(¹²9·Ö) ¢ÅÓÃpHÊÔÖ½²â¶¨ÈÜÒºµÄpH£¬ÕýÈ·²Ù×÷ÊÇ£º    ¡ø    

¢ÆÔÚ25¡æÌõ¼þϽ«pH=11µÄ°±Ë®Ï¡ÊÍ100±¶ºóÈÜÒºµÄpHΪ£¨ÌîÐòºÅ£©   ¡ø   ¡£

A£®9         B£®13         C£®11¡«13Ö®¼ä        D£®9¡«11Ö®¼ä

¢Ç25¡æʱ£¬Ïò0.1mol/LµÄ°±Ë®ÖмÓÈëÉÙÁ¿ÂÈ»¯ï§¹ÌÌ壬µ±¹ÌÌåÈܽâºó£¬²âµÃÈÜÒºpH¼õС£¬Ö÷Òª£¨Ö±½ÓµÄ£©Ô­ÒòÊÇ£¨ÌîÐòºÅ£©   ¡ø   ¡£

A£®°±Ë®ÓëÂÈ»¯ï§·¢Éú»¯Ñ§·´Ó¦        B£®ÂÈ»¯ï§ÈÜҺˮ½âÏÔËáÐÔ£¬Ôö¼ÓÁËc(H+)

C£®ÂÈ»¯ï§ÈÜÓÚË®£¬µçÀë³ö´óÁ¿ï§Àë×Ó£¬ÒÖÖÆÁË°±Ë®µÄµçÀ룬ʹc(OH£­)¼õС

£¨¹²9·Ö£©

¢Å°ÑС¿épHÊÔÖ½·ÅÔÚ±íÃæÃ󣨻ò²£Á§Æ¬£©ÉÏ£¬ÓÃõ´Óдý²âÈÜÒºµÄ²£Á§°ôµãÔÚÊÔÖ½µÄÖв¿£¬ÊÔÖ½±äÉ«ºó£¬Óë±ê×¼±ÈÉ«¿¨±È½ÏÀ´È·¶¨ÈÜÒºµÄpH¡££¨3·Ö£©    

¢ÆD£¨3·Ö£©       ¢ÇC£¨3·Ö£©

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨¹²9·Ö£©ÏÖÓÃÈçͼËùʾµÄ×°ÖÃÖÆÈ¡½Ï¶àÁ¿µÄ±¥ºÍÂÈË®²¢²â¶¨±¥ºÍÂÈË®µÄpH¡£»Ø´ðÓйØÎÊÌ⣺

£¨1£©Ð´³öÓйػ¯Ñ§·½³Ìʽ¡£

×°Öüףº________________________£»

×°Öö¡£º          _____________ ¡£

£¨2£©Ö¤Ã÷ÂÈË®Òѱ¥ºÍµÄÏÖÏóÊÇ         ¡£

£¨3£©ÖÆÈ¡½áÊøʱ£¬×°ÖñûµÄÒºÌåÖк¬ÓÐ×î¶àµÄ΢Á£ÊÇ         £¨Ë®·Ö×Ó³ýÍ⣩£»

×°ÖÃÒÒµÄ×÷ÓÃÊÇ                    ¡£

£¨4£©ÓÐÈçϸĽø´ëÊ©»ò½¨Ò飬Çë×÷³öÆÀ¼Û£º

¢ÙÔÚ×°ÖÃÒҺͱûÖ®¼äÔö¼ÓÈçͼ£¨a£©ËùʾµÄ×°Öã¬ÄãÈÏΪÓÐÎÞ±ØÒª£¿         ¡£

¢ÚÔÚ×°ÖñûµÄ³¤µ¼¹ÜÏ¿ڴ¦£¬½ÓÈçͼ£¨b£©ËùʾµÄ¶à¿×ÇòÅÝ£¬ÕâÑù×öµÄºÃ´¦ÊÇ£º                ¡£

¢ÛÈô³·È¥×°ÖÃÒÒ£¬Ö±½Ó½«×°Öü׺ͱûÏàÁ¬¡£ÕâÑù×ö¶ÔʵÑé½á¹ûµÄÓ°ÏìÊÇ£º

                                                         ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨¹²9·Ö,ÿ¿Õ1·Ö£©ÎïÖÊÔÚË®ÖпÉÄÜ´æÔÚµçÀëƽºâ¡¢ÑεÄË®½âƽºâºÍ³ÁµíµÄÈܽâƽºâ£¬ËüÃǶ¼¿É¿´×÷»¯Ñ§Æ½ºâ¡£Çë¸ù¾ÝËùѧ֪ʶµÄ»Ø´ð£º

£¨1£©AΪ0.1mol¡¤L£­1µÄ(NH4)2SO4ÈÜÒº£¬ÔÚ¸ÃÈÜÒºÖи÷ÖÖÀë×ÓµÄŨ¶ÈÓÉ´óµ½Ð¡Ë³ÐòΪ

                                                                 ¡£

£¨2£©BΪ0.1mol¡¤L£­1NaHCO3ÈÜÒº£¬ÔÚNaHCO3ÈÜÒºÖдæÔڵĸ÷ÖÖƽºâÌåϵΪ£¨ÓÃÀë×Ó·½

³Ìʽ±íʾ£©£º                             £»                              £»

ʵÑé²âµÃNaHCO3ÈÜÒºµÄpH > 7£¬Çë·ÖÎöNaHCO3ÈÜÒºÏÔ¼îÐÔµÄÔ­Òò£º

                                                                   ¡£

 £¨3£©CΪFeCl3ÈÜÒº£¬ÊµÑéÊÒÖÐÅäÖÆFeCl3ÈÜҺʱͨ³£ÐèÒªÏòÆäÖмÓÈë              ,Ä¿µÄÊÇ                                                          £»

Èô°ÑBºÍCÈÜÒº»ìºÏ£¬½«²úÉúºìºÖÉ«³ÁµíºÍÎÞÉ«ÆøÌ壬¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽΪ

                                                                   ¡£

£¨4£©DΪº¬ÓÐ×ãÁ¿AgCl¹ÌÌåµÄ±¥ºÍÈÜÒº£¬ÂÈ»¯ÒøÔÚË®ÖдæÔÚ³ÁµíÈܽâƽºâ£º

        AgCl(S)  Ag+(aq)+ Cl£­(aq) ÔÚ25¡æʱ£¬ÂÈ»¯ÒøµÄKsp = 1.8¡Á10£­10

25¡æʱ£¬ÏÖ½«×ãÁ¿ÂÈ»¯Òø·Ö±ð·ÅÈ룺¢Ù100mLÕôÁóË®ÖУ»¢Ú100mL 0.2 mol¡¤L£­1AgNO3ÈÜÒºÖУ»¢Û100mL 0.1 mol¡¤L£­1ÂÈ»¯ÂÁÈÜÒºÖУ»¢Ü100mL 0.1 mol¡¤L£­1ÑÎËáÈÜÒºÖС£³ä·Ö½Á¶¶ºó£¬ÏàͬζÈÏÂÒøÀë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ                        £¨ÌîдÐòºÅ£©£»¢ÚÖÐÂÈÀë×ÓµÄŨ¶ÈΪ                 mol¡¤L£­1

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010ÄêÕã½­Ê¡Õ㶫±±ÈýУ¸ß¶þµÚ¶þѧÆÚÆÚÖÐÁª¿¼»¯Ñ§ÊÔÌâ ÌâÐÍ£ºÌî¿ÕÌâ

£¨¹²9·Ö,ÿ¿Õ1·Ö£©ÎïÖÊÔÚË®ÖпÉÄÜ´æÔÚµçÀëƽºâ¡¢ÑεÄË®½âƽºâºÍ³ÁµíµÄÈܽâƽºâ£¬ËüÃǶ¼¿É¿´×÷»¯Ñ§Æ½ºâ¡£Çë¸ù¾ÝËùѧ֪ʶµÄ»Ø´ð£º
£¨1£©AΪ0.1 mol¡¤L£­1µÄ(NH4)2SO4ÈÜÒº£¬ÔÚ¸ÃÈÜÒºÖи÷ÖÖÀë×ÓµÄŨ¶ÈÓÉ´óµ½Ð¡Ë³ÐòΪ
                                                                 ¡£
£¨2£©BΪ0.1 mol¡¤L£­1NaHCO3ÈÜÒº£¬ÔÚNaHCO3ÈÜÒºÖдæÔڵĸ÷ÖÖƽºâÌåϵΪ£¨ÓÃÀë×Ó·½
³Ìʽ±íʾ£©£º                             £»                              £»
ʵÑé²âµÃNaHCO3ÈÜÒºµÄpH > 7£¬Çë·ÖÎöNaHCO3ÈÜÒºÏÔ¼îÐÔµÄÔ­Òò£º
                                                                   ¡£
£¨3£©CΪFeCl3ÈÜÒº£¬ÊµÑéÊÒÖÐÅäÖÆFeCl3ÈÜҺʱͨ³£ÐèÒªÏòÆäÖмÓÈë              ,Ä¿µÄÊÇ                                                          £»
Èô°ÑBºÍCÈÜÒº»ìºÏ£¬½«²úÉúºìºÖÉ«³ÁµíºÍÎÞÉ«ÆøÌ壬¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽΪ
                                                                   ¡£
£¨4£©DΪº¬ÓÐ×ãÁ¿AgCl¹ÌÌåµÄ±¥ºÍÈÜÒº£¬ÂÈ»¯ÒøÔÚË®ÖдæÔÚ³ÁµíÈܽâƽºâ£º
AgCl(S)  Ag+(aq)+ Cl£­(aq) ÔÚ25¡æʱ£¬ÂÈ»¯ÒøµÄKsp = 1.8¡Á10£­10
25¡æʱ£¬ÏÖ½«×ãÁ¿ÂÈ»¯Òø·Ö±ð·ÅÈ룺¢Ù100mLÕôÁóË®ÖУ»¢Ú100mL 0.2 mol¡¤L£­1AgNO3ÈÜÒºÖУ»¢Û100mL 0.1 mol¡¤L£­1ÂÈ»¯ÂÁÈÜÒºÖУ»¢Ü100mL 0.1 mol¡¤L£­1ÑÎËáÈÜÒºÖС£³ä·Ö½Á¶¶ºó£¬ÏàͬζÈÏÂÒøÀë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ                        £¨ÌîдÐòºÅ£©£»¢ÚÖÐÂÈÀë×ÓµÄŨ¶ÈΪ                 mol¡¤L£­1

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2014½ìɽÎ÷Ê¡¸ßÒ»2ÔÂÔ¿¼»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÊµÑéÌâ

£¨¹²9·Ö£©ÏÖÓÃÈçͼËùʾµÄ×°ÖÃÖÆÈ¡½Ï¶àÁ¿µÄ±¥ºÍÂÈË®²¢²â¶¨±¥ºÍÂÈË®µÄpH¡£»Ø´ðÓйØÎÊÌ⣺

£¨1£©Ð´³öÓйػ¯Ñ§·½³Ìʽ¡£

×°Öüףº________________________£»

×°Öö¡£º           _____________ ¡£

£¨2£©Ö¤Ã÷ÂÈË®Òѱ¥ºÍµÄÏÖÏóÊÇ         ¡£

£¨3£©ÖÆÈ¡½áÊøʱ£¬×°ÖñûµÄÒºÌåÖк¬ÓÐ×î¶àµÄ΢Á£ÊÇ          £¨Ë®·Ö×Ó³ýÍ⣩£»

×°ÖÃÒÒµÄ×÷ÓÃÊÇ                     ¡£

£¨4£©ÓÐÈçϸĽø´ëÊ©»ò½¨Ò飬Çë×÷³öÆÀ¼Û£º

¢ÙÔÚ×°ÖÃÒҺͱûÖ®¼äÔö¼ÓÈçͼ£¨a£©ËùʾµÄ×°Öã¬ÄãÈÏΪÓÐÎÞ±ØÒª£¿          ¡£

¢ÚÔÚ×°ÖñûµÄ³¤µ¼¹ÜÏ¿ڴ¦£¬½ÓÈçͼ£¨b£©ËùʾµÄ¶à¿×ÇòÅÝ£¬ÕâÑù×öµÄºÃ´¦ÊÇ£º                 ¡£

¢ÛÈô³·È¥×°ÖÃÒÒ£¬Ö±½Ó½«×°Öü׺ͱûÏàÁ¬¡£ÕâÑù×ö¶ÔʵÑé½á¹ûµÄÓ°ÏìÊÇ£º

                                                          ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010ÄêÕã½­Ê¡Õ㶫±±ÈýУ¸ß¶þµÚ¶þѧÆÚÆÚÖÐÁª¿¼»¯Ñ§ÊÔÌâ ÌâÐÍ£ºÌî¿ÕÌâ

£¨¹²9·Ö,ÿ¿Õ1·Ö£©ÎïÖÊÔÚË®ÖпÉÄÜ´æÔÚµçÀëƽºâ¡¢ÑεÄË®½âƽºâºÍ³ÁµíµÄÈܽâƽºâ£¬ËüÃǶ¼¿É¿´×÷»¯Ñ§Æ½ºâ¡£Çë¸ù¾ÝËùѧ֪ʶµÄ»Ø´ð£º

£¨1£©AΪ0.1 mol¡¤L£­1µÄ(NH4)2SO4ÈÜÒº£¬ÔÚ¸ÃÈÜÒºÖи÷ÖÖÀë×ÓµÄŨ¶ÈÓÉ´óµ½Ð¡Ë³ÐòΪ

                                                                  ¡£

£¨2£©BΪ0.1 mol¡¤L£­1NaHCO3ÈÜÒº£¬ÔÚNaHCO3ÈÜÒºÖдæÔڵĸ÷ÖÖƽºâÌåϵΪ£¨ÓÃÀë×Ó·½

³Ìʽ±íʾ£©£º                              £»                               £»

ʵÑé²âµÃNaHCO3ÈÜÒºµÄpH > 7£¬Çë·ÖÎöNaHCO3ÈÜÒºÏÔ¼îÐÔµÄÔ­Òò£º

                                                                    ¡£

 £¨3£©CΪFeCl3ÈÜÒº£¬ÊµÑéÊÒÖÐÅäÖÆFeCl3ÈÜҺʱͨ³£ÐèÒªÏòÆäÖмÓÈë               ,Ä¿µÄÊÇ                                                           £»

Èô°ÑBºÍCÈÜÒº»ìºÏ£¬½«²úÉúºìºÖÉ«³ÁµíºÍÎÞÉ«ÆøÌ壬¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽΪ

                                                                    ¡£

£¨4£©DΪº¬ÓÐ×ãÁ¿AgCl¹ÌÌåµÄ±¥ºÍÈÜÒº£¬ÂÈ»¯ÒøÔÚË®ÖдæÔÚ³ÁµíÈܽâƽºâ£º

        AgCl(S)  Ag+(aq)+ Cl£­(aq) ÔÚ25¡æʱ£¬ÂÈ»¯ÒøµÄKsp = 1.8¡Á10£­10

25¡æʱ£¬ÏÖ½«×ãÁ¿ÂÈ»¯Òø·Ö±ð·ÅÈ룺¢Ù100mLÕôÁóË®ÖУ»¢Ú100mL 0.2 mol¡¤L£­1AgNO3ÈÜÒºÖУ»¢Û100mL 0.1 mol¡¤L£­1ÂÈ»¯ÂÁÈÜÒºÖУ»¢Ü100mL 0.1 mol¡¤L£­1ÑÎËáÈÜÒºÖС£³ä·Ö½Á¶¶ºó£¬ÏàͬζÈÏÂÒøÀë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ                         £¨ÌîдÐòºÅ£©£»¢ÚÖÐÂÈÀë×ÓµÄŨ¶ÈΪ                  mol¡¤L£­1

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸