½«4 mol AºÍ2 mol B·ÅÈë2 LÃܱÕÈÝÆ÷Öз¢Éú·´Ó¦£º2A(g)£«B(g) 2C(g)¡¡¦¤H<0¡£4 sºó·´Ó¦´ïµ½Æ½ºâ״̬£¬´Ëʱ²âµÃCµÄŨ¶ÈΪ0.6 mol·L£­1¡£ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ           (¡¡¡¡)¡£

A£®4 sÄÚ£¬v(B)£½0.075 mol·L£­1·s£­1

B£®4 sºóƽºâ״̬Ï£¬c(A)¡Ãc(C)£½2¡Ã1

C£®´ïµ½Æ½ºâ״̬ºó£¬ÈôÖ»Éý¸ßζȣ¬ÔòCµÄÎïÖʵÄÁ¿Å¨¶ÈÔö´ó

D£®´ïµ½Æ½ºâ״̬ºó£¬ÈôζȲ»±ä£¬ËõСÈÝÆ÷µÄÌå»ý£¬ÔòAµÄת»¯ÂʽµµÍ

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÏÂÁи÷±íÊöÓëʾÒâͼͼÖÐÒ»ÖµÄÊÇ  

A£®Í¼¢Ù±íʾÏòº¬Mg2£«¡¢Al3£«¡¢NH4£«µÄÑÎÈÜÒºÖеμÓNaOHÈÜҺʱ£¬³ÁµíµÄÁ¿ÓëNaOHµÄÌå»ýµÄ¹Øϵͼ¡£ÔòÈýÖÖÀë×ÓµÄÎïÖʵÄÁ¿Ö®±ÈΪ£ºn(Mg2£«)¡Ãn(Al3£«):n( NH4£«)£½2¡Ã3¡Ã2

B£®Í¼¢ÙÖÐʹÓõÄNaOHµÄŨ¶ÈΪ10 mol/L 

C£®Í¼¢Ú±íʾ25¡æʱ£¬ÓÃ0.1 mol¡¤L£­1ÑÎËáµÎ¶¨20 mL 0.1 mol¡¤L£­1 NaOHÈÜÒº£¬ÈÜÒºµÄpHËæ¼ÓÈëËáÌå»ýµÄ±ä»¯ 

D£®Í¼¢ÛÖÐÇúÏß±íʾ3N2(g)+N2(g)2NH3(g)·´Ó¦¹ý³ÌµÄÄÜÁ¿±ä»¯£¬ÈôʹÓô߻¯¼Á£¬Bµã»áÉý¸ß

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


¹ûÖ­ÔÚÉú²ú¹ý³ÌÖÐÌí¼ÓÑÇÁòËá¼°ÆäÑÎÀ࣬ÒÔÒÖÖÆÓк¦Î¢ÉúÎïµÄÉú³¤¼°¿¹Ñõ»¯¡£Ä³»¯Ñ§ÐËȤС×é²éÔÄÎÄÏ׺ó£¬ÓÃÏÂͼËùʾװÖòⶨij¹ûÖ­ÑùÆ·ÖÐSO2²ÐÁôÁ¿¡£

ʵÑé²½Ö裺

£¨¢¡£©ÔÚÉÕÆ¿ÖмÓÈë50.00 mL¹ûÖ­ÑùÆ·Óë3mLŨÁòËáµÄ»ìºÏÒº£¬¼ÓÈÈ10 min¡£

£¨¢¢£©ÒƳö׶ÐÎÆ¿£¬Ñ¸ËÙµÎÈë2~3µÎ·Ó̪ÊÔÒº£¬ÓÃ0.01000 mol¡¤L£­1NaOH±ê×¼ÈÜÒºµÎ¶¨¡£

»Ø´ðÎÊÌ⣺

£¨1£©ÊµÑéÊÒÅäÖÆNaOH±ê×¼ÈÜҺʱ£¬²»ÐèÒªÓõ½µÄÒÇÆ÷ÊÇ         ¡£

A£®ÈÝÁ¿Æ¿         B£®½ºÍ·µÎ¹Ü        C£®ÉÕÆ¿        D£®²£Á§°ô

£¨2£©½«50. 00 mL¹ûÖ­ÑùÆ·Óë3mLŨÁòËá»ìºÏµÄ²Ù×÷ÊÇ                ¡£

£¨3£©×¶ÐÎÆ¿Öз¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ                   ¡£

£¨4£©Èô²½Ö裨¢¢£©ÏûºÄNaOH±ê×¼ÈÜÒº25. 00 mL£¬Ôò¹ûÖ­ÑùÆ·ÖÐSO2²ÐÁôÁ¿ÊÇ     g/L¡£

£¨5£©Èô¸ÄÓÃ0.5%µÄµâË®10 mL×÷ÎüÊÕÒº£¬ÊµÑéÖÐÏûºÄNaOH±ê×¼ÈÜÒºÌå»ý          ¡£

A£®V = 25 mL              B£®25 mL£¼V£¼50 mL          C£®V£¾50 mL       

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÔÚÈÝ»ýΪ1.00 LµÄÈÝÆ÷ÖУ¬Í¨ÈëÒ»¶¨Á¿µÄN2O4£¬·¢Éú·´Ó¦N2O4(g) 2NO2(g)£¬ËæζÈÉý¸ß£¬»ìºÏÆøÌåµÄÑÕÉ«±äÉî¡£

»Ø´ðÏÂÁÐÎÊÌ⣺

(1)·´Ó¦µÄ¦¤H________0(Ìî¡°´óÓÚ¡±»ò¡°Ð¡ÓÚ¡±)£»100 ¡æʱ£¬ÌåϵÖи÷ÎïÖÊŨ¶ÈËæʱ¼ä±ä»¯ÈçͼËùʾ¡£ÔÚ0¡«60 sʱ¶Î£¬·´Ó¦ËÙÂÊv(N2O4)Ϊ________mol·L£­1·s£­1£»·´Ó¦µÄƽºâ³£ÊýK1Ϊ________¡£

    (2)100 ¡æʱ´ïƽºâºó£¬¸Ä±ä·´Ó¦Î¶ÈΪT£¬c(N2O4)ÒÔ0.002 0 mol·L£­1·s£­1µÄƽ¾ùËÙÂʽµµÍ£¬¾­10 sÓִﵽƽºâ¡£

 ¢ÙT________100 ¡æ(Ìî¡°´óÓÚ¡±»ò¡°Ð¡ÓÚ¡±)£¬ÅжÏÀíÓÉÊÇ____________________________¡£

 ¢ÚÁÐʽ¼ÆËãζÈTʱ·´Ó¦µÄƽºâ³£ÊýK2£º_______________________________________

________________________________________________________________________¡£

(3)ζÈTʱ·´Ó¦´ïƽºâºó£¬½«·´Ó¦ÈÝÆ÷µÄÈÝ»ý¼õÉÙÒ»°ë£¬Æ½ºâÏò________(Ìî¡°Õý·´Ó¦¡±»ò¡°Äæ·´Ó¦¡±)·½ÏòÒƶ¯£¬ÅжÏÀíÓÉÊÇ__________________________________________________

________________________________________________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÒÑ֪ij»¯Ñ§·´Ó¦µÄƽºâ³£Êý±í´ïʽΪK£½£¬ÔÚ²»Í¬µÄζÈϸ÷´Ó¦µÄƽºâ³£ÊýÈçÏÂ±í£º

 

t ¡æ

700

800

830

1 000

1 200

K

1.67

1.11

1.00

0.60

0.38

ÏÂÁÐÓйØÐðÊö²»ÕýÈ·µÄÊÇ                                    (¡¡¡¡)¡£

A£®¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇCO(g)£«H2O(g) CO2(g)£«H2(g)

B£®ÉÏÊö·´Ó¦µÄÕý·´Ó¦ÊÇ·ÅÈÈ·´Ó¦

C£®ÈôÔÚ1 LµÄÃܱÕÈÝÆ÷ÖÐͨÈëCO2ºÍH2¸÷1 mol,5 minºóζÈÉý¸ßµ½830 ¡æ£¬´Ëʱ²âµÃCO2Ϊ0.4 mol£¬¸Ã·´Ó¦´ïµ½Æ½ºâ״̬

D£®ÈôƽºâŨ¶È·ûºÏ¹Øϵʽ£½£¬Ôò´ËʱµÄζÈΪ1 000 ¡æ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


Ïò¼×ÒÒÁ½¸öÈÝ»ý¾ùΪ1 LµÄºãÈÝÈÝÆ÷ÖУ¬·Ö±ð³äÈë2 mol A¡¢2 mol BºÍ1 mol A¡¢1 mol B¡£ÏàͬÌõ¼þÏÂ(ζÈT ¡æ)£¬·¢ÉúÏÂÁз´Ó¦£ºA(g)£«B(g)xC(g)¡¡¦¤H<0¡£²âµÃÁ½ÈÝÆ÷ÖÐc(A)Ëæʱ¼ätµÄ±ä»¯ÈçͼËùʾ£º

»Ø´ðÏÂÁÐÎÊÌ⣺

(1)ÒÒÈÝÆ÷ÖУ¬Æ½ºâºóÎïÖÊBµÄת»¯ÂÊΪ________¡£

(2)x£½________¡£

(3)T ¡æʱ¸Ã·´Ó¦µÄƽºâ³£ÊýΪ________¡£

(4)ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ(¡¡¡¡)¡£

A£®ÏòƽºâºóµÄÒÒÈÝÆ÷ÖгäÈ뺤Æø¿Éʹc(A)Ôö´ó

B£®½«ÒÒÈÝÆ÷µ¥¶ÀÉýοÉʹÒÒÈÝÆ÷ÄÚ¸÷ÎïÖʵÄÌå»ý·ÖÊýÓë¼×ÈÝÆ÷ÄÚÏàͬ

C£®ÈôÏò¼×ÈÝÆ÷ÖÐÔÙ³äÈë2 mol A¡¢2 mol B£¬Ôòƽºâʱ¼×ÈÝÆ÷ÖÐ0.78 mol·L£­1<c(A)<1.56 mol·L£­1

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


SO2¡¢NOÊÇ´óÆøÎÛȾÎï¡£ÎüÊÕSO2 ºÍNO£¬»ñµÃNa2S2O4ºÍNH4NO3²úÆ·µÄÁ÷³ÌͼÈçÏ£¨CeΪîæÔªËØ£©£º

£¨1£©×°ÖâñÖÐÉú³ÉHSO3£­µÄÀë×Ó·½³ÌΪ                  ¡£

£¨2£©º¬Áò¸÷΢Á££¨H2SO3¡¢HSO3£­ºÍSO32£­£©´æÔÚÓÚSO2ÓëNaOHÈÜÒº·´Ó¦ºóµÄÈÜÒºÖУ¬ËüÃǵÄÎïÖʵÄÁ¿·ÖÊýX(i)ÓëÈÜÒºpH µÄ¹ØϵÈçÓÒͼËùʾ¡£

¢ÙÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ         £¨Ìî×ÖĸÐòºÅ£©¡£

a£®pH=8ʱ£¬ÈÜÒºÖÐc(HSO3£­) < c(SO32£­)

b£®pH=7ʱ£¬ÈÜÒºÖÐc(Na+) =c(HSO3£­)+c(SO32£­)

c£®Îª»ñµÃ¾¡¿ÉÄÜ´¿µÄNaHSO3£¬¿É½«ÈÜÒºµÄpH¿ØÖÆÔÚ4¡«5×óÓÒ

¢ÚÏòpH=5µÄNaHSO3ÈÜÒºÖеμÓÒ»¶¨Å¨¶ÈµÄCaCl2ÈÜÒº£¬ÈÜÒºÖгöÏÖ»ë×Ç£¬pH½µÎª2£¬Óû¯Ñ§Æ½ºâÒƶ¯Ô­Àí½âÊÍÈÜÒºpH½µµÍµÄÔ­Òò£º                                       ¡£

£¨3£©×°ÖâòÖУ¬ËáÐÔÌõ¼þÏ£¬NO±»Ce4+Ñõ»¯µÄ²úÎïÖ÷ÒªÊÇNO3£­¡¢NO2£­£¬Ð´³öÉú³ÉNO3£­µÄÀë×Ó·½³Ìʽ                  ¡£

£¨4£©×°ÖâóµÄ×÷ÓÃÖ®Ò»ÊÇÔÙÉúCe4+£¬ÆäÔ­ÀíÈçÏÂͼËùʾ¡£

 ¢ÙÉú³ÉCe4+µÄµç¼«·´Ó¦Ê½Îª                               ¡£

 ¢ÚÉú³ÉCe4+´Óµç½â²ÛµÄ         £¨Ìî×ÖĸÐòºÅ£©¿ÚÁ÷³ö¡£

£¨5£©ÒÑÖª½øÈë×°ÖâôµÄÈÜÒºÖУ¬NO2£­µÄŨ¶ÈΪa g·L-1£¬ÒªÊ¹1 m3¸ÃÈÜÒºÖеÄNO2£­Íêȫת»¯ÎªNH4NO3£¬ÐèÖÁÉÙÏò×°ÖâôÖÐͨÈë±ê×¼×´¿öϵÄO2          L¡££¨Óú¬a´úÊýʽ±íʾ£¬¼ÆËã½á¹û±£ÁôÕûÊý£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


Äø¾ßÓÐÓÅÁ¼µÄÎïÀíºÍ»¯Ñ§ÌØÐÔ£¬ÊÇÐí¶àÁìÓòÓÈÆäÊǸ߼¼Êõ²úÒµµÄÖØÒªÔ­ÁÏ¡£ôÊ»ù·¨Ìá´¿´ÖÄøÉæ¼°µÄÁ½²½·´Ó¦ÒÀ´ÎΪ£º

¢ÙNi(s)£«4CO(g)Ni(CO)4(g)£«Q

¢ÚNi(CO)4(g)Ni(s)£«4CO(g)

Íê³ÉÏÂÁÐÌî¿Õ£º

(1)ÔÚζȲ»±äµÄÇé¿öÏ£¬ÒªÌá¸ß·´Ó¦¢ÙÖÐNi(CO)4µÄ²úÂÊ£¬¿É²ÉÈ¡µÄ´ëÊ©ÓÐ____________¡¢____________ ¡£

(2)Èô·´Ó¦¢Ú´ïµ½Æ½ºâºó£¬±£³ÖÆäËûÌõ¼þ²»±ä£¬½µµÍζȣ¬ÖØдﵽƽºâʱ_______________  ¡£

a£®Æ½ºâ³£ÊýKÔö´ó¡¡¡¡¡¡¡¡    b£®COµÄŨ¶È¼õС

c£®NiµÄÖÊÁ¿¼õС             d£®vÄæ[Ni(CO)4]Ôö´ó

(3)¼òÊöôÊ»ù·¨Ìá´¿´ÖÄøµÄ²Ù×÷¹ý³Ì¡£

______________________________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ʵÑéÊÒÐèÓÃ240mL 1mol/LµÄÇâÑõ»¯ÄÆÈÜÒº¡£Ìî¿Õ²¢Çë»Ø´ðÏÂÁÐÎÊÌ⣺

 (1) ÅäÖÆËùÐèÌå»ýµÄ 1mol/LµÄÇâÑõ»¯ÄÆÈÜÒº

Ó¦³ÆÈ¡ÇâÑõ»¯ÄƹÌÌåµÄÖÊÁ¿/g

ӦѡÓÃÈÝÁ¿Æ¿µÄ¹æ¸ñ/mL

³ýÉÕ±­¡¢ÍÐÅÌÌìƽ¡¢ÈÝÁ¿Æ¿¡¢Á¿Í²Í⻹ÐèµÄÆäËüÒÇÆ÷

(2)ÅäÖÆʱ£¬ÆäÕýÈ·µÄ²Ù×÷˳ÐòÊÇ(×Öĸ±íʾ£¬Ã¿¸ö×ÖĸֻÄÜÓÃÒ»´Î)                     £»

A£®ÓÃ30mLˮϴµÓÉÕ±­2¡ª3´Î£¬Ï´µÓÒº¾ù×¢ÈëÈÝÁ¿Æ¿£¬Õñµ´

B£®ÓÃÍÐÅÌÌìƽ׼ȷ³ÆÈ¡ËùÐèµÄÇâÑõ»¯ÄƹÌÌ壬µ¹ÈëÉÕ±­ÖУ¬ÔÙ¼ÓÈëÉÙÁ¿Ë®£¨Ô¼30mL£©£¬Óò£Á§°ôÂýÂý½Á¶¯£¬Ê¹Æä³ä·ÖÈܽâ

C£®½«ÒÑÀäÈ´µÄÈÜÒºÑز£Á§°ô×¢ÈëÒ»¶¨¹æ¸ñµÄÈÝÁ¿Æ¿ÖÐ

D£®½«ÈÝÁ¿Æ¿¸Ç½ô£¬Õñµ´£¬Ò¡ÔÈ

E£®¸ÄÓýºÍ·µÎ¹Ü¼ÓË®£¬Ê¹ÈÜÒº°¼ÃæÇ¡ºÃÓë¿Ì¶ÈÏàÇÐ

F£®¼ÌÐøÍùÈÝÁ¿Æ¿ÄÚСÐļÓË®£¬Ö±µ½ÒºÃæ½Ó½ü¿Ì¶È1¡ª2cm´¦

(3)²Ù×÷AÖУ¬½«Ï´µÓÒº¶¼ÒÆÈëÈÝÁ¿Æ¿£¬ÆäÄ¿µÄÊÇ                               £¬ÈÜҺעÈëÈÝÁ¿Æ¿Ç°Ðè»Ö¸´µ½ÊÒΣ¬ÕâÊÇÒòΪ                                      

                                                                  £»

(4)Èô³öÏÖÈçÏÂÇé¿ö£¬¶ÔËùÅäÈÜҺŨ¶È½«ÓкÎÓ°Ï죨Ìî¡°Æ«¸ß¡±¡¢¡°Æ«µÍ¡±»ò¡°ÎÞÓ°Ï족£©?

ÈôûÓнøÐÐA²Ù×÷             £»Èô¼ÓÕôÁóˮʱ²»É÷³¬¹ýÁ˿̶Ƞ             £»Èô¶¨ÈÝʱ¸©Êӿ̶ÈÏß___________________¡£

(5)ÈôʵÑé¹ý³ÌÖгöÏÖÈçÏÂÇé¿öÈçºÎ´¦Àí£¿

¼ÓÕôÁóˮʱ²»É÷³¬¹ýÁ˿̶Ƞ                                   £»

ÏòÈÝÁ¿Æ¿ÖÐתÒÆÈÜҺʱ(ʵÑé²½Öè¢Ú)²»É÷ÓÐÒºµÎµôÔÚÈÝÁ¿Æ¿ÍâÃæ                   

                                                              ¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸