ÒÑ֪ijÖÖȼÁϺ¬ÓÐ̼¡¢Çâ¡¢ÑõÈýÖÖÔªËØ¡£ÎªÁ˲ⶨÕâÖÖȼÁÏÖÐ̼ºÍÇâÁ½ÖÖÔªËصÄÖÊÁ¿±È£¬¿É½«Æø̬ȼÁÏ·ÅÈë×ãÁ¿µÄÑõÆøÖÐȼÉÕ£¬²¢Ê¹²úÉúµÄÆøÌåÈ«²¿Í¨ÈëÈçÉÏͼËùʾµÄ×°Ö㬵õ½ÈçϱíËùÁеÄʵÑé½á¹û(¼ÙÉè²úÉúµÄÆøÌåÍêÈ«±»ÎüÊÕ)£º

 

ʵÑéÇ°

ʵÑéºó

(¸ÉÔï¼Á+UÐιÜ)µÄÖÊÁ¿

101.1 g

102.9 g

(ʯ»ÒË®+¹ã¿ÚÆ¿)µÄÖÊÁ¿

312.0 g

314.2 g

¸ù¾ÝʵÑéÊý¾ÝÍê³ÉÏÂÁÐÎÊÌ⣺

(1)ʵÑéÍê±Ïºó£¬Éú³ÉÎïÖÐË®µÄÖÊÁ¿Îª_______________g£¬¼ÙÉè¹ã¿ÚÆ¿ÀïÉú³ÉÒ»ÖÖÕýÑΣ¬ÆäÖÊÁ¿Îª_______________ g¡£

(2)Éú³ÉµÄË®ÖÐÇâÔªËصÄÖÊÁ¿Îª_______________ g¡£

(3)Éú³ÉµÄ¶þÑõ»¯Ì¼ÖÐ̼ԪËصÄÖÊÁ¿Îª_______________ g¡£

(4)¸ÃȼÁÏÖÐ̼ԪËØÓëÇâÔªËصÄÖÊÁ¿±ÈΪ_______________¡£

(5)ÒÑÖªÕâÖÖȼÁϵÄÿ¸ö·Ö×ÓÖÐÖ»Äܺ¬ÓÐÒ»¸öÑõÔ­×Ó£¬Ôò¸ÃȼÁϵķÖ×ÓʽΪ______________,½á¹¹¼òʽΪ_______________¡£

(1)1.8  5  (2)0.2  (3)0.6  (4)3¡Ã1  (5)CH4O  CH3OH

½âÎö£º(1)m(H2O)=102.9 g-101.1 g=1.8 g

ÓÉCO2¡ªCaCO3

m(CO2)=314.2 g-312.0 g=2.2 g

 

 

(4)m(C)¡Ãm(H)=0.6 g¡Ã0.2 g=3¡Ã1

(5)¸ÃȼÁÏ·Ö×Ó×é³ÉÖÐN(C)¡ÃN(H)=¡Ã=1¡Ã4£¬ÓÖ֪ÿ¸ö·Ö×ÓÖк¬1¸öÑõÔ­×Ó£¬ÓÉÓڸ÷Ö×ÓN(C)¡ÃN(H)ÒÑ´ïµ½±¥ºÍ½á¹¹£¬¹Ê·Ö×ÓʽΪCH4O£¬½á¹¹¼òʽΪCH3OH¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÒÑ֪ijÖÖȼÁϺ¬ÓÐ̼¡¢Çâ¡¢ÑõÈýÖÖÔªËØ¡£ÎªÁ˲ⶨÕâÖÖȼÁÏÖÐ̼ºÍÇâÁ½ÖÖÔªËصÄÖÊÁ¿±È£¬¿É½«Æø̬ȼÁÏ·ÅÈë×ãÁ¿µÄÑõÆøÖÐȼÉÕ£¬²¢Ê¹²úÉúµÄÆøÌåÈ«²¿Í¨ÈëÈçÉÏͼËùʾµÄ×°Ö㬵õ½ÈçϱíËùÁеÄʵÑé½á¹û£¨¼ÙÉè²úÉúµÄÆøÌåÍêÈ«±»ÎüÊÕ£©£º

ʵÑéÇ°

ʵÑéºó

£¨¸ÉÔï¼Á+UÐιܣ©µÄÖÊÁ¿

101.1 g

102.9 g

£¨Ê¯»ÒË®+¹ã¿ÚÆ¿£©µÄÖÊÁ¿

312.0 g

314.2 g

¸ù¾ÝʵÑéÊý¾ÝÍê³ÉÏÂÁÐÎÊÌ⣺

£¨1£©ÊµÑéÍê±Ïºó£¬Éú³ÉÎïÖÐË®µÄÖÊÁ¿Îª_______________g£¬¼ÙÉè¹ã¿ÚÆ¿ÀïÉú³ÉÒ»ÖÖÕýÑΣ¬ÆäÖÊÁ¿Îª_______________ g¡£

£¨2£©Éú³ÉµÄË®ÖÐÇâÔªËصÄÖÊÁ¿Îª_______________ g¡£

£¨3£©Éú³ÉµÄ¶þÑõ»¯Ì¼ÖÐ̼ԪËصÄÖÊÁ¿Îª_______________ g¡£

£¨4£©¸ÃȼÁÏÖÐ̼ԪËØÓëÇâÔªËصÄÖÊÁ¿±ÈΪ_______________¡£

£¨5£©ÒÑÖªÕâÖÖȼÁϵÄÿ¸ö·Ö×ÓÖÐÖ»Äܺ¬ÓÐÒ»¸öÑõÔ­×Ó£¬Ôò¸ÃȼÁϵķÖ×ÓʽΪ______________,½á¹¹¼òʽΪ_______________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012ÄêÈ˽̰æ¸ßÖл¯Ñ§±ØÐÞ¶þ4.2 »¯Ñ§Óë×ÊÔ´×ÛºÏÀûÓû·¾³±£»¤Á·Ï°¾í£¨½âÎö°æ£© ÌâÐÍ£º¼ÆËãÌâ

ÒÑ֪ijÖÖȼÁϺ¬ÓÐ̼¡¢Çâ¡¢Ñõ3ÖÖÔªËØ¡£ÎªÁ˲ⶨÕâÖÖȼÁÏÖÐ̼ºÍÇâÁ½ÖÖÔªËصÄÖÊÁ¿±È£¬¿É½«Æø̬ȼÁÏ·ÅÈë×ãÁ¿µÄÑõÆøÖÐȼÉÕ£¬²¢Ê¹²úÉúµÄÆøÌåÈ«²¿Í¨ÈëÈçͼËùʾµÄ×°Ö㬵õ½ÈçϱíËùÁеÄʵÑé½á¹û(¼ÙÉè²úÉúµÄÆøÌåÍêÈ«±»ÎüÊÕ)

 

 

ʵÑéÇ°

ʵÑéºó

(¸ÉÔï¼Á£«UÐιÜ)µÄÖÊÁ¿

101.1 g

102.9 g

(ʯ»ÒË®£«¹ã¿ÚÆ¿)µÄÖÊÁ¿

312.0 g

314.2 g

¸ù¾ÝʵÑéÊý¾ÝÇó£º

(1)ʵÑéÍê±Ïºó£¬Éú³ÉÎïÖÐË®ÖÊÁ¿Îª________g£¬¼ÙÉè¹ã¿ÚÆ¿ÀïÉú³ÉÒ»ÖÖÕýÑΣ¬ÆäÖÊÁ¿Îª________g£»

(2)Éú³ÉµÄË®ÖÐÇâÔªËصÄÖÊÁ¿Îª________g£»

(3)Éú³ÉµÄ¶þÑõ»¯Ì¼ÖÐ̼ԪËصÄÖÊÁ¿Îª________g£»

(4)¸ÃȼÁÏÖÐ̼ԪËØÓëÇâÔªËصÄÖÊÁ¿±ÈΪ________£»

(5)ÒÑÖªÕâÖÖȼÁϵÄÿ¸ö·Ö×ÓÖк¬ÓÐÒ»¸öÑõÔ­×Ó£¬Ôò¸ÃȼÁϵķÖ×ÓʽΪ________£¬½á¹¹¼òʽΪ________¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£ºÍ¬²½Ìâ ÌâÐÍ£ºÊµÑéÌâ

ÒÑ֪ijÖÖȼÁϺ¬ÓÐ̼¡¢Çâ¡¢Ñõ3ÖÖÔªËØ¡£ÎªÁ˲ⶨÕâÖÖȼÁÏÖÐ̼ºÍÇâ2ÖÖÔªËصÄÖÊÁ¿±È£¬¿É½«Æø̬ȼÁÏ·ÅÈë×ãÁ¿µÄO2ÖÐȼÉÕ£¬²¢½«²úÉúµÄÆøÌåÈ«²¿Í¨¹ýÏÂͼËùʾװÖ㬵õ½ÈçϱíËùÁеÄʵÑéÊý¾Ý£¨¼ÙÉè²úÉúµÄÆøÌåÍêÈ«±»ÎüÊÕ£©¡£
¸ù¾ÝʵÑéÊý¾ÝÌî¿Õ£º
(1)ʵÑéÍê±Ïºó£¬Éú³ÉÎïÖÐË®µÄÖÊÁ¿Îª__________g£¬¼ÙÉè¹ã¿ÚÆ¿ÀïÉú³É1ÖÖÕýÑΣ¬ÆäÖÊÁ¿Îª________ g¡£
(2)Éú³ÉµÄË®ÖÐÇâÔªËصÄÖÊÁ¿Îª______________g¡£
(3)Éú³ÉµÄCO2ÖÐ̼ԪËصÄÖÊÁ¿Îª____________g¡£
(4)¸ÃȼÁÏÖÐ̼¡¢ÇâÔªËØÖÊÁ¿±ÈΪ____________¡£
(5)ÒÑÖªÕâÖÖȼÁϵÄÿ¸ö·Ö×ÓÖÐÖ»ÓÐ1¸öÑõÔ­×Ó£¬Ôò¸ÃȼÁϵķÖ×ÓʽΪ________£¬½á¹¹¼òʽΪ__________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÒÑ֪ijÖÖȼÁϺ¬ÓÐ̼¡¢Çâ¡¢Ñõ3ÖÖÔªËØ¡£ÎªÁ˲ⶨÕâÖÖȼÁÏÖÐ̼ºÍÇâ2ÖÖÔªËصÄÖÊÁ¿±È£¬¿É½«Æø̬ȼÁÏ·ÅÈë×ãÁ¿µÄÑõÆøÖÐȼÉÕ£¬²¢Ê¹²úÉúµÄÆøÌåÈ«²¿Í¨ÈëÈçͼËùʾµÄ×°Ö㬵õ½ÈçϱíËùÁеÄʵÑé½á¹û£¨¼ÙÉè²úÉúµÄÆøÌåÍêÈ«±»ÎüÊÕ£©£º

 

ʵÑéÇ°

ʵÑéºó

£¨¸ÉÔï¼Á+UÐιܣ©µÄÖÊÁ¿

101.1 g

102.9 g

£¨Ê¯»ÒË®+¹ã¿ÚÆ¿£©µÄÖÊÁ¿

312.0 g

314.2 g

                           

¸ù¾ÝʵÑéÊý¾ÝÇó£º

£¨1£©ÊµÑéÍê±Ïºó£¬Éú³ÉÎïÖÐË®µÄÖÊÁ¿Îª_________g¡£¼ÙÉè¹ã¿ÚÆ¿ÀïÉú³ÉÒ»ÖÖÕýÑΣ¬ÆäÖÊÁ¿Îª_________g¡£

£¨2£©¸ÃȼÁÏÖÐ̼ԪËØÓëÇâÔªËصÄÖÊÁ¿±ÈΪ_________¡£

£¨3£©ÒÑÖªÕâÖÖȼÁϵÄÿ¸ö·Ö×ÓÖк¬ÓÐÒ»¸öÑõÔ­×Ó£¬Ôò¸ÃȼÁϵķÖ×ÓʽΪ_________£¬½á¹¹¼òʽΪ_________¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸