£¨1£©ÏÂÃæÊÇʯÀ¯ÓÍÔÚ³ãÈÈËé´ÉƬµÄ×÷ÓÃϲúÉúÒÒÏ©²¢¼ìÑéÆäÐÔÖʵÄʵÑ飬Íê³ÉÏÂÁÐÎÊÌâ¡£

¢ÙAÖÐËé´ÉƬµÄ×÷ÓÃÊÇ                        ¡£

¢ÚBÖз´Ó¦ÀàÐÍÊÇ                      ¡£CÖÐʵÑéÏÖÏóÊÇ                        ¡£

£¨2£©ÖÆÈ¡ÂÈÒÒÍ飨CH3CH2Cl£©µÄ×î¼Ñ·½·¨ÊÇ£¨Óû¯Ñ§·½³Ìʽ±íʾ£©£º

                                              £»

£¨3£©ÓÿÕÆø´µäåË®µ½SO2  ÈÜÒºÖеĻ¯Ñ§·½³Ìʽ£º

                                                   £»

£¨4£©°Ñ¸Éº£´ø·ÅÔÚ    £¨ÒÇÆ÷µÄÃû³Æ£©ÖÐ×ÆÉÕ¡£×ÆÉÕºóµÄº£´øÈÜÓÚË®ÖУ¬¹ýÂ˺óµÄÂËÒºÖÐËữºó¼Ó¹ýÑõ»¯ÇâµÄÀë×Ó·½³Ìʽ        

£¨5£©ÔÚÊÔ¹ÜAÖмÓÈë3 mL ÒÒ´¼£¬È»ºó±ßÕñµ´ÊԹܱßÂýÂý¼ÓÈë2 mL ŨÁòËáºÍ2 mL ÒÒËᣬ°´ÏÂͼËùʾÁ¬½ÓºÃ×°ÖÃÖÆÈ¡ÒÒËáÒÒõ¥¡£

¢ÙÊÔ¹ÜBÖÐÊ¢·Å±¥ºÍNa2CO3ÈÜÒºµÄ×÷ÓÃÊÇ£ºÖкÍÒÒËá¡¢ÈܽâÒÒ´¼ºÍ                                  ¡£

¢ÚʵÑéÍê³Éºó£¬ÈôÒª·ÖÀëBÖеÄÒºÌå»ìºÏÎÐèÒªÓõ½µÄ²£Á§ÒÇÆ÷Ö÷ÒªÊÇ                    ¡£

£¨1£©¢Ù´ß»¯×÷Ó㻢ÚÑõ»¯·´Ó¦£»äåµÄËÄÂÈ»¯Ì¼ÍÊÉ«£»

£¨2£©CH2===CH2 £« HClCH3CH2Cl£¨3£©Br2+SO2+2H2O=H2SO4+2HBr

(4) ÛáÛö£»H2O2+2I-+2H+=I2+2H2O2

£¨5£© ¢Ù½µµÍÒÒËáÒÒõ¥µÄÈܽâ¶È     ¢Ú·ÖҺ©¶·

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º¸ßÒ»»¯Ñ§¡¡µÚÈýÕ¡¡Óлú»¯ºÏÎï¡¡3.2.1ÒÒÏ©(È˽̰æ±ØÐÞ2) ÌâÐÍ£º058

ÏÂÃæÊÇʯÀ¯ÓÍÔÚ³ãÈÈËé´ÉƬµÄ×÷ÓÃϲúÉúC2H4²¢¼ìÑéC2H4ÐÔÖʵÄʵÑ飬Íê³ÉÏÂÁи÷ÎÊÌ⣮

(1)BÖÐÈÜÒºÍÊÉ«£¬ÊÇÒòΪÒÒÏ©±»________£®

(2)CÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ________£®

(3)ÔÚD´¦µãȼʱ±ØÐë½øÐеIJÙ×÷ÊÇ________________£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄê¸ÊËàÊ¡À¼ÖÝÒ»ÖиßÒ»ÏÂѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨´ø½âÎö£© ÌâÐÍ£ºÊµÑéÌâ

£¨12·Ö£©
£¨1£©ÏÂÃæÊÇʯÀ¯ÓÍÔÚ³ãÈÈËé´ÉƬµÄ×÷ÓÃϲúÉúÒÒÏ©²¢¼ìÑéÆäÐÔÖʵÄʵÑ飬Íê³ÉÏÂÁÐÎÊÌâ¡£

¢ÙAÖÐËé´ÉƬµÄ×÷ÓÃÊÇ                       ¡£
¢ÚBÖз´Ó¦ÀàÐÍÊÇ                     ¡£CÖÐʵÑéÏÖÏóÊÇ                       ¡££¨2£©ÖÆÈ¡ÂÈÒÒÍ飨CH3CH2Cl£©µÄ×î¼Ñ·½·¨ÊÇ£¨Óû¯Ñ§·½³Ìʽ±íʾ£©£º                  £»£¨3£©ÓÿÕÆø´µäåË®µ½SO2ÈÜÒºÖеĻ¯Ñ§·½³Ìʽ£º                                    £»£¨4£©°Ñ¸Éº£´ø·ÅÔÚ   £¨ÒÇÆ÷µÄÃû³Æ£©ÖÐ×ÆÉÕ¡£×ÆÉÕºóµÄº£´øÈÜÓÚË®ÖУ¬¹ýÂ˺óµÄÂËÒºÖÐËữºó¼Ó¹ýÑõ»¯ÇâµÄÀë×Ó·½³Ìʽ        
£¨5£©ÔÚÊÔ¹ÜAÖмÓÈë3 mL ÒÒ´¼£¬È»ºó±ßÕñµ´ÊԹܱßÂýÂý¼ÓÈë2 mL ŨÁòËáºÍ2 mL ÒÒËᣬ°´ÏÂͼËùʾÁ¬½ÓºÃ×°ÖÃÖÆÈ¡ÒÒËáÒÒõ¥¡£
¢ÙÊÔ¹ÜBÖÐÊ¢·Å±¥ºÍNa2CO3ÈÜÒºµÄ×÷ÓÃÊÇ£ºÖкÍÒÒËá¡¢ÈܽâÒÒ´¼ºÍ                      ¡£
¢ÚʵÑéÍê³Éºó£¬ÈôÒª·ÖÀëBÖеÄÒºÌå»ìºÏÎÐèÒªÓõ½µÄ²£Á§ÒÇÆ÷Ö÷ÒªÊÇ              ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2015½ì¼ªÁÖÊ¡ËÉÔ­ÊиßÒ»ÏÂÆÚÖп¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÊµÑéÌâ

£¨1£©ÏÂÃæÊÇʯÀ¯ÓÍÔÚ³ãÈÈËé´ÉƬµÄ×÷ÓÃϲúÉúÒÒÏ©²¢¼ìÑéÆäÐÔÖʵÄʵÑ飬Íê³ÉÏÂÁÐÎÊÌâ¡£

¢ÙAÖÐËé´ÉƬµÄ×÷ÓÃÊÇ              ¡£

¢ÚBÖз´Ó¦ÀàÐÍÊÇ              ¡£CÖÐʵÑéÏÖÏóÊÇ                          ¡£

¢ÛÔÚD´¦µãȼǰ±ØÐë½øÐеIJÙ×÷ÊÇ                           ¡£

£¨2£©ÖÆÈ¡ÂÈÒÒÍ飨CH3CH2Cl£©µÄ×î¼Ñ·½·¨ÊÇ£¨Óû¯Ñ§·½³Ìʽ±íʾ£©£º                ¡£

£¨3£©À´×ÔʯÓ͵ÄÁíÒ»²úÆ·ÊDZ½£¬Çëд³öÓɱ½ÖÆÏõ»ù±½µÄ»¯Ñ§·½³Ìʽ£º               ¡£

£¨4£©¸ÃʵÑéÖÐD´¦ÒÒϩȼÉյĻ¯Ñ§·½³Ìʽ£º                                     ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2014½ì¸ÊËàÊ¡¸ßÒ»ÏÂѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÊµÑéÌâ

£¨12·Ö£©

£¨1£©ÏÂÃæÊÇʯÀ¯ÓÍÔÚ³ãÈÈËé´ÉƬµÄ×÷ÓÃϲúÉúÒÒÏ©²¢¼ìÑéÆäÐÔÖʵÄʵÑ飬Íê³ÉÏÂÁÐÎÊÌâ¡£

¢ÙAÖÐËé´ÉƬµÄ×÷ÓÃÊÇ                        ¡£

¢ÚBÖз´Ó¦ÀàÐÍÊÇ                      ¡£CÖÐʵÑéÏÖÏóÊÇ                        ¡££¨2£©ÖÆÈ¡ÂÈÒÒÍ飨CH3CH2Cl£©µÄ×î¼Ñ·½·¨ÊÇ£¨Óû¯Ñ§·½³Ìʽ±íʾ£©£º                   £»£¨3£©ÓÿÕÆø´µäåË®µ½SO2ÈÜÒºÖеĻ¯Ñ§·½³Ìʽ£º                                     £»£¨4£©°Ñ¸Éº£´ø·ÅÔÚ    £¨ÒÇÆ÷µÄÃû³Æ£©ÖÐ×ÆÉÕ¡£×ÆÉÕºóµÄº£´øÈÜÓÚË®ÖУ¬¹ýÂ˺óµÄÂËÒºÖÐËữºó¼Ó¹ýÑõ»¯ÇâµÄÀë×Ó·½³Ìʽ        

£¨5£©ÔÚÊÔ¹ÜAÖмÓÈë3 mL ÒÒ´¼£¬È»ºó±ßÕñµ´ÊԹܱßÂýÂý¼ÓÈë2 mL ŨÁòËáºÍ2 mL ÒÒËᣬ°´ÏÂͼËùʾÁ¬½ÓºÃ×°ÖÃÖÆÈ¡ÒÒËáÒÒõ¥¡£

¢ÙÊÔ¹ÜBÖÐÊ¢·Å±¥ºÍNa2CO3ÈÜÒºµÄ×÷ÓÃÊÇ£ºÖкÍÒÒËá¡¢ÈܽâÒÒ´¼ºÍ                       ¡£

¢ÚʵÑéÍê³Éºó£¬ÈôÒª·ÖÀëBÖеÄÒºÌå»ìºÏÎÐèÒªÓõ½µÄ²£Á§ÒÇÆ÷Ö÷ÒªÊÇ               ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸