ÒÑÖª298 K¡¢101 kPaÌõ¼þÏ£º
¢Ù4Al(s)+3O2(g)=2Al2O3(s)   ¦¤H£½-2834.9 kJ¡¤mol-1
¢Ú4Al(s)+2O3(g)=2Al2O3(s)   ¦¤H£½-3119.1 kJ¡¤mol-1
Óɴ˵óöµÄÕýÈ·½áÂÛÊÇ


  1. A.
    µÈÖÊÁ¿µÄO2±ÈO3ÄÜÁ¿µÍ£¬ÓÉO2±äΪO3Ϊ·ÅÈÈ·´Ó¦
  2. B.
    O3±ÈO2Îȶ¨£¬ÓÉO2±äΪO3ΪÎüÈÈ·´Ó¦
  3. C.
    O2±ÈO3Îȶ¨£¬ÓÉO2±äΪO3Ϊ·ÅÈÈ·´Ó¦
  4. D.
    µÈÖÊÁ¿µÄO2±ÈO3ÄÜÁ¿µÍ£¬ÓÉO2±äΪO3ΪÎüÈÈ·´Ó¦
D
ÊÔÌâ·ÖÎö£ºÒÑÖª25¡æ¡¢101kpaÌõ¼þÏ£º
£¨1£©4Al£¨s£©+302£¨g£©¨T2Al2O3£¨s£©£»¡÷H=-2834.9kJ¡¤mol£­1
£¨2£©4Al£¨s£©+2O3£¨g£©¨T2Al2O3£¨s£©£»¡÷H=-3119.1KJ¡¤mol£­1
¸ù¾Ý¸Ç˹¶¨ÂÉ£¨1£©-£¨2£©µÃµ½£º3O2£¨g£©¨T2O3£¨g£©¡÷H=-2834.9kJ¡¤mol£­1-£¨-3119.1KJ¡¤mol£­1£©=284.1KJ¡¤mol£­1¡£A£®ÑõÆøת»¯Îª³ôÑõÊÇÎüÈÈ·´Ó¦£¬3molÑõÆøÉú³É2mol³ôÑõÎüÊÕµÄÈÈÁ¿284.2kJ£¬A´íÎó£»B£®µÈÖÊÁ¿µÄO2±ÈO3µÄÄÜÁ¿µÍ£¬ËùÒÔO2±ÈO3Îȶ¨£¬B´íÎó£»C£®ÓÉO2±äΪO3µÄ»¯Ñ§·´Ó¦ÎªÎüÈÈ·´Ó¦£¬C´íÎó£»D£®µÈÖÊÁ¿µÄO2±ÈO3ÄÜÁ¿µÍ£¬ÓÉO2±äΪO3ΪÎüÈÈ·´Ó¦£¬DÕýÈ·£»Ñ¡D£®
¿¼µã£º»¯Ñ§ÄÜÓëÈÈÄܵÄÏ໥ת»¯£»·´Ó¦ÈȺÍìʱä
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

´ÓÂÁÍÁ¿ó£¨Ö÷Òª³É·ÖÊÇAl2O3,º¬SiO2¡¢Fe2O3¡¢MgOµÈÔÓÖÊ£©ÖÐÌáÈ¡Ñõ»¯ÂÁµÄÁ½ÖÖ¹¤ÒÕÁ÷³ÌÈçÏ£º

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©Á÷³Ì¼×¼ÓÈëÑÎËáºóÉú³ÉAl3+µÄÀë×Ó·½³ÌʽΪ______________________________¡£

£¨2£©Á÷³ÌÒÒ¼ÓÈëÉÕ¼îºóÉú³ÉµÄÀë×Ó·½³ÌʽΪ_____________________________¡£

£¨3£©ÑéÖ¤ÂËÒºBº¬Fe3+£¬¿ÉÈ¡ÉÙÁ¿ÂËÒº²¢¼ÓÈë_______________£¨ÌîÊÔ¼ÁÃû³Æ£©¡£

£¨4£©ÂËÒºE¡¢KÖÐÈÜÖʵÄÖ÷Òª³É·ÖÊÇ_______________£¨Ìѧʽ£©£¬Ð´³ö¸ÃÈÜÖʵÄÒ»ÖÖÓÃ;_______________¡£

£¨5£©ÒÑÖª298 Kʱ£¬Mg(OH)2µÄÈܶȻý³£ÊýKsp=5.6¡Á10-12¡£È¡ÊÊÁ¿µÄÂËÒºB£¬¼ÓÈëÒ»¶¨Á¿µÄÉÕ¼îÖÁ´ïµ½³ÁµíÈܽâƽºâ£¬²âµÃpH=13.00£¬Ôò´ËζÈϲÐÁôÔÚÈÜÒºÖеÄc(Mg2+)=__________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010½ìÌì½òлªÖÐѧ¸ßÈýÏÂѧÆÚµÚÈý´ÎÔ¿¼»¯Ñ§¾í ÌâÐÍ£ºÌî¿ÕÌâ

´ÓÂÁÍÁ¿ó(Ö÷Òª³É·ÖÊÇAl2O3£¬º¬SiO2¡¢Fe2O3¡¢MgOµÈÔÓÖÊ)ÖÐÌáÈ¡Á½ÖÖ¹¤ÒÕÆ·µÄÁ÷³ÌÈçÏ£º

Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©Á÷³Ì¼×¼ÓÈëÑÎËáºóÉú³ÉAl3+µÄ·½³ÌʽΪ                                 ¡£
£¨2£©Á÷³ÌÒÒ¼ÓÈëÉÕ¼îºóÉú³ÉSiO32£­µÄÀë×Ó·½³ÌʽΪ                            ¡£
£¨3£©ÑéÖ¤ÂËÒºBº¬Fe3+£¬¿ÉÈ¡ÉÙÁ¿ÂËÒº²¢¼ÓÈë              £¨ÌîÊÔ¼ÁÃû³Æ£©¡£
£¨4£©ÂËÒºEÖÐÈÜÖʵÄÖ÷Òª³É·ÝÊÇ         £¨Ìѧʽ£©£¬Ð´³ö¸ÃÎïÖʵÄÒ»ÖÖ¾ßÌåÓÃ;            ¡£
£¨5£©ÒÑÖª298 Kʱ£¬Mg(OH)2µÄÈݶȻý³£ÊýKsp=5.6¡Á10£­12£¬È¡ÊÊÁ¿µÄÂËÒºB£¬¼ÓÈëÒ»¶¨Á¿µÄÉÕ¼î´ïµ½³ÁµíÈÜҺƽºâ£¬²âµÃpH=13.00£¬Ôò´ËζÈϲÐÁôÔÚÈÜÒºÖеÄc(Mg2+) =             ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2015½ìÖØÇìÊи߶þÉÏѧÆÚÆÚÖп¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ

ÄÑÈÜÐÔÔÓ±ʯ(K2SO4¡¤MgSO4¡¤2CaSO4¡¤2H2O)ÊôÓÚ¡°´ô¿ó¡±£¬ÔÚË®ÖдæÔÚÈçÏÂÈܽâƽºâ£º

K2SO4¡¤MgSO4¡¤2CaSO4¡¤2H2O(s)2Ca2£«£«2K£«£«Mg2£«£«4SO42-£«2H2O¡£ÎªÄܳä·ÖÀûÓüØ×ÊÔ´£¬Óñ¥ºÍCa(OH)2ÈÜÒºÈܽþÔÓ±ʯÖƱ¸ÁòËá¼Ø£¬¹¤ÒÕÁ÷³ÌÈçÏ£º

£¨1£©ÂËÔüÖ÷Òª³É·ÖÓÐ________ºÍCaSO4ÒÔ¼°Î´ÈÜÔÓ±ʯ¡£

£¨2£©Óû¯Ñ§Æ½ºâÒƶ¯Ô­Àí½âÊÍCa(OH)2ÈÜÒºÄÜÈܽâÔÓ±ʯ½þ³öK£«µÄÔ­Òò£º

                                                                                      ¡£

£¨3£©¡°³ýÔÓ¡±»·½ÚÖУ¬ÏȼÓÈë             ÈÜÒº£¬¾­½Á°èµÈ²Ù×÷ºó£¬¹ýÂË£¬ÔÙ¼ÓÈë         ÈÜÒºµ÷ÂËÒºpHÖÁÖÐÐÔ¡£

£¨4£©²»Í¬Î¶ÈÏ£¬K£«µÄ½þ³öŨ¶ÈÓëÈܽþʱ¼äµÄ¹Øϵ¼ûÓÒͼ¡£ÓÉͼ¿ÉµÃ£¬Ëæ×ÅζÈÉý¸ß£¬

¢Ù                                      £¬

¢Ú                                       £¬

¢ÛÈܽþ³öµÄK£«µÄƽºâŨ¶ÈÔö´ó¡£

£¨5£©ÓÐÈËÒÔ¿ÉÈÜÐÔ̼ËáÑÎΪÈܽþ¼Á£¬ÔòÈܽþ¹ý³ÌÖлᷢÉú£ºCaSO4(s)£«CO32-CaCO3(s)£«SO42-¡£ÒÑÖª298 Kʱ£¬Ksp(CaCO3)£½2.80¡Á10£­9£¬Ksp(CaSO4)£½4.90¡Á10£­5£¬¼ÆËã´ËζÈϸ÷´Ó¦µÄƽºâ³£Êý£¬K£½                                   ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012-2013ѧÄêºÓ±±Ê¡Ê¯¼ÒׯÊиßÈýÊîÆÚµÚ¶þ´Î¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ

£¨6·Ö£©´ÓÂÁÍÁ¿ó(Ö÷Òª³É·ÖÊÇAl2O3£¬º¬SiO2¡¢Fe2O3¡¢MgOµÈÔÓÖÊ)ÖÐÌáÈ¡Á½ÖÖ¹¤ÒÕÆ·µÄÁ÷³ÌÈçÏ£º

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

(1)Á÷³Ì¼×¼ÓÈëÑÎËáºóÉú³ÉAl3£«µÄÀë×Ó·½³ÌʽΪ                           ¡£

(2)Á÷³ÌÒÒ¼ÓÈëÉÕ¼îºóÉú³ÉSiO32¡ªµÄÀë×Ó·½³ÌʽΪ                             ¡£

(3)ÑéÖ¤ÂËÒºBº¬Fe3£«£¬¿ÉÈ¡ÉÙÁ¿ÂËÒº²¢¼ÓÈë              (ÌîÊÔ¼ÁÃû³Æ)¡£

(4)ÂËÒºE¡¢KÖÐÈÜÖʵÄÖ÷Òª³É·ÝÊÇ           (Ìѧʽ)£¬Ð´³ö¸ÃÈÜÒºµÄÒ»ÖÖÓÃ;

                 ¡£

(5)ÒÑÖª298 Kʱ£¬Mg(OH)2µÄÈܶȻý³£ÊýKsp£½5.6¡Á10£­12£¬È¡ÊÊÁ¿µÄÂËÒºB£¬¼ÓÈëÒ»¶¨Á¿µÄÉÕ¼î´ïµ½³ÁµíÈܽâƽºâ£¬²âµÃpH£½13.00£¬Ôò´ËζÈϲÐÁôÔÚÈÜÒºÖеÄc(Mg2£«)£½         ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012-2013ѧÄêɽ¶«Ê¡¸ßÈý10Ô½׶βâÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ

£¨10·Ö£©´ÓÂÁÍÁ¿ó(Ö÷Òª³É·ÖÊÇAl2O3£¬º¬SiO2¡¢Fe2O3¡¢MgOµÈÔÓÖÊ)ÖÐÌáÈ¡Ñõ»¯ÂÁµÄÁ½ÖÖ¹¤ÒÕÁ÷³ÌÈçÏ£º

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©Á÷³Ì¼×ͨÈë¹ýÁ¿CO2ºóÉú³É³ÁµíFµÄÀë×Ó·´Ó¦·½³ÌʽΪ______________________________________¡£

(2Á÷³ÌÒÒ¼ÓÈëÉÕ¼îÈܽâSiO2µÄ»¯Ñ§·´Ó¦·½³Ìʽ____________________¡£

(3)ÑéÖ¤ÂËÒºBº¬Fe3£«£¬¿ÉÈ¡ÉÙÁ¿ÂËÒº²¢¼ÓÈë________(ÌîÊÔ¼ÁÃû³Æ)¡£

(4)ÂËÒºE¡¢KÖÐÈÜÖʵÄÖ÷Òª³É·ÖÊÇ________(Ìѧʽ)£¬Ð´³ö¸ÃÈÜÖʵÄÒ»ÖÖÓÃ;____________________¡£

(5)ÒÑÖª298 Kʱ£¬Mg(OH)2µÄÈܶȻý³£ÊýKsp£½5.6¡Á10£­12£¬È¡ÊÊÁ¿µÄÂËÒºB£¬¼ÓÈëÒ»¶¨Á¿µÄÉÕ¼îÖÁ´ïµ½³ÁµíÈܽâƽºâ£¬²âµÃpH£½12£¬Ôò´ËζÈϲÐÁôÔÚÈÜÒºÖеÄc(Mg2£«)£½________________¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸