(6·Ö)£¨1£©Ö¤Ã÷¹¤Òµ¾Æ¾«Öк¬ÓÐÉÙÁ¿Ë®·Ý£¬¿ÉÑ¡ÓõÄÊÔ¼ÁΪ                      ¡£

£¨2£©³ýÈ¥±½ÖлìÓеÄÉÙÁ¿±½·Ó£¬Ó¦ÏȼÓÈë             ÈÜÒº³ä·ÖÕñµ´ºó¾²Öã¬ÔÙÓà       ·½·¨·ÖÀë¡£

£¨3£©É½Î÷¼Ù¾Æ°¸Ôøºä¶¯È«¹ú£¬Ê¹¶àÈËÊܶ¾º¦ÖÂËÀµÄÎïÖÊÊÇ                  £¬ÔÚËüµÄͬϵÎïÖУ¬²»ÄÜ·¢Éú·Ö×ÓÄÚÏûÈ¥·´Ó¦Ïà¶Ô·Ö×ÓÖÊÁ¿×îСµÄÎïÖʵķÖ×ÓʽÊÇ                  ¡£

£¨4£©Éè¼ÆÑéÖ¤äåÒÒÍéÖк¬ÓÐäåÔªËصÄʵÑ飬ÏÂÁÐÊÔ¼Á£º ¢ÙNaOHÈÜÒº    ¢ÚAgNO3ÈÜÒº    ¢ÛKIÈÜÒº¢ÜÏ¡ÏõËá ¢ÝCCl4 ¢ÞË®£¬ ÆäÖбØÐëÓõ½µÄÊÇ£¨°´Ê¹ÓÃÏȺó˳Ðò£©                ¡£

£¨1£©ÎÞË®ÁòËáÍ­·ÛÄ©£»

£¨2£©NaOHÈÜÒº£»·ÖÒº£»

£¨3£©¼×´¼£¨»òCH3OH£©£»C5H12O£»

£¨4£©¢Ù¢Ü¢Ú

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

д³öÏÂÁл¯Ñ§·½³Ìʽ£¨¹²6·Ö£©

(1) ÒÒȲÓëÂÈ»¯Çâ°´ÎïÖʵÄÁ¿±È1£º1·´Ó¦                                     

 

(2) ±½ÓëŨÏõËᡢŨÁòËáµÄ»ìºÏËá¹²ÈÈ__________                                         

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ÄêÕã½­Ê¡ÉÜÐËÒ»ÖиßÒ»ÉÏѧÆÚÆÚÖп¼ÊÔ»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÊµÑéÌâ

(6·Ö)£¨1£©ÓÃ18.0 mol/L H2SO4ÅäÖÆ100 mL 1.00mol/L H2SO4£¬ÔòÐèÒªµÄʵÑéÒÇÆ÷³ýÁËÉÕ±­¡¢²£Á§°ô¡¢½ºÍ·µÎ¹ÜÒÔÍ⻹Ӧ¸ÃÓУº______
ÅäÖƹý³ÌÖУ¬ÏÂÁÐÇé¿ö»áʹÅäÖƽá¹ûÆ«¸ßµÄÊÇ(ÌîÐòºÅ)____  
¢Ù¶¨ÈÝÊǸ©Êӿ̶ÈÏß¹Û²ìÒºÃæ
¢ÚÈÝÁ¿Æ¿Ê¹ÓÃʱδ¸ÉÔï
¢Û¶¨Èݺó¾­Õñµ´¡¢Ò¡ÔÈ¡¢¾²Ö㬷¢ÏÖÒºÃæµÍÓڿ̶ÈÏߣ¬ÔÙ¼ÓÕôÁóË®²¹ÖÁ¿Ì¶È
¢ÜÈÝÁ¿Æ¿Ê¢¹ýH2SO4ÈÜÒº£¬Ê¹ÓÃǰδϴµÓ
£¨2£©ÔÚÈÝÁ¿Æ¿Ê¹Ó÷½·¨ÖУ¬ÏÂÁвÙ×÷²»ÕýÈ·µÄÊÇ(Ìî×Öĸ)_________
A£®Ê¹ÓÃÈÝÁ¿Æ¿Ç°¼ì²éËüÊÇ·ñ©ˮ
B£®ÈÝÁ¿Æ¿ÓÃÕôÁóˮϴ¾»ºó£¬ÔÙÓôýÅäÒºÈóÏ´
C£®ÅäÖÆÈÜҺʱ£¬Èç¹ûÊÔÑùÊÇÒºÌ壬ÓÃÁ¿Í²Á¿È¡ÊÔÑùºóÖ±½Óµ¹ÈëÈÝÁ¿Æ¿ÖУ¬»ºÂý¼ÓÈëÕôÁóË®µ½½Ó½ü±êÏß1¡«2©M´¦£¬ÔÙ¸ÄÓýºÍ·µÎ¹Ü¼ÓÕôÁóË®µ½¿Ì¶ÈÏß
D£®¸ÇºÃÆ¿Èû£¬ÓÃʳָ¶¥×¡Æ¿Èû£¬ÓÃÁíÒ»Ö»ÊÖÍÐסƿµ×,°ÑÈÝÁ¿Æ¿µ¹×ªÒ¡ÔÈ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

(6·Ö)½»¾¯ÎªÈ·¶¨¼ÝʻԱÊÇ·ñ¾Æ×íºó¼Ý³µ£¬³£²ÉÓúôÎü²â×í·ÖÎö·¨¡£ÔÚ310Kʱȡ50.0cm3±»¼ì²âÈ˵ĺôÎüÑùÆ·¹ÄÅÝͨ¹ýËáÐÔÖظõËáÑÎÈÜÒº¡£ÓÉÓÚÒÒ´¼µÄ»¹Ô­×÷ÓòúÉúÁË3.30¡Á10£­5mol Cr(¢ó)£¬ÖظõËáÑεÄÏûºÄ¿ÉÓ÷ֹâ¹â¶È·¨²â¶¨¡£·¨ÂÉÉϹ涨ѪҺÖеÄÒÒ´¼º¬Á¿³¬¹ý0.05£¥(ÖÊÁ¿°Ù·ÖÊý)±ãËã¾Æ×í¡£Çë»Ø´ðÒÔÏÂÎÊÌ⣺

    (1) д³öÒÔÉϼì²â·´Ó¦µÄÀë×Ó·½³Ìʽ£º                                         

(2) Çëͨ¹ý¼ÆËãÈ·¶¨´ËÈËÊÇ·ñΪ·¨¶¨µÄ¾Æ×í¡£¼ÆËãÖмٶ¨£º310Kʱ£¬º¬ÓÐ0.45£¥ÒÒ´¼µÄѪҺÉÏÃæÒÒ´¼µÄ·ÖѹΪ1.00¡Á104Pa¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

(6·Ö)ÓÃNa2SO3¿ÉÒÔÖÎÀí¹¤ÒµSO2βÆøÎÛȾ£¬ÕâÊÇÒ»ÖÖÖÎÀíSO2ÎÛȾ±È½ÏÐÂÓ±µÄ·½·¨¡£¾ßÌå²Ù×÷£º¢Ù½«º¬ÓÐSO2ÆøÌåµÄβÆøͨÈëµ½Na2SO3ÈÜÒºÖУ¬·¢Éú»¯ºÏ·´Ó¦Éú³ÉNaHSO3£»¢Ú½«·´Ó¦ºóµÄÈÜÒº¼ÓÈÈ£¬¼´¿ÉÒݳöSO2ÆøÌ壬ÕâЩSO2¿ÉÒÔÓ¦ÓÃÓÚÖÆÈ¡H2SO4¡£¸Ã·½·¨ÖÐNa2SO3¿ÉÒÔÑ­»·Ê¹Ó㬷ûºÏÂÌÉ«»¯Ñ§µÄ»ù±¾Ô­Ôò¡£Çë¸ù¾ÝÉÏÊöÐÅÏ¢½â´ðÏÂÁÐÊÔÌ⣺

£¨1£©Ð´³ö¢Ù¡¢¢ÚÁ½²½µÄ»¯Ñ§·½³Ìʽ£º

¢Ù                                 £»¢Ú                                      ¡£

£¨2£©µ±89.6m3£¨±ê×¼×´¿ö£©º¬ÓÐSO2µÄβÆøͨÈëÈÜÒºÖÐʱ£¬Ç¡ºÃÓë10m3µÄ0.1mol/LµÄNa2SO3ÈÜÒº·¢Éú·´Ó¦¡£Çó¸ÃβÆøÖÐSO2ÆøÌåµÄÌå»ý·ÖÊý¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸