ÉñÖÛÊ®ºÅ·É´¬ÊÇÖйú¡°ÉñÖÛ¡±ºÅϵÁзɴ¬Ö®Ò»£¬ËüÊÇÖйúµÚÎåËÒ´îÔØÌ«¿ÕÈ˵ķɴ¬¡£ÉñÖÛÊ®ºÅ·É´¬·¢Éä³É¹¦ºó£¬½«Óë2011Äê·¢ÉäÉý¿ÕµÄÌ칬һºÅÄ¿±ê·ÉÐÐÆ÷½øÐн»»á¶Ô½Ó£¬¿ªÕ¹Ïà¹Ø¿Õ¼ä¿ÆѧÊÔÑé¡£»ð¼ýÍƽøÆ÷Êdzɹ¦·¢ÉäµÄÖØÒªÒòËØ£¬ÊÂʵÉÏ£¬ÍƽøÆ÷µÄ·¢Õ¹¾­ÀúÁËÒ»¸öÂþ³¤µÄ¹ý³Ì¡£
(1)20ÊÀ¼ÍÇ°£¬ºÚ»ðÒ©ÊÇÊÀ½çÉÏΨһµÄ»ð¼ýÍƽø¼Á£¬ºÚ»ðÒ©ÊÇÓÉÏõËá¼Ø¡¢Áò»Ç¡¢Ä¾Ì¿×é³É£¬ºÚ»ðÒ©±¬Õ¨µÄ»¯Ñ§·½³ÌʽΪ£ºS+3C+2KNO3£½K2S+N2¡ü+3CO2¡ü¡£
¢ÙK2SµÄµç×ÓʽΪ   £¬CO2µÄ½á¹¹Ê½Îª   ¡£
¢ÚÒÑÖªSºÍÂÈË®·´Ó¦»áÉú³ÉÁ½ÖÖÇ¿ËᣬÆäÀë×Ó·½³ÌʽΪ           ¡£
¢ÛÈ¡ºÚ»ðÒ©±¬Õ¨ºóµÄ²ÐÁô¹ÌÌ壬¼ÓË®Èܽâ¹ýÂË£¬µÃµ½ÂËÒº¡£Ð´³ö¼ìÑé´ËÈÜÒºÖÐÊÇ·ñº¬ÓÐK£«µÄʵÑé²Ù×÷·½·¨                   ¡£
(2)20ÊÀ¼Í60Äê´ú£¬»ð¼ýʹÓõÄÊÇÒºÌåÍƽø¼Á£¬³£ÓõÄÑõ»¯¼ÁÓÐËÄÑõ»¯¶þµª¡¢ÒºÑõµÈ£¬¿ÉȼÎïÓÐ÷루N2 H4£©¡¢ÒºÇâµÈ¡£
¢Ù루N2 H4£©ÈÜÓÚË®ÏÔ¼îÐÔ£¬ÆäÔ­ÀíÓë°±ÏàËÆ£¬µ«Æä¼îÐÔ²»È簱ǿ£¬Ð´³öÆäÈÜÓÚË®³Ê¼îÐÔµÄÀë×Ó·½³Ìʽ£º                   ¡£
¢ÚÒ»ÖÖÓëN2 H4µç×ÓÊýÏàµÈµÄÂÌÉ«Ñõ»¯¼Á£¬Äܽ«ÓÍ»­±íÃæºÚÉ«µÄPbSÑõ»¯³É°×É«µÄPbSO4£¬Ê¹ÓÍ»­±ä°×¡¢·­Ð£¬»¯Ñ§·½³ÌʽΪ£º           ¡£
(3)ÒÔÉϵĻð¼ýÍƽø¼ÁÒ»°ãº¬ÓеªÔªËØ£¬º¬µª»¯ºÏÎïÖÖÀà·á¸»¡£ÓÐÒ»º¬µª»¯ºÏÎ¾ßÓкÜÇ¿µÄ±¬Õ¨ÐÔ,86g¸Ã»¯ºÏÎﱬը·Ö½â»áÉú³É±ê¿öÏÂN267. 2LºÍÁíÒ»ÖÖÆøÌåµ¥ÖÊH2¡£Ð´³öÆ䱬ըµÄ»¯Ñ§·½³Ìʽ   ¡£
£¨1£©¢Ù£¨2·Ö£© O£½C£½O£¨2·Ö£©¢ÚS£«3Cl2£«4H2O£½SO42£­£«8H£«6Cl£­£¨2·Ö£©¢ÛÓýྻµÄ²¬Ë¿ÕºÈ¡´ý²âÒº£¬·ÅÔÚ»ðÑæÉÏ×ÆÉÕ£¬Í¸¹ýÀ¶É«µÄîܲ£Á§¹Û²ì»ðÑæÑÕÉ«¡£Èô»ðÑæ³Ê×ÏÉ«£¬ÔòÈÜÒºÖк¬ÓмØÀë×Ó£¬·´Ö®Ã»ÓУ¨2·Ö£©
£¨2£©¢ÙN2H4£«H2ONH2NH3£«£«OH£­£¨2·Ö£©¢ÚPbS£«4H2O2£½PbSO4£«4H2O£¨2·Ö£©
£¨3£©2HN3£½3N2+H2£¨2·Ö£©

ÊÔÌâ·ÖÎö£º£¨1£©¢ÙK2SÊÇÀë×Ó»¯ºÏÎÆäµç×ÓʽΪ£»CO2ÊÇÖ±ÏßÐι²¼Û»¯ºÏÎÆä½á¹¹Ê½ÎªO£½C£½O¡£
¢ÚÒÑÖªSºÍÂÈË®·´Ó¦»áÉú³ÉÁ½ÖÖÇ¿ËᣬÔò¸ù¾ÝÔ­×ÓÊغãÒÔ¼°ÂÈÆø¾ßÓÐÇ¿Ñõ»¯ÐÔ¿ÉÖª£¬Á½ÖÖËáÓ¦¸ÃÊÇÑÎËáºÍÁòËᣬÔòÆäÀë×Ó·½³ÌʽΪS£«3Cl2£«4H2O£½SO42£­£«8H£«6Cl£­¡£
¢Û¼ØÔªËصļìÑéÖ»ÄܽèÖúÓÚÑæÉ«·´Ó¦£¬Ôò¼ìÑé´ËÈÜÒºÖÐÊÇ·ñº¬ÓÐK£«µÄʵÑé²Ù×÷·½·¨ÊÇÓýྻµÄ²¬Ë¿ÕºÈ¡´ý²âÒº£¬·ÅÔÚ»ðÑæÉÏ×ÆÉÕ£¬Í¸¹ýÀ¶É«µÄîܲ£Á§¹Û²ì»ðÑæÑÕÉ«¡£Èô»ðÑæ³Ê×ÏÉ«£¬ÔòÈÜÒºÖк¬ÓмØÀë×Ó£¬·´Ö®Ã»ÓС£
£¨2£©¢Ù루N2 H4£©ÈÜÓÚË®ÏÔ¼îÐÔ£¬ÆäÔ­ÀíÓë°±ÏàËÆ£¬Ôò¸ù¾ÝһˮºÏ°±µÄµçÀë·½³Ìʽ¿ÉÖª£¬ÆäÈÜÓÚË®³Ê¼îÐÔµÄÀë×Ó·½³ÌʽΪN2H4£«H2ONH2NH3£«£«OH£­¡£
¢ÚÓëN2 H4µç×ÓÊýÏàµÈµÄÂÌÉ«Ñõ»¯¼ÁÊÇË«ÑõË®£¬Äܽ«ÓÍ»­±íÃæºÚÉ«µÄPbSÑõ»¯³É°×É«µÄPbSO4£¬Ê¹ÓÍ»­±ä°×¡¢·­Ð£¬»¯Ñ§·½³ÌʽΪPbS£«4H2O2£½PbSO4£«4H2O¡£
(3) 86g¸Ã»¯ºÏÎﱬը·Ö½â»áÉú³É±ê¿öÏÂN267. 2LºÍÁíÒ»ÖÖÆøÌåµ¥ÖÊH2£¬Ôò¸ù¾ÝÔ­×ÓÊغã¿ÉÖª¸Ã»¯ºÏÎïÊÇÓÉNºÍHÁ½ÖÖÔªËع¹³ÉµÄ¡£µªÆøµÄÎïÖʵÄÁ¿ÊÇ67.2L¡Â22.4L/mol£½3mol£¬É軯ѧʽΪHNx£¬Ôò·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ2HNx£½xN2+H2£¬Òò´Ë¡Á£½3£¬½âµÃx£½3£¬ËùÒÔ·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ2HN3£½3N2+H2¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÏÂÁз´Ó¦µÄÀë×Ó·½³ÌʽÊéдÕýÈ·µÄÊÇ
A£®µç½â±¥ºÍʳÑÎË®£º2Cl£­+ 2H2O2OH£­+ H2¡ü+ Cl2¡ü
B£®´×Ëá³ýȥˮ¹¸ÖеÄCaCO3£ºCaCO3+ 2H+£½Ca2+ + H2O + CO2¡ü
C£®Æ¯°×·ÛÈÜÒºÔÚ¿ÕÆøÖÐʧЧ£ºClO£­+ CO2 + H2O£½HClO + HCO
D£®ÏòNaHSO4ÈÜÒºÖеμÓNaHCO3ÈÜÒº£ºHSO+ HCO£½ H2O + SO+ CO2¡ü

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÏÂÁÐÏà¹Ø·´Ó¦µÄÀë×Ó·½³ÌʽÊéдÕýÈ·µÄÊÇ
A£®ÇâÑõ»¯ÌúÈÜÓÚÇâµâË᣺Fe(OH)3£«3H£«=Fe3£«£«3H2O
B£®ÁòËáÍ­ÈÜÒºÏÔËáÐÔ£ºCu2£«£«2H2O=Cu(OH)2¡ý£«2H£«
C£®Ïò̼ËáÇâï§ÈÜÒºÖмӹýÁ¿Ê¯»ÒË®²¢¼ÓÈÈ£º£«OH£­=NH3¡ü£«H2O
D£®ÓÃËữµÄ¸ßÃÌËá¼ØÈÜÒºÑõ»¯Ë«ÑõË®£º2£«6H£«£«5H2O2=2Mn2£«£«5O2¡ü£«8H2O

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÏÂÁл¯Ñ§·´Ó¦µÄÀë×Ó·½³ÌʽÊéдÕýÈ·µÄÊÇ(¡¡¡¡)¡£
A£®Ï¡ÏõËáºÍ¹ýÁ¿Ìúм·´Ó¦£ºFe£«4H£«£«NO3£­=Fe3£«£«NO¡ü£«2H2O
B£®ÏòÁòËáÇâï§ÈÜÒºÖмÓÈëÉÙÁ¿ÇâÑõ»¯ÄÆÈÜÒº£ºNH4£«£«OH£­=NH3¡ü£«H2O
C£®ÂÈ»¯ÂÁÈÜÒºÖмÓÈë¹ýÁ¿°±Ë®£ºAl3£«£«4NH3¡¤H2O=AlO2£­£«4NH4£«£«2H2O
D£®H2C2O4ʹËáÐÔKMnO4ÈÜÒºÍÊÉ«£º5H2C2O4£«6H£«£«2MnO4£­=10CO2¡ü£«2Mn2£«£«8H2O

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

ij¹¤³§ÅųöµÄÎÛË®Öк¬ÓдóÁ¿µÄFe2£«¡¢Zn2£«¡¢Hg2£«ÈýÖÖ½ðÊôÀë×Ó¡£ÒÔÏÂÊÇij»¯Ñ§Ñо¿ÐÔѧϰС×éµÄͬѧÉè¼Æ³ýÈ¥ÎÛË®ÖеĽðÊôÀë×Ó£¬²¢»ØÊÕÂÌ·¯¡¢ð©·¯(ZnSO4¡¤7H2O)ºÍ¹¯µÄ·½°¸¡£
¡¾Ò©Æ·¡¿NaOHÈÜÒº¡¢Áò»¯ÄÆÈÜÒº¡¢Áò»¯ÑÇÌú¡¢Ï¡ÁòËá¡¢Ìú·Û
¡¾ÊµÑé·½°¸¡¿

¡¾ÎÊÌâ̽¾¿¡¿
(1)²½Öè¢òËù·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ                                ¡£
(2)²½Öè¢óÖгéÂ˵ÄÄ¿µÄÊÇ           £¬¸Ã²½Öè²úÉúFe(OH)3µÄ·´Ó¦µÄÀë×Ó·½³ÌʽΪ                                         ¡£
(3)²½Öè¢öÖеõ½ÁòËáпÈÜÒºµÄÀë×Ó·½³ÌʽΪ                                                               ¡£
(4)ÓûʵÏÖ²½Öè¢õ£¬Ðè¼ÓÈëµÄÊÔ¼ÁÓР      ¡¢       £¬ËùÉæ¼°µÄÖ÷Òª²Ù×÷ÒÀ´ÎΪ                                                         ¡£
(5)²½Öè¢ô³£Óõķ½·¨ÊÇ       £¬¸Ã²½ÖèÊÇ·ñ¶Ô»·¾³ÓÐÓ°Ï죿       (Ìî¡°ÊÇ¡±»ò¡°·ñ¡±)£¬ÈçÓÐÓ°Ï죬ÇëÄãÉè¼ÆÒ»¸öÂÌÉ«»·±£·½°¸À´ÊµÏÖ²½Öè¢ôµÄ·´Ó¦£º                                                            ¡£
(6)¸ÃÑо¿Ð¡×éµÄͬѧÔÚÇ¿¼îÈÜÒºÖУ¬ÓôÎÂÈËáÄÆÓëFe(OH)3·´Ó¦»ñµÃÁ˸ßЧ¾»Ë®¼ÁNa2FeO4£¬¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽΪ                             ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÏÂÁз´Ó¦µÄÀë×Ó·½³ÌʽÕýÈ·µÄÊÇ£¨   £©
A£®ÄÆÓëË®·´Ó¦£ºNa£«H2O£½Na£«£«OH£­£«H2¡ü
B£®ÂÈÆøÓëË®·´Ó¦£ºCl2£«H2O£½2H£«£«Cl£­£«ClO£­
C£®Ì¼ËáÇâÄÆÈÜÒºÖмÓÈëÇâÑõ»¯ÄÆ£ºHCO3£­ £«OH¡ª£½ CO2¡ü£«H2O
D£®ÇâÑõ»¯ÂÁÖкÍθË᣺Al(OH)3£«3H£«£½Al3£«£«3H2O

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

Ïòº¬ÓеÈÎïÖʵÄÁ¿µÄNH4+¡¢Al3£«¡¢H£«µÄ»ìºÏÈÜÒºÖУ¬ÂýÂýµÎ¼ÓNaOHÈÜÒºÖ±ÖÁ¹ýÁ¿£¬
²¢²»¶Ï½Á°è£¬ÒÀ´Î·¢ÉúÁËÊý¸öÀë×Ó·´Ó¦£¬ÔòµÚÈý¸öÀë×Ó·´Ó¦ÊÇ£¨  £©
A£®H£«£«OH£­=H2O
B£®Al3£«£«3OH£­=Al(OH)3¡ý
C£®Al(OH)3£«OH£­=AlO2-£«2H2O
D£®NH4+£«OH£­=NH3¡¤H2O

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÏÂÁÐÀë×Ó·½³ÌʽÊéдÕýÈ·µÄÊÇ
A£®Í­¸úÏ¡ÏõËá·´Ó¦£º3Cu+ 8H++2NO3-=3Cu2++2NO¡ü+4H2O
B£®ÊµÑéÊÒÓôóÀíʯºÍÏ¡ÑÎËáÖÆÈ¡CO2£º2H+ + CO32-£½CO2¡ü+ H2O
C£®½ðÊôÌúÓëÏ¡ÁòËá·´Ó¦£º2Fe+6H+=2Fe3+ + 3H2¡ü
D£®ÄÆÓëË®·´Ó¦£º Na£«H2O£½Na£«£«OH£­£«H2¡ü

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

îÑÓÐÇ¿¶È¸ßºÍÖʵØÇáµÄÓŵ㣬¹ã·ºÓ¦ÓÃÓÚ·É»úÖÆÔìÒµµÈ¡£¹¤ÒµÉÏÀûÓÃîÑÌú¿ó£¬ÆäÖ÷Òª³É·ÖΪîÑËáÑÇÌú£¨FeTiO3£©ÖƱ¸îѽðÊô£¬¹¤ÒµÁ÷³ÌÈçÏ£º ÒÑÖª£ºTiÓëTiO2»¯Ñ§ÐÔÖÊÎȶ¨£¬²»ÈÜÓÚÏ¡ÁòËᡢϡÑÎËáµÈ¡£

£¨1£©Çëд³öFeTiO3ÓëÏ¡ÑÎËá·´Ó¦µÄÀë×Ó·½³Ìʽ£º                                          ¡£
£¨2£©Çëд³ö¡°ÈÛÈÚÑõ»¯¡±µÄ»¯Ñ§·½³Ìʽ£º                                                    ¡£
£¨3£©µç½âÂÈ»¯Ã¾µÄÒõ¼«·´Ó¦Ê½Îª£º                                                £¬¿ÉÑ­»·ÀûÓõÄÎïÖÊΪ£º                              £¨Ìѧʽ£©¡£
£¨4£©ÈÈ»¹Ô­·¨ÖÐÄÜ·ñ¸ÄÓÃÄÆ´úÌæþ×÷»¹Ô­¼Á£º    £¨Ìî¡°ÄÜ¡±»ò¡°²»ÄÜ¡±£©£»Ô­ÒòΪ£º                                                                 ¡£
£¨5£©Óô˷½·¨ÖƱ¸µÃµ½µÄTi½ðÊô³£»ìÓÐMgCl2ºÍMg£¬³ýÔÓÊÔ¼ÁÊÇ         £¨Ìѧʽ£©¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸