ij¹¤Òµ·ÏË®½öº¬Ï±íÖеÄijЩÀë×Ó£¬ÇÒ¸÷ÖÖÀë×ÓµÄÎïÖʵÄÁ¿Å¨¶ÈÏàµÈ£¬¾ùΪ0.1 mol/L(´ËÊýÖµºöÂÔË®µÄµçÀë¼°Àë×ÓµÄË®½â)¡£

ÑôÀë×Ó

K£«

Ag£«

Mg2£«

Cu2£«

Al3£«

NH

ÒõÀë×Ó

Cl£­

CO

NO

SO

SiO

I£­

¼×ͬѧÓû̽¾¿·ÏË®µÄ×é³É£¬½øÐÐÁËÈçÏÂʵÑ飺

¢ñ.È¡¸ÃÎÞÉ«ÈÜÒº5 mL£¬µÎ¼ÓÒ»µÎ°±Ë®ÓгÁµíÉú³É£¬ÇÒÀë×ÓÖÖÀàÔö¼Ó¡£

¢ò.Óò¬Ë¿ÕºÈ¡ÈÜÒº£¬ÔÚ»ðÑæÉÏ×ÆÉÕ£¬Í¸¹ýÀ¶É«îܲ£Á§¹Û²ì£¬ÎÞ×ÏÉ«»ðÑæ¡£

¢ó.ÁíÈ¡ÈÜÒº¼ÓÈë¹ýÁ¿ÑÎËᣬÓÐÎÞÉ«ÆøÌåÉú³É£¬¸ÃÎÞÉ«ÆøÌåÓö¿ÕÆø±ä³Éºì×ØÉ«¡£

¢ô.Ïò¢óÖÐËùµÃµÄÈÜÒºÖмÓÈëBaCl2ÈÜÒº£¬Óа×É«³ÁµíÉú³É¡£

ÇëÍƶϣº

(1)ÓÉ¢ñ¡¢¢òÅжϣ¬ÈÜÒºÖÐÒ»¶¨²»º¬ÓеÄÑôÀë×ÓÊÇ______¡£

(2)¢óÖмÓÈëÑÎËáÉú³ÉÎÞÉ«ÆøÌåµÄÀë×Ó·½³ÌʽÊÇ________________¡£

(3)¼×ͬѧ×îÖÕÈ·¶¨Ô­ÈÜÒºÖÐËùº¬ÑôÀë×ÓÓÐ________£¬ÒõÀë×ÓÓÐ________£»²¢¾Ý´ËÍƲâÔ­ÈÜÒºÓ¦¸Ã³Ê________ÐÔ£¬Ô­ÒòÊÇ________________________(ÇëÓÃÀë×Ó·½³Ìʽ˵Ã÷)¡£

(4)ÁíÈ¡100 mLÔ­ÈÜÒº£¬¼ÓÈë×ãÁ¿µÄNaOHÈÜÒº£¬´Ë¹ý³ÌÖÐÉæ¼°µÄÀë×Ó·½³ÌʽΪ_____________________________________________________

___________________________________________________________¡£

³ä·Ö·´Ó¦ºó¹ýÂË£¬Ï´µÓ£¬×ÆÉÕ³ÁµíÖÁºãÖØ£¬µÃµ½µÄ¹ÌÌåÖÊÁ¿Îª________g¡£


½âÎö¡¡(1)¸ù¾Ý¢ñ£¬ÈÜҺΪÎÞÉ«£¬ÔòÈÜÒºÖв»º¬Cu2£«£¬Éú³É³ÁµíºóÀë×ÓÖÖÀàÔö¼Ó£¬ËµÃ÷Ô­ÈÜÒºÖв»º¬NH£»¸ù¾Ý¢ò¿ÉÈ·¶¨ÈÜÒºÖв»º¬K£«¡£(2)¸ù¾Ý¢óµÄÃèÊö¿ÉÈ·¶¨Éú³ÉµÄÎÞÉ«ÆøÌåΪNO£¬ÔòÔ­ÈÜÒºÖÐÒ»¶¨º¬ÓÐNOºÍI£­£¬¸ù¾ÝתÒƵç×ÓÊýÄ¿ÏàµÈ¡¢µçºÉÊغã¿Éд³öÀë×Ó·½³Ìʽ¡£(3)½áºÏ¢ôºÍÈÜÒºÖи÷Àë×ÓŨ¶ÈÏàµÈ¿ÉÈ·¶¨ÈÜÒºÖк¬ÓеÄÒõÀë×ÓΪSO¡¢Cl£­¡¢NOºÍI£­£¬ÈÜÒºÖк¬ÓеÄÑôÀë×ÓΪMg2£«¡¢Al3£«£»½áºÏÈÜÒºµÄ×é³É¿ÉÈ·¶¨ÈÜÒºÏÔËáÐÔ£¬ÊÇMg2£«¡¢Al3£«Ë®½âµÄÔµ¹Ê¡£(4)¼ÓÈëNaOHÈÜÒº£¬Mg2£«×ª»¯ÎªMg(OH)2³Áµí£¬Al3£«×îºóת»¯ÎªNaAlO2£¬×îÖյõ½0.01 mol Mg(OH)2³Áµí£¬×ÆÉÕÖÁºãÖصõ½0.4 g MgO¡£

´ð°¸¡¡(1)K£«¡¢NH¡¢Cu2£«

(2)6I£­£«2NO£«8H£«===3I2£«2NO¡ü£«4H2O

(3)Mg2£«¡¢Al3£«¡¡Cl£­¡¢NO¡¢SO¡¢I£­¡¡Ëá¡¡Mg2£«£«2H2OMg(OH)2£«2H£«¡¢Al3£«£«3H2OAl(OH)3£«3H£«

(4)Mg2£«£«2OH£­===Mg(OH)2¡ý¡¢Al3£«£«4OH£­===AlO£«2H2O¡¡0.4


Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÏàͬζÈÏ£¬ÓÐÏÂÁÐÈý¸öÈÈ»¯Ñ§·½³Ìʽ£º

£¨1£©2H2£¨l£©+O2£¨g£©=== 2H2O£¨l£©    ¡÷H1= -Q1 kJ• mol-1

£¨2£©2H2£¨g£©+O2£¨g£©=== 2H2O£¨l£©     ¡÷H1= -Q2 kJ• mol-1

£¨3£©2H2£¨l£©+O2£¨g£©=== 2H2O£¨g£©     ¡÷H1= -Q3 kJ• mol-1

ÔòQ1¡¢Q2¡¢Q3µÄ¹Øϵ±íʾÕýÈ·µÄÊÇ£¨    £©

A. Q1=Q2<Q3      B. Q2 > Q1 >Q3    C. Q3> Q2> Q1      D. Q1=Q2=Q3

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÓûÓÃ98%µÄŨÁòËá(p£½1.84g¡¤cm£­3 )ÅäÖƳÉŨ¶ÈΪ0.5mol¡¤L£­1µÄÏ¡ÁòËá500ml¡£ 

(1) Ñ¡ÓõÄÖ÷ÒªÒÇÆ÷ÓУº 

 ¢Ù__________£¬¢Ú__________£¬¢Û__________£¬¢Ü____________£¬¢Ý____________¡£

  (2) Ç뽫ÏÂÁи÷²Ù×÷£¬°´ÕýÈ·µÄÐòºÅÌîÔÚºáÏßÉÏ¡£ 

 A£®ÓÃÁ¿Í²Á¿È¡Å¨H2SO4            B£®·´¸´µßµ¹Ò¡ÔÈ 

C£®ÓýºÍ·µÎ¹Ü¼ÓÕôÁóË®ÖÁ¿Ì¶ÈÏß    D£®Ï´¾»ËùÓÃÒÇÆ÷ 

E£®Ï¡ÊÍŨH2SO4                  F£®½«ÈÜҺתÈëÈÝÁ¿Æ¿  

  Æä²Ù×÷ÕýÈ·µÄ˳ÐòÒÀ´ÎΪ__________                __________________¡£ 

 (3)¼òÒª»Ø´ðÏÂÁÐÎÊÌ⣺ 

¢ÙËùÐèŨÁòËáµÄÌå»ýΪ____________mL¡£ 

 (4)תÒÆ¡¢Ï´µÓ¡£ÔÚתÒÆʱӦʹÓÃ________ÒýÁ÷£¬ÐèҪϴµÓÉÕ±­2¡«3´ÎÊÇΪÁË______________________________________________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÏÖÓÐÎåÖÖ¿ÉÈÜÐÔÎïÖÊA¡¢B¡¢C¡¢

D¡¢E£¬ËüÃÇËùº¬Òõ¡¢ÑôÀë×Ó»¥²»Ïàͬ£¬·Ö±ðº¬ÓÐÎåÖÖÑôÀë×ÓNa£«¡¢Al3£«¡¢Mg2£«¡¢Ba2£«¡¢Fe3£«ºÍÎåÖÖÒõÀë×ÓCl£­¡¢OH£­¡¢NO¡¢CO¡¢XÖеÄÒ»ÖÖ¡£

(1)ijͬѧͨ¹ý±È½Ï·ÖÎö£¬ÈÏΪÎÞÐè¼ìÑé¾Í¿ÉÅжÏÆäÖбØÓеÄÁ½ÖÖÎïÖÊÊÇ________ºÍ________(Ìѧʽ)¡£

(2)ΪÁËÈ·¶¨X£¬ÏÖ½«(1)ÖеÄÁ½ÖÖÎïÖʼÇΪAºÍB£¬º¬XµÄÎïÖʼÇΪC£¬µ±CÓëBµÄÈÜÒº»ìºÏʱ£¬²úÉúºìºÖÉ«³ÁµíºÍÎÞÉ«ÎÞζÆøÌ壻µ±CÓëAµÄÈÜÒº»ìºÏʱ²úÉú×Ø»ÆÉ«³Áµí£¬Ïò¸Ã³ÁµíÖеÎÈëÏ¡ÏõËá³Áµí²¿·ÖÈܽ⣬×îºóÁôÓа×É«³Áµí²»ÔÙÈܽ⡣ÔòXΪ________(ÌîÑ¡Ïî×Öĸ)¡£

A£®SO¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡                B£®SO

C£®CH3COO£­                              D£®SiO

(3)½«CuͶÈëµ½×°ÓÐDÈÜÒºµÄÊÔ¹ÜÖУ¬Cu²»Èܽ⣻ÔٵμÓÏ¡H2SO4£¬CuÖð½¥Èܽ⣬¹Ü¿Ú¸½½üÓкì×ØÉ«ÆøÌå³öÏÖ¡£ÔòÎïÖÊDÒ»¶¨º¬ÓÐÉÏÊöÀë×ÓÖеÄ________(ÌîÏàÓ¦µÄÀë×Ó·ûºÅ)¡£Óйط´Ó¦µÄÀë×Ó·½³ÌʽΪ_____________¡£

(4)ÀûÓÃÉÏÊöÒѾ­È·¶¨µÄÎïÖÊ£¬¿ÉÒÔ¼ìÑé³öD¡¢EÖеÄÑôÀë×Ó¡£Çë¼òÊöʵÑé²Ù×÷²½Öè¡¢ÏÖÏó¼°½áÂÛ_______________________________________________________________________________________________________________________________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÏÂÁÐÀë×Ó·½³ÌʽÖУ¬ÕýÈ·µÄÊÇ(¡¡¡¡)

A£®ÏòNaOHÈÜÒºÖмÓÈëÉÙÁ¿Mg(HCO3)2ÈÜÒº£º2OH£­£«Mg2£«===Mg(OH)2¡ý

B£®Ïò×ãÁ¿NaHSO4ÈÜÒºÖÐÖð½¥µÎÈëBa(HCO3)2ÈÜÒº£ºHCO£«Ba2£«£«H£«£«SO===BaSO4¡ý£«H2O£«CO2¡ü

C£®ËáÐÔKMnO4ÈÜÒºÓëH2O2·´Ó¦£º2MnO£«10H£«£«3H2O2===2Mn2£«£«3O2¡ü£«8H2O

D£®ÏòFe(NO3)3ÈÜÒºÖмÓÈë¹ýÁ¿HIÈÜÒº£ºFe3£«£«3NO£«12H£«£«10I£­===Fe2£«£«3NO¡ü£«5I2£«6H2O

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


H2ºÍI2ÔÚÒ»¶¨Ìõ¼þÏÂÄÜ·¢Éú·´Ó¦£ºH2(g)£«I2(g)2HI(g)¡¡¦¤H£½£­a kJ¡¤mol£­1

ÒÑÖª£º

(a¡¢b¡¢c¾ù´óÓÚÁã)

ÏÂÁÐ˵·¨²»ÕýÈ·µÄÊÇ(¡¡¡¡)

A£®·´Ó¦ÎïµÄ×ÜÄÜÁ¿¸ßÓÚÉú³ÉÎïµÄ×ÜÄÜÁ¿

B£®¶Ï¿ª1 mol H¡ªH¼üºÍ1 mol I¡ªI¼üËùÐèÄÜÁ¿´óÓڶϿª2 mol H¡ªI¼üËùÐèÄÜÁ¿

C£®¶Ï¿ª2 mol H¡ªI¼üËùÐèÄÜÁ¿Ô¼Îª(c£«b£«a) kJ

D£®ÏòÃܱÕÈÝÆ÷ÖмÓÈë2 mol H2ºÍ2 mol I2£¬³ä·Ö·´Ó¦ºó·Å³öµÄÈÈÁ¿Ð¡ÓÚ2a kJ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÓÃCH4´ß»¯»¹Ô­NOx¿ÉÒÔÏû³ýµªÑõ»¯ÎïµÄÎÛȾ¡£ÒÑÖªCH4(g)£«4NO2(g)===4NO(g)£«CO2(g)£«2H2O(g)¡¡¦¤H£½£­574 kJ¡¤mol£­1£¬CH4(g)£«4NO(g)===2N2(g)£«CO2(g)£«2H2O(g)

¦¤H£½£­1 160 kJ¡¤mol£­1¡£ÈôÔÚ±ê×¼×´¿öÏÂ4.48 L CH4Ç¡ºÃÄܽ«Ò»¶¨Á¿NO2»¹Ô­³ÉN2ºÍH2O(g)£¬ÔòÕû¸ö¹ý³ÌÖзųöµÄÈÈÁ¿Îª(¡¡¡¡)

A£®114.8 kJ                             B£®232 kJ

C£®368.8 kJ                             D£®173.4 kJ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÈçͼËùʾ£¬Ä³Í¬Ñ§Éè¼ÆÁËÒ»¸öȼÁϵç³Ø²¢Ì½¾¿ÂȼҵԭÀíºÍ´ÖÍ­µÄ¾«Á¶Ô­Àí£¬ÆäÖÐÒÒ×°ÖÃÖÐXΪÑôÀë×Ó½»»»Ä¤¡£Çë°´ÒªÇó»Ø´ðÏà¹ØÎÊÌ⣺

(1)¼×ÍéȼÁϵç³Ø¸º¼«·´Ó¦Ê½ÊÇ______________________ __________________________________________________¡£

(2)ʯī(C)¼«µÄµç¼«·´Ó¦Ê½Îª________________ __________________________¡£

(3)ÈôÔÚ±ê×¼×´¿öÏ£¬ÓÐ2.24 LÑõÆø²Î¼Ó·´Ó¦£¬ÔòÒÒ×°ÖÃÖÐÌú¼«ÉÏÉú³ÉµÄÆøÌåÌå»ýΪ________L£»±û×°ÖÃÖÐÒõ¼«Îö³öÍ­µÄÖÊÁ¿Îª________g¡£

(4)ijͬѧÀûÓü×ÍéȼÁϵç³ØÉè¼Æµç½â·¨ÖÆȡƯ°×Òº»òFe(OH)2µÄʵÑé×°ÖÃ(ÈçͼËùʾ)¡£

ÈôÓÃÓÚÖÆƯ°×Òº£¬aΪµç³ØµÄ____¼«£¬µç½âÖÊÈÜÒº×îºÃÓÃ______¡£

ÈôÓÃÓÚÖÆFe(OH)2£¬Ê¹ÓÃÁòËáÄÆ×÷µç½âÖÊÈÜÒº£¬Ñô¼«Ñ¡ÓÃ________×÷µç¼«¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÏÖÓÐÒÒËáºÍÁ½ÖÖÁ´×´µ¥Ï©Ìþ(·Ö×ÓÖк¬Ò»¸ö̼̼˫¼ü)µÄ»ìºÏÎÈôÆäÖÐÑõµÄÖÊÁ¿·ÖÊýΪa£¬Ôò̼µÄÖÊÁ¿·ÖÊýÊÇ(¡¡¡¡)

A.                                  B.a

C.(1£­a)                            D.(1£­a)

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸