Ϊ²â¶¨´ÖÑõ»¯Í­£¨ÆäÖк¬ÉÙÁ¿Ñõ»¯ÑÇÌú¼°²»ÈÜÓÚËáµÄÔÓÖÊ£©ÖÐCuOµÄÖÊÁ¿·ÖÊý£¬²¢ÖÆÈ¡ÎÞË®ÁòËáÍ­£¬Ä³»¯Ñ§»î¶¯Ð¡×é½øÐÐÁËÏÂÁÐʵÑ飺

ÒÑÖªFe3+¡¢Cu2+¡¢Fe2+ÈýÖÖÀë×ÓÔÚÈÜÒºÖÐÐγÉÇâÑõ»¯Îï³ÁµíµÄpH·¶Î§ÈçÏ£º

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©ÔÚÕû¸öʵÑé¹ý³ÌÖУ¬ÏÂÁÐʵÑé×°Öò»¿ÉÄÜÓõ½µÄÊÇ        £¨Ìî×Öĸ£©£¬×°ÖÃdÖÐÒÇÆ÷AºÍBµÄÃû³Æ·Ö±ðΪ                                   ¡£

£¨2£©ÈÜÒºAÖÐËùº¬ÈÜÖʵĻ¯Ñ§Ê½Îª                                      ¡£

£¨3£©²½Öè¢Ú·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ                                       ¡£

£¨4£©³ÁµíIIµÄ»¯Ñ§Ê½Îª                  ¡£

£¨5£©´ÖÑõ»¯Í­ÑùÆ·ÖÐCuOµÄÖÊÁ¿·ÖÊýΪ                         ¡££¨Áгö¼ÆËãʽ£©

£¨1£©d £»ÕôÁóÉÕÆ¿£»ÀäÄý¹Ü     (6·Ö)

£¨2£©FeSO4 £»CuSO4 £»H2SO4       (3·Ö)

(3)2Fe2++H2O2+2H+=2Fe3++2H2O      (2·Ö)

(4)Fe(OH)3      (2·Ö)     £¨5£©ÂÔ (3·Ö)

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

Ϊ²â¶¨´ÖÑõ»¯Í­£¨ÆäÖк¬ÉÙÁ¿Ñõ»¯ÑÇÌú¼°²»ÈÜÓÚËáµÄÔÓÖÊ£©ÖÐCuOµÄÖÊÁ¿·ÖÊý£¬²¢ÖÆÈ¡ÎÞË®ÁòËáÍ­£¬Ä³»¯Ñ§»î¶¯Ð¡×é½øÐÐÁËÏÂÁÐʵÑ飺

ÒÑÖªFe3+¡¢Cu2+¡¢Fe2+ÈýÖÖÀë×ÓÔÚÈÜÒºÖÐÐγÉÇâÑõ»¯Îï³ÁµíµÄpH·¶Î§ÈçÏ£º

Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÔÚÕû¸öʵÑé¹ý³ÌÖУ¬ÏÂÁÐʵÑé×°Öò»¿ÉÄÜÓõ½µÄÊÇ
d
d
£¨Ìî×Öĸ£©£¬×°ÖÃdÖÐÒÇÆ÷AºÍBµÄÃû³Æ·Ö±ðΪ
ÕôÁóÉÕÆ¿£¬ÀäÄý¹Ü
ÕôÁóÉÕÆ¿£¬ÀäÄý¹Ü
£®

£¨2£©ÈÜÒºAÖÐËùº¬ÈÜÖʵĻ¯Ñ§Ê½Îª
FeSO4¡¢CuSO4¡¢H2SO4
FeSO4¡¢CuSO4¡¢H2SO4
£®
£¨3£©²½Öè¢Ú·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ
2Fe2++H2O2+2H+=2Fe3++2H2O
2Fe2++H2O2+2H+=2Fe3++2H2O
£®
£¨4£©³ÁµíIIµÄ»¯Ñ§Ê½Îª
Fe£¨OH£©3
Fe£¨OH£©3
£®
£¨5£©´ÖÑõ»¯Í­ÑùÆ·ÖÐCuOµÄÖÊÁ¿·ÖÊýΪ
m1-m2-
72m3
107
m1
¡Á100%
m1-m2-
72m3
107
m1
¡Á100%
£®£¨Áгö¼ÆËãʽ£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

Ϊ²â¶¨´ÖÑõ»¯Í­£¨ÆäÖк¬ÉÙÁ¿Ñõ»¯ÑÇÌú¼°²»ÈÜÓÚËáµÄÔÓÖÊ£©ÖÐCuOµÄÖÊÁ¿·ÖÊý£¬²¢ÖÆÈ¡ÎÞË®ÁòËáÍ­£¬Ä³»¯Ñ§»î¶¯Ð¡×é½øÐÐÁËÏÂÁÐʵÑ飺

ÒÑÖªFe3+¡¢Cu2+¡¢Fe2+ÈýÖÖÀë×ÓÔÚÈÜÒºÖÐÐγÉÇâÑõ»¯Îï³ÁµíµÄpH·¶Î§ÈçÏ£º

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©ÔÚÕû¸öʵÑé¹ý³ÌÖУ¬ÏÂÁÐʵÑé×°Öò»¿ÉÄÜÓõ½µÄÊÇ        £¨Ìî×Öĸ£©£¬×°ÖÃdÖÐÒÇÆ÷AºÍBµÄÃû³Æ·Ö±ðΪ                                   ¡£

£¨2£©ÈÜÒºAÖÐËùº¬ÈÜÖʵĻ¯Ñ§Ê½Îª                                      ¡£

£¨3£©²½Öè¢Ú·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ                                       ¡£

£¨4£©³ÁµíIIµÄ»¯Ñ§Ê½Îª                  ¡£

£¨5£©´ÖÑõ»¯Í­ÑùÆ·ÖÐCuOµÄÖÊÁ¿·ÖÊýΪ                         ¡££¨Áгö¼ÆËãʽ£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

Ϊ²â¶¨´ÖÑõ»¯Í­£¨ÆäÖк¬ÉÙÁ¿Ñõ»¯ÑÇÌú¼°²»ÈÜÓÚËáµÄÔÓÖÊ£©ÖÐCuOµÄÖÊÁ¿·ÖÊý£¬²¢ÖÆÈ¡ÎÞË®ÁòËáÍ­£¬Ä³»¯Ñ§»î¶¯Ð¡×é½øÐÐÁËÏÂÁÐʵÑ飺

ÒÑÖªFe3+¡¢Cu2+¡¢Fe2+ÈýÖÖÀë×ÓÔÚÈÜÒºÖÐÐγÉÇâÑõ»¯Îï³ÁµíµÄpH·¶Î§ÈçÏ£º

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©ÔÚÕû¸öʵÑé¹ý³ÌÖУ¬ÏÂÁÐʵÑé×°Öò»¿ÉÄÜÓõ½µÄÊÇ       £¨Ìî×Öĸ£©£¬×°ÖÃdÖÐÒÇÆ÷AºÍBµÄÃû³Æ·Ö±ðΪ                                  ¡£

£¨2£©ÈÜÒºAÖÐËùº¬ÈÜÖʵĻ¯Ñ§Ê½Îª                                     ¡£

£¨3£©²½Öè¢Ú·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ                                      ¡£

£¨4£©³ÁµíIIµÄ»¯Ñ§Ê½Îª                 ¡£

£¨5£©´ÖÑõ»¯Í­ÑùÆ·ÖÐCuOµÄÖÊÁ¿·ÖÊýΪ                        ¡££¨Áгö¼ÆËãʽ£©

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011½ìºÓ±±Ê¡ÌÆɽһÖиßÈýÏÂѧÆÚµÚÒ»´Îµ÷Ñп¼ÊÔ£¨Àí×Û£©»¯Ñ§²¿·Ö ÌâÐÍ£ºÊµÑéÌâ

Ϊ²â¶¨´ÖÑõ»¯Í­£¨ÆäÖк¬ÉÙÁ¿Ñõ»¯ÑÇÌú¼°²»ÈÜÓÚËáµÄÔÓÖÊ£©ÖÐCuOµÄÖÊÁ¿·ÖÊý£¬²¢ÖÆÈ¡ÎÞË®ÁòËáÍ­£¬Ä³»¯Ñ§»î¶¯Ð¡×é½øÐÐÁËÏÂÁÐʵÑ飺

ÒÑÖªFe3+¡¢Cu2+¡¢Fe2+ÈýÖÖÀë×ÓÔÚÈÜÒºÖÐÐγÉÇâÑõ»¯Îï³ÁµíµÄpH·¶Î§ÈçÏ£º

Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÔÚÕû¸öʵÑé¹ý³ÌÖУ¬ÏÂÁÐʵÑé×°Öò»¿ÉÄÜÓõ½µÄÊÇ       £¨Ìî×Öĸ£©£¬×°ÖÃdÖÐÒÇÆ÷AºÍBµÄÃû³Æ·Ö±ðΪ                                  ¡£

£¨2£©ÈÜÒºAÖÐËùº¬ÈÜÖʵĻ¯Ñ§Ê½Îª                                     ¡£
£¨3£©²½Öè¢Ú·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ                                      ¡£
£¨4£©³ÁµíIIµÄ»¯Ñ§Ê½Îª                 ¡£
£¨5£©´ÖÑõ»¯Í­ÑùÆ·ÖÐCuOµÄÖÊÁ¿·ÖÊýΪ                        ¡££¨Áгö¼ÆËãʽ£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010-2011ѧÄêºÓ±±Ê¡¸ßÈýÏÂѧÆÚµÚÒ»´Îµ÷Ñп¼ÊÔ£¨Àí×Û£©»¯Ñ§²¿·Ö ÌâÐÍ£ºÊµÑéÌâ

Ϊ²â¶¨´ÖÑõ»¯Í­£¨ÆäÖк¬ÉÙÁ¿Ñõ»¯ÑÇÌú¼°²»ÈÜÓÚËáµÄÔÓÖÊ£©ÖÐCuOµÄÖÊÁ¿·ÖÊý£¬²¢ÖÆÈ¡ÎÞË®ÁòËáÍ­£¬Ä³»¯Ñ§»î¶¯Ð¡×é½øÐÐÁËÏÂÁÐʵÑ飺

ÒÑÖªFe3+¡¢Cu2+¡¢Fe2+ÈýÖÖÀë×ÓÔÚÈÜÒºÖÐÐγÉÇâÑõ»¯Îï³ÁµíµÄpH·¶Î§ÈçÏ£º

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©ÔÚÕû¸öʵÑé¹ý³ÌÖУ¬ÏÂÁÐʵÑé×°Öò»¿ÉÄÜÓõ½µÄÊÇ        £¨Ìî×Öĸ£©£¬×°ÖÃdÖÐÒÇÆ÷AºÍBµÄÃû³Æ·Ö±ðΪ                                   ¡£

£¨2£©ÈÜÒºAÖÐËùº¬ÈÜÖʵĻ¯Ñ§Ê½Îª                                      ¡£

£¨3£©²½Öè¢Ú·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ                                       ¡£

£¨4£©³ÁµíIIµÄ»¯Ñ§Ê½Îª                  ¡£

£¨5£©´ÖÑõ»¯Í­ÑùÆ·ÖÐCuOµÄÖÊÁ¿·ÖÊýΪ                         ¡££¨Áгö¼ÆËãʽ£©

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸