»¯ºÏÎïA¡¢BÊÇÖÐѧ³£¼ûµÄÎïÖÊ£¬ÆäÒõ¡¢ÑôÀë×ÓÖ»ÄÜ´ÓϱíÖÐÑ¡Ôñ£º
ÑôÀë×Ó | K£«¡¢Na£«¡¢Fe2£«¡¢Ba2£«¡¢NH¡¢Ca2£« |
ÒõÀë×Ó | OH£¡¢NO¡¢I£¡¢HCO¡¢[Al(OH)4]£¡¢HSO |
(1)ÈôA¡¢BµÄË®ÈÜÒº¾ùΪÎÞÉ«£¬ÇÒAµÄË®ÈÜÒº³ÊÇ¿ËáÐÔ£¬BµÄË®ÈÜÒº³ÊÇ¿¼îÐÔ¡£»ìºÏºó²úÉú²»ÈÜÓÚÏ¡ÑÎËáµÄ°×É«³Áµí¼°ÄÜʹʪÈóµÄºìɫʯÈïÊÔÖ½±äÀ¶É«µÄÆøÌå¡£
¢ÙBµÄ»¯Ñ§Ê½Îª__________________________________________________________¡£
¢ÚA¡¢BÈÜÒº»ìºÏ¼ÓÈÈ·´Ó¦µÄÀë×Ó·½³Ìʽ_____________________________________¡£
(2)ÈôAµÄË®ÈÜÒº³ÊdzÂÌÉ«£¬BµÄË®ÈÜÒºÎÞÉ«ÇÒÆäÑæÉ«·´Ó¦Îª»ÆÉ«¡£ÏòAµÄË®ÈÜÒºÖмÓÈëÏ¡ÑÎËáÎÞÃ÷ÏÔÏÖÏó£¬ÔÙ¼ÓÈëBºóÈÜÒº±ä»Æ£¬µ«A¡¢BµÄË®ÈÜÒº»ìºÏÒàÎÞÃ÷ÏԱ仯¡£Ôò
¢ÙAµÄ»¯Ñ§Ê½Îª__________________________________________________________¡£
¢Ú¾·ÖÎöÉÏÊö¹ý³ÌÖÐÈÜÒº±ä»ÆµÄÔÒò¿ÉÄÜÓÐÁ½ÖÖ(ÓÃÀë×Ó·½³Ìʽ±íʾ)
¢ñ________________________________________________________________________£»
¢ò________________________________________________________________________¡£
¢ÛÇëÓÃÒ»¼òÒ×·½·¨Ö¤Ã÷ÉÏÊöÈÜÒº±ä»ÆµÄÔÒò___________________________________¡£
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨ £©
A£®ÌúÊÇλÓÚµÚËÄÖÜÆÚµÚ¢øB×åÔªËØ, ÊÇÒ»ÖÖÖØÒªµÄ¹ý¶ÉÔªËØ
B£®ËÄÑõ»¯ÈýÌúÊÇÑõ»¯ÌúºÍÑõ»¯ÑÇÌú×é³ÉµÄ»ìºÏÎï
C£®14¿ËÌú·ÛºÍ7¿ËÁò·Û»ìºÏºó¸ßÎÂϳä·Ö·´Ó¦ÄÜÉú³É21¿ËÁò»¯ÑÇÌú
D£®ÌúÔÚäåÕôÆøÖеãȼ¿ÉÉú³ÉFeBr3
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ÒÑÖª£ºA¡¢B¡¢C¡¢D¡¢E¡¢FÔÚ³£ÎÂϾùΪÆøÌ壬ËüÃÇÓÐÒÔÏÂת»¯¹Øϵ£¨²¿·Ö·´Ó¦Ìõ¼þ¡¢²úÎïÒÑÂÔÈ¥£©¡£
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©½«AµãȼºóÉìÈëµ½×°ÓÐEµÄ¼¯ÆøÆ¿ÖУ¬¿É¹Û²ìµ½µÄÏÖÏóÊÇ_________________.
£¨2£©CµÄŨÈÜÒºÓëºÚÉ«·ÛÄ©·´Ó¦Éú³ÉEµÄ»¯Ñ§·½³ÌʽΪ________________________¡£
£¨3£©Èô½«ÈÜÒº¢òµÎÈëµ½µâ»¯¼ØÈÜÒºÖУ¬·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ__________________£¬Ïò·´Ó¦ºóµÄÈÜÒºÖмÓÈëÊÊÁ¿CCl4£¬³ä·ÖÕñµ´ºó¾²Ö㬿ÉÒԹ۲쵽µÄÏÖÏóÊÇ_______________¡£
£¨4£©ÓëÈÜÒº¢ñ±È½Ï£¬ÈÜÒº¢òÖжà³öµÄÎïÖÊÊÇ £¨Ìѧʽ£©¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ÏÖÓÐһƿ±êÇ©ÉÏ×¢Ã÷ΪÆÏÌÑÌÇËáÑÎ(ÄÆ¡¢Ã¾¡¢¸Æ¡¢Ìú)µÄ¸´ºÏÖƼÁ£¬Ä³Í¬Ñ§ÎªÁËÈ·ÈÏÆä³É·Ö£¬È¡²¿·ÖÖƼÁ×÷ΪÊÔÒº£¬Éè¼Æ²¢Íê³ÉÁËÈçÏÂʵÑ飺
ÒÑÖª£º¿ØÖÆÈÜÒºpH£½4ʱ£¬Fe(OH)3³ÁµíÍêÈ«£¬Ca2£«¡¢Mg2£«²»³Áµí¡£
¸ÃͬѧµÃ³öµÄ½áÂÛÕýÈ·µÄÊÇ (¡¡¡¡)
A£®¸ù¾ÝÏÖÏó1¿ÉÍƳö¸ÃÊÔÒºÖк¬ÓÐNa£«
B£®¸ù¾ÝÏÖÏó2¿ÉÍƳö¸ÃÊÔÒºÖв¢²»º¬ÓÐÆÏÌÑÌÇËá¸ù
C£®¸ù¾ÝÏÖÏó3ºÍ4¿ÉÍƳö¸ÃÊÔÒºÖк¬ÓÐCa2£«£¬µ«Ã»ÓÐMg2£«
D£®¸ù¾ÝÏÖÏó5¿ÉÍƳö¸ÃÊÔÒºÖÐÒ»¶¨º¬ÓÐFe2£«
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ÒÑÖªËÄÖÖÇ¿µç½âÖÊÈÜÒº£¬·Ö±ðº¬ÓÐÏÂÁÐÒõ¡¢ÑôÀë×ÓÖеĸ÷Ò»ÖÖ£¬²¢ÇÒ»¥²»Öظ´£ºNH4£«¡¢Ba2£«¡¢Na£«¡¢H£«¡¢SO42£¡¢NO3£¡¢OH£¡¢CO32£¡£½«ÕâËÄÖÖÈÜÒº·Ö±ð±ê¼ÇΪA¡¢B¡¢C¡¢D£¬½øÐÐÈçÏÂʵÑ飺
¢ÙÔÚA»òDÖеÎÈëC£¬¾ùÓгÁµíÉú³É£»¢ÚDºÍB·´Ó¦Éú³ÉµÄÆøÌåÄܱ»AÎüÊÕ£»¢ÛAºÍD·´Ó¦Éú³ÉµÄÆøÌåÄܱ»BÎüÊÕ¡£
ÊԻشðÏÂÁÐÎÊÌ⣺
(1)DµÄ»¯Ñ§Ê½ÊÇ________£¬ÅжÏÀíÓÉÊÇ__________________________¡£
(2)д³öÆäÓ༸ÖÖÎïÖʵĻ¯Ñ§Ê½£ºA________£¬B________£¬C________¡£
(3)д³öʵÑé¢ÚÖÐÓйط´Ó¦µÄÀë×Ó·½³Ìʽ____________________________________¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ÒÑ֪ijÈÜÒºÖдæÔڽ϶àµÄH£«¡¢SO¡¢NO£¬Ôò¸ÃÈÜÒºÖл¹¿ÉÄÜ´óÁ¿´æÔÚµÄÀë×Ó×éÊÇ(¡¡¡¡)
A£®Al3£«¡¢CH3COO£¡¢Cl£¡¡¡¡¡¡¡¡ B£®Na£«¡¢NH¡¢Cl£
C£®Mg2£«¡¢Cl£¡¢Ag£« D£®Mg2£«¡¢Ba2£«¡¢Cl£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ÏÂÁÐÀë×Ó·½³Ìʽ´íÎóµÄÊÇ
A£®ÏòBa(OH)2ÈÜÒºÖеμÓÏ¡ÁòË᣺Ba2£«£«2OH££«2H£«£« SO42 £ =BaS04¡ý£«2H2O
B£®ËáÐÔ½éÖÊÖÐKMnO4Ñõ»¯ H2O2£º2MnO4£ £«5H2O2£«6H£« = 2Mn2£«£«5O2¡ü£« 8H2O
C£®µÈÎïÖʵÄÁ¿µÄMgCl2¡¢Ba(OH)2 ºÍ HC1 ÈÜÒº»ìºÏ£ºMg2£«£«2OH£= Mg(OH)2¡ý
D£®Ç¦ËáÐîµç³Ø³äµçʱµÄÕý¼«·´Ó¦£ºPbSO4£«2H2O£2e- = PbO2£«4H£«£«SO42
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ÏÂÁÐÏà¹Ø·´Ó¦µÄÀë×Ó·½³ÌʽÊéдÕýÈ·µÄÊÇ (¡¡¡¡)
A£®ÇâÑõ»¯ÌúÈÜÓÚÇâµâË᣺Fe(OH)3£«3H£«=Fe3£«£«3H2O
B£®ÁòËáÍÈÜÒºÏÔËáÐÔ£ºCu2£«£«2H2O=Cu(OH)2¡ý£«2H£«
C£®Ïò̼ËáÇâï§ÈÜÒºÖмӹýÁ¿Ê¯»ÒË®²¢¼ÓÈÈ£ºNH£«OH£=NH3¡ü£«H2O
D£®ÓÃËữµÄ¸ßÃÌËá¼ØÈÜÒºÑõ»¯Ë«ÑõË®£º2MnO£«6H£«£«5H2O2=2Mn2£«£«5O2¡ü£«8H2O
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
NAΪ°¢·ü¼ÓµÂÂÞ³£ÊýµÄÊýÖµ£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ(¡¡¡¡)
A£®Ò»¶¨Ìõ¼þÏ£¬1.5 mol H2ºÍ0.5 mol N2³ä·Ö·´Ó¦ºó¿ÉµÃµ½NH3µÄ·Ö×ÓÊýΪNA
B£®×ãÁ¿µÄFeÓëCl2·´Ó¦Éú³É0.1 mol²úÎïʱʧȥµÄµç×ÓÊýΪ0.3NA
C£®³£Î³£Ñ¹Ï£¬18 g H2Oº¬Óеĵç×Ó×ÜÊýΪ8NA
D£®±ê×¼×´¿öÏ£¬22.4 LµÄ¼ºÏ©Öк¬ÓеķÖ×ÓÊýΪNA
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com