£¨1£©ÏÂͼ¸÷ÉÕ±­ÖÐÊ¢Óк£Ë®£¬ÌúÔÚÆäÖи¯Ê´¡£ÌúµÄ¸¯Ê´ËÙÂÊÓÉ¿ìµ½ÂýµÄ˳ÐòΪ_________________
£¨2£©ÒÑÖª£ºN2(g)+2O2(g)£½2NO2(g)£»¡÷H£½£«67£®7kJ/mol
N2H4(g)+O2(g)£½N2(g)+2H2O(g)£»¡÷H£½£­534kJ/mol
·¢ÉäÎÀÐÇÓÃ루¼´N2H4£©µÄÆøÌåΪԭÁÏ£¬ÒÔNO2ΪÑõ»¯¼Á£¬Á½ÖÖÎïÖÊ·´Ó¦Éú³ÉµªÆøºÍË®ÕôÆø£¬ÊÔд³ö¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ________________________¡£
£¨1£©¢Ü>¢Ú>¢Ù>¢Û
£¨2£©2N2H4(g)+2NO2(g)£½3N2(g)+4H2O(g)£»¡÷H£½£­1135.7kJ/mol
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º¸£½¨Ê¡ËĵØÁùУ2011£­2012ѧÄê¸ßÒ»ÉÏѧÆÚµÚ¶þ´ÎÔ¿¼»¯Ñ§ÊÔÌâ ÌâÐÍ£º058

ijÐËȤС×éÄâÀûÓÃÈçÏÂͼװÖÃ̽¾¿ÑéÖ¤¸ÉÔïµÄCl2ºÍ³±ÊªµÄCl2ÓÐÎÞƯ°×ÐÔ£®

»Ø´ðÏÂÁÐÎÊÌ⣺

(1)A×°ÖÃÖеÄÖ÷Òª²£Á§ÒÇÆ÷ÓУºµ¼¹Ü¡¢¾Æ¾«µÆ¡¢Ô²µ×ÉÕÆ¿¡¢________£®

A×°ÖÃÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ________£®

F×°ÖÃÖеÄÊÔ¼ÁӦΪ________£¬×÷ÓÃΪ________£®

(2)°´ÆøÌå´Ó×óÏòÓÒÁ÷Ïò½«¸÷×°ÖÃÒÀ´ÎÁ¬½ÓÆðÀ´(Ìî½Ó¿Ú±êºÅ)£ºa½Ó________£¬________½Ó________£¬________½Ó________£¬________½Ó________£¬________½Ó________£®

(3)ͨÈëCl2ºó£¬´Ó¼¯ÆøÆ¿A¡¢BÖкìÉ«²¼ÌõµÄÏÖÏó¿ÉµÃ³öµÄ½áÂÛÊÇ________£»ÆäÖз¢ÉúµÄ·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ________£®

(4)ΪÁËÈ·Ö¤ÊÇHClOʹʪÈóµÄºìÉ«²¼ÌõÍÊÉ«£¬ÄãÈÏΪ»¹Ó¦Ôö¼ÓµÄʵÑéÊÇ________£®

(5)ÉÕ±­EÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ________£®

(6)Ϊ±£Ö¤ÊµÑ鰲ȫ£¬µ±ÂÈÆøÒÔÿ·ÖÖÓ1.12 L(±ê×¼×´¿ö)µÄÁ÷ËÙÔÈËÙͨÈëʱ£¬ÈôʵÑéÐèºÄʱ4·ÖÖÓ£¬Ð¡ÉÕ±­ÖÐÊ¢4 mol¡¤L£­1µÄNaOHÈÜÒºµÄÌå»ýÖÁÉÙӦΪ________mL£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º¸£½¨Ê¡ËĵØÁùУ2011£­2012ѧÄê¸ßÒ»µÚ¶þ´ÎÔ¿¼»¯Ñ§ÊÔÌâ ÌâÐÍ£º058

ijÐËȤС×éÄâÀûÓÃÈçÏÂͼװÖÃ̽¾¿ÑéÖ¤¸ÉÔïµÄCl2ºÍ³±ÊªµÄCl2ÓÐÎÞƯ°×ÐÔ£®

»Ø´ðÏÂÁÐÎÊÌ⣺

(1)A×°ÖÃÖеÄÖ÷Òª²£Á§ÒÇÆ÷ÓУºµ¼¹Ü¡¢¾Æ¾«µÆ¡¢Ô²µ×ÉÕÆ¿¡¢________£®

A×°ÖÃÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ________£®

F×°ÖÃÖеÄÊÔ¼ÁӦΪ________£¬×÷ÓÃΪ________£®

(2)°´ÆøÌå´Ó×óÏòÓÒÁ÷Ïò½«¸÷×°ÖÃÒÀ´ÎÁ¬½ÓÆðÀ´(Ìî½Ó¿Ú±êºÅ)£ºa½Ó________£¬________½Ó________£¬________½Ó________£¬________½Ó________£¬________½Ó________£®

(3)ͨÈëCl2ºó£¬´Ó¼¯ÆøÆ¿A¡¢BÖкìÉ«²¼ÌõµÄÏÖÏó¿ÉµÃ³öµÄ½áÂÛÊÇ________£»ÆäÖз¢ÉúµÄ·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ________£®

(4)ΪÁËÈ·Ö¤ÊÇHClOʹʪÈóµÄºìÉ«²¼ÌõÍÊÉ«£¬ÄãÈÏΪ»¹Ó¦Ôö¼ÓµÄʵÑéÊÇ________£®

(5)ÉÕ±­EÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ________£®

(6)Ϊ±£Ö¤ÊµÑ鰲ȫ£¬µ±ÂÈÆøÒÔÿ·ÖÖÓ1.12 L(±ê×¼×´¿ö)µÄÁ÷ËÙÔÈËÙͨÈëʱ£¬ÈôʵÑéÐèºÄʱ4·ÖÖÓ£¬Ð¡ÉÕ±­ÖÐÊ¢4 mol¡¤L£­1µÄNaOHÈÜÒºµÄÌå»ýÖÁÉÙӦΪ________mL£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ijѧÉúÓõç×ÓÌìƽºÍ±ØÒªµÄ»¯Ñ§ÊµÑéÒÇÆ÷²â¶¨ÌúÂÁºÏ½ðÖи÷×é·Öº¬Á¿£¬ÆäʵÑé×°ÖÃÈçÏÂͼËùʾ£º

ʵÑéʱ£¬È¡Ò»¿éÌúÂÁºÏ½ð£¬½«ÆäÇгÉËé¿éºóÈ«²¿¼ÓÈ뵽ʢÓÐ50 mL 5.0 mol¡¤L-1 NaOHÈÜÒºµÄÉÕ±­ÖС£ÊÔÍê³ÉÏÂÁÐÎÊÌ⣺

(1)ºÏ½ð±íÃæ×îÏȲúÉúÆøÅݵÄλÖÃÊÇ___________ (Ìî¡°ÇпڶÏÃ桱»ò¡°·ÇÇпڶÏÃ桱)£¬·´Ó¦µÄÀë×Ó·½³ÌʽΪ£º__________________________________¡£

(2)ºÏ½ð±íÃæ»áÐγÉÔ­µç³Ø£¬Æ为¼«µÄµç¼«·´Ó¦Ê½Îª£º__________________________________¡£

(3)²»Í¬Ê±¼äµç×ÓÌìƽµÄ¶ÁÊýÈçϱíËùʾ£º

ʵÑé²Ù×÷¹ý³Ì

ʱ¼ä/min

µç×ÓÌìƽµÄ¶ÁÊý/g

ÉÕ±­+NaOHÈÜÒº

 

80.0

ÉÕ±­+ÈÜÒº+ÑùÆ·

0

87.8

1

87.5

2

87.3

3

87.2

4

87.2

ÔòºÏ½ðÖÐÌúµÄÖÊÁ¿·ÖÊýΪ____________(±£ÁôÈýλÓÐЧÊý×Ö£¬ÏÂͬ)¡£

(4)ÉÏÊö50 mL NaOHÈÜÒºÖÐ×î¶à¿É¼ÓÈëµÄÌúÂÁºÏ½ðÑùÆ·ÖÊÁ¿Îª___________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄ긣½¨Ê¡ËĵØÁùУ¸ßÒ»µÚ¶þ´ÎÔ¿¼»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÊµÑéÌâ

£¨ 16·Ö£©Ä³ÐËȤС×éÄâÀûÓÃÈçÏÂͼװÖÃ̽¾¿ÑéÖ¤¸ÉÔïµÄCl2ºÍ³±ÊªµÄCl2ÓÐÎÞƯ°×ÐÔ¡£

»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©A×°ÖÃÖеÄÖ÷Òª²£Á§ÒÇÆ÷ÓУºµ¼¹Ü¡¢¾Æ¾«µÆ¡¢Ô²µ×ÉÕÆ¿¡¢         ¡£
A×°ÖÃÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ                                   ¡£
F×°ÖÃÖеÄÊÔ¼ÁӦΪ            £¬×÷ÓÃΪ                         ¡£
£¨2£©°´ÆøÌå´Ó×óÏòÓÒÁ÷Ïò½«¸÷×°ÖÃÒÀ´ÎÁ¬½ÓÆðÀ´£¨Ìî½Ó¿Ú±êºÅ£©£º a ½Ó    £¬
    ½Ó  £¬  ½Ó    £¬    ½Ó     £¬    ½Ó     ¡£
£¨3£©Í¨ÈëCl2ºó£¬´Ó¼¯ÆøÆ¿A¡¢BÖкìÉ«²¼ÌõµÄÏÖÏó¿ÉµÃ³öµÄ½áÂÛÊÇ            
                                                                £»ÆäÖз¢ÉúµÄ·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ                                         ¡£
£¨4£©ÎªÁËÈ·Ö¤ÊÇHClOʹʪÈóµÄºìÉ«²¼ÌõÍÊÉ«£¬ÄãÈÏΪ»¹Ó¦Ôö¼ÓµÄʵÑéÊÇ         
                                                                           ¡£
£¨5£©ÉÕ±­EÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ                               ¡£
£¨6£©Îª±£Ö¤ÊµÑ鰲ȫ£¬µ±ÂÈÆøÒÔÿ·ÖÖÓ1.12L£¨±ê×¼×´¿ö£©µÄÁ÷ËÙÔÈËÙͨÈëʱ£¬ÈôʵÑéÐèºÄʱ4·ÖÖÓ£¬Ð¡ÉÕ±­ÖÐÊ¢4 mol¡¤L£­1µÄNaOHÈÜÒºµÄÌå»ýÖÁÉÙӦΪ        mL¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º¸£½¨Ê¡Ô¿¼Ìâ ÌâÐÍ£ºÊµÑéÌâ

ijÐËȤС×éÄâÀûÓÃÈçÏÂͼװÖÃ̽¾¿ÑéÖ¤¸ÉÔïµÄCl2ºÍ³±ÊªµÄCl2ÓÐÎÞƯ°×ÐÔ¡£   »Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©A×°ÖÃÖеÄÖ÷Òª²£Á§ÒÇÆ÷ÓУºµ¼¹Ü¡¢¾Æ¾«µÆ¡¢Ô²µ×ÉÕÆ¿¡¢__________¡£ A×°ÖÃÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ____________¡£ F×°ÖÃÖеÄÊÔ¼ÁӦΪ____________£¬×÷ÓÃΪ___________¡£
£¨2£©°´ÆøÌå´Ó×óÏòÓÒÁ÷Ïò½«¸÷×°ÖÃÒÀ´ÎÁ¬½ÓÆðÀ´£¨Ìî½Ó¿Ú±êºÅ£©£º a  ½Ó_________£¬   _______½Ó______£¬______½Ó_______ £¬_______½Ó_______£¬_______½Ó________¡£
£¨3£©Í¨ÈëCl2ºó£¬´Ó¼¯ÆøÆ¿A¡¢BÖкìÉ«²¼ÌõµÄÏÖÏó¿ÉµÃ³öµÄ½áÂÛÊÇ__________ £»ÆäÖз¢ÉúµÄ·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ_______________¡£
£¨4£©ÎªÁËÈ·Ö¤ÊÇHClOʹʪÈóµÄºìÉ«²¼ÌõÍÊÉ«£¬ÄãÈÏΪ»¹Ó¦Ôö¼ÓµÄʵÑéÊÇ___________¡£
£¨5£©ÉÕ±­EÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ______________¡£
£¨6£©Îª±£Ö¤ÊµÑ鰲ȫ£¬µ±ÂÈÆøÒÔÿ·ÖÖÓ1.12L£¨±ê×¼×´¿ö£©µÄÁ÷ËÙÔÈËÙͨÈëʱ£¬ÈôʵÑéÐèºÄʱ4·ÖÖÓ£¬Ð¡ÉÕ±­ÖÐÊ¢4 mol¡¤L£­1µÄNaOHÈÜÒºµÄÌå»ýÖÁÉÙӦΪ___________mL¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸