ó¦ÊìÁ·×¢ÒâÔªËØ»¯ºÏÎï֪ʶ£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÒÑÖª¼×¡¢ÒÒ¡¢±ûΪ³£¼ûµÄµ¥ÖÊ£¬A¡¢B¡¢C¡¢D¡¢E¡¢F¡¢G¡¢H¾ùΪ³£¼ûµÄ»¯ºÏÎBºÍHµÄĦ¶ûÖÊÁ¿Ïàͬ£¬EµÄÏà¶Ô·Ö×ÓÖÊÁ¿±ÈD´ó16£¬ÔÚÒ»¶¨Ìõ¼þÏ£¬¸÷ÎïÖÊÏ໥ת»¯¹ØϵÈçͼ1Ëùʾ£¨²úÎïÖÐË®ÒѺöÂÔ£©£º

£¨1£©Ð´³öÏÂÁÐÎïÖʵĻ¯Ñ§Ê½£º±û£º
O2
O2
H£º
Na2S
Na2S

£¨2£©Ð´³öBºÍF·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º
Na2O2+SO2=Na2SO4
Na2O2+SO2=Na2SO4
£®
£¨3£©ÒÑÖª25¡æ£¬101Kpaʱ£¬ÒÒµÄȼÉÕÈÈΪakJ/mol£¬Ð´³öÒÒȼÉÕµÄÈÈ»¯Ñ§·½³Ìʽ
S£¨s£©+O2£¨g£©=SO2£¨g£©£»¡÷H=-akJ/mol
S£¨s£©+O2£¨g£©=SO2£¨g£©£»¡÷H=-akJ/mol
£®
£¨4£©Ð´³öB+H2O¡ú±û+CµÄ»¯Ñ§·½³Ìʽ
2Na2O2+2H2O=4NaOH+O2¡ü
2Na2O2+2H2O=4NaOH+O2¡ü
£®
£¨5£©ÔÚ2LµÄÃܱÕÈÝÆ÷ÄÚ£¬500¡æʱ£¬·´Ó¦2F£¨g£©+±û£¨g£©¨T2G£¨g£©£¬n£¨F£©Ëæʱ¼ä±ä»¯ÈçÏÂ±í£º
ʱ¼ä£¨s£© 0 1 2 3 4 5
n£¨F£©/mol 0.020 0.010 0.008 0.007 0.007 0.007
Èçͼ2ÖбíʾGµÄ±ä»¯ÇúÏßÊÇ
b
b
£®Óñû±íʾ´Ó0¡«2sÄڸ÷´Ó¦µÄƽ¾ùËÙÂÊ
0.0015mol?L-1?s-1
0.0015mol?L-1?s-1
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÒÑÖª¼×¡¢ÒÒ¡¢±ûΪ³£¼ûµ¥ÖÊ£¬ÇÒ±ûÊÇÎÞÉ«ÆøÌ壻A-G¾ùΪ³£¼ûµÄ»¯ºÏÎBΪµ­»ÆÉ«¹ÌÌ壬BµÄʽÁ¿±ÈAµÄʽÁ¿´ó16£¬EÊÇÐγÉËáÓêµÄÖ÷ÒªÎïÖÊ£¬ÔÚÒ»¶¨Ìõ¼þÏ£¬¸÷ÎïÖÊÏ໥ת»¯¹ØϵÈçͼËùʾ£¨²úÎïÖÐË®ÒѺöÂÔ£©£º

£¨1£©Ð´³öÏÂÁÐÎïÖʵĻ¯Ñ§Ê½£ºG
Na2S
Na2S
£¬F
SO3
SO3
£»
£¨2£©Ð´³öÏÂÁб仯µÄ»¯Ñ§·½³ÌʽB+H2O¡ú±û+C£º
2Na2O2+2H2O=O2¡ü+4NaOH
2Na2O2+2H2O=O2¡ü+4NaOH
£»
£¨3£©EÊÇÒ»ÖÖÓж¾ÆøÌ壬¹¤ÒµÉϳ£ÓÃÉúʯ»Ò¶ÔEÆøÌå½øÐд¦Àí£®Ð´³öÆ仯ѧ·´Ó¦·½³Ìʽ
CaO+SO2=CaSO3
CaO+SO2=CaSO3
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

Àý

ÒÑÖª¼×¡¢ÒÒ¡¢±ûΪ³£¼ûµ¥ÖÊ£¬A¡¢B¡¢C¡¢D¡¢E¡¢F¡¢G¡¢X¾ùΪ³£¼ûµÄ»¯ºÏÎBºÍXµÄĦ¶ûÖÊÁ¿Ïàͬ£¬EµÄÏà¶Ô·Ö×ÓÖÊÁ¿±ÈDµÄÏà¶Ô·Ö×ÓÖÊÁ¿´ó16£¬ÔÚÒ»¶¨Ìõ¼þÏ£¬¸÷ÎïÖÊÏ໥ת»¯¹ØϵÈçÏÂͼËùʾ£º

(1)д³öXµÄµç×ÓʽºÍGµÄ»¯Ñ§Ê½£ºX__________£¬G__________£»

(2)д³öÓйر仯µÄ»¯Ñ§·½³Ìʽ£º

        B£«H2O£º______________________________£»

        D£«±û£º______________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2009-2010ѧÄêÕý¶¨ÖÐѧ¸ßÒ»ÏÂѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§£¨Àí¿Æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

£¨6·Ö£©ÒÑÖª¼×¡¢ÒÒ¡¢±ûΪ³£¼ûµ¥ÖÊ£¬A¡¢B¡¢C¡¢D¡¢E¡¢F¡¢G¡¢X¾ùΪ³£¼ûµÄ»¯ºÏÎBºÍXµÄĦ¶ûÖÊÁ¿Ïàͬ£¬EµÄÏà¶Ô·Ö×ÓÖÊÁ¿±ÈDµÄÏà¶Ô·Ö×ÓÖÊÁ¿´ó16£¬ÔÚÒ»¶¨Ìõ¼þÏ£¬¸÷ÎïÖÊÏ໥ת»¯¹ØϵÈçÏÂͼËùʾ£º

¢Å д³öXµÄµç×ÓʽºÍGµÄ»¯Ñ§Ê½£ºX__________£¬G__________£»

¢Æ д³öÓйر仯µÄ»¯Ñ§·½³Ìʽ£º

    B£«H2O£º______________________________£»

D£«±û£º______________________________¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸